a 1400 m long train crosses a tree in 100 sec , how much time will it take to pass a platform 700 m long ?

Explanation: "l = s * t s = 1400 / 100 s = 14 m / sec . total length ( d ) = 2100 m t = d / s t = 2100 / 14 t = 150 sec answer : c"

<gadget id="calculator">1_400 + 700</gadget>
<output>2_100</output>
<gadget id="calculator">1_400 / 100</gadget>
<output>14</output>
<gadget id="calculator">2_100 / 14</gadget>
<output>150</output>
<result>150</result>


during the last 4 years , a large truck company purchased diesel at rates of $ 1.2 , $ 1.3 , $ 1.8 and $ 2.1 per gallon . what was the mean cost of diesel over the 4 - year period if the company spends the same amount of dollars on diesel each year ?

Explanation: finding the harmonic mean here . hm = 4 / ( 1 / 12 + 1 / 13 + 1 / 18 + 1 / 21 ) = 15.18 c

<gadget id="calculator">1.2 + 1.3</gadget>
<output>2.5</output>
<gadget id="calculator">1.8 + 2.1</gadget>
<output>3.9</output>
<gadget id="calculator">2.5 + 3.9</gadget>
<output>6.4</output>
<gadget id="calculator">6.4 / 4</gadget>
<output>1.6</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">1.6 - (2/25)</gadget>
<output>1.52</output>
<result>1.52</result>


after spending rs . 5000 on rent , rs . 1500 on milk , rs . 4500 on groceries , rs . 2500 on childrens education rs . 2000 on petrol and rs . 5200 on miscellaneous expenses , mr . kishore saved 10 % of his monthly salary . how much did he save in rs . ?

Explanation: "explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 5200 = 20700 exp in % = 100 - 10 = 90 % , 20700 = 90 % saving = 10 % = 20700 x 10 / 90 = rs . 2300 answer : d"

<gadget id="calculator">5_000 + 1_500</gadget>
<output>6_500</output>
<gadget id="calculator">6_500 + 4_500</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 + 2_500</gadget>
<output>13_500</output>
<gadget id="calculator">13_500 + 2_000</gadget>
<output>15_500</output>
<gadget id="calculator">15_500 + 5_200</gadget>
<output>20_700</output>
<gadget id="calculator">20_700 * 100</gadget>
<output>2_070_000</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">2_070_000 / 90</gadget>
<output>23_000</output>
<gadget id="calculator">23_000 - 20_700</gadget>
<output>2_300</output>
<result>2_300</result>


shekar scored 76 , 65 , 82 , 47 and 85 marks in mathematics , science , social studies , english and biology respectively . what are his average marks ?

Explanation: "explanation : average = ( 76 + 65 + 82 + 47 + 85 ) / 5 = 355 / 5 = 71 hence average = 71 answer : a"

<gadget id="calculator">76 + 65</gadget>
<output>141</output>
<gadget id="calculator">141 + 82</gadget>
<output>223</output>
<gadget id="calculator">223 + 47</gadget>
<output>270</output>
<gadget id="calculator">270 + 85</gadget>
<output>355</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">355 / 5</gadget>
<output>71</output>
<result>71</result>


how many multiples of 4 are there between 12 and 104 , inclusive ?

Explanation: "the multiples of 4 are from 4 * 3 up to 4 * 26 . 26 - 3 + 1 = 24 . the answer is d ."

add(divide(subtract(104, 12), 4), const_1)

<gadget id="calculator">104 - 12</gadget>
<output>92</output>
<gadget id="calculator">92 / 4</gadget>
<output>23</output>
<gadget id="calculator">23 + 1</gadget>
<output>24</output>
<result>24</result>


how many kg of rice at rs . 6.60 per kg . be mixed with 56 kg of rice at rs . 9.60 per kg to get a mixture worth rs . 8.20 per kg

Explanation: explanation : by the rule of alligation , we have cost of 1 kg of 1 st kind rice cost of 1 kg of 2 nd kind rice 6.6 9.6 price of 1 kg of the mixture 8.2 9.6 - 8.2 = 1.4 8.2 - 6.6 = 1.6 quantity of 1 st kind rice : quantity of 2 nd kind rice = 1.4 : 1.6 = 7 : 8 quantity of 1 st kind rice : 56 = 7 : 8 = > quantity of 1 st kind rice = 56 × 78 = 49 answer : option d

divide(subtract(multiply(9.6, 56), multiply(56, 8.2)), subtract(8.2, 6.6))

<gadget id="calculator">9.6 * 56</gadget>
<output>537.6</output>
<gadget id="calculator">56 * 8.2</gadget>
<output>459.2</output>
<gadget id="calculator">537.6 - 459.2</gadget>
<output>78.4</output>
<gadget id="calculator">8.2 - 6.6</gadget>
<output>1.6</output>
<gadget id="calculator">78.4 / 1.6</gadget>
<output>49</output>
<result>49</result>


a box measuring 36 inches long by 45 inches wide by 18 inches deep is to be filled entirely with identical cubes . no space is to be left unfilled . what is the smallest number of cubes that can accomplish this objective ?

Explanation: "least number of cubes will be required when the cubes that could fit in are biggest . 9 is the biggest number that could divide all three , 36 , 45 and 18 . thus side of cube must be 9 , and total number of cubes = 36 / 9 * 45 / 9 * 18 / 9 = 40 ans d ."

divide(multiply(multiply(36, 45), 18), volume_cube(divide(18, const_2)))

<gadget id="calculator">36 * 45</gadget>
<output>1_620</output>
<gadget id="calculator">1_620 * 18</gadget>
<output>29_160</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 ** 3</gadget>
<output>729</output>
<gadget id="calculator">29_160 / 729</gadget>
<output>40</output>
<result>40</result>


tanks a and b are each in the shape of a right circular cylinder . the interior of tank a has a height of 10 meters and a circumference of 8 meters , and the interior of tank b has a height of 8 meters and a circumference of 10 meters . the capacity of tank a is what percent of the capacity of tank b ?

Explanation: "circumference of a = 2 ( pie ) r = 8 so r = 4 / pie volume = pie ( 4 / pie ) ^ 2 * 10 = 160 / pie circumference of b = 2 ( pie ) r = 10 so r = 5 / pie volume = pie ( 5 / pie ) ^ 2 * 8 = 200 / pie so ratio of capacities = 160 / 200 = 0.8 so capacity of a will be 80 % of the capacity of b answer : e"

multiply(multiply(power(divide(8, 10), const_2), divide(10, 8)), const_100)

<gadget id="calculator">8 / 10</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) ** 2</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">10 / 8</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(16/25) * (5/4)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>80</result>


at joes steakhouse the hourly wage for a chef is 20 % greater than that of a dishwasher , and the hourly wage of a dishwasher is half as much as the hourly wage of a manager . if a managers wage is $ 6.50 per hour , how much less than a manager does a chef earn each hour ?

Explanation: manager wages per hour = $ 6.50 dishwasher wages per hour = half of manager ' s wages . = 1 / 2 ( $ 6.50 ) = = > $ 3.25 chef wages per hour = 20 % greater than dishwasher wages - - > 20 % of $ 3.25 = ( 20 * ( $ 3.25 ) ) / 100 - - > ( $ 65 ) / 100 - - > $ 0.65 therefore , chef wages per hour = $ 3.25 + $ 0.65 = = > $ 3.9 difference of wages between manager and chef = $ 6.50 - $ 3.9 = = > $ 2.6 answer : a

multiply(subtract(const_1, multiply(divide(add(const_100, 20), const_100), divide(const_1, const_2))), 6.5)

<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(6/5) * (1/2)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 6.5</gadget>
<output>2.6</output>
<result>2.6</result>


the cost of paint is 60 per kilograme . a kilogram paint covers 20 square feet . how much will it cost to paint the outside of a cube having each side 10 feet ?

Explanation: area of cube = 6 × ( side ) 2 = 6 × 10 × 10 = 600 square feet . cost to paint outside of the cube = 600 ⁄ 20 × 60 = 1800 answer c

multiply(divide(multiply(multiply(const_2, const_3), power(10, const_2)), 20), 60)

<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 / 20</gadget>
<output>30</output>
<gadget id="calculator">30 * 60</gadget>
<output>1_800</output>
<result>1_800</result>


the original price of a suit is $ 160 . the price increased 25 % , and after this increase , the store published a 25 % off coupon for a one - day sale . given that the consumers who used the coupon on sale day were getting 25 % off the increased price , how much did these consumers pay for the suit ?

Explanation: 0.75 * ( 1.25 * 160 ) = $ 150 the answer is c .

subtract(add(160, divide(multiply(160, 25), const_100)), divide(multiply(add(160, divide(multiply(160, 25), const_100)), 25), const_100))

<gadget id="calculator">160 * 25</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 100</gadget>
<output>40</output>
<gadget id="calculator">160 + 40</gadget>
<output>200</output>
<gadget id="calculator">200 * 25</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 100</gadget>
<output>50</output>
<gadget id="calculator">200 - 50</gadget>
<output>150</output>
<result>150</result>


in a throw of dice what is the probability of getting number greater than 5

Explanation: "number greater than 5 is 6 , so only 1 number total cases of dice = [ 1,2 , 3,4 , 5,6 ] so probability = 1 / 6 b )"

<gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>1/6 = around 0.166667</result>


of 60 children , 30 are happy , 10 are sad , and 20 are neither happy nor sad . there are 19 boys and 41 girls . if there are 6 happy boys and 4 sad girls , how many boys are neither happy nor sad ?

Explanation: "venn diagrams are useful for multiple values of a single variable e . g . state of mind - happy / sad / neither . when you have two or more variables such as here where you have gender - boy / girl too , it becomes unwieldy . in this case , either use the table or logic . table method is shown above ; here is how you will use logic : there are 6 happy boys . there are 4 sad girls but total 10 sad children . so rest 6 sad children must be sad boys . we have 6 happy boys and 6 sad boys . total we have 19 boys . so 19 - 6 - 6 = 7 boys must be neither happy nor sad . answer ( b )"

subtract(subtract(19, subtract(10, 4)), 6)

<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">19 - 6</gadget>
<output>13</output>
<gadget id="calculator">13 - 6</gadget>
<output>7</output>
<result>7</result>


a store sells chairs and tables . if the price of 2 chairs and 1 table is 60 % of the price of 1 chair and 2 tables , and the price of 1 table and 1 chair is $ 64 , what is the price , in dollars , of 1 table ? ( assume that every chair has the same price and every table has the same price . )

Explanation: "let c = chair ; t = table 2 c + 1 t = 0.6 ( 1 c + 2 t ) or c ( 2 - 0.6 ) = 1.2 t - 1 t or 1.4 c = 0.2 t therefore c = 0.2 / 1.4 t = 1 / 7 t ic + 1 t = 64 or 1 / 7 t + 1 t = 64 therefore t = 64 * 7 / 8 = 56 e"

divide(subtract(multiply(64, 2), multiply(64, divide(60, const_100))), add(divide(60, const_100), 1))

<gadget id="calculator">64 * 2</gadget>
<output>128</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">64 * (3/5)</gadget>
<output>192/5 = around 38.4</output>
<gadget id="calculator">128 - (192/5)</gadget>
<output>448/5 = around 89.6</output>
<gadget id="calculator">(3/5) + 1</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(448/5) / (8/5)</gadget>
<output>56</output>
<result>56</result>


if the radius of a circle that centers at the origin is 5 , how many points q on the circle have integer coordinates ?

