13 buckets of water fill a tank when the capacity of each bucket is 51 litres . how many buckets will be needed to fill the same tank , if the capacity of each bucket is 17 litres ?

Explanation: "capacity of the tank = ( 13 × 51 ) litre number of buckets required of capacity of each bucket is 17 litre = 13 × 51 / 17 = 13 × 3 = 39 answer is a"

<gadget id="calculator">51 * 13</gadget>
<output>663</output>
<gadget id="calculator">663 / 17</gadget>
<output>39</output>
<result>39</result>


a candidate appearing for an examination has to secure 55 % marks to pass paper i . but he secured only 45 marks and failed by 25 marks . what is the maximum mark for paper i ?

Explanation: he secured 45 marks nd fail by 25 marks so total marks for pass the examinatn = 70 let toal marks x x * 55 / 100 = 70 x = 127 answer : a

divide(add(45, 25), divide(55, const_100))

<gadget id="calculator">45 + 25</gadget>
<output>70</output>
<gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">70 / (11/20)</gadget>
<output>1_400/11 = around 127.272727</output>
<result>1_400/11 = around 127.272727</result>


by selling 15 pencils for a rupee a man loses 20 % . how many for a rupee should he sell in order to gain 20 % ?

Explanation: "80 % - - - 15 120 % - - - ? 80 / 120 * 15 = 10 answer : e"

multiply(divide(const_1, multiply(add(const_100, 20), divide(const_1, subtract(const_100, 20)))), 15)

<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">120 * (1/80)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">1 / (3/2)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 15</gadget>
<output>10</output>
<result>10</result>


a sum of money is to be divided among ann , bob and chloe . first , ann receives $ 4 plus one - half of what remains . next , bob receives $ 4 plus one - third of what remains . finally , chloe receives the remaining $ 32 . how much money n did bob receive ?

Explanation: "notice that we need not consider ann ' s portion in the solution . we can just let k = the money remaining after ann has received her portion and go from there . our equation will use the fact that , once we remove bob ' s portion , we have $ 32 for chloe . so , we getk - bob ' s $ = 32 bob received 4 dollars plus one - third of what remained once bob receives $ 4 , the amount remaining is k - 4 dollars . so , bob gets a 1 / 3 of that as well . 1 / 3 of k - 4 is ( k - 4 ) / 3 so altogether , bob receives 4 + ( k - 4 ) / 3 so , our equation becomes : k - [ 4 + ( k - 4 ) / 3 ] = 32 simplify to get : k - 4 - ( k - 4 ) / 3 = 32 multiply both sides by 3 to get : 3 k - 12 - k + 4 = 96 simplify : 2 k - 8 = 96 solve : k = 52 plug this k - value intok - bob ' s $ = 32 to get : 52 - bob ' s $ = 32 so , bob ' s $ n = 20 answer : b"

<gadget id="calculator">32 * 2</gadget>
<output>64</output>
<gadget id="calculator">64 / 3</gadget>
<output>64/3 = around 21.333333</output>
<result>64/3 = around 21.333333</result>


two trains leave a station traveling the same direction . train a leaves the station traveling at a constant speed of 60 mph , and train b leaves the station traveling at a constant speed of 80 mph . if both trains maintain constant speeds , in how many minutes will train b overtake train a if train a left 40 minutes prior to train b ?

Explanation: we can use d = rt [ distance = rate * time ] train a will have traveled for 40 minutes longer than train b when b overtakes a , so time of train a : t + 40 minutes = t + ( 2 / 3 ) hours ( use hours since the rate is in hours ) time of train b : t rate of train a : 60 mph rate of train b : 80 mph the distances traveled by each will be equal when train b overtakes train a , so we can set the right sides of d = rt equal for the two trains ( rate of train a ) * ( time of train a ) = ( rate of train b ) * ( time of train b ) 60 * ( t + 2 / 3 ) = 80 * t 60 t + 40 = 80 t 40 = 20 t 2 = t 2 hours = 120 minutes d

multiply(divide(multiply(divide(40, const_60), 60), subtract(80, 60)), const_60)

<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 60</gadget>
<output>40</output>
<gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<result>120</result>


if the average of 5 positive integers is 50 and the difference between the largest and the smallest of these 5 numbers is 10 , what is the maximum value possible for the largest of these 5 integers ?

Explanation: sum of 5 integer ( a , b , c , d , e ) = 5 * 50 = 250 e - a = 10 i . e . e = a + 10 for e to be maximum remaining 4 must be as small as possible since smallest of 5 numbers is a so to minimize other numbers we can take them equal to the smallest of 5 numbers i . e . a + a + a + a + ( a + 10 ) = 250 i . e . 5 a = 240 i . e . a = 48 i . e . largest e = 48 + 10 = 58 answer : option b

add(divide(subtract(multiply(50, 5), 10), 5), 10)

<gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">250 - 10</gadget>
<output>240</output>
<gadget id="calculator">240 / 5</gadget>
<output>48</output>
<gadget id="calculator">48 + 10</gadget>
<output>58</output>
<result>58</result>


what is the smallest number which , when increased by 7 , is divisible by 8 , 11 , and 24 ?

Explanation: "lcm ( 8 , 11,24 ) = 24 x 11 = 264 so the least divisible number is 264 , and the number we are looking for is 264 - 7 = 257 . the answer is b ."

