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The number of adult wolf in Beverly Forest equals 1 plus the sum of the average number of newborn children per adult wolf in Cedar Valley and the number of adult racoon in Cedar Valley. The number of adult deer in Beverly Forest equals 2. The average number of newborn children per adult wolf in Beverly Forest equals 3 times the number of adult racoon in Maple Creek. The average number of newborn children per adult deer in Beverly Forest equals 2. The average number of newborn children per adult wolf in Maple Creek equals 2 plus the sum of the average number of newborn children per adult fox in Maple Creek, the total number of adult animals in Cedar Valley, and the average number of newborn children per adult fox in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals the sum of the number of adult racoon in Cedar Valley, the average number of newborn children per adult deer in Beverly Forest, the number of adult fox in Maple Creek, and the number of adult deer in Beverly Forest. The number of adult wolf in Cedar Valley equals 2 plus the sum of the average number of newborn children per adult deer in Beverly Forest, the number of adult deer in Beverly Forest, and the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult wolf in Cedar Valley equals 1. The average number of newborn children per adult fox in Maple Creek equals 2. The number of adult bear in Maple Creek equals 4. The average number of newborn children per adult deer in Cedar Valley equals the average number of newborn children per adult fox in Maple Creek. The number of adult racoon in Maple Creek equals the sum of the number of adult bear in Maple Creek and the average number of newborn children per adult deer in Beverly Forest. The number of adult deer in Cedar Valley equals 3. The number of adult racoon in Cedar Valley equals 2. The number of adult wolf in Maple Creek equals 4 times the sum of the number of adult deer in Beverly Forest, the average number of newborn children per adult deer in Cedar Valley, and the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult racoon in Cedar Valley equals 2 times the average number of newborn children per adult racoon in Maple Creek. The number of adult fox in Maple Creek equals the number of adult deer in Beverly Forest. The average number of newborn children per adult racoon in Maple Creek equals the number of adult deer in Beverly Forest. | What is the average number of newborn children per adult deer in Cedar Valley? | Define average number of newborn children per adult fox in Maple Creek as q; so q = 2. Define average number of newborn children per adult deer in Cedar Valley as l; so l = q = 2. Answer: 2. | 2 | 21 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult wolf in Beverly Forest equals 1 plus the sum of the average number of newborn children per adult wolf in Cedar Valley and the number of adult racoon in Cedar Valley. The number of adult deer in Beverly Forest equals 2. The average number of newborn children per adult wolf in Beverly Forest equals 3 times the number of adult racoon in Maple Creek. The average number of newborn children per adult deer in Beverly Forest equals 2. The average number of newborn children per adult wolf in Maple Creek equals 2 plus the sum of the average number of newborn children per adult fox in Maple Creek, the total number of adult animals in Cedar Valley, and the average number of newborn children per adult fox in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals the sum of the number of adult racoon in Cedar Valley, the average number of newborn children per adult deer in Beverly Forest, the number of adult fox in Maple Creek, and the number of adult deer in Beverly Forest. The number of adult wolf in Cedar Valley equals 2 plus the sum of the average number of newborn children per adult deer in Beverly Forest, the number of adult deer in Beverly Forest, and the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult wolf in Cedar Valley equals 1. The average number of newborn children per adult fox in Maple Creek equals 2. The number of adult bear in Maple Creek equals 4. The average number of newborn children per adult deer in Cedar Valley equals the average number of newborn children per adult fox in Maple Creek. The number of adult racoon in Maple Creek equals the sum of the number of adult bear in Maple Creek and the average number of newborn children per adult deer in Beverly Forest. The number of adult deer in Cedar Valley equals 3. The number of adult racoon in Cedar Valley equals 2. The number of adult wolf in Maple Creek equals 4 times the sum of the number of adult deer in Beverly Forest, the average number of newborn children per adult deer in Cedar Valley, and the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult racoon in Cedar Valley equals 2 times the average number of newborn children per adult racoon in Maple Creek. The number of adult fox in Maple Creek equals the number of adult deer in Beverly Forest. The average number of newborn children per adult racoon in Maple Creek equals the number of adult deer in Beverly Forest. Question: What is the average number of newborn children per adult deer in Cedar Valley? Solution: "
}
] |