Explanation: "i understand this might not be required but i used the equation of a circle . since the origin is at 0 , x ^ 2 + y ^ 2 = 5 ^ 2 . x , y could be + / - ( 0,5 or 5,0 ) - 4 possibilities . x , y could be + / - ( 3,4 or 4,3 ) - 8 possibilities . ans : q = c"

subtract(subtract(multiply(5, 5), add(5, const_4)), power(const_2, const_2))

<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">25 - 9</gadget>
<output>16</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">16 - 4</gadget>
<output>12</output>
<result>12</result>


the ratio of the radius of two circles is 1 : 5 , and then the ratio of their areas is ?

Explanation: "r 1 : r 2 = 1 : 5 î r 1 ^ 2 : î r 2 ^ 2 r 1 ^ 2 : r 2 ^ 2 = 1 : 25 answer : c"

<gadget id="calculator">pi * (1 ** 2)</gadget>
<output>pi = around 3.141593</output>
<gadget id="calculator">pi * (5 ** 2)</gadget>
<output>25*pi = around 78.539816</output>
<gadget id="calculator">pi / (25*pi)</gadget>
<output>1/25 = around 0.04</output>
<result>1/25 = around 0.04</result>


the average of 11 numbers is 60 . out of 11 numbers the average of first 6 no . is 98 , and last 6 numbers is 65 then find 6 th number ?

Explanation: 6 th number = sum of 1 st 6 no . s + sum of last 6 no . s - sum of 11 no . s answer = 6 * 98 + 6 * 65 - 11 * 60 = 318 answer is a

subtract(add(multiply(6, 98), multiply(6, 65)), multiply(11, 60))

<gadget id="calculator">6 * 98</gadget>
<output>588</output>
<gadget id="calculator">6 * 65</gadget>
<output>390</output>
<gadget id="calculator">588 + 390</gadget>
<output>978</output>
<gadget id="calculator">11 * 60</gadget>
<output>660</output>
<gadget id="calculator">978 - 660</gadget>
<output>318</output>
<result>318</result>


a man bought 40 shares of rs . 60 at 8 discount , the rate of dividend being 1212 % the rate of interest obtained is

Explanation: "explanation : face value of a share = rs . 60 he bought each share at rs . 60 - rs . 8 = rs . 52 number of shares = 40 dividend = 12 1 / 2 % = 25 / 2 % dividend per share = 60 × 25 / 2 × 100 = rs . 7.5 total dividend = ( 40 × 7.5 ) ie , he got a dividend of ( 40 × 7.5 ) for an investment of rs . ( 40 × 52 ) interest obtained = 40 × 7.5 × 100 / 40 × 52 = 14.42 % answer : option d"

divide(multiply(multiply(40, 60), divide(1212, const_100)), multiply(40, subtract(60, 8)))

<gadget id="calculator">40 * 60</gadget>
<output>2_400</output>
<gadget id="calculator">1_212 / 100</gadget>
<output>303/25 = around 12.12</output>
<gadget id="calculator">2_400 * (303/25)</gadget>
<output>29_088</output>
<gadget id="calculator">60 - 8</gadget>
<output>52</output>
<gadget id="calculator">40 * 52</gadget>
<output>2_080</output>
<gadget id="calculator">29_088 / 2_080</gadget>
<output>909/65 = around 13.984615</output>
<result>909/65 = around 13.984615</result>


the area of a triangle is 615 m 2 . if one of its sides is 123 metre , find the length of the perpendicular dropped on that side from opposite vertex .

Explanation: in a triangle , area = 1 ⁄ 2 × length of perpendicular × base or 615 = 1 ⁄ 2 × length of perpendicular × 123 ∴ length of perpendicular = 615 × 2 / 123 = 10 m answer c

<gadget id="calculator">615 * 2</gadget>
<output>1_230</output>
<gadget id="calculator">1_230 / 123</gadget>
<output>10</output>
<result>10</result>


in an election between the two candidates , the candidates who gets 60 % of votes polled is wined by 280 votes majority . what is the total number of votes polled ?

Explanation: note : majority ( 20 % ) = difference in votes polled to win ( 60 % ) & defeated candidates ( 40 % ) 20 % = 60 % - 40 % 20 % - - - - - > 280 ( 20 × 14 = 280 ) 100 % - - - - - > 1400 ( 100 × 14 = 1400 ) a

divide(multiply(const_100, 280), subtract(60, subtract(const_100, 60)))

<gadget id="calculator">100 * 280</gadget>
<output>28_000</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">28_000 / 20</gadget>
<output>1_400</output>
<result>1_400</result>


what is the remainder if 7 ^ 12 is divided by 100 ?

Explanation: 7 ^ 16 can be written as ( 7 ^ 4 ) ^ 3 if we divide 7 ^ 4 by 100 the reminder is 1 so , ( 7 ^ 4 ) ^ 3 by 100 , the reminder is 1 ^ 3 = 1 answer : a

subtract(divide(100, const_2), multiply(7, 7))

<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">50 - 49</gadget>
<output>1</output>
<result>1</result>


calculate the average of all the numbers between 10 and 86 which are divisible by 9 .

Explanation: "explanation : numbers divisible by 9 are 18,27 , 36,45 , 54,63 , 72,81 , average = ( 18 + 27 + 36 + 45 + 54 + 63 + 72 + 81 , ) / 8 = 396 / 8 = 49.5 answer : a"

multiply(divide(add(add(floor(divide(10, 9)), const_1), floor(divide(86, 9))), const_2), 9)

<gadget id="calculator">10 / 9</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">floor(10/9)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">86 / 9</gadget>
<output>86/9 = around 9.555556</output>
<gadget id="calculator">floor(86/9)</gadget>
<output>9</output>
<gadget id="calculator">2 + 9</gadget>
<output>11</output>
<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) * 9</gadget>
<output>99/2 = around 49.5</output>
<result>99/2 = around 49.5</result>


what is the length of a bridge ( in meters ) , which a train 156 meters long and travelling at 45 km / h can cross in 30 seconds ?

Explanation: speed = 45 km / h = 45000 m / 3600 s = 25 / 2 m / s in 30 seconds , the train can travel 25 / 2 * 30 = 375 meters 375 = length of train + length of bridge length of bridge = 375 - 156 = 219 meters the answer is c .

subtract(multiply(multiply(45, const_0_2778), 30), 156)

<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">45 * (5/18)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 156</gadget>
<output>219</output>
<result>219</result>


the average of first 17 even numbers is ?

Explanation: "sum of 17 even numbers = 17 * 18 = 306 average = 306 / 17 = 18 answer : c"

<gadget id="calculator">17 + 1</gadget>
<output>18</output>
<result>18</result>


a and b are two multiples of 14 , and q is the set of consecutive integers between a and b , inclusive . if q contains 11 multiples of 14 , how many multiples of 7 are there in q ?

Explanation: "halfway between the multiples of 14 , there will be another multiple of 7 . the total number of multiples of 7 is 11 + 10 = 21 . the answer is c ."

<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">22 - 1</gadget>
<output>21</output>
<result>21</result>


the ratio between the presents of the a and b is 2 : 3 . if b is 5 years older than a , what will be the ratio of the ages of a and b after 5 years ?

Explanation: "let a and b ages will be 2 x and 3 x 3 x - 2 x = 5 x = 5 required ratio = 2 x + 5 : 3 x + 5 = 15 : 20 = 3 : 4 answer is a"

divide(add(subtract(multiply(3, 5), 5), 5), add(multiply(3, 5), 5))

<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">15 / 20</gadget>
<output>3/4 = around 0.75</output>
<result>3/4 = around 0.75</result>


if x * y = xy – 2 ( x + y ) for all integers x and y , then 1 * ( – 3 ) =

Explanation: "1 * ( - 3 ) = 1 * ( - 3 ) - 2 ( 1 + ( - 3 ) ) = - 3 + 4 = 1 option ( e )"

add(negate(multiply(add(negate(3), 1), 2)), multiply(negate(3), 1))

<gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(-3) + 1</gadget>
<output>-2</output>
<gadget id="calculator">(-2) * 2</gadget>
<output>-4</output>
<gadget id="calculator">-(-4)</gadget>
<output>4</output>
<gadget id="calculator">(-3) * 1</gadget>
<output>-3</output>
<gadget id="calculator">4 + (-3)</gadget>
<output>1</output>
<result>1</result>


on increasing the price of t . v . sets by 40 % , their sale decreases by 20 % . what is the effect on the revenue receipts of the shop ?

Explanation: "explanation : let the price be = rs . 100 , and number of units sold = 100 then , sale value = rs . ( 100 × 100 ) = rs . 10000 new sale value = rs . ( 140 × 80 ) = rs . 11200 increase % = 1200 / 10000 × 100 = 12 % answer : d"

subtract(add(const_100, 40), add(divide(multiply(add(const_100, 40), 20), const_100), const_100))

<gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">140 * 20</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 100</gadget>
<output>28</output>
<gadget id="calculator">28 + 100</gadget>
<output>128</output>
<gadget id="calculator">140 - 128</gadget>
<output>12</output>
<result>12</result>


a 10 % stock yields 8 % . the market value of the stock is :

Explanation: "solution to obtain rs . 8 , investment = rs . 100 . to obtain rs . 10 , investment = rs . ( 100 / 8 x 10 ) = rs . 125 ∴ market value of rs . 100 stock = rs . 125 answer b"

<gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 10</gadget>
<output>125</output>
<result>125</result>


a certain sum is invested at simple interest at 18 % p . a . for two years instead of investing at 12 % p . a . for the same time period . therefore the interest received is more by rs . 300 . find the sum ?

Explanation: "let the sum be rs . x . ( x * 18 * 2 ) / 100 - ( x * 12 * 2 ) / 100 = 300 = > 36 x / 100 - 24 x / 100 = 300 = > 12 x / 100 = 300 = > x = 2500 . answer : b"

divide(300, divide(multiply(subtract(18, 12), const_2), const_100))

<gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">300 / (3/25)</gadget>
<output>2_500</output>
<result>2_500</result>


at a monthly meeting , 3 / 5 of the attendees were males and 7 / 8 of the male attendees arrived on time . if 4 / 5 of the female attendees arrived on time , what fraction of the attendees at the monthly meeting did not arrive on time ?

Explanation: "males who did not arrive on time are 1 / 8 * 3 / 5 = 3 / 40 of the attendees . females who did not arrive on time are 1 / 5 * 2 / 5 = 2 / 25 of the attendees . the fraction of all attendees who did not arrive on time is 3 / 40 + 2 / 25 = 31 / 200 the answer is b ."

add(multiply(subtract(const_1, divide(4, 5)), subtract(const_1, divide(3, 5))), multiply(subtract(const_1, divide(7, 8)), divide(3, 5)))

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/5) * (2/5)</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">1 - (7/8)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * (3/5)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(2/25) + (3/40)</gadget>
<output>31/200 = around 0.155</output>
<result>31/200 = around 0.155</result>


how many quarters are equal to 4 dollars ?