<gadget id="calculator">lcm(24, 11)</gadget>
<output>264</output>
<gadget id="calculator">264 - 7</gadget>
<output>257</output>
<result>257</result>


in a college the ratio of the numbers of boys to the girls is 8 : 5 . if there are 210 girls , the total number of students in the college is ?

Explanation: "let the number of boys and girls be 8 x and 5 x then , 5 x = 210 x = 42 total number of students = 13 x = 13 * 42 = 546 answer is e"

<gadget id="calculator">8 / 5</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 210</gadget>
<output>336</output>
<gadget id="calculator">336 + 210</gadget>
<output>546</output>
<result>546</result>


the grade point average of one third of the classroom is 15 ; the grade point average of the rest is 18 . what is the grade point average of the whole class ?

Explanation: "let n = total students in class total points for 1 / 3 class = 15 n / 3 = 5 n total points for 2 / 3 class = 18 * 2 n / 3 = 12 n total points for whole class = 5 n + 12 n = 17 n 17 n total class points / n total students = 17 grade point average for total class answer : a"

add(multiply(divide(18, const_3), const_2), divide(15, const_3))

<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">12 + 5</gadget>
<output>17</output>
<result>17</result>


if the operation @ is defined for all a and b by the equation a @ b = ( a - b ) / 5 , then ( 3 @ - 2 ) @ 6 = ?

Explanation: work within the parenthesis first so solve ( 3 @ - 2 ) first ( 3 @ - 2 ) = ( 3 - ( - 2 ) ) / 5 = ( 3 + 2 ) / 5 = 1 now take 1 plug back into equation and solve the rest ( 1 @ 6 ) = ( 1 - 6 ) / 5 = - 5 / 5 = - 1 so - 1 is the answer . . . . this question is merely testing order of operations remember pemdas answer is option : e

<gadget id="calculator">2 - 3</gadget>
<output>-1</output>
<result>-1</result>


a goods train runs at the speed of 72 km / hr and crosses a 250 m long platform in 15 sec . what is the length of the goods train ?

Explanation: "speed = 72 * 5 / 18 = 20 m / sec . time = 15 sec . let the length of the train be x meters . then , ( x + 250 ) / 15 = 20 x = 50 m . answer : e"

subtract(multiply(multiply(divide(72, const_3600), const_1000), 15), 250)

<gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">300 - 250</gadget>
<output>50</output>
<result>50</result>


a goods train runs at the speed of 72 km / hr and crosses a 290 m long platform in 26 sec . what is the length of the goods train ?

Explanation: "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 290 ) / 26 = 20 x = 230 m . answer : d"

subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 290)

<gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 290</gadget>
<output>230</output>
<result>230</result>


the contents of a certain box consist of 24 oranges and 30 kiwis . how many kiwis must be added to the box so that exactly 30 % of the pieces of fruit in the box will be oranges ?

Explanation: oranges = ( oranges + kiwi + x ) * 0.3 24 = ( 30 + 24 + x ) * 0.3 x = 26 . answer : b .

divide(subtract(24, multiply(divide(30, const_100), add(24, 30))), divide(30, const_100))

<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">24 + 30</gadget>
<output>54</output>
<gadget id="calculator">(3/10) * 54</gadget>
<output>81/5 = around 16.2</output>
<gadget id="calculator">24 - (81/5)</gadget>
<output>39/5 = around 7.8</output>
<gadget id="calculator">(39/5) / (3/10)</gadget>
<output>26</output>
<result>26</result>


if s is the sum of reciprocals of a list of consecutive integers from 55 to 64 , inclusive , s is approximately equal to

Explanation: we need to find the approximate value of 1 / 55 + 1 / 56 + 1 / 57 + 1 / 58 + 1 / 59 + 1 / 60 + 1 / 61 + 1 / 62 + 1 / 63 + 1 / 64 . now , the sum of these 10 terms will be very close to 10 times 1 / 60 , which is 0.016 * 10 = 0.16 . answer : a .

add(add(add(add(add(add(add(add(divide(const_1, 55), divide(const_1, add(55, const_1))), divide(const_1, add(add(55, const_1), const_1))), divide(const_1, add(add(add(55, const_1), const_1), const_1))), divide(const_1, add(add(add(add(55, const_1), const_1), const_1), const_1))), divide(const_1, add(add(add(add(add(55, const_1), const_1), const_1), const_1), const_1))), divide(const_1, add(add(add(add(add(add(add(55, const_1), const_1), const_1), const_1), const_1), const_1), const_1))), divide(const_1, add(add(add(add(add(add(add(add(55, const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1))), divide(const_1, 64))