The number of adult parrot in Maple Creek equals the average number of newborn children per adult parrot in Maple Creek. The number of adult blue jay in Pine Ridge equals 2. The average number of newborn children per adult blue jay in Pine Ridge equals the number of adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals 3. The number of adult parrot in Pine Ridge equals the difference between the average number of newborn children per adult parrot in Maple Creek and the total number of adult animals in Pine Ridge. The average number of newborn children per adult blue jay in Maple Creek equals 2 times the number of adult blue jay in Pine Ridge. The average number of newborn children per adult parrot in Maple Creek equals 4. The average number of newborn children per adult parrot in Pine Ridge equals 1 plus the difference between the number of adult parrot in Maple Creek and the average number of newborn children per adult blue jay in Pine Ridge. | What is the average number of newborn children per adult blue jay in Pine Ridge? | Define adult blue jay in Maple Creek as r; so r = 3. Define average number of newborn children per adult blue jay in Pine Ridge as b; so b = r = 3. Answer: 3. | 2 | 6 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult parrot in Maple Creek equals the average number of newborn children per adult parrot in Maple Creek. The number of adult blue jay in Pine Ridge equals 2. The average number of newborn children per adult blue jay in Pine Ridge equals the number of adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals 3. The number of adult parrot in Pine Ridge equals the difference between the average number of newborn children per adult parrot in Maple Creek and the total number of adult animals in Pine Ridge. The average number of newborn children per adult blue jay in Maple Creek equals 2 times the number of adult blue jay in Pine Ridge. The average number of newborn children per adult parrot in Maple Creek equals 4. The average number of newborn children per adult parrot in Pine Ridge equals 1 plus the difference between the number of adult parrot in Maple Creek and the average number of newborn children per adult blue jay in Pine Ridge. Question: What is the average number of newborn children per adult blue jay in Pine Ridge? Solution: "
}
] |
The number of adult owl in Pine Ridge equals the number of adult parrot in Oakridge Riverside. The average number of newborn children per adult parrot in Oakridge Riverside equals the difference between the average number of newborn children per adult parrot in Maple Creek and the average number of newborn children per adult owl in Pine Ridge. The number of adult blue jay in Beverly Forest equals 4. The number of adult eagle in Pine Ridge equals 3. The number of adult parrot in Oakridge Riverside equals 2. The number of adult blue jay in Maple Creek equals 4. The number of adult parrot in Maple Creek equals 3 plus the difference between the number of adult owl in Pine Ridge and the average number of newborn children per adult owl in Pine Ridge. The average number of newborn children per adult eagle in Pine Ridge equals 1 plus the sum of the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult parrot in Maple Creek. The average number of newborn children per adult blue jay in Maple Creek equals 2 times the total number of adult animals in Beverly Forest. The average number of newborn children per adult owl in Pine Ridge equals 3. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult parrot in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals 3 times the average number of newborn children per adult owl in Pine Ridge. | What is the total number of adult animals in Oakridge Riverside? | Define adult parrot in Oakridge Riverside as i; so i = 2. Define total number of adult animals in Oakridge Riverside as r; so r = i = 2. Answer: 2. | 2 | 20 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult owl in Pine Ridge equals the number of adult parrot in Oakridge Riverside. The average number of newborn children per adult parrot in Oakridge Riverside equals the difference between the average number of newborn children per adult parrot in Maple Creek and the average number of newborn children per adult owl in Pine Ridge. The number of adult blue jay in Beverly Forest equals 4. The number of adult eagle in Pine Ridge equals 3. The number of adult parrot in Oakridge Riverside equals 2. The number of adult blue jay in Maple Creek equals 4. The number of adult parrot in Maple Creek equals 3 plus the difference between the number of adult owl in Pine Ridge and the average number of newborn children per adult owl in Pine Ridge. The average number of newborn children per adult eagle in Pine Ridge equals 1 plus the sum of the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult parrot in Maple Creek. The average number of newborn children per adult blue jay in Maple Creek equals 2 times the total number of adult animals in Beverly Forest. The average number of newborn children per adult owl in Pine Ridge equals 3. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult parrot in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals 3 times the average number of newborn children per adult owl in Pine Ridge. Question: What is the total number of adult animals in Oakridge Riverside? Solution: "
}
] |