Explanation: "4 * 4 = 16 quarters answer : a"

<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<result>16</result>


danny and steve are running towards each other , each one from his own house . danny can reach steve ' s house in 33 minutes of running , which is half the time it takes steve to reach danny ' s house . if the two started to run at the same time , how much time longer will it take steve to reach the halfway point between their houses than danny to reach the halfway point between their houses ?

Explanation: "danny ' s time is 33 minutes . the time to reach halfway is 16.5 minutes . steve ' s time is 66 minutes . the time to reach halfway is 33 minutes . the time difference is 33 - 16.5 = 16.5 minutes the answer is a ."

<gadget id="calculator">33 / 2</gadget>
<output>33/2 = around 16.5</output>
<result>33/2 = around 16.5</result>


a fair 2 sided coin is flipped 4 times . what is the probability that tails will be the result at least twice , but not more than 4 times ?

Explanation: "at least twice , but not more than 4 timesmeans exactly 2 times , 3 times , 4 times the probability of getting exactly k results out of n flips is nck / 2 ^ n 4 c 2 / 2 ^ 4 + 4 c 3 / 2 ^ 4 = 10 / 16 = 5 / 8 option : c"

subtract(const_1, add(multiply(inverse(power(2, 4)), 4), add(inverse(power(2, 4)), inverse(power(2, 4)))))

<gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(1/16) * 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/16) + (1/16)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/4) + (1/8)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">1 - (3/8)</gadget>
<output>5/8 = around 0.625</output>
<result>5/8 = around 0.625</result>


find the sum of divisors of 544 which are perfect squares .

Explanation: "544 = 25 + 171 = ( 2 ) 0 + ( 2 ) 1 + ( 2 ) 2 + ( 2 ) 3 + ( 2 ) 4 + ( 2 ) 5 x ( 17 ) 0 + ( 17 ) 1 . here 20 = 1 = 11 a perfect square , 22 and 24 = 16 = 44 are perfect squares , hence , 1 + 4 + 16 = 21 . correct answer is : d"

add(divide(divide(544, divide(divide(divide(divide(divide(544, const_2), const_2), const_2), const_2), const_2)), const_2), add(const_1, sqrt(divide(divide(544, divide(divide(divide(divide(divide(544, const_2), const_2), const_2), const_2), const_2)), const_2))))

<gadget id="calculator">544 / 2</gadget>
<output>272</output>
<gadget id="calculator">272 / 2</gadget>
<output>136</output>
<gadget id="calculator">136 / 2</gadget>
<output>68</output>
<gadget id="calculator">68 / 2</gadget>
<output>34</output>
<gadget id="calculator">34 / 2</gadget>
<output>17</output>
<gadget id="calculator">544 / 17</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">16 + 5</gadget>
<output>21</output>
<result>21</result>


a glass was filled with 10 ounces of water , and 0.03 ounce of the water evaporated each day during a 20 - day period . what percent of the original amount of water evaporated during this period ?

Explanation: "we are given that 0.03 ounces of water evaporated each day . furthermore , we know that this process happened over a 20 - day period . to calculate the total amount of water that evaporated during this time frame we need to multiply 0.01 by 20 . this gives us : 0.03 x 20 = 0.6 ounces finally , we are asked for “ what percent ” of the original amount of water evaporated during this period . to determine this percentage , we have to make sure we translate the expression correctly . we can translate it to : ( amount evaporated / original amount ) x 100 % ( 0.6 / 10 ) x 100 % ( 6 / 100 ) x 100 % = 6 % answer d"

multiply(divide(multiply(0.03, 20), 10), const_100)

<gadget id="calculator">0.03 * 20</gadget>
<output>0.6</output>
<gadget id="calculator">0.6 / 10</gadget>
<output>0.06</output>
<gadget id="calculator">0.06 * 100</gadget>
<output>6</output>
<result>6</result>


a cistern is normally filled in 6 hours but takes two hours longer to fill because of a leak in its bottom . if the cistern is full , the leak will empty it in ?

Explanation: 1 / 6 - 1 / x = 1 / 8 x = 24 answer : c

inverse(subtract(divide(const_1, 6), divide(const_1, add(6, const_2))))

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) - (1/8)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>24</result>


a mobile battery in 1 hour charges to 20 percent . how much time ( in minute ) will it require more to charge to 50 percent .

Explanation: 1 hr = 20 percent . thus 15 min = 5 percent . now to charge 50 percent 150 min . answer : b

<gadget id="calculator">50 / 20</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 60</gadget>
<output>150</output>
<result>150</result>


the diagonals of a rhombus are 10 cm and 12 cm . find its area ?

Explanation: "1 / 2 * 10 * 12 = 60 answer : b"

<gadget id="calculator">(10 * 12) / 2</gadget>
<output>60</output>
<result>60</result>


a hollow iron pipe is 21 cm long and its external diameter is 8 cm . if the thickness of the pipe is 1 cm and iron weighs 8 g / cm 3 , then the weight of the pipe is :

Explanation: "solution external radius = 4 cm , internal radius = 3 cm . volume of iron = ( 22 / 7 × ( 42 ) - ( 32 ) × 21 ) cm 3 = ( 22 / 7 × 7 × 1 × 21 ) cm 3 = 462 cm 3 . weight of iron = ( 462 x 8 ) gm = 3696 gm = 3.696 kg . answer b"

divide(multiply(subtract(volume_cylinder(divide(8, const_2), 21), volume_cylinder(subtract(divide(8, const_2), 1), 21)), 8), const_1000)

<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 21</gadget>
<output>336*pi = around 1_055.575132</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">pi * (3 ** 2) * 21</gadget>
<output>189*pi = around 593.761012</output>
<gadget id="calculator">(336*pi) - (189*pi)</gadget>
<output>147*pi = around 461.81412</output>
<gadget id="calculator">(147*pi) * 8</gadget>
<output>1176*pi = around 3_694.512961</output>
<gadget id="calculator">(1176*pi) / 1_000</gadget>
<output>147*pi/125 = around 3.694513</output>
<result>147*pi/125 = around 3.694513</result>


in the forestside summer camp there are 50 children . 90 % of the children are boys and the rest are girls . the camp administrator decided to make the number of girls only 5 % of the total number of children in the camp . how many more boys must she bring to make that happen ?

Explanation: given there are 50 students in the forestside summer camp , 90 % of 50 = 45 boys and remaining 5 girls . now here 90 % are boys and 10 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 5 % . . if we add 50 to existing 45 then the count will be 95 and the girls number will be 5 as it . now boys are 95 % and girls are 5 % . ( out of 100 students = 95 boys + 5 girls ) . imo option a is correct .

subtract(divide(multiply(50, subtract(const_1, divide(90, const_100))), divide(5, const_100)), 50)

<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">50 * (1/10)</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">5 / (1/20)</gadget>
<output>100</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<result>50</result>


on dividing 109 by a number , the quotient is 9 and the remainder is 1 . find the divisor ?

Explanation: "d = ( d - r ) / q = ( 109 - 1 ) / 9 = 108 / 9 = 12 b )"

<gadget id="calculator">109 / 9</gadget>
<output>109/9 = around 12.111111</output>
<gadget id="calculator">floor(109/9)</gadget>
<output>12</output>
<result>12</result>


if 0.75 : x : : 10 : 8 , then x is equal to :

Explanation: "( x * 10 ) = ( 0.75 * 8 ) x = 6 / 10 x = 0.6 answer = a"

<gadget id="calculator">0.75 * 8</gadget>
<output>6</output>
<gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<result>3/5 = around 0.6</result>


there are 2 sections a and b in a class , consisting of 36 and 44 students respectively . if the average weight of section a is 40 kg and that of section b is 35 kg , find the average of the whole class ?

Explanation: total weight of 36 + 44 students = 36 * 44 + 44 * 35 = 2980 average weight of the class is = 2980 / 80 = 37.25 kg answer is b

divide(add(multiply(36, 40), multiply(44, 35)), add(36, 44))

<gadget id="calculator">36 * 40</gadget>
<output>1_440</output>
<gadget id="calculator">44 * 35</gadget>
<output>1_540</output>
<gadget id="calculator">1_440 + 1_540</gadget>
<output>2_980</output>
<gadget id="calculator">36 + 44</gadget>
<output>80</output>
<gadget id="calculator">2_980 / 80</gadget>
<output>149/4 = around 37.25</output>
<result>149/4 = around 37.25</result>


a box contains 100 pairs of shoes ( 200 shoes in total ) . if two shoes are selected at random , what it is the probability that they are matching shoes ?

Explanation: "the problem with your solution is that we do n ' t choose 1 shoe from 200 , but rather choose the needed one after we just took one and need the second to be the pair of it . so , the probability would simply be : 1 / 1 * 1 / 199 ( as after taking one at random there are 199 shoes left and only one is the pair of the first one ) = 1 / 199 answer : c ."

<gadget id="calculator">200 - 1</gadget>
<output>199</output>
<gadget id="calculator">1 / 199</gadget>
<output>1/199 = around 0.005025</output>
<result>1/199 = around 0.005025</result>


the nasdaq index has decreased by 70 % since year 2000 . how much should the index increase in order to gain the same value as in year 2000 ?

Explanation: let x be the index in the year 2000 . after the decrease it becomes 0.3 x now for 0.3 x to reach 1 x it has to raise by 0.7 x . the increase needs to be 0.7 x / 0.3 x * 100 = 233.3 % answer c

multiply(divide(divide(70, const_100), subtract(const_1, divide(70, const_100))), const_100)

<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 - (7/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(7/10) / (3/10)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 100</gadget>
<output>700/3 = around 233.333333</output>
<result>700/3 = around 233.333333</result>


if the simple interest on a sum of money for 2 years at 5 % per annum is rs . 52 , what is the compound interest on the same sum at the rate and for the same time ?

Explanation: explanation : sum = ( 52 * 100 ) / ( 2 * 5 ) = rs . 520 amount = [ 520 * ( 1 + 5 / 100 ) 2 ] = rs . 573.3 c . i . = ( 573.3 - 520 ) = rs . 53.30 . answer : a

subtract(add(add(divide(multiply(divide(52, multiply(divide(5, const_100), 2)), 5), const_100), divide(52, multiply(divide(5, const_100), 2))), divide(multiply(add(divide(multiply(divide(52, multiply(divide(5, const_100), 2)), 5), const_100), divide(52, multiply(divide(5, const_100), 2))), 5), const_100)), divide(52, multiply(divide(5, const_100), 2)))

<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">52 / (1/10)</gadget>
<output>520</output>
<gadget id="calculator">520 * 5</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 / 100</gadget>
<output>26</output>
<gadget id="calculator">26 + 520</gadget>
<output>546</output>
<gadget id="calculator">546 * 5</gadget>
<output>2_730</output>
<gadget id="calculator">2_730 / 100</gadget>
<output>273/10 = around 27.3</output>
<gadget id="calculator">546 + (273/10)</gadget>
<output>5_733/10 = around 573.3</output>
<gadget id="calculator">(5_733/10) - 520</gadget>
<output>533/10 = around 53.3</output>
<result>533/10 = around 53.3</result>


29 persons can repair a road in 16 days , working 5 hours a day . in how many days will 30 persons , working 6 hours a day , complete the work ?