<gadget id="calculator">1 / 55</gadget>
<output>1/55 = around 0.018182</output>
<gadget id="calculator">55 + 1</gadget>
<output>56</output>
<gadget id="calculator">1 / 56</gadget>
<output>1/56 = around 0.017857</output>
<gadget id="calculator">(1/55) + (1/56)</gadget>
<output>111/3_080 = around 0.036039</output>
<gadget id="calculator">56 + 1</gadget>
<output>57</output>
<gadget id="calculator">1 / 57</gadget>
<output>1/57 = around 0.017544</output>
<gadget id="calculator">(111/3_080) + (1/57)</gadget>
<output>9_407/175_560 = around 0.053583</output>
<gadget id="calculator">57 + 1</gadget>
<output>58</output>
<gadget id="calculator">1 / 58</gadget>
<output>1/58 = around 0.017241</output>
<gadget id="calculator">(9_407/175_560) + (1/58)</gadget>
<output>360_583/5_091_240 = around 0.070824</output>
<gadget id="calculator">58 + 1</gadget>
<output>59</output>
<gadget id="calculator">1 / 59</gadget>
<output>1/59 = around 0.016949</output>
<gadget id="calculator">(360_583/5_091_240) + (1/59)</gadget>
<output>26_365_637/300_383_160 = around 0.087773</output>
<gadget id="calculator">59 + 1</gadget>
<output>60</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(26_365_637/300_383_160) + (1/60)</gadget>
<output>10_457_341/100_127_720 = around 0.10444</output>
<gadget id="calculator">60 + 1</gadget>
<output>61</output>
<gadget id="calculator">61 + 1</gadget>
<output>62</output>
<gadget id="calculator">1 / 62</gadget>
<output>1/62 = around 0.016129</output>
<gadget id="calculator">(10_457_341/100_127_720) + (1/62)</gadget>
<output>374_241_431/3_103_959_320 = around 0.120569</output>
<gadget id="calculator">62 + 1</gadget>
<output>63</output>
<gadget id="calculator">1 / 63</gadget>
<output>1/63 = around 0.015873</output>
<gadget id="calculator">(374_241_431/3_103_959_320) + (1/63)</gadget>
<output>3_811_595_639/27_935_633_880 = around 0.136442</output>
<gadget id="calculator">1 / 64</gadget>
<output>1/64 = around 0.015625</output>
<gadget id="calculator">(3_811_595_639/27_935_633_880) + (1/64)</gadget>
<output>33_984_719_347/223_485_071_040 = around 0.152067</output>
<result>33_984_719_347/223_485_071_040 = around 0.152067</result>


a swimmer swims downstream 55 km and upstream 10 km taking 5 hours each time ; what is the speed of the current ?

Explanation: 55 - - - 5 ds = 11 ? - - - - 1 10 - - - - 5 us = 2 ? - - - - 1 s = ? s = ( 11 - 2 ) / 2 = 4.5 answer : b

divide(subtract(divide(55, 5), divide(10, 5)), const_2)

<gadget id="calculator">55 / 5</gadget>
<output>11</output>
<gadget id="calculator">10 / 5</gadget>
<output>2</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<result>9/2 = around 4.5</result>


a is half good a work man as b and together they finish a job in 13 days . in how many days working alone b finish the job ?

Explanation: c 39 / 2 wc = 1 : 2 2 x + x = 1 / 13 = > x = 1 / 39 2 x = 2 / 39 = > 39 / 2 days

<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">13 * (3/2)</gadget>
<output>39/2 = around 19.5</output>
<result>39/2 = around 19.5</result>


33 persons can repair a road in 12 days , working 5 hours a day . in how many days will 30 persons , working 6 hours a day , complete the work ?

Explanation: let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 30 : 33 : : 12 : x working hours / day 6 : 5 30 x 6 x x = 33 x 5 x 12 x = ( 33 x 5 x 12 ) / ( 30 x 6 ) x = 11 answer b

divide(multiply(multiply(33, 12), 5), multiply(30, 6))

<gadget id="calculator">33 * 12</gadget>
<output>396</output>
<gadget id="calculator">396 * 5</gadget>
<output>1_980</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">1_980 / 180</gadget>
<output>11</output>
<result>11</result>


the diagonal of a rectangle is √ 41 cm and its area is 20 sq . cm . the perimeter of the rectangle must be :

Explanation: explanation : l 2 + b 2 = 41 also , lb = 20 ( l + b ) 2 = l 2 + b 2 + 2 lb = 41 + 40 = 81 ( l + b ) = 9 perimeter = 2 ( l + b ) = 18 cm . answer : a

multiply(sqrt(add(power(sqrt(41), const_2), multiply(20, const_2))), const_2)

<gadget id="calculator">41 ** (1/2)</gadget>
<output>sqrt(41) = around 6.403124</output>
<gadget id="calculator">(sqrt(41)) ** 2</gadget>
<output>41</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">41 + 40</gadget>
<output>81</output>
<gadget id="calculator">81 ** (1/2)</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>18</result>


there is a square with sides of 12 . what is the circumference of the biggest circle that can be cut out of this square ?

Explanation: circumference of a circle = c = 2 ï € r square is 12 wide , so circle ' s diameter would be 12 , and radius would be 6 c = 2 ï € 6 which is approximately 37.7 answer is e

<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">2 * pi * 6</gadget>
<output>12*pi = around 37.699112</output>
<result>12*pi = around 37.699112</result>


Explanation: "answer 0.36 = 36 / 100 = 9 / 25 correct option : d"

divide(multiply(multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2)), 0.36), multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2)))

<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 0.36</gadget>
<output>36</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<result>9/25 = around 0.36</result>


a box contain the number of balls which is as much greater than 44 is less than 70 . the number of balls is ?

Explanation: answer let the number be x . then , x - 44 = 70 - x â ‡ ’ 2 x = 70 + 44 = 114 â ‡ ’ 2 x = 114 â ˆ ´ x = 57 correct option : e

<gadget id="calculator">70 + 44</gadget>
<output>114</output>
<gadget id="calculator">114 / 2</gadget>
<output>57</output>
<result>57</result>


robert ' s salary was decreased by 20 % and subsequently increased by 20 % . how much percentage does he lose ?