The average number of newborn children per adult wolf in Beverly Forest equals the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult racoon in Maple Creek equals 1. The average number of newborn children per adult bear in Cedar Valley equals 4. The average number of newborn children per adult racoon in Cedar Valley equals 3. The average number of newborn children per adult bear in Maple Creek equals the number of adult wolf in Beverly Forest. The number of adult racoon in Beverly Forest equals 3. The average number of newborn children per adult wolf in Cedar Valley equals 1 plus the sum of the average number of newborn children per adult racoon in Cedar Valley, the average number of newborn children per adult wolf in Beverly Forest, and the average number of newborn children per adult bear in Beverly Forest. The number of adult racoon in Maple Creek equals the average number of newborn children per adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 3 plus the difference between the average number of newborn children per adult bear in Cedar Valley and the number of adult bear in Beverly Forest. The number of adult bear in Beverly Forest equals the difference between the average number of newborn children per adult bear in Beverly Forest and the average number of newborn children per adult racoon in Beverly Forest. The average number of newborn children per adult racoon in Beverly Forest equals 3. The number of adult wolf in Cedar Valley equals 4. The number of adult racoon in Cedar Valley equals 1 plus the sum of the average number of newborn children per adult racoon in Beverly Forest, the average number of newborn children per adult bear in Cedar Valley, and the average number of newborn children per adult bear in Beverly Forest. The number of adult wolf in Beverly Forest equals the average number of newborn children per adult racoon in Maple Creek. The number of adult bear in Maple Creek equals the number of adult racoon in Maple Creek. The average number of newborn children per adult bear in Beverly Forest equals 2 plus the average number of newborn children per adult racoon in Beverly Forest. | What is the average number of newborn children per adult wolf in Beverly Forest? | Define average number of newborn children per adult racoon in Maple Creek as j; so j = 1. Define average number of newborn children per adult wolf in Beverly Forest as N; so N = j = 1. Answer: 1. | 2 | 22 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult wolf in Beverly Forest equals the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult racoon in Maple Creek equals 1. The average number of newborn children per adult bear in Cedar Valley equals 4. The average number of newborn children per adult racoon in Cedar Valley equals 3. The average number of newborn children per adult bear in Maple Creek equals the number of adult wolf in Beverly Forest. The number of adult racoon in Beverly Forest equals 3. The average number of newborn children per adult wolf in Cedar Valley equals 1 plus the sum of the average number of newborn children per adult racoon in Cedar Valley, the average number of newborn children per adult wolf in Beverly Forest, and the average number of newborn children per adult bear in Beverly Forest. The number of adult racoon in Maple Creek equals the average number of newborn children per adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 3 plus the difference between the average number of newborn children per adult bear in Cedar Valley and the number of adult bear in Beverly Forest. The number of adult bear in Beverly Forest equals the difference between the average number of newborn children per adult bear in Beverly Forest and the average number of newborn children per adult racoon in Beverly Forest. The average number of newborn children per adult racoon in Beverly Forest equals 3. The number of adult wolf in Cedar Valley equals 4. The number of adult racoon in Cedar Valley equals 1 plus the sum of the average number of newborn children per adult racoon in Beverly Forest, the average number of newborn children per adult bear in Cedar Valley, and the average number of newborn children per adult bear in Beverly Forest. The number of adult wolf in Beverly Forest equals the average number of newborn children per adult racoon in Maple Creek. The number of adult bear in Maple Creek equals the number of adult racoon in Maple Creek. The average number of newborn children per adult bear in Beverly Forest equals 2 plus the average number of newborn children per adult racoon in Beverly Forest. Question: What is the average number of newborn children per adult wolf in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult blue jay in Hamilton Farm equals the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The average number of newborn children per adult owl in Bundle Ranch equals 4. The average number of newborn children per adult eagle in Jefferson Circus equals 2 times the sum of the number of adult crow in Jefferson Circus, the number of adult eagle in Hamilton Farm, and the average number of newborn children per adult eagle in Hamilton Farm. The number of adult blue jay in Bundle Ranch equals 3. The number of adult owl in Jefferson Circus equals 3. The average number of newborn children per adult owl in Hamilton Farm equals the average number of newborn children per adult owl in Jefferson Circus. The number of adult owl in Hamilton Farm equals 3 times the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult eagle in Bundle Ranch equals 4. The number of adult crow in Hamilton Farm equals 1 plus the sum of the average number of newborn children per adult eagle in Hamilton Farm and the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult crow in Jefferson Circus equals the average number of newborn children per adult owl in Jefferson