Explanation: "let the required number of days be x more persons , less days ( indirect proportion ) more hours , less days ( indirect proportion ) hence we can write as ( persons ) 29 : 30 } : : x : 16 ( hours ) 5 : 6 29 * 5 * 16 = 30 * 6 * x x = 12.88 answer : a"

divide(multiply(multiply(29, 16), 5), multiply(30, 6))

<gadget id="calculator">29 * 16</gadget>
<output>464</output>
<gadget id="calculator">464 * 5</gadget>
<output>2_320</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">2_320 / 180</gadget>
<output>116/9 = around 12.888889</output>
<result>116/9 = around 12.888889</result>


the income tax in country x is 8 % of any income up to $ 5000 . for incomes over $ 5000 , an 8 % tax is imposed on the first $ 5000 , and a 10 % tax is imposed on the portion of the total income in excess of $ 5000 . if perry paid $ 950 in income tax last month , then what was perry ' s income ?

Explanation: given : for incomes over $ 5,000 , an 8 % tax is imposed on the first $ 5,000 , and a 10 % tax is imposed on the portion of the total income in excess of $ 5000 . if perry paid $ 950 in income tax last month , then what was perry ' s income ? for first 5000 , 8 % tax then we get 400 $ as tax . now perry paid 950 $ tax . . . we need to check which option is going to yield 550 $ on the remaining amount . a . $ 10,500 - 5000 = 5500 , then we get 10 % tax , we get 550 $ . . . ( $ 10,500 - 5000 - here already for 5000 $ we have calculated the tax and we need to tally for the remaining amount ) 550 + 400 = 950 $ . . . hence this is the option . answer : option a .

<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">5_000 * (2/25)</gadget>
<output>400</output>
<gadget id="calculator">950 - 400</gadget>
<output>550</output>
<gadget id="calculator">5_000 + 550</gadget>
<output>5_550</output>
<gadget id="calculator">5_550 + 5_000</gadget>
<output>10_550</output>
<result>10_550</result>


a shopkeeper sold an book offering a discount of 5 % and earned a profit of 23.5 % . what would have been the percentage of profit earned if no discount was offered ?

Explanation: c 130 % let c . p . be $ 100 . then , s . p . = $ 123.50 let marked price be $ x . then , 95 / 100 x = 123.50 x = 12350 / 95 = $ 130 now , s . p . = $ 130 , c . p . = $ 100 profit % = 30 % .

multiply(const_100, divide(add(const_100, 23.5), subtract(const_100, 5)))

<gadget id="calculator">100 + 23.5</gadget>
<output>123.5</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">123.5 / 95</gadget>
<output>1.3</output>
<gadget id="calculator">100 * 1.3</gadget>
<output>130</output>
<result>130</result>


if n = 2 ^ 0.15 and n ^ b = 8 , b must equal

Explanation: "15 / 100 = 3 / 20 n = 2 ^ 3 / 20 n ^ b = 2 ^ 3 ( 2 ^ 3 / 20 ) ^ b = 2 ^ 3 b = 20 answer : c"

<gadget id="calculator">log(8)</gadget>
<output>log(8) = around 2.079442</output>
<gadget id="calculator">2 ** 0.15</gadget>
<output>1.109569</output>
<gadget id="calculator">log(1.109569)</gadget>
<output>0.103972</output>
<gadget id="calculator">log(8) / 0.103972</gadget>
<output>9.61797406994191*log(8) = around 20.000015</output>
<result>9.61797406994191*log(8) = around 20.000015</result>


last year sandy saved 10 % of her annual salary . this year , she made 10 % more money than last year , and she saved 6 % of her salary . the amount saved this year was what percent of the amount she saved last year ?

Explanation: "let last year ' s salary be x . last year , sandy save 0.1 x this year , sandy saved 0.06 * 1.1 x = 0.066 x 0.066 x / 0.1 x = 0.66 = 66 % the answer is a ."

multiply(divide(multiply(divide(6, const_100), add(const_100, 10)), divide(multiply(10, const_100), const_100)), const_100)

<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(3/50) * 110</gadget>
<output>33/5 = around 6.6</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 100</gadget>
<output>10</output>
<gadget id="calculator">(33/5) / 10</gadget>
<output>33/50 = around 0.66</output>
<gadget id="calculator">(33/50) * 100</gadget>
<output>66</output>
<result>66</result>


the value of a scooter depreciates in such a way that its value of the end of each year is 3 / 4 of its value of the beginning of the same year . if the initial value of the scooter is rs . 40000 , what is the value at the end of 2 years ?

Explanation: explanation : 40,000 * ( 3 / 4 ) ^ 2 answer : c

<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 2</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">40_000 * (9/16)</gadget>
<output>22_500</output>
<result>22_500</result>


5 years ago , paula was 3 times as old as karl . in 6 years , paula will be twice as old as karl . what is the sum of their ages now ?

Explanation: p - 5 = 3 ( k - 5 ) and so p = 3 k - 10 p + 6 = 2 ( k + 6 ) ( 3 k - 10 ) + 6 = 2 k + 12 k = 16 p = 38 p + k = 54 the answer is d .

add(subtract(multiply(add(negate(subtract(6, multiply(6, const_2))), subtract(multiply(5, 3), 5)), const_3), subtract(multiply(5, 3), 5)), add(negate(subtract(6, multiply(6, const_2))), subtract(multiply(5, 3), 5)))

<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">6 - 12</gadget>
<output>-6</output>
<gadget id="calculator">-(-6)</gadget>
<output>6</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 - 10</gadget>
<output>38</output>
<gadget id="calculator">38 + 16</gadget>
<output>54</output>
<result>54</result>


one fourth of a solution that was 8 % sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight . the second solution was what percent sugar by weight ?

Explanation: "say the second solution ( which was 1 / 4 th of total ) was x % sugar , then 3 / 4 * 0.08 + 1 / 4 * x = 1 * 0.16 - - > x = 0.4 . alternately you can consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.08 + 25 * x = 100 * 0.16 - - > x = 0.4 . answer : c ."

multiply(divide(subtract(multiply(const_100, divide(16, const_100)), multiply(subtract(const_100, multiply(divide(const_1, const_4), const_100)), divide(8, const_100))), multiply(divide(const_1, const_4), const_100)), const_100)

<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">100 * (4/25)</gadget>
<output>16</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">75 * (2/25)</gadget>
<output>6</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">10 / 25</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>40</result>


a and b invests rs . 2000 and rs . 4000 respectively in a business . if a doubles his capital after 6 months . in what ratio should a and b divide that year ' s profit ?

Explanation: "( 2 * 6 + 4 * 6 ) : ( 4 * 12 ) 36 : 48 = > 3 : 4 answer : b"

divide(add(multiply(2000, 6), multiply(multiply(2000, const_2), 6)), multiply(4000, add(6, 6)))

<gadget id="calculator">2_000 * 6</gadget>
<output>12_000</output>
<gadget id="calculator">2_000 * 2</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 * 6</gadget>
<output>24_000</output>
<gadget id="calculator">12_000 + 24_000</gadget>
<output>36_000</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">4_000 * 12</gadget>
<output>48_000</output>
<gadget id="calculator">36_000 / 48_000</gadget>
<output>3/4 = around 0.75</output>
<result>3/4 = around 0.75</result>


two trains of equal lengths take 8 sec and 15 sec respectively to cross a telegraph post . if the length of each train be 120 m , in what time will they cross other travelling in opposite direction ?

Explanation: "speed of the first train = 120 / 8 = 15 m / sec . speed of the second train = 120 / 15 = 8 m / sec . relative speed = 15 + 8 = 23 m / sec . required time = ( 120 + 120 ) / 23 = 10 sec . answer : d"

divide(multiply(120, const_2), add(speed(120, 15), speed(120, 8)))

<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<gadget id="calculator">120 / 8</gadget>
<output>15</output>
<gadget id="calculator">8 + 15</gadget>
<output>23</output>
<gadget id="calculator">240 / 23</gadget>
<output>240/23 = around 10.434783</output>
<result>240/23 = around 10.434783</result>


a certain list consists of 21 different numbers . if n is in the list and n is 5 times the average ( arithmetic mean ) of the other 20 numbers in the list , then n is what fraction of the sum of the 21 numbers in the list ?

Explanation: "series : a 1 , a 2 . . . . a 20 , n sum of a 1 + a 2 + . . . + a 20 = 20 * x ( x = average ) so , n = 5 * x hence , a 1 + a 2 + . . + a 20 + n = 25 x so , the fraction asked = 5 x / 25 x = 1 / 5 answer c"

divide(multiply(const_1, const_1), subtract(subtract(multiply(divide(add(divide(20, const_4.0), 21), const_4.0), const_2), 5), const_3))

<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 + 21</gadget>
<output>26</output>
<gadget id="calculator">26 / 4</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(13/2) * 2</gadget>
<output>13</output>
<gadget id="calculator">13 - 5</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<result>1/5 = around 0.2</result>


danny and steve are running towards each other , each one from his own house . danny can reach steve ' s house in 27 minutes of running , which is half the time it takes steve to reach danny ' s house . if the two started to run at the same time , how much time longer will it take steve to reach the halfway point between their houses than danny to reach the halfway point between their houses ?

Explanation: "danny ' s time is 27 minutes . the time to reach halfway is 13.5 minutes . steve ' s time is 54 minutes . the time to reach halfway is 27 minutes . the time difference is 27 - 13.5 = 13.5 minutes the answer is a ."

<gadget id="calculator">27 / 2</gadget>
<output>27/2 = around 13.5</output>
<result>27/2 = around 13.5</result>


a number exceeds by 40 from its 3 / 8 part . then the number is ?

Explanation: "x – 3 / 8 x = 40 x = 64 answer : c"

<gadget id="calculator">40 * 8</gadget>
<output>320</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">320 / 5</gadget>
<output>64</output>
<result>64</result>


amar takes as much time in running 22 meters as a car takes in covering 58 meters . what will be the distance covered by amar during the time the car covers 2.6 km ?

Explanation: "distance covered by amar = 22 / 58 ( 2.6 km ) = 11 / 29 ( 2600 ) = 986 m answer : d"

divide(multiply(22, multiply(2.6, const_1000)), 58)

<gadget id="calculator">2.6 * 1_000</gadget>
<output>2_600</output>
<gadget id="calculator">22 * 2_600</gadget>
<output>57_200</output>
<gadget id="calculator">57_200 / 58</gadget>
<output>28_600/29 = around 986.206897</output>
<result>28_600/29 = around 986.206897</result>


a 340 - liter solution of kola is made from 88 % water , 5 % concentrated kola and the rest is made from sugar . if 3.2 liters of sugar , 10 liter of water and 6.8 liters of concentrated kola were added to the solution , what percent of the solution is made from sugar ?