Explanation: "let original salary be $ 100 salary after decreasing 20 % = 100 - 100 x 20 / 100 = $ 80 salary after increasing 20 % on $ 80 = 80 + 80 x 20 / 100 = $ 96 percentage of loss = 100 - 96 = 4 % answer : a"

multiply(divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 20), add(const_100, 20))), multiply(const_100, const_100)), const_100)

<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">80 * 120</gadget>
<output>9_600</output>
<gadget id="calculator">10_000 - 9_600</gadget>
<output>400</output>
<gadget id="calculator">400 / 10_000</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<result>4</result>


12 . what is the dividend . divisor 17 , the quotient is 9 and the remainder is 6 .

Explanation: "d = d * q + r d = 17 * 9 + 6 d = 153 + 6 d = 159 answer d"

<gadget id="calculator">17 * 9</gadget>
<output>153</output>
<gadget id="calculator">153 + 6</gadget>
<output>159</output>
<result>159</result>


what is the probability that the sum of two dice will yield a 5 , and then when both are thrown again , their sum will again yield a 5 ? assume that each die has 4 sides with faces numbered 1 to 4 .

Explanation: "solution - rolling dices is an independent event . the combinations to get 5 are ( 1,4 ) , ( 4,1 ) , ( 2,3 ) , ( 3,2 ) , and total combinations of both dices is 16 . the probability of getting 5 in first attempt is 4 / 16 = 1 / 4 . probability of getting 5 again in second attempt = ( 1 / 4 ) * ( 1 / 4 ) = 1 / 16 . ans d"

multiply(divide(4, power(4, const_2)), divide(4, power(4, const_2)))

<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * (1/4)</gadget>
<output>1/16 = around 0.0625</output>
<result>1/16 = around 0.0625</result>


a , b , c and d enter into partnership . a subscribes 1 / 3 of the capital b 1 / 4 , c 1 / 5 and d the rest . how much share did a get in a profit of rs . 2400 ?

Explanation: "2400 * 1 / 3 = 800 option a"

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_400 * (1/3)</gadget>
<output>800</output>
<result>800</result>


a shopkeeper sells 200 metres of cloth for rs . 12000 at a loss of rs . 12 per metre . find his cost price for one metre of cloth ?

Explanation: "sp per metre = 12000 / 200 = rs . 60 loss per metre = rs . 12 cp per metre = 60 + 12 = rs . 72 answer : b"

<gadget id="calculator">12_000 / 200</gadget>
<output>60</output>
<gadget id="calculator">60 + 12</gadget>
<output>72</output>
<result>72</result>


a pipe can empty 2 / 3 rd of a cistern in 12 mins . in 6 mins , what part of the cistern will be empty ?

Explanation: "2 / 3 - - - - 12 ? - - - - - 6 = = > 1 / 3 e"

<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 6</gadget>
<output>4</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<result>1/3 = around 0.333333</result>


a grocer has a sale of rs . 5420 , rs . 5660 , rs . 6200 , rs . 6350 and rs . 6500 for 5 consecutive months . find the sale he should have in the sixth month , so that he gets an average sale of rs . 6400 ?

Explanation: "explanation : total sale for 5 months = rs . ( 5420 + 5660 + 6200 + 6350 + 6500 ) = rs . 30,130 therefore , required sale = rs . [ ( 6400 * 6 ) – 30,130 ] = rs . ( 38400 – 30,130 ) = rs . 8270 answer b"

<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_400</gadget>
<output>38_400</output>
<gadget id="calculator">5_420 + 5_660</gadget>
<output>11_080</output>
<gadget id="calculator">11_080 + 6_200</gadget>
<output>17_280</output>
<gadget id="calculator">17_280 + 6_350</gadget>
<output>23_630</output>
<gadget id="calculator">23_630 + 6_500</gadget>
<output>30_130</output>
<gadget id="calculator">38_400 - 30_130</gadget>
<output>8_270</output>
<result>8_270</result>


the sum of first n consecutive odd integers is n ^ 2 . what is the sum of all odd integers between 9 and 39 inclusive .

Explanation: "we ' re dealing with a sequence of consecutive odd integers : 9 to 39 , inclusive . we ' re asked for the sum of this group . 1 ) start with the sum of the smallest and the biggest : 9 + 39 = 48 2 ) now look at the ' next smallest ' and the ' next biggest ' : 11 + 37 = 48 now we have proof that there is no middle term . we have 8 bunches of 48 8 ( 48 ) = 384 b"

subtract(power(divide(add(39, const_1), 2), 2), power(divide(add(subtract(9, 2), const_1), 2), 2))

<gadget id="calculator">39 + 1</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">400 - 16</gadget>
<output>384</output>
<result>384</result>


huey ' s hip pizza sells two sizes of square pizzas : a small pizza that measures 12 inches on a side and costs $ 10 , and a large pizza that measures 18 inches on a side and costs $ 20 . if two friends go to huey ' s with $ 30 apiece , how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone ?

Explanation: "in the first case each can buy one pizza of $ 10 and one pizza of $ 20 . in square inches that would be ( 12 * 12 = 144 ) for the small pizza and ( 18 * 18 = 324 ) for the large pizza . in total sq inches that would be ( 144 + 324 ) * 2 = 936 sq inches . in the second case if they pool their money together they can buy 3 large pizzas . in terms of square inches that would be 3 * 324 = 972 sq inches . hence , the difference is 36 square inches more ( 972 - 936 ) . the correct answer is b"

subtract(multiply(power(18, const_2), const_3), add(add(power(12, const_2), power(18, const_2)), add(power(12, const_2), power(18, const_2))))

<gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">324 * 3</gadget>
<output>972</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">144 + 324</gadget>
<output>468</output>
<gadget id="calculator">468 + 468</gadget>
<output>936</output>
<gadget id="calculator">972 - 936</gadget>
<output>36</output>
<result>36</result>


if each participant of a chess tournament plays exactly one game with each of the remaining participants , then 153 games will be played during the tournament . find the number of participants .