Circus. The number of adult crow in Jefferson Circus equals the sum of the average number of newborn children per adult eagle in Hamilton Farm and the number of adult eagle in Hamilton Farm. The number of adult eagle in Bundle Ranch equals 1. The number of adult blue jay in Hamilton Farm equals the number of adult owl in Jefferson Circus. The average number of newborn children per adult blue jay in Bundle Ranch equals 3. The number of adult eagle in Jefferson Circus equals the average number of newborn children per adult crow in Jefferson Circus. The number of adult eagle in Hamilton Farm equals 3. The average number of newborn children per adult crow in Hamilton Farm equals 3 times the average number of newborn children per adult eagle in Jefferson Circus. The number of adult owl in Bundle Ranch equals the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult owl in Jefferson Circus equals 2. | What is the average number of newborn children per adult blue jay in Hamilton Farm? | Define average number of newborn children per adult blue jay in Bundle Ranch as R; so R = 3. Define average number of newborn children per adult blue jay in Hamilton Farm as I; so I = R = 3. Answer: 3. | 2 | 10 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult blue jay in Hamilton Farm equals the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The average number of newborn children per adult owl in Bundle Ranch equals 4. The average number of newborn children per adult eagle in Jefferson Circus equals 2 times the sum of the number of adult crow in Jefferson Circus, the number of adult eagle in Hamilton Farm, and the average number of newborn children per adult eagle in Hamilton Farm. The number of adult blue jay in Bundle Ranch equals 3. The number of adult owl in Jefferson Circus equals 3. The average number of newborn children per adult owl in Hamilton Farm equals the average number of newborn children per adult owl in Jefferson Circus. The number of adult owl in Hamilton Farm equals 3 times the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult eagle in Bundle Ranch equals 4. The number of adult crow in Hamilton Farm equals 1 plus the sum of the average number of newborn children per adult eagle in Hamilton Farm and the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult crow in Jefferson Circus equals the average number of newborn children per adult owl in Jefferson Circus. The number of adult crow in Jefferson Circus equals the sum of the average number of newborn children per adult eagle in Hamilton Farm and the number of adult eagle in Hamilton Farm. The number of adult eagle in Bundle Ranch equals 1. The number of adult blue jay in Hamilton Farm equals the number of adult owl in Jefferson Circus. The average number of newborn children per adult blue jay in Bundle Ranch equals 3. The number of adult eagle in Jefferson Circus equals the average number of newborn children per adult crow in Jefferson Circus. The number of adult eagle in Hamilton Farm equals 3. The average number of newborn children per adult crow in Hamilton Farm equals 3 times the average number of newborn children per adult eagle in Jefferson Circus. The number of adult owl in Bundle Ranch equals the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult owl in Jefferson Circus equals 2. Question: What is the average number of newborn children per adult blue jay in Hamilton Farm? Solution: "
}
] |
The average number of newborn children per adult eagle in Beverly Forest equals the number of adult eagle in Beverly Forest. The average number of newborn children per adult blue jay in Oakridge Riverside equals 1. The average number of newborn children per adult crow in Beverly Forest equals the sum of the total number of adult animals in Oakridge Riverside and the average number of newborn children per adult blue jay in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 2 plus the difference between the number of adult blue jay in Beverly Forest and the number of adult crow in Beverly Forest. The number of adult crow in Oakridge Riverside equals 1. The number of adult blue jay in Pine Ridge equals the sum of the number of adult blue jay in Beverly Forest, the number of adult blue jay in Oakridge Riverside, and the average number of newborn children per adult crow in Oakridge Riverside. The number of adult eagle in Beverly Forest equals 4. The average number of newborn children per adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Oakridge Riverside equals 4. The average number of newborn children per adult eagle in Pine Ridge equals the difference between the average number of newborn children per adult crow in Oakridge Riverside and the total number of adult animals in Pine Ridge. The number of adult crow in Beverly Forest equals 2 times the number of adult blue jay in Beverly Forest. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult owl in Oakridge Riverside equals the difference between the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult blue jay in Pine Ridge. The number of adult owl in Pine Ridge equals the difference between the number of adult crow in Oakridge Riverside and the total number of adult animals in Beverly Forest. The average number of newborn children per adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Pine Ridge equals the average number of newborn children per adult blue jay in Beverly Forest. The number of adult blue jay in Beverly Forest equals 2. The number of adult eagle in Pine Ridge equals 2. | What is the average number of newborn children per adult blue jay in Pine Ridge? | Define average number of newborn children per adult blue jay in Beverly Forest as w; so w = 2. Define average number of newborn children per adult blue jay in Pine Ridge as Q; so Q = w = 2. Answer: 2. | 2 | 18 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult eagle in Beverly Forest equals the number of adult eagle in Beverly Forest. The average number of newborn children per adult blue jay in Oakridge Riverside equals 1. The average number of newborn children per adult crow in Beverly Forest equals the sum of the total number of adult animals in Oakridge Riverside and the average number of newborn children per adult blue jay in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 2 plus the difference between the number of adult blue jay in Beverly Forest and the number of adult crow in Beverly Forest. The number of adult crow in Oakridge Riverside equals 1. The number of adult blue jay in Pine Ridge equals the sum of the number of adult blue jay in Beverly Forest, the number of adult blue jay in Oakridge Riverside, and the average number of newborn children per adult crow in Oakridge Riverside. The number of adult eagle in Beverly Forest equals 4. The average number of newborn children per adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Oakridge Riverside equals 4. The average number of newborn children per adult eagle in Pine Ridge equals the difference between the average number of newborn children per adult crow in Oakridge Riverside and the total number of adult animals in Pine Ridge. The number of adult crow in Beverly Forest equals 2 times the number of adult blue jay in Beverly Forest. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult owl in Oakridge Riverside equals the difference between the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult blue jay in Pine Ridge. The number of adult owl in Pine Ridge equals the difference between the number of adult crow in Oakridge Riverside and the total number of adult animals in Beverly Forest. The average number of newborn children per adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Pine Ridge equals the average number of newborn children per adult blue jay in Beverly Forest. The number of adult blue jay in Beverly Forest equals 2. The number of adult eagle in Pine Ridge equals 2. Question: What is the average number of newborn children per adult blue jay in Pine Ridge? Solution: "
}
] |
The number of adult owl in Maple Creek equals 4 plus the sum of the total number of newborn animal children in Beverly Forest, the average number of newborn children per adult parrot in Pine Ridge, and the number of adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals 2 times the sum of the number of adult blue jay in Pine Ridge, the number of adult parrot in Pine Ridge, and the average number of newborn children per adult owl in Maple Creek. The number of adult parrot in Cedar Valley equals the sum of the average number of newborn children per adult crow in Beverly Forest, the average number of newborn children per adult crow in Beverly Forest, and the total number of newborn animal children in Beverly Forest. The number of adult parrot in Pine Ridge equals the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult owl in Maple Creek equals 3. The average number of newborn children per adult blue jay in Cedar Valley equals the average number of newborn children per adult crow in Beverly Forest. The number of adult blue jay in Pine Ridge equals 3. The average number of newborn children per adult crow in Beverly Forest equals 3. The number of adult crow in Pine Ridge equals the average number of newborn children per adult parrot in Pine Ridge. The average number of newborn children per adult parrot in Pine Ridge equals 3. The number of adult blue jay in Beverly Forest equals 2. The number of adult blue jay in Cedar Valley equals 4 plus the number of adult parrot in Cedar Valley. The average number of newborn children per adult crow in Pine Ridge equals the average number of newborn children per adult crow in Beverly Forest. The average number of newborn children per adult owl in Cedar Valley equals the total number of adult animals in Maple Creek. The number of adult blue jay in Maple Creek equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals 3. The number of adult parrot in Beverly Forest equals 2. The number of adult crow in Beverly Forest equals 3. The average number of newborn children per adult parrot in Beverly Forest equals 4. The average number of newborn children per adult blue jay in Pine Ridge equals 3. The average number of newborn children per adult blue jay in Maple Creek equals 1 plus the sum of the average number of newborn children per adult parrot in Pine Ridge, the number of adult blue jay in Pine Ridge, and the average number of newborn children per adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the number of adult blue jay in Beverly Forest. | What is the average number of newborn children per adult blue jay in Cedar Valley? | Define average number of newborn children per adult crow in Beverly Forest as A; so A = 3. Define average number of newborn children per adult blue jay in Cedar Valley as i; so i = A = 3. Answer: 3. | 2 | 16 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult owl in Maple Creek equals 4 plus the sum of the total number of newborn animal children in Beverly Forest, the average number