Explanation: "denominator : 340 + 10 + 3.2 + 6.8 = 360 numerator : 340 ( 1 - . 88 - . 05 ) + 3.2 340 ( 0.07 ) + 3.2 23.8 + 3.2 27 ratio : 27 / 360 = 3 / 40 answer : b"

multiply(divide(add(subtract(subtract(340, multiply(340, divide(88, const_100))), multiply(340, divide(5, const_100))), 3.2), add(add(add(340, 3.2), 10), 6.8)), const_100)

<gadget id="calculator">88 / 100</gadget>
<output>22/25 = around 0.88</output>
<gadget id="calculator">340 * (22/25)</gadget>
<output>1_496/5 = around 299.2</output>
<gadget id="calculator">340 - (1_496/5)</gadget>
<output>204/5 = around 40.8</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">340 * (1/20)</gadget>
<output>17</output>
<gadget id="calculator">(204/5) - 17</gadget>
<output>119/5 = around 23.8</output>
<gadget id="calculator">(119/5) + 3.2</gadget>
<output>27</output>
<gadget id="calculator">340 + 3.2</gadget>
<output>343.2</output>
<gadget id="calculator">343.2 + 10</gadget>
<output>353.2</output>
<gadget id="calculator">353.2 + 6.8</gadget>
<output>360</output>
<gadget id="calculator">27 / 360</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(3/40) * 100</gadget>
<output>15/2 = around 7.5</output>
<result>15/2 = around 7.5</result>


when the perimeter of a regular polygon is divided by 5 , the length of a side is 25 . what is the name of the polygon ? what is the perimeter ?

Explanation: regular polygon . a polygon with equal sides and equal sides . divided by 5 to get the length of a side . it is the pentagon since it has 5 sides . so p = 5 × s to get the perimeter , just multiply a side by 5 . since 25 × 5 = 125 , the perimeter is 125 . answer a

<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">25 * 5</gadget>
<output>125</output>
<result>125</result>


a vessel of capacity 60 litres is fully filled with pure milk . nine litres of milk is removed from the vessel and replaced with water . nine litres of the solution thus formed is removed and replaced with water . find the quantity of pure milk in the final milk solution ?

Explanation: explanation : let the initial quantity of milk in vessel be t litres . let us say y litres of the mixture is taken out and replaced by water for n times , alternatively . quantity of milk finally in the vessel is then given by [ ( t - y ) / t ] ^ n * t for the given problem , t = 60 , y = 9 and n = 2 . hence , quantity of milk finally in the vessel = [ ( 60 - 9 ) / 60 ] ^ 2 ( 60 ) = 43.35 litres . answer : option d

subtract(subtract(60, multiply(const_3, const_3)), multiply(divide(subtract(60, multiply(const_3, const_3)), 60), multiply(const_3, const_3)))

<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">60 - 9</gadget>
<output>51</output>
<gadget id="calculator">51 / 60</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 9</gadget>
<output>153/20 = around 7.65</output>
<gadget id="calculator">51 - (153/20)</gadget>
<output>867/20 = around 43.35</output>
<result>867/20 = around 43.35</result>


an empty wooden vessel weighs 8 % of its total weight when filled with paint . if the weight of a partially filled vessel is one half that of a completely filled vessel , what fraction of the vessel is filled .

Explanation: "an empty wooden vessel weighs 8 % of its total weight when filled with paint : vessel = 0.08 ( vessel + paint ) ; 8 v = v + p ( so the weight of completely filled vessel is 8 v ) p = 7 v ( so the weight of the paint when the vessels is completely filled is 7 v ) . the weight of a partially filled vessel is one half that of a completely filled vessel : v + p ' = 1 / 2 * 8 v ; p ' = 3 v ( so the weight of the paint when the vessels is partially filled is 3 v ) . what fraction of the vessel is filled ? so , we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled : p ' / p = 3 v / 7 v = 3 / 7 . answer : a ."

divide(subtract(divide(8, const_2), const_1), subtract(8, const_1))

<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<result>3/7 = around 0.428571</result>


in a government institute 20 nos . staffs are employed . in a festival season their boss give festival allowance to all . he says his accountant to calculate for 30 days @ 100 . also he says balance payment will give to driver and cleaning staff and to be adjust from petty cash . he had given rs . 65000 / - to the accountant . how much amount will taken from petty cash ?

Explanation: for 20 staffs : 300 * 100 * 20 = 60000 for driver and cleaning staff : 300 * 100 * 2 = 6000 from petty cash : 1000 answer is a

divide(65000, subtract(100, add(20, divide(30, const_2))))

<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">20 + 15</gadget>
<output>35</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">65_000 / 65</gadget>
<output>1_000</output>
<result>1_000</result>


if $ 5,000 is invested in an account that earns 4 % interest compounded semi - annually , then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8 % simple yearly interest ?

Explanation: "solution amount ( ci ) = p + ( 1 + r / n ) ^ nt = 5000 + ( 1 + 0.04 / 2 ) ^ 2 = 5404 amount ( si ) = p + ptr / 100 = 5000 + ( 5000 * 1 * 4 / 100 ) = 5400 difference = 5404 - 5400 = 4 $ a"

<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<result>4</result>


an amount of money is to be distributed among faruk , vasim and ranjith in the ratio 3 : 5 : 7 . if vasims share is rs . 1500 , what is the difference between faruk ' s and ranjith ' s shares ?

Explanation: "explanation : let p = faruk , q = vasim , r = ranjith let p = 3 x , q = 5 x and r = 7 x . then , 5 x = 1500 ? x = 300 . p = 900 , q = 1500 and r = 2100 . hence , ( r - p ) = ( 2100 - 900 ) = 1200 answer : a"

multiply(divide(1500, 5), subtract(7, 3))

<gadget id="calculator">1_500 / 5</gadget>
<output>300</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">300 * 4</gadget>
<output>1_200</output>
<result>1_200</result>


if a sum of money doubles itself in 25 years at simple interest , the ratepercent per annum is

Explanation: "explanation : let sum = x then simple interest = x rate = ( 100 * x ) / ( x * 25 ) = 4 option e"

divide(divide(const_2, divide(25, const_100)), const_2)

<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">2 / (1/4)</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>4</result>


a company produces 50000 bottles of water everyday . if a case can hold 25 bottles of water . how many cases are required by the company to hold its one day production

Explanation: "number of bottles that can be held in a case = 25 number of cases required to hold 50000 bottles = 50000 / 25 = 2000 cases . so the answer is a = 2000"

<gadget id="calculator">50_000 / 25</gadget>
<output>2_000</output>
<result>2_000</result>


a type of extra - large suv averages 12.2 miles per gallon ( mpg ) on the highway , but only 7.6 mpg in the city . what is the maximum distance , in miles , that this suv could be driven on 25 gallons of gasoline ?

Explanation: "to maximize the distance that suv could be driven on 25 gallons of gasoline , we need consider only highway driving . max distance = 25 * 12.2 = 305 answer d"

<gadget id="calculator">12.2 * 25</gadget>
<output>305</output>
<result>305</result>


5 men are equal to as many women as are equal to 8 boys . all of them earn rs . 120 only . men â € ™ s wages are ?

Explanation: "5 m = xw = 8 b 5 m + xw + 8 b - - - - - 120 rs . 5 m + 5 m + 5 m - - - - - 120 rs . 15 m - - - - - - 120 rs . = > 1 m = 8 rs . answer : e"

<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<result>8</result>


a and b are two partially filled buckets of water . if 5 liters are transferred from a to b , then a would contain one - third of the amount of water in b . alternatively , if 4 liters are transferred from b to a , b would contain one - half of the amount of water in a . bucket a contains how many liters of water ?

Explanation: "let a contains a , b contains b liters so , ( a - 5 ) / ( b + 5 ) = 1 / 3 . . . . . . . ( 1 ) again , ( b - 4 ) / ( a + 4 ) = 1 / 2 . . . . . . . . . . ( 2 ) from ( 1 ) ( 2 ) we find a = 52 / 5 ans : ( b )"

divide(multiply(add(add(5, const_3), const_2), divide(5, const_2)), add(const_2, divide(const_1, const_2)))

<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">10 * (5/2)</gadget>
<output>25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">25 / (5/2)</gadget>
<output>10</output>
<result>10</result>


a company pays 12.5 % dividend to its investors . if an investor buys rs . 60 shares and gets 25 % on investment , at what price did the investor buy the shares ?

Explanation: explanation : dividend on 1 share = ( 12.5 * 60 ) / 100 = rs . 7.5 rs . 25 is income on an investment of rs . 100 rs . 7.5 is income on an investment of rs . ( 7.5 * 100 ) / 25 = rs . 30 answer : c

divide(multiply(divide(multiply(12.5, 60), const_100), const_100), 25)

<gadget id="calculator">12.5 * 60</gadget>
<output>750</output>
<gadget id="calculator">750 / 100</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 100</gadget>
<output>750</output>
<gadget id="calculator">750 / 25</gadget>
<output>30</output>
<result>30</result>


what is the 10 digit to the right of the decimal point , in the decimal expansion of ( 1 / 2 ) ^ 10 ?

Explanation: step 1 convert fraction to decimal with two decimal places 1 / 2 = 0.50 then convert to scientific number = 5 * 10 ^ - 1 step 2 multiply 5 ^ 10 by 10 ^ - 10 step 3 5 has the sequence 5 , 25 , 125 answer is e

<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>5</result>


find the curved surface area , if the radius of a cone is 35 m and slant height is 30 m ?

Explanation: "cone curved surface area = ï € rl 22 / 7 ã — 35 ã — 30 = 110 ã — 30 = 3300 m ( power 2 ) answer is c ."

<gadget id="calculator">35 * 30</gadget>
<output>1_050</output>
<gadget id="calculator">pi * 1_050</gadget>
<output>1050*pi = around 3_298.672286</output>
<result>1050*pi = around 3_298.672286</result>


a man have 8 t - shirt and some pant . he can dress in 72 ways . then tell me the no . of pant that man have .

Explanation: let he have x pant . by fundamental principle total no . of ways in which he can dress = 8 x 8 x = 72 x = 9 pants answer b

<gadget id="calculator">72 / 8</gadget>
<output>9</output>
<result>9</result>


on average , machine a will produce a completed item once every 4 minutes , and machine b will produce a completed item once every 5 minutes . the number of items machine a produces in a 24 - hour period is approximately what percent greater than the number of items machine b would produce in that same period ?

Explanation: machine a : 1 item in 4 minutes - - > 1 / 4 items in 1 minute ; machine b : 1 item in 5 minutes - - > 1 / 5 items in 1 minute . in the same time period , machine a produces ( 1 / 4 - 1 / 5 ) / ( 1 / 5 ) * 100 = ~ 25 % more items than machine b . answer : a .

subtract(multiply(divide(multiply(divide(const_60, 4), 24), multiply(divide(const_60, 5), 24)), const_100), const_100)

<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">15 * 24</gadget>
<output>360</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 24</gadget>
<output>288</output>
<gadget id="calculator">360 / 288</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 100</gadget>
<output>125</output>
<gadget id="calculator">125 - 100</gadget>
<output>25</output>
<result>25</result>


what is the divisor ? the dividend is 76 , the remainder is 8 , the quotient is 4

Explanation: divisor = dividend - remainder divided by the quotient divisor = 76 - 8 divided by 4 divisor = 68 / 4 divisor = 17

<gadget id="calculator">76 - 8</gadget>
<output>68</output>
<gadget id="calculator">68 / 4</gadget>
<output>17</output>
<result>17</result>


at what rate percent per annum will a sum of money double in 6 years .

Explanation: "let principal = p , then , s . i . = p and time = 8 years rate = [ ( 100 x p ) / ( p x 6 ) ] % = 16.6 % per annum . answer : e"

<gadget id="calculator">100 / 6</gadget>
<output>50/3 = around 16.666667</output>
<result>50/3 = around 16.666667</result>


if 8 gallons of gasoline are added to a tank that is already filled to 3 / 4 of its capacity , the tank is then filled to 9 / 10 of its capacity . how many gallons does the tank hold ?