Explanation: "if the number of participants is 3 ( say a , b , c ) the number of games played will be 2 ( a plays against b and c ) + 1 ( b plays against c ) = 3 using the same logic , if the number of participants is n , the number of games played will be ( n - 1 ) + ( n - 2 ) + ( n - 3 ) + . . . 3 + 2 + 1 given that this sum = 153 = 1 + 2 + 3 + . . . ( n - 1 ) sum of first m positive integers is given by m ( m + 1 ) / 2 . so sum of first ( n - 1 ) positive integers is ( n - 1 ) * n / 2 153 = ( n - 1 ) * n / 2 ( n - 1 ) * n = 306 17 * 18 = 306 ( we know that 15 ^ 2 = 225 so the two consecutive numbers must be greater than 15 . also , 20 ^ 2 = 400 so the two numbers must be less than 20 . the pair of numbers in between 15 and 20 whose product ends with 6 is 17 and 18 ) so n = 18 answer ( d )"

divide(add(sqrt(add(multiply(multiply(153, const_2), const_4), const_1)), const_1), const_2)

<gadget id="calculator">153 * 2</gadget>
<output>306</output>
<gadget id="calculator">306 * 4</gadget>
<output>1_224</output>
<gadget id="calculator">1_224 + 1</gadget>
<output>1_225</output>
<gadget id="calculator">1_225 ** (1/2)</gadget>
<output>35</output>
<gadget id="calculator">35 + 1</gadget>
<output>36</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>18</result>


if a lends rs . 2000 to b at 15 % per annum and b lends the same sum to c at 17 % per annum then the gain of b in a period of 4 years is ?

Explanation: "( 2000 * 2 * 4 ) / 100 = > 160 answer : d"

subtract(divide(multiply(multiply(2000, 17), 4), const_100), divide(multiply(multiply(2000, 15), 4), const_100))

<gadget id="calculator">2_000 * 17</gadget>
<output>34_000</output>
<gadget id="calculator">34_000 * 4</gadget>
<output>136_000</output>
<gadget id="calculator">136_000 / 100</gadget>
<output>1_360</output>
<gadget id="calculator">2_000 * 15</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 4</gadget>
<output>120_000</output>
<gadget id="calculator">120_000 / 100</gadget>
<output>1_200</output>
<gadget id="calculator">1_360 - 1_200</gadget>
<output>160</output>
<result>160</result>


how much time will a train of length 400 m moving at a speed of 72 kmph take to cross another train of length 300 m , moving at 36 kmph in the same direction ?

Explanation: "the distance to be covered = sum of their lengths = 400 + 300 = 700 m . relative speed = 72 - 36 = 36 kmph = 36 * 5 / 18 = 10 mps . time required = d / s = 700 / 10 = 70 sec . answer : d"

divide(add(400, 300), multiply(subtract(72, 36), const_0_2778))

<gadget id="calculator">400 + 300</gadget>
<output>700</output>
<gadget id="calculator">72 - 36</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">700 / 10</gadget>
<output>70</output>
<result>70</result>


length of a rectangular plot is 26 mtr more than its breadth . if the cost of fencin gthe plot at 26.50 per meter is rs . 5300 , what is the length of the plot in mtr ?

Explanation: "let breadth = x metres . then , length = ( x + 26 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 26 ) + x ] = 200 2 x + 26 = 100 2 x = 74 x = 37 hence , length = x + 26 = 63 m b"

divide(add(divide(5300, 26.50), multiply(const_2, 26)), const_4)

<gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 26</gadget>
<output>52</output>
<gadget id="calculator">200 + 52</gadget>
<output>252</output>
<gadget id="calculator">252 / 4</gadget>
<output>63</output>
<result>63</result>


on a map the distance between two mountains is 312 inches . the actual distance between the mountains is 136 km . ram is camped at a location that on the map is 34 inch from the base of the mountain . how many km is he from the base of the mountain ?

Explanation: explanation : since 312 inch = 136 km so 1 inch = 136 / 312 km so 34 inch = ( 136 × 34 ) / 312 = 14.82 km answer : d

<gadget id="calculator">34 * 136</gadget>
<output>4_624</output>
<gadget id="calculator">4_624 / 312</gadget>
<output>578/39 = around 14.820513</output>
<result>578/39 = around 14.820513</result>


the sum of the present ages of a father and his son is 42 years . 6 years ago , father ' s age was 4 times the age of the son . after 6 years , son ' s age will be :

Explanation: let the present ages of son and father be x and ( 42 - x ) years respectively . then , ( 42 - x ) - 6 = 4 ( x - 6 ) 36 - x = 4 x - 24 x = 12 the son ' s age after 6 years will be 18 . the answer is c .

add(divide(add(42, subtract(multiply(4, 6), 6)), add(4, const_1)), 6)

<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 - 6</gadget>
<output>18</output>
<gadget id="calculator">42 + 18</gadget>
<output>60</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<result>18</result>


a recipe requires 2 1 / 2 ( mixed number ) cups of flour 2 3 / 4 ( mixed number ) cups of sugar and 1 1 / 3 ( mixed number ) cups of milk to make one cake . victor has 15 cups if flour , 16 cups of sugar and 8 cups of milk . what is the greatest number of cakes tom can make using this recipe ?