of newborn children per adult parrot in Pine Ridge, and the number of adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals 2 times the sum of the number of adult blue jay in Pine Ridge, the number of adult parrot in Pine Ridge, and the average number of newborn children per adult owl in Maple Creek. The number of adult parrot in Cedar Valley equals the sum of the average number of newborn children per adult crow in Beverly Forest, the average number of newborn children per adult crow in Beverly Forest, and the total number of newborn animal children in Beverly Forest. The number of adult parrot in Pine Ridge equals the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult owl in Maple Creek equals 3. The average number of newborn children per adult blue jay in Cedar Valley equals the average number of newborn children per adult crow in Beverly Forest. The number of adult blue jay in Pine Ridge equals 3. The average number of newborn children per adult crow in Beverly Forest equals 3. The number of adult crow in Pine Ridge equals the average number of newborn children per adult parrot in Pine Ridge. The average number of newborn children per adult parrot in Pine Ridge equals 3. The number of adult blue jay in Beverly Forest equals 2. The number of adult blue jay in Cedar Valley equals 4 plus the number of adult parrot in Cedar Valley. The average number of newborn children per adult crow in Pine Ridge equals the average number of newborn children per adult crow in Beverly Forest. The average number of newborn children per adult owl in Cedar Valley equals the total number of adult animals in Maple Creek. The number of adult blue jay in Maple Creek equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals 3. The number of adult parrot in Beverly Forest equals 2. The number of adult crow in Beverly Forest equals 3. The average number of newborn children per adult parrot in Beverly Forest equals 4. The average number of newborn children per adult blue jay in Pine Ridge equals 3. The average number of newborn children per adult blue jay in Maple Creek equals 1 plus the sum of the average number of newborn children per adult parrot in Pine Ridge, the number of adult blue jay in Pine Ridge, and the average number of newborn children per adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the number of adult blue jay in Beverly Forest. Question: What is the average number of newborn children per adult blue jay in Cedar Valley? Solution: "
}
] |
The average number of newborn children per adult wolf in South Zoo equals the sum of the number of adult wolf in Hamilton Farm, the number of adult bear in South Zoo, and the average number of newborn children per adult bear in South Zoo. The number of adult bear in South Zoo equals the average number of newborn children per adult bear in Hamilton Farm. The average number of newborn children per adult wolf in Hamilton Farm equals 3. The average number of newborn children per adult bear in Bundle Ranch equals the average number of newborn children per adult wolf in Bundle Ranch. The average number of newborn children per adult bear in South Zoo equals 4. The average number of newborn children per adult fox in South Zoo equals the average number of newborn children per adult bear in Hamilton Farm. The number of adult wolf in South Zoo equals 2. The number of adult bear in Bundle Ranch equals 1. The number of adult wolf in Hamilton Farm equals 3 plus the average number of newborn children per adult wolf in Bundle Ranch. The average number of newborn children per adult wolf in Bundle Ranch equals 4. The number of adult fox in South Zoo equals the difference between the average number of newborn children per adult wolf in Hamilton Farm and the average number of newborn children per adult fox in Hamilton Farm. The average number of newborn children per adult fox in Bundle Ranch equals the difference between the average number of newborn children per adult bear in Bundle Ranch and the number of adult bear in Bundle Ranch. The average number of newborn children per adult bear in Hamilton Farm equals 4. The number of adult fox in Bundle Ranch equals the average number of newborn children per adult fox in Bundle Ranch. The average number of newborn children per adult fox in Hamilton Farm equals the average number of newborn children per adult wolf in Hamilton Farm. The number of adult fox in Hamilton Farm equals the difference between the average number of newborn children per adult wolf in Bundle Ranch and the number of adult fox in Bundle Ranch. The number of adult wolf in Bundle Ranch equals the sum of the average number of newborn children per adult wolf in Hamilton Farm, the average number of newborn children per adult wolf in Hamilton Farm, the number of adult fox in Hamilton Farm, and the average number of newborn children per adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals 4 plus the average number of newborn children per adult wolf in Bundle Ranch. | What is the average number of newborn children per adult fox in Hamilton Farm? | Define average number of newborn children per adult wolf in Hamilton Farm as W; so W = 3. Define average number of newborn children per adult fox in Hamilton Farm as h; so h = W = 3. Answer: 3. | 2 | 15 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult wolf in South Zoo equals the sum of the number of adult wolf in Hamilton Farm, the number of adult bear in South Zoo, and the average number of newborn children per