Explanation: "let the capacity of the tank = c ( 3 / 4 ) c + 8 = ( 9 / 10 ) c = > ( 9 / 10 ) c - ( 3 / 4 ) c = 8 = > ( 3 / 20 ) c = 8 = > c = ( 8 * 20 ) / 3 = 53.33 number of gallons of gasoline that the tank currently holds = 3 / 4 * c + 8 = 39.99 + 8 = 47.99 = 48 answer d"

add(multiply(divide(8, subtract(divide(9, 10), divide(3, 4))), divide(3, 4)), 8)

<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(9/10) - (3/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">8 / (3/20)</gadget>
<output>160/3 = around 53.333333</output>
<gadget id="calculator">(160/3) * (3/4)</gadget>
<output>40</output>
<gadget id="calculator">40 + 8</gadget>
<output>48</output>
<result>48</result>


a certain company ’ s profit in 1996 was 15 percent greater than its profit in 1995 , and its profit in 1997 was 20 percent greater than its profit in 1996 . the company ’ s profit in 1997 was what percent greater than its profit in 1995 ?

Explanation: "soln : - profit in 1995 - 100 profit in 1996 - 115 % increase profit in 1997 in comparison to 1995 = 15 + 115 * 20 % = 38 % answer : e"

multiply(subtract(multiply(add(divide(20, const_100), const_1), add(const_1, divide(15, const_100))), const_1), const_100)

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(6/5) * (23/20)</gadget>
<output>69/50 = around 1.38</output>
<gadget id="calculator">(69/50) - 1</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">(19/50) * 100</gadget>
<output>38</output>
<result>38</result>


i chose a number and divide it by 2 . then i subtracted 100 from the result and got 4 . what was the number i chose ?

Explanation: "let x be the number i chose , then x / 2 − 100 = 4 x / 2 = 104 x = 208 answer is b ."

<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">104 * 2</gadget>
<output>208</output>
<result>208</result>


the perimeter of an isosceles right triangle is 12 + 12 sq rt 2 . what is the length of the hypotenuse of the triangle ?

Explanation: side of triangle is a then perimeter = a + a + a . sqrt 2 ( right angle and pythagorus ) = 2 a + a . sqrt 2 = 12 + 12 sqrt 2 or , a . ( 2 + sqrt 2 ) = 12 ( 1 + sqrt 2 ) , a = 12 * ( 1 + sqrt 2 ) / 2 + sqrt 2 = 12 * 2.414 / 3.414 = then hypotenuse = 8.485 d

<gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">12 * (sqrt(2))</gadget>
<output>12*sqrt(2) = around 16.970563</output>
<gadget id="calculator">(12*sqrt(2)) / 2</gadget>
<output>6*sqrt(2) = around 8.485281</output>
<result>6*sqrt(2) = around 8.485281</result>


a certain protective additive increases from 50 days to 60 days the time between required maintenance checks on an industrial vehicle . by what percent is the time between maintenance checks increased by using the additive ?

Explanation: "general formula for percent increase or decrease , ( percent change ) : percent = change / original ∗ 100 so , the time between maintenance checks increased by 60 − 50 / 50 ∗ 100 = 20 answer : e ."

multiply(divide(subtract(60, 50), 50), const_100)

<gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">10 / 50</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>20</result>


given that 268 * 74 = 19832 , find the values of 2.68 * 0.74 .

Explanation: sum of decimal places = ( 2 + 2 ) = 4 2.68 * 0.74 = 1.9832 . answer is b .

<gadget id="calculator">2.68 * 0.74</gadget>
<output>1.9832</output>
<result>1.9832</result>


the probability of two events a and b are 0.25 and 0.40 respectively . the probability that both a and b occur is 0.15 . the probability that neither a nor b occur is _________

Explanation: "we are apply that formula . . . . . . . . . . . . . . p ( aorb ) = p ( a ) + p ( b ) - p ( a and b ) = . 25 + . 40 - . 15 = . 50 but the probability of neither a nor b = 1 - . 50 = 0.50 answer : c"

subtract(const_1, subtract(add(0.25, 0.40), 0.15))

<gadget id="calculator">0.25 + 0.4</gadget>
<output>0.65</output>
<gadget id="calculator">0.65 - 0.15</gadget>
<output>0.5</output>
<gadget id="calculator">1 - 0.5</gadget>
<output>0.5</output>
<result>0.5</result>


if henry were to add 9 gallons of water to a tank that is already 3 / 4 full of water , the tank would be 7 / 8 full . how many gallons of water would the tank hold if it were full ?

Explanation: "7 / 8 x - 3 / 4 x = 9 galls 1 / 8 * x = 9 gallons x = 72 gallons answer d"

multiply(9, divide(const_1, subtract(divide(7, 8), divide(3, 4))))

<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(7/8) - (3/4)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<gadget id="calculator">9 * 8</gadget>
<output>72</output>
<result>72</result>


bruce and anne can clean their house in 4 hours working together at their respective constant rates . if anne ’ s speed were doubled , they could clean their house in 3 hours working at their respective rates . how many w hours does it currently take anne to clean the house on her own ?

Explanation: "lets suppose anne and bruce take a and b hrs working separately so in 1 hour they can together finish 1 / a + 1 / b portion of the work which equals 1 / 4 ( as the work is completed in 4 hours ) after anne doubles her rate of work the portion completed by the both is 1 / a + 2 / b which is w equal to 1 / 3 ( as the work is completed in w = 3 hours ) solving these 2 equations we can find b as 12 so , d"

inverse(subtract(divide(const_1, 3), divide(const_1, 4)))

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>12</result>


the price of a book is increased from $ 300 to $ 330 . what is the % of increase in its price ?

Explanation: explanation : change in the price = rs 330 – rs 300 = rs 30 percentage of increase = change in the price initial price * 100 . percentage increase in price = ( 30 / 300 ) * 100 = 10 % a

multiply(divide(subtract(330, 300), 300), const_100)

<gadget id="calculator">330 - 300</gadget>
<output>30</output>
<gadget id="calculator">30 / 300</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>10</result>


a sum of 14,800 amounts to 19,800 in 3 years at the rate of simple interest . what is the rate of interest ?

Explanation: "b 11 % s . i . = ( 19800 - 14800 ) = 5000 . rate = ( 100 x 5000 ) / ( 14800 x 3 ) % = 11 %"

multiply(divide(divide(const_3, 3), add(multiply(const_3, 3), add(const_0_25, const_0_25))), const_100)

<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">9 + (1/2)</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">1 / (19/2)</gadget>
<output>2/19 = around 0.105263</output>
<gadget id="calculator">(2/19) * 100</gadget>
<output>200/19 = around 10.526316</output>
<result>200/19 = around 10.526316</result>


from the sale of sleeping bags , a retailer made a gross profit of 16 % of the wholesale cost . if each sleeping bag was sold for $ 28 , what was the wholesale cost per bag ?

Explanation: "cost price * 1.16 = selling price - - > cost price * 1.16 = $ 28 - - > cost price = $ 24.13 . answer : c ."

divide(multiply(28, const_100), add(const_100, 16))

<gadget id="calculator">28 * 100</gadget>
<output>2_800</output>
<gadget id="calculator">100 + 16</gadget>
<output>116</output>
<gadget id="calculator">2_800 / 116</gadget>
<output>700/29 = around 24.137931</output>
<result>700/29 = around 24.137931</result>


a number is doubled and 5 is added . if the resultant is trebled , it becomes 129 . what is that number ?

Explanation: explanation : let the number be x . therefore , 3 ( 2 x + 5 ) = 129 6 x + 15 = 129 6 x = 114 x = 19 answer : d

divide(subtract(129, multiply(const_3, 5)), multiply(const_3, const_2))

<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">129 - 15</gadget>
<output>114</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">114 / 6</gadget>
<output>19</output>
<result>19</result>


the average temperature for tuesday , wednesday and thursday was 42 ° c . the average temperature for wednesday , thursday and friday was 44 ° c . if the temperature on friday be 43 ° c , what was the temperature on tuesday ?

Explanation: "explanation : t + w + t = 42 × 3 = 126 ° c w + t + f = 44 × 3 = 132 ° c also , temperature on friday = 43 ° c temperature on tuesday = 126 + 43 - 132 = 37 ° c answer : option c"

subtract(multiply(42, const_3), subtract(multiply(44, const_3), 43))

<gadget id="calculator">42 * 3</gadget>
<output>126</output>
<gadget id="calculator">44 * 3</gadget>
<output>132</output>
<gadget id="calculator">132 - 43</gadget>
<output>89</output>
<gadget id="calculator">126 - 89</gadget>
<output>37</output>
<result>37</result>


if a , b , and c are positive real numbers such that a ( b + c ) = 152 , b ( c + a ) = 162 , and c ( a + b ) = 170 , then abc is

Explanation: ab + bc = 152 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 1 ) bc + ba = 162 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 2 ) ac + ab = 170 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 3 ) re - writing equation 3 as follows : ac + cb = 162 + 8 ac + cb = bc + ba + 8 ac = ba + 8 . . . . . . . . . . . . . . . ( 4 ) adding ( 1 ) ( 4 ) 2 ac = 160 ac = 80 abc has to be multiple of 80 , only 720 fits in answer = d

<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">170 + 162</gadget>
<output>332</output>
<gadget id="calculator">152 + 332</gadget>
<output>484</output>
<gadget id="calculator">170 + 484</gadget>
<output>654</output>
<gadget id="calculator">4 + 654</gadget>
<output>658</output>
<gadget id="calculator">20 + 658</gadget>
<output>678</output>
<gadget id="calculator">678 + 20</gadget>
<output>698</output>
<result>698</result>


Explanation: "last term = first term + ( total no . of terms - 1 ) consecutive difference s is a set of 50 consecutive multiples of 2 . if the smallest number in s is 56 , then the greatest number in s is first term = 56 ; total terms = 50 ; difference = 2 56 + ( 49 ) 2 = 154 ans b"

add(56, multiply(subtract(50, const_1), 2))

<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">49 * 2</gadget>
<output>98</output>
<gadget id="calculator">56 + 98</gadget>
<output>154</output>
<result>154</result>


the total number of digit used in numbering the pages of a book having 366 pages , is :

Explanation: solution total number of digits = ( no . of digits in 1 - digits page nos . + no . of digits in 2 - digits page nos . + no . of digits i 3 - digits page nos . ) = ( 1 * 9 + 2 * 90 + 3 * 267 ) = ( 9 + 180 + 801 ) = 990 . answer b

add(add(subtract(const_10, const_1), multiply(const_2, multiply(const_10, subtract(const_10, const_1)))), multiply(const_3, subtract(366, subtract(const_100, const_1))))

<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<gadget id="calculator">2 * 90</gadget>
<output>180</output>
<gadget id="calculator">9 + 180</gadget>
<output>189</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">366 - 99</gadget>
<output>267</output>
<gadget id="calculator">3 * 267</gadget>
<output>801</output>
<gadget id="calculator">189 + 801</gadget>
<output>990</output>
<result>990</result>


running at the same constant rate , 6 identical machines can produce a total of 240 bottles per minute . at this rate , how many bottles could 10 such machines produce in 4 minutes ?