Explanation: less work up front : go through each item and see what the greatest number of cakes you can make with each . the lowest of these will be the right answer . flour : 15 cups , we need 2.5 cups each . just keep going up the line to see how many cakes we can make : that means i can make 2 cakes with 5 cups , so 6 cakes overall with 15 cups . i ' ve already got the answer narrowed to either a or b . sugar : 16 cups , we need 2.75 cups each . same principle . i can make 2 cups with 5.5 cups , so to make 6 cakes i ' d need 16.5 cups . i do n ' t have that much sugar , so we ' re limited to 5 cakes . no need to even do milk because we ' re already at 5 . sugar will be the limiting factor . answer is a

min(min(divide(15, add(2, divide(const_1, const_2))), floor(divide(16, add(divide(const_3, const_4), 2)))), divide(8, add(divide(1, 3), 1)))

<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">15 / (5/2)</gadget>
<output>6</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) + 2</gadget>
<output>11/4 = around 2.75</output>
<gadget id="calculator">16 / (11/4)</gadget>
<output>64/11 = around 5.818182</output>
<gadget id="calculator">floor(64/11)</gadget>
<output>5</output>
<gadget id="calculator">min(6, 5)</gadget>
<output>5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 1</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">8 / (4/3)</gadget>
<output>6</output>
<gadget id="calculator">min(5, 6)</gadget>
<output>5</output>
<result>5</result>


the c . p of 10 pens is equal to the s . p of 5 pens . find his gain % or loss % ?

Explanation: 10 cp = 5 sp 10 - - - 5 cp gain 100 - - - ? = > 50 % ( gain ) answer : a

multiply(divide(subtract(10, 5), 10), const_100)

<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>50</result>


the average of 6 no . ' s is 3.95 . the average of 2 of them is 4.2 , while the average of theother 2 is 3.85 . what is the average of the remaining 2 no ' s ?

Explanation: "sum of the remaining two numbers = ( 3.95 * 6 ) - [ ( 4.2 * 2 ) + ( 3.85 * 2 ) ] = 7.60 . required average = ( 7.6 / 2 ) = 3.8 . d"

divide(subtract(multiply(6, 3.95), add(multiply(2, 4.2), multiply(2, 3.85))), 2)

<gadget id="calculator">6 * 3.95</gadget>
<output>23.7</output>
<gadget id="calculator">2 * 4.2</gadget>
<output>8.4</output>
<gadget id="calculator">2 * 3.85</gadget>
<output>7.7</output>
<gadget id="calculator">8.4 + 7.7</gadget>
<output>16.1</output>
<gadget id="calculator">23.7 - 16.1</gadget>
<output>7.6</output>
<gadget id="calculator">7.6 / 2</gadget>
<output>3.8</output>
<result>3.8</result>


20 one identical machines , running continuously at the same constant rate , take 9 days to complete a shipment . how many additional machines , each running at the same constant rate , would be needed to reduce the time required to complete a shipment by two days ?

Explanation: from the question you know that 21 r = 1 / 9 . the question asks you ( partially ) to make the rate from 1 / 9 to 1 / 7 ( drop from 9 day to 7 ) . so the only thing that you need to do is to find the magic number than can convert 1 / 9 to 1 / 7 . so 1 / 9 * x = 1 / 7 ( 1 equation with one unknown ) . so by solving this you get x = 9 / 7 . thats it then ! take the magic number 9 / 7 and multiply both sides of the original equation and you have : 21 * ( 9 / 7 ) * r = ( 9 / 7 ) * 1 / 9 27 * r = 1 / 7 , hence 27 r = 1 / 7 , therefore 6 more machines ! d

subtract(divide(multiply(20, 9), subtract(9, const_2)), 20)

<gadget id="calculator">20 * 9</gadget>
<output>180</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">180 / 7</gadget>
<output>180/7 = around 25.714286</output>
<gadget id="calculator">(180/7) - 20</gadget>
<output>40/7 = around 5.714286</output>
<result>40/7 = around 5.714286</result>


the number of sailors on a ship is 78 % more than the number of officers . the ratio of sailors to officers would be

Explanation: sailor = 1.78 * officer sailor / officer = 1.78 / 1 = 178 / 100 = 89 / 50 answer will be d

<gadget id="calculator">78 + 100</gadget>
<output>178</output>
<gadget id="calculator">178 / 100</gadget>
<output>89/50 = around 1.78</output>
<result>89/50 = around 1.78</result>


how much more would rs . 10000 fetch , after two years , if it is put at 20 % p . a . compound interest payable half yearly than if is put at 20 % p . a . compound interest payable yearly ?

Explanation: "10000 ( 11 / 10 ) 4 - 10000 ( 6 / 5 ) 2 = 241 answer : a"

subtract(multiply(power(add(const_1, divide(divide(20, const_100), const_2)), const_4), 10000), multiply(power(add(divide(20, const_100), const_1), const_2), 10000))

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">(14_641/10_000) * 10_000</gadget>
<output>14_641</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) * 10_000</gadget>
<output>14_400</output>
<gadget id="calculator">14_641 - 14_400</gadget>
<output>241</output>
<result>241</result>


what is the decimal equivalent of ( 1 / 4 ) ^ 2 ?