adult bear in South Zoo. The number of adult bear in South Zoo equals the average number of newborn children per adult bear in Hamilton Farm. The average number of newborn children per adult wolf in Hamilton Farm equals 3. The average number of newborn children per adult bear in Bundle Ranch equals the average number of newborn children per adult wolf in Bundle Ranch. The average number of newborn children per adult bear in South Zoo equals 4. The average number of newborn children per adult fox in South Zoo equals the average number of newborn children per adult bear in Hamilton Farm. The number of adult wolf in South Zoo equals 2. The number of adult bear in Bundle Ranch equals 1. The number of adult wolf in Hamilton Farm equals 3 plus the average number of newborn children per adult wolf in Bundle Ranch. The average number of newborn children per adult wolf in Bundle Ranch equals 4. The number of adult fox in South Zoo equals the difference between the average number of newborn children per adult wolf in Hamilton Farm and the average number of newborn children per adult fox in Hamilton Farm. The average number of newborn children per adult fox in Bundle Ranch equals the difference between the average number of newborn children per adult bear in Bundle Ranch and the number of adult bear in Bundle Ranch. The average number of newborn children per adult bear in Hamilton Farm equals 4. The number of adult fox in Bundle Ranch equals the average number of newborn children per adult fox in Bundle Ranch. The average number of newborn children per adult fox in Hamilton Farm equals the average number of newborn children per adult wolf in Hamilton Farm. The number of adult fox in Hamilton Farm equals the difference between the average number of newborn children per adult wolf in Bundle Ranch and the number of adult fox in Bundle Ranch. The number of adult wolf in Bundle Ranch equals the sum of the average number of newborn children per adult wolf in Hamilton Farm, the average number of newborn children per adult wolf in Hamilton Farm, the number of adult fox in Hamilton Farm, and the average number of newborn children per adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals 4 plus the average number of newborn children per adult wolf in Bundle Ranch. Question: What is the average number of newborn children per adult fox in Hamilton Farm? Solution: "
}
] |
The average number of newborn children per adult fox in Oakridge Riverside equals the difference between the total number of adult animals in Oakridge Riverside and the number of adult fox in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the sum of the number of adult bear in Maple Creek, the number of adult bear in Oakridge Riverside, the average number of newborn children per adult fox in Cedar Valley, and the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult bear in Cedar Valley equals 2 plus the sum of the average number of newborn children per adult wolf in Cedar Valley, the average number of newborn children per adult wolf in Oakridge Riverside, and the average number of newborn children per adult wolf in Cedar Valley. The number of adult fox in Cedar Valley equals 3 plus the number of adult bear in Cedar Valley. The number of adult bear in Maple Creek equals 2 plus the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult fox in Cedar Valley equals the number of adult wolf in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals 2. The average number of newborn children per adult bear in Maple Creek equals the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Oakridge Riverside equals 4. The average number of newborn children per adult wolf in Cedar Valley equals the average number of newborn children per adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 4. The number of adult wolf in Cedar Valley equals 4. The number of adult bear in Cedar Valley equals the number of adult bear in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals the average number of newborn children per adult wolf in Oakridge Riverside. | What is the average number of newborn children per adult wolf in Cedar Valley? | Define average number of newborn children per adult wolf in Oakridge Riverside as G; so G = 4. Define average number of newborn children per adult wolf in Cedar Valley as W; so W = G = 4. Answer: 4. | 2 | 17 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult fox in Oakridge Riverside equals the difference between the total number of adult animals in Oakridge Riverside and the number of adult fox in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the sum of the number of adult bear in Maple Creek, the number of adult bear in Oakridge Riverside, the average number of newborn children per adult fox in Cedar Valley, and the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult bear in Cedar Valley equals 2 plus the sum of the average number of newborn children per adult wolf in Cedar Valley, the average number of newborn children per adult wolf in Oakridge Riverside, and the average number of newborn children per adult wolf in Cedar Valley. The number of adult fox in Cedar Valley equals 3 plus the number of adult bear in Cedar Valley. The number of adult bear in Maple Creek equals 2 plus the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult fox in Cedar Valley equals the number of adult wolf in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals 2. The average number of newborn children per adult bear in Maple Creek equals the number of adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Oakridge Riverside equals 4. The average number of newborn children per adult wolf in Cedar Valley equals the average number of newborn children per adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 4. The number of adult wolf in Cedar Valley equals 4. The number of adult bear in Cedar Valley equals the number of adult bear in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals the average number of newborn children per adult wolf in Oakridge Riverside. Question: What is the average number of newborn children per adult wolf in Cedar Valley? Solution: "