Explanation: "6 machines produce 240 bottles per minute ; 1 machine produces 240 / 6 = 40 bottles per minute ; 10 machines produce 40 * 10 = 400 bottles per minute ; in 4 minutes 10 machines produce 400 * 4 = 1,600 bottles . answer : c ."

multiply(multiply(divide(240, 6), 4), 10)

<gadget id="calculator">240 / 6</gadget>
<output>40</output>
<gadget id="calculator">40 * 4</gadget>
<output>160</output>
<gadget id="calculator">160 * 10</gadget>
<output>1_600</output>
<result>1_600</result>


there are 5 boxes in a cargo . the weight of the 1 st box is 200 kg , the weight of the 2 nd box is 20 % higher than the third box , whose weight is 25 % higher than the 1 st box weight . the 4 th box which weighs 350 kg is 30 % lighter than the 5 th box . find the difference in average weight of the 4 heaviest boxes and the 4 lightest boxes .

Explanation: weight of 1 st box = 200 weight of 3 rd box = ( 125 / 100 ) * 200 = 250 weight of 2 nd box = ( 120 / 100 ) * 250 = 300 weight of 4 th box = 350 weight of 5 th box = ( 10 / 7 ) * 350 = 500 average of 4 highest weighted boxes = ( 500 + 350 + 300 + 250 ) / 4 = 350 average of 4 lightest boxes = ( 350 + 300 + 250 + 200 ) / 4 = 275 therefore difference = 350 - 275 = 75 answer : b

divide(subtract(subtract(350, 25), 25), 4)

<gadget id="calculator">350 - 25</gadget>
<output>325</output>
<gadget id="calculator">325 - 25</gadget>
<output>300</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<result>75</result>


veena ranks 73 rd from the top in a class of 198 . what is her rank from the bottom if 22 students have failed the examination ?

Explanation: "total student = 198 failed = 22 paasd student = 198 - 22 = 176 from bottom her rank is = 176 - 73 + 1 = 104 answer : b"

subtract(subtract(subtract(198, 22), subtract(73, const_1)), const_4)

<gadget id="calculator">198 - 22</gadget>
<output>176</output>
<gadget id="calculator">73 - 1</gadget>
<output>72</output>
<gadget id="calculator">176 - 72</gadget>
<output>104</output>
<gadget id="calculator">104 - 4</gadget>
<output>100</output>
<result>100</result>


by selling 20 pencils for a rupee a man loses 30 % . how many for a rupee should he sell in order to gain 30 % ?

Explanation: "70 % - - - 20 130 % - - - ? 70 / 130 * 20 = 10.75 answer : b"

multiply(divide(const_1, multiply(add(const_100, 30), divide(const_1, subtract(const_100, 30)))), 20)

<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">1 / 70</gadget>
<output>1/70 = around 0.014286</output>
<gadget id="calculator">130 * (1/70)</gadget>
<output>13/7 = around 1.857143</output>
<gadget id="calculator">1 / (13/7)</gadget>
<output>7/13 = around 0.538462</output>
<gadget id="calculator">(7/13) * 20</gadget>
<output>140/13 = around 10.769231</output>
<result>140/13 = around 10.769231</result>


a man buys 60 pens at marked price of 46 pens from a whole seller . if he sells these pens giving a discount of 1 % , what is the profit percent ?

Explanation: explanation : let marked price be re . 1 each c . p . of 60 pens = rs . 46 s . p . of 60 pens = 99 % of rs . 60 = rs . 59.4 profit % = ( profit / c . p . ) x 100 profit % = ( 13.4 / 46 ) x 100 = 29.13 % answer : c

multiply(const_100, divide(subtract(multiply(60, subtract(const_100, 1)), multiply(46, const_100)), multiply(46, const_100)))

<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">60 * 99</gadget>
<output>5_940</output>
<gadget id="calculator">46 * 100</gadget>
<output>4_600</output>
<gadget id="calculator">5_940 - 4_600</gadget>
<output>1_340</output>
<gadget id="calculator">1_340 / 4_600</gadget>
<output>67/230 = around 0.291304</output>
<gadget id="calculator">100 * (67/230)</gadget>
<output>670/23 = around 29.130435</output>
<result>670/23 = around 29.130435</result>


a sells a bicycle to b and makes a profit of 25 % . b sells the same bicycle to c at a profit of 25 % . if the final s . p . of the bicycle was rs . 225 , find out the cost price of the bicycle for a .

Explanation: "explanation : let cp be 100 a sells at 25 % profit so sp = 125 b sells at 25 % profit = 125 x ( 1 + 25 / 100 ) = 156.25 cp sp 100 - - - 156.25 x - - - 225 cp = 225 x 100 / 156.25 = 144 answer : e"

divide(divide(225, divide(add(const_100, 25), const_100)), divide(add(25, const_100), const_100))

<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">225 / (5/4)</gadget>
<output>180</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">180 / (5/4)</gadget>
<output>144</output>
<result>144</result>


what is the area of a regular hexagon with sides 1 in . long ?

Explanation: "a regular hexagon of side 1 inch can be divided in to 6 equilateral triangle of side 1 inch . area of each triangle = ( root 3 / 4 ) * side ^ 2 = ( root 3 / 4 ) area of 6 triangles = 6 * ( root 3 / 4 ) = 1.5 root 3 = 2.59 square inch answer : b"

multiply(multiply(multiply(divide(divide(multiply(sqrt(1), const_4), const_pi), const_2), divide(divide(multiply(sqrt(1), const_4), const_pi), const_2)), const_pi), const_2)

<gadget id="calculator">1 ** (1/2)</gadget>
<output>1</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">4 / pi</gadget>
<output>4/pi = around 1.27324</output>
<gadget id="calculator">(4/pi) / 2</gadget>
<output>2/pi = around 0.63662</output>
<gadget id="calculator">(2/pi) * (2/pi)</gadget>
<output>4/pi**2 = around 0.405285</output>
<gadget id="calculator">(4/pi**2) * pi</gadget>
<output>4/pi = around 1.27324</output>
<gadget id="calculator">(4/pi) * 2</gadget>
<output>8/pi = around 2.546479</output>
<result>8/pi = around 2.546479</result>


ratio between rahul and deepak is 4 : 2 , after 10 years rahul age will be 26 years . what is deepak present age

Explanation: "explanation : present age is 4 x and 3 x , = > 4 x + 10 = 26 = > x = 4 so deepak age is = 2 ( 4 ) = 8 answer : option e"

divide(multiply(subtract(26, 10), 2), 4)

<gadget id="calculator">26 - 10</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<result>8</result>


what is the rate percent when the simple interest on rs . 800 amount to rs . 160 in 5 years ?

Explanation: "160 = ( 800 * 5 * r ) / 100 r = 4 % answer : e"

divide(multiply(const_100, 160), multiply(800, 5))

<gadget id="calculator">100 * 160</gadget>
<output>16_000</output>
<gadget id="calculator">800 * 5</gadget>
<output>4_000</output>
<gadget id="calculator">16_000 / 4_000</gadget>
<output>4</output>
<result>4</result>


a plant manager must assign 12 new workers to one of five shifts . she needs a first , second , and third shift , and two alternate shifts . each of the shifts will receive 3 new workers . how many different ways can she assign the new workers ?

Explanation: "whatever : my take selecting team of 3 out of 12 to assign to the shifts = 12 c 3 = 220 ways . now 3 out of 12 means total of 4 group possible . so putting them in shifts = counting methode : first , second , third , alt , alt = 4 * 3 * 2 * 1 = 24 here alt and alt are the same : so 24 / 2 = 12 ways . total ways of selecting = ( selecting 3 out of 12 ) * arranging those teams in shifts = 220 * 24 = 2640 ans : b"

multiply(divide(factorial(divide(12, 3)), const_2), divide(factorial(12), multiply(factorial(subtract(12, 3)), factorial(3))))

<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">factorial(12)</gadget>
<output>479_001_600</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">362_880 * 6</gadget>
<output>2_177_280</output>
<gadget id="calculator">479_001_600 / 2_177_280</gadget>
<output>220</output>
<gadget id="calculator">12 * 220</gadget>
<output>2_640</output>
<result>2_640</result>


a and b invests rs . 5000 and rs . 6000 in a business . after 6 months , a withdraws two - fifth of his capital and 2 months later , b withdraws one - third of his capital . in what ratio should they share the profits at the end of the year ?

Explanation: "a : b ( 5000 * 6 ) + ( 3000 * 6 ) : ( 6000 * 8 ) + ( 4000 * 4 ) 48000 : 64000 3 : 4 answer : d"

divide(add(multiply(5000, const_4.0), multiply(divide(6000, const_3), multiply(2, 6))), add(multiply(6000, multiply(2, const_3)), multiply(subtract(6000, divide(6000, const_3)), multiply(2, const_3))))

<gadget id="calculator">5_000 * 4</gadget>
<output>20_000</output>
<gadget id="calculator">6_000 / 3</gadget>
<output>2_000</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">2_000 * 12</gadget>
<output>24_000</output>
<gadget id="calculator">20_000 + 24_000</gadget>
<output>44_000</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6_000 * 6</gadget>
<output>36_000</output>
<gadget id="calculator">6_000 - 2_000</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 * 6</gadget>
<output>24_000</output>
<gadget id="calculator">36_000 + 24_000</gadget>
<output>60_000</output>
<gadget id="calculator">44_000 / 60_000</gadget>
<output>11/15 = around 0.733333</output>
<result>11/15 = around 0.733333</result>


in a maths test , students were asked to find 5 / 16 of a certain number . one of the students by mistake found 5 / 6 th of that number and his answer was 150 more than the correct answer . find the number .

Explanation: "explanation : let the number be x . 5 * x / 6 = 5 * x / 16 + 150 25 * x / 48 = 150 x = 288 answer b"

divide(multiply(multiply(150, 16), 6), subtract(multiply(5, 16), multiply(5, 6)))

<gadget id="calculator">150 * 16</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 * 6</gadget>
<output>14_400</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<gadget id="calculator">14_400 / 50</gadget>
<output>288</output>
<result>288</result>


a , b and c enter into a partnership by investing $ 7000 , $ 11000 and $ 18000 respectively . at the end of 8 months , b receives $ 880 as his share . find the share of a .

Explanation: "the ratio of capital of a , b and c = 7000 : 11000 : 18000 = 7 : 11 : 18 a ' s share = ( 7 / 11 ) * 880 = $ 560 the answer is c ."

divide(multiply(multiply(7000, divide(880, divide(multiply(11000, 8), const_100))), 8), const_100)

<gadget id="calculator">11_000 * 8</gadget>
<output>88_000</output>
<gadget id="calculator">88_000 / 100</gadget>
<output>880</output>
<gadget id="calculator">880 / 880</gadget>
<output>1</output>
<gadget id="calculator">7_000 * 1</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 * 8</gadget>
<output>56_000</output>
<gadget id="calculator">56_000 / 100</gadget>
<output>560</output>
<result>560</result>


bill downloads the movierevenge of the avengersto his computer in 2.5 hours , using a download manager that downloads from 3 sources marked a , b and c . each source provides download at a constant rate , but the rates of different sources are not necessarily identical . if the movie was downloaded from sources a and c alone , it would take 4 hours to complete the download . the next day , source b is available , but the other sources are inactive . how long will it take to download the trailer of the movie , a file that is 10 times smaller , from source b alone ?