Explanation: "1 / 4 = 25 / 100 = > ( 25 / 100 ) ^ 2 = 625 / 10000 = 0.0625 answer : b"

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) ** 2</gadget>
<output>1/16 = around 0.0625</output>
<result>1/16 = around 0.0625</result>


a paint store mixes 3 / 4 pint of red paint and 2 / 3 pint of white paint to make a new paint color called perfect pink . how many pints of red paint would be needed to make 33 pints of perfect pink paint ?

Explanation: "3 / 4 pint is required to make 3 / 4 + 2 / 3 = 17 / 12 pint of perfect pink so 17 / 12 pint requires 3 / 4 pint of red . . 1 pint will require 3 / 4 * 12 / 17 = 9 / 17 . . 33 pints will require 9 / 17 * 33 = 17 pints . . c"

multiply(33, divide(multiply(3, 2), multiply(4, 3)))

<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">33 * (1/2)</gadget>
<output>33/2 = around 16.5</output>
<result>33/2 = around 16.5</result>


Explanation: we ' re given the equation 5 + 7 / x = 6 - 5 / x . we ' re asked for the value of x . the common - denominator of these 4 numbers is x , so we need to multiply both sides of the equation by x , giving us . . . 5 x + 7 x / x = 6 x - 5 x / x we can then eliminate that denominator , which gives us . . . . 5 x + 7 = 6 x - 5 12 = x c

<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">12 / 1</gadget>
<output>12</output>
<result>12</result>


kelly has had 3 pay cuts in her salary in the past 6 months . if the first pay cut was 8 % , the second pay cut was 14 % and the third was 18 % . what will be the percentage decrease , if the salary is decreased in a single shot ?

Explanation: let rs . 100 be initial salary . salary after 1 st decrease , 8 % = 92 salary after 2 nd decrease , 14 % = 79.12 i . e . reduced by 14 percent of 92 salary after 3 rd decrease , 18 % = 64.88 i . e . reduced by 18 percent of 79.12 so if its decreased in single shot = i = ( ( b - a ) / b ) * 100 = 35.12 % answer : d

multiply(subtract(const_1, multiply(multiply(subtract(const_1, divide(8, const_100)), subtract(const_1, divide(14, const_100))), subtract(const_1, divide(18, const_100)))), const_100)

<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">1 - (2/25)</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">1 - (7/50)</gadget>
<output>43/50 = around 0.86</output>
<gadget id="calculator">(23/25) * (43/50)</gadget>
<output>989/1_250 = around 0.7912</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">1 - (9/50)</gadget>
<output>41/50 = around 0.82</output>
<gadget id="calculator">(989/1_250) * (41/50)</gadget>
<output>40_549/62_500 = around 0.648784</output>
<gadget id="calculator">1 - (40_549/62_500)</gadget>
<output>21_951/62_500 = around 0.351216</output>
<gadget id="calculator">(21_951/62_500) * 100</gadget>
<output>21_951/625 = around 35.1216</output>
<result>21_951/625 = around 35.1216</result>


a and b began business with rs . 3000 and rs . 4000 after 8 months , a withdraws rs . 1000 and b advances rs . 1000 more . at the end of the year , their profits amounted to rs . 630 find the share of a ?

Explanation: "( 3 * 8 + 2 * 4 ) : ( 4 * 8 + 5 * 4 ) 8 : 13 8 / 21 * 630 = 240 answer : a"

multiply(divide(630, add(add(multiply(3000, 8), multiply(subtract(3000, 1000), subtract(const_12, 8))), add(multiply(4000, 8), multiply(add(4000, 1000), subtract(const_12, 8))))), add(multiply(3000, 8), multiply(subtract(3000, 1000), subtract(const_12, 8))))

<gadget id="calculator">3_000 * 8</gadget>
<output>24_000</output>
<gadget id="calculator">3_000 - 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">2_000 * 4</gadget>
<output>8_000</output>
<gadget id="calculator">24_000 + 8_000</gadget>
<output>32_000</output>
<gadget id="calculator">4_000 * 8</gadget>
<output>32_000</output>
<gadget id="calculator">4_000 + 1_000</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 * 4</gadget>
<output>20_000</output>
<gadget id="calculator">32_000 + 20_000</gadget>
<output>52_000</output>
<gadget id="calculator">32_000 + 52_000</gadget>
<output>84_000</output>
<gadget id="calculator">630 / 84_000</gadget>
<output>3/400 = around 0.0075</output>
<gadget id="calculator">(3/400) * 32_000</gadget>
<output>240</output>
<result>240</result>


the population of a bacteria culture doubles every 2 minutes . approximately how many minutes will it take for the population to grow from 1000 to 1000000 bacteria

Explanation: the question basically asks how many minutes it takes for a population to increase by factor 1000 ( 1000000 / 1000 = 1000 ) . now you know that every two minutes the population doubles , i . e . is multiplied by 2 . so the equation becomes : 2 ^ x > = 1000 , where x represents the number of times the population doubles . a lot of people remember that 2 ^ 10 = 1024 . i . e . the population has to double 10 times . since it takes the population 2 minutes to double once it takes 10 * 2 minutes = 20 minutes to double nine times . thus , solution e = 20 is correct .

multiply(divide(divide(1000000, 1000), const_100), const_2)

<gadget id="calculator">1_000_000 / 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 100</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<result>20</result>


a woman bought a pack of 36 eggs , but the seller told her that there were 3 rotten eggs in the pack . she forgot it and begun to prepare a recipe that needs 2 eggs . what is the probability that both choosen eggs will be rotten ?

Explanation: there are 3 rotten eggs in a pack of 36 . thus the probability of picking 2 rotten eggs is : ( 3 / 36 ) ( 2 / 35 ) = 1 / 210 . the correct answer is a .

multiply(divide(2, subtract(36, const_1)), divide(3, 36))

<gadget id="calculator">36 - 1</gadget>
<output>35</output>
<gadget id="calculator">2 / 35</gadget>
<output>2/35 = around 0.057143</output>
<gadget id="calculator">3 / 36</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(2/35) * (1/12)</gadget>
<output>1/210 = around 0.004762</output>
<result>1/210 = around 0.004762</result>


if a person walks at 20 km / hr instead of 10 km / hr , he would have walked 20 km more . the actual distance traveled by him is :

Explanation: "let the actual distance travelled be x km . x / 10 = ( x + 20 ) / 14 20 x = 10 x + 200 10 x = 200 x = 20 km . answer : a"

multiply(10, divide(20, subtract(20, 10)))

<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<result>20</result>


20 % of a number is more than 30 % of 120 by 80 . find the number ?

Explanation: ( 20 / 100 ) * x – ( 30 / 100 ) * 120 = 80 1 / 5 x = 116 x = 580 answer : c

divide(multiply(add(divide(multiply(120, 30), const_100), 80), const_100), 20)

<gadget id="calculator">120 * 30</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 100</gadget>
<output>36</output>
<gadget id="calculator">36 + 80</gadget>
<output>116</output>
<gadget id="calculator">116 * 100</gadget>
<output>11_600</output>
<gadget id="calculator">11_600 / 20</gadget>
<output>580</output>
<result>580</result>


the population of a bacteria colony doubles every day . if it was started 9 days ago with 2 bacteria and each bacteria lives for 12 days , how large is the colony today ?

Explanation: "it started 9 days ago . so bacterias keep growing for 9 days + today = 10 days 2 ^ 10 = 1024 c is the answer"

subtract(power(2, add(9, const_1)), const_1)

<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">2 ** 10</gadget>
<output>1_024</output>
<gadget id="calculator">1_024 - 1</gadget>
<output>1_023</output>
<result>1_023</result>


on dividing 190 by a number , the quotient is 9 and the remainder is 1 . find the divisor ?

Explanation: "d = ( d - r ) / q = ( 190 - 1 ) / 9 = 189 / 9 = 21 e )"

<gadget id="calculator">190 / 9</gadget>
<output>190/9 = around 21.111111</output>
<gadget id="calculator">floor(190/9)</gadget>
<output>21</output>
<result>21</result>


exactly 28 % of the reporters for a certain wire service cover local politics in country x . if 30 % of the reporters who cover politics for the wire service do not cover local politics in country x , what percent of the reporters for the wire service do not cover politics ?

Explanation: "let ' s assume there are 100 reporters - - > 28 reporters cover local politics . now , as 30 % of the reporters who cover all politics do not cover local politics then the rest 70 % of the reporters who cover politics do cover local politics , so if there are x reporters who cover politics then 70 % of them equal to 28 ( # of reporters who cover local politics ) : 0.7 x = 28 - - > x = 40 , hence 40 reporters cover politics and the rest 100 - 40 = 60 reporters do not cover politics at all . answer : d ."

multiply(subtract(const_1, divide(28, subtract(const_100, 30))), const_100)

<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">28 / 70</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>60</result>


a group of students decided to collect as many paise from each member of group as is the number of members . if the total collection amounts to rs . 98.01 , the number of the member is the group is :

Explanation: "money collected = ( 98.01 x 100 ) paise = 9801 paise . number of members = square root of 9801 = 99 . answer : option d"

<gadget id="calculator">98.01 * 100</gadget>
<output>9_801</output>
<gadget id="calculator">9_801 ** (1/2)</gadget>
<output>99</output>
<result>99</result>


the speed of a car is 60 km in the first hour and 30 km in the second hour . what is the average speed of the car ?

Explanation: "explanation : s = ( 60 + 30 ) / 2 = 45 kmph a )"

<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<result>45</result>


how many figures are required for numbering the pages of a book containing 1000 pages ?

Explanation: "explanation : 1 to 9 = 9 * 1 = 9 10 to 99 = 90 * 2 = 180 100 to 999 = 900 * 3 = 2700 1000 = 4 - - - - - - - - - - - 2893 answer : c"

add(add(subtract(divide(divide(1000, const_10), const_10), const_1), subtract(subtract(divide(1000, const_10), const_1), subtract(divide(divide(1000, const_10), const_10), const_1))), multiply(subtract(subtract(1000, const_1), subtract(divide(1000, const_10), const_1)), const_3))

<gadget id="calculator">1_000 / 10</gadget>
<output>100</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">99 - 9</gadget>
<output>90</output>
<gadget id="calculator">9 + 90</gadget>
<output>99</output>
<gadget id="calculator">1_000 - 1</gadget>
<output>999</output>
<gadget id="calculator">999 - 99</gadget>
<output>900</output>
<gadget id="calculator">900 * 3</gadget>
<output>2_700</output>
<gadget id="calculator">99 + 2_700</gadget>
<output>2_799</output>
<result>2_799</result>


if the length of the longest chord of a certain circle is 10 , what is the radius of that certain circle ?

Explanation: longest chord of a circle is the diameter of the circle diameter = 2 * radius if diameter of the circle is given as 10 = 2 * 5 so radius of the circle = 5 correct answer - b

<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>5</result>