Explanation: let the movie size be 400 u . given , a + c = 4 hrs . a + c = 100 u / hr and a + b + c = 2.5 hrs or 400 / 2.5 = 160 u / hr b alone = 160 - 100 = 60 u / hr trailer = 40 times smaller or 400 / 10 = 40 u b will take 40 / 60 hrs or 40 minutes . ans a

subtract(subtract(multiply(multiply(3, 4), 4), 4), 4)

<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">44 - 4</gadget>
<output>40</output>
<result>40</result>


a bowl of fruit contains 14 apples and 21 oranges . how many oranges must be removed so that 70 % of the pieces of fruit in the bowl will be apples ?

Explanation: "number of apples = 14 number of oranges = 23 let number of oranges that must be removed so that 70 % of pieces of fruit in bowl will be apples = x total number of fruits after x oranges are removed = 14 + ( 21 - x ) = 35 - x 14 / ( 35 - x ) = 7 / 10 = > 20 = 35 - x = > x = 15 answer b"

divide(subtract(multiply(add(14, 21), divide(70, const_100)), 14), divide(70, const_100))

<gadget id="calculator">14 + 21</gadget>
<output>35</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">35 * (7/10)</gadget>
<output>49/2 = around 24.5</output>
<gadget id="calculator">(49/2) - 14</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">(21/2) / (7/10)</gadget>
<output>15</output>
<result>15</result>


the present worth of rs . 2310 due 2 years hence , the rate of interest being 15 % per annum , is :

Explanation: "p . w . = rs . 100 x 2310 = rs . 1680 . 100 + 15 x 5 2 answer : b"

divide(2310, power(add(divide(15, const_100), const_1), 2))

<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) + 1</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) ** 2</gadget>
<output>529/400 = around 1.3225</output>
<gadget id="calculator">2_310 / (529/400)</gadget>
<output>924_000/529 = around 1_746.691871</output>
<result>924_000/529 = around 1_746.691871</result>


after decreasing 24 % in the price of an article costs rs . 684 . find the actual cost of an article ?

Explanation: "cp * ( 76 / 100 ) = 684 cp = 9 * 100 = > cp = 900 answer : c"

divide(684, subtract(const_1, divide(24, const_100)))

<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 - (6/25)</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">684 / (19/25)</gadget>
<output>900</output>
<result>900</result>


a man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream . the ratio of the speed of the boat in still water and stream is

Explanation: "explanation : let speed downstream = x kmph then speed upstream = 2 x kmph so ratio will be , ( 2 x + x ) / 2 : ( 2 x - x ) / 2 = > 3 x / 2 : x / 2 = > 3 : 1 option a"

divide(add(const_1, const_2), subtract(const_2, const_1))

<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">3 / 1</gadget>
<output>3</output>
<result>3</result>


ritesh and co . generated revenue of rs . 1,600 in 2006 . this was 12.5 % of its gross revenue . in 2007 , the gross revenue grew by rs . 2,500 . what is the percentage increase in the revenue in 2007 ?

Explanation: explanation : given , ritesh and co . generated revenue of rs . 1,600 in 2006 and that this was 12.5 % of the gross revenue . hence , if 1600 is 12.5 % of the revenue , then 100 % ( gross revenue ) is : = > ( 100 / 12.5 ) × 1600 . = > 12,800 . hence , the total revenue by end of 2007 is rs . 12,800 . in 2006 , revenue grew by rs . 2500 . this is a growth of : = > ( 2500 / 12800 ) × 100 . = > 19.53 % . answer : b

multiply(divide(add(multiply(const_2, multiply(multiply(const_2, add(const_1, const_4)), const_100)), multiply(add(const_1, const_4), const_100)), divide(add(multiply(multiply(const_2, add(const_1, const_4)), const_100), multiply(add(const_2, const_4), const_100)), divide(12.5, const_100))), const_100)

<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">2_000 + 500</gadget>
<output>2_500</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">1_000 + 600</gadget>
<output>1_600</output>
<gadget id="calculator">12.5 / 100</gadget>
<output>0.125</output>
<gadget id="calculator">1_600 / 0.125</gadget>
<output>12_800</output>
<gadget id="calculator">2_500 / 12_800</gadget>
<output>25/128 = around 0.195312</output>
<gadget id="calculator">(25/128) * 100</gadget>
<output>625/32 = around 19.53125</output>
<result>625/32 = around 19.53125</result>


the average ( arithmetic mean ) of the integers from 100 to 400 , inclusive , is how much greater than the average of the integers from 50 to 250 , inclusive ?

Explanation: for an ap the mean or average of series is average of first and last term . so , average of numbers between 100 to 400 , inclusive = ( 100 + 400 ) / 2 = 250 average of numbers between 50 to 250 , inclusive = ( 50 + 250 ) / 2 = 150 difference = 250 - 150 = 100 answer is a

subtract(divide(add(100, 400), const_2), divide(add(50, 250), const_2))

<gadget id="calculator">100 + 400</gadget>
<output>500</output>
<gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">50 + 250</gadget>
<output>300</output>
<gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">250 - 150</gadget>
<output>100</output>
<result>100</result>


a tourist does not have to pay tax on the first $ 600 of goods he purchases in country b , but does have to pay a 11 percent tax on the portion of the total value that is in excess of $ 600 . what tax must be paid by a tourist if he buys goods with a total value of $ 1720 ?

Explanation: "correct answer : e the tourist must pay tax on $ 1720 - $ 600 = $ 1120 . thus , the amount of tax he has to pay is 0.11 ( $ 1120 ) = $ 123.20 . the correct answer is e ."

divide(multiply(subtract(1720, 600), 11), const_100)

<gadget id="calculator">1_720 - 600</gadget>
<output>1_120</output>
<gadget id="calculator">1_120 * 11</gadget>
<output>12_320</output>
<gadget id="calculator">12_320 / 100</gadget>
<output>616/5 = around 123.2</output>
<result>616/5 = around 123.2</result>


how much is 60 % of 40 is greater than 4 / 5 of 30 ?

Explanation: "( 60 / 100 ) * 40 â € “ ( 4 / 5 ) * 30 24 - 24 = 0 answer : d"

subtract(multiply(40, divide(60, const_100)), multiply(divide(4, 5), 30))

<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">40 * (3/5)</gadget>
<output>24</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 30</gadget>
<output>24</output>
<gadget id="calculator">24 - 24</gadget>
<output>0</output>
<result>0</result>


find the greatest number which on dividing 6215 and 7373 , leaves a reminder of 23 and 29 respectively

Explanation: "explanation : in this type of question , its obvious we need to calculate the hcf , trick is hcf of ( 6215 - 23 ) and ( 7373 - 29 ) = hcf ( 6192 , 7344 ) = 144 option e"

<gadget id="calculator">6_215 - 23</gadget>
<output>6_192</output>
<gadget id="calculator">7_373 - 29</gadget>
<output>7_344</output>
<gadget id="calculator">gcd(6_192, 7_344)</gadget>
<output>144</output>
<result>144</result>


the pinedale bus line travels at an average speed of 60 km / h , and has stops every 5 minutes along its route . yahya wants to go from his house to the pinedale mall , which is 8 stops away . how far away , in kilometers , is pinedale mall away from yahya ' s house ?

Explanation: "number of stops in an hour : 60 / 5 = 12 distance between stops : 60 / 12 = 5 km distance between yahya ' s house and pinedale mall : 5 x 8 = 40 km imo , correct answer is ` ` c . ' '"

multiply(60, divide(multiply(5, 8), 60))

<gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">60 * (2/3)</gadget>
<output>40</output>
<result>40</result>


the sum of ages of 5 children born at the intervals of 2 years each is 55 years . what is the age of the youngest child ?

Explanation: "let the ages of children be x , ( x + 2 ) , ( x + 4 ) , ( x + 6 ) and ( x + 8 ) years . then , x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) = 50 5 x = 55 - 20 = 35 x = 7 . age of the youngest child = x = 7 years . answer : b"

<gadget id="calculator">55 / 5</gadget>
<output>11</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<result>7</result>


two goods trains each 820 m long are running in opposite directions on parallel tracks . their speeds are 45 km / hr and 30 km / hr respectively . find the time taken by the slower train to pass the driver of the faster one ?

Explanation: relative speed = 45 + 30 = 75 km / hr . 75 * 5 / 18 = 125 / 6 m / sec . distance covered = 820 + 820 = 1640 m . required time = 1640 * 6 / 125 = 78.72 sec . answer : d

<gadget id="calculator">45 + 30</gadget>
<output>75</output>
<result>75</result>


20 beavers , working together in a constant pace , can build a dam in 3 hours . how many hours c will it take 12 beavers that work at the same pace , to build the same dam ?

Explanation: "c . 5 hrs if there were 10 beavers it qould have taken double c = 6 hrs . . so closest to that option is 5 ."

<gadget id="calculator">3 * 20</gadget>
<output>60</output>
<gadget id="calculator">60 / 12</gadget>
<output>5</output>
<result>5</result>


indu gave bindu rs . 1875 on compound interest for 2 years at 4 % per annum . how much loss would indu has suffered had she given it to bindu for 2 years at 4 % per annum simple interest ?

Explanation: "1875 = d ( 100 / 4 ) 2 d = 3 answer : d"

subtract(subtract(multiply(1875, power(add(const_1, divide(4, const_100)), 2)), 1875), multiply(multiply(1875, divide(4, const_100)), 2))

<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">1_875 * (676/625)</gadget>
<output>2_028</output>
<gadget id="calculator">2_028 - 1_875</gadget>
<output>153</output>
<gadget id="calculator">1_875 * (1/25)</gadget>
<output>75</output>
<gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">153 - 150</gadget>
<output>3</output>
<result>3</result>


how many integers are between 7 and 57 / 4 , inclusive ?

Explanation: "57 / 4 = 14 . xx we are not concerned about the exact value of 57 / 4 as we just need the integers . since the values are small , we can write down the integers . the different integers between 7 and 57 / 4 would be 7 , 8 , 9 , 10 , 11 , 12 , 13,14 total number of integers = 8 option d"

add(subtract(divide(57, 4), 7), const_1)

<gadget id="calculator">57 / 4</gadget>
<output>57/4 = around 14.25</output>
<gadget id="calculator">(57/4) - 7</gadget>
<output>29/4 = around 7.25</output>
<gadget id="calculator">(29/4) + 1</gadget>
<output>33/4 = around 8.25</output>
<result>33/4 = around 8.25</result>


Explanation: we need to simplify the expression using pemdas . parentheses exponents multiplication anddivision addition andsubtraction the calculation of an equation or expression must be carried out in the following order : 1 ) operations within parentheses ( or absolute value bars or radicals ) 2 ) exponents 3 ) multiplication and division from left to right 4 ) addition and subtraction from left to right the answer is a .

subtract(multiply(divide(3, 5), divide(add(divide(2, 3), divide(3, 8)), 2)), divide(1, 16))

<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(2/3) + (3/8)</gadget>
<output>25/24 = around 1.041667</output>
<gadget id="calculator">(25/24) / 2</gadget>
<output>25/48 = around 0.520833</output>
<gadget id="calculator">(3/5) * (25/48)</gadget>
<output>5/16 = around 0.3125</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(5/16) - (1/16)</gadget>
<output>1/4 = around 0.25</output>
<result>1/4 = around 0.25</result>