}
] |
The average number of newborn children per adult eagle in Pine Ridge equals 3 times the number of adult crow in Maple Creek. The number of adult eagle in Beverly Forest equals the sum of the average number of newborn children per adult eagle in Beverly Forest, the average number of newborn children per adult eagle in Maple Creek, the average number of newborn children per adult blue jay in Maple Creek, and the total number of newborn animal children in Maple Creek. The average number of newborn children per adult owl in Cedar Valley equals 1 plus the average number of newborn children per adult parrot in Oakridge Riverside. The average number of newborn children per adult crow in Pine Ridge equals the total number of adult animals in Maple Creek. The average number of newborn children per adult blue jay in Pine Ridge equals the sum of the number of adult eagle in Maple Creek, the average number of newborn children per adult crow in Beverly Forest, the average number of newborn children per adult eagle in Beverly Forest, and the total number of newborn animal children in Maple Creek. The number of adult crow in Maple Creek equals 1. The number of adult parrot in Oakridge Riverside equals the sum of the average number of newborn children per adult eagle in Maple Creek and the average number of newborn children per adult crow in Beverly Forest. The number of adult blue jay in Pine Ridge equals the sum of the total number of newborn animal children in Maple Creek, the average number of newborn children per adult crow in Maple Creek, and the number of adult eagle in Beverly Forest. The average number of newborn children per adult crow in Beverly Forest equals 3. The average number of newborn children per adult eagle in Maple Creek equals 3. The average number of newborn children per adult parrot in Oakridge Riverside equals 1. The average number of newborn children per adult eagle in Beverly Forest equals the average number of newborn children per adult crow in Beverly Forest. The average number of newborn children per adult blue jay in Maple Creek equals 3. The number of adult parrot in Maple Creek equals 4. The number of adult eagle in Pine Ridge equals 2. The number of adult eagle in Maple Creek equals 4. The number of adult crow in Pine Ridge equals 4. The number of adult crow in Beverly Forest equals 2 times the sum of the total number of adult animals in Pine Ridge, the total number of newborn animal children in Maple Creek, and the number of adult eagle in Maple Creek. The number of adult owl in Cedar Valley equals the sum of the average number of newborn children per adult eagle in Pine Ridge, the average number of newborn children per adult eagle in Maple Creek, the average number of newborn children per adult blue jay in Maple Creek, and the average number of newborn children per adult eagle in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals 4. The average number of newborn children per adult crow in Maple Creek equals 2. The number of adult blue jay in Maple Creek equals 1. | What is the average number of newborn children per adult eagle in Beverly Forest? | Define average number of newborn children per adult crow in Beverly Forest as A; so A = 3. Define average number of newborn children per adult eagle in Beverly Forest as e; so e = A = 3. Answer: 3. | 2 | 8 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult eagle in Pine Ridge equals 3 times the number of adult crow in Maple Creek. The number of adult eagle in Beverly Forest equals the sum of the average number of newborn children per adult eagle in Beverly Forest, the average number of newborn children per adult eagle in Maple Creek, the average number of newborn children per adult blue jay in Maple Creek, and the total number of newborn animal children in Maple Creek. The average number of newborn children per adult owl in Cedar Valley equals 1 plus the average number of newborn children per adult parrot in Oakridge Riverside. The average number of newborn children per adult crow in Pine Ridge equals the total number of adult animals in Maple Creek. The average number of newborn children per adult blue jay in Pine Ridge equals the sum of the number of adult eagle in Maple Creek, the average number of newborn children per adult crow in Beverly Forest, the average number of newborn children per adult eagle in Beverly Forest, and the total number of newborn animal children in Maple Creek. The number of adult crow in Maple Creek equals 1. The number of adult parrot in Oakridge Riverside equals the sum of the average number of newborn children per adult eagle in Maple Creek and the average number of newborn children per adult crow in Beverly Forest. The number of adult blue jay in Pine Ridge equals the sum of the total number of newborn animal children in Maple Creek, the average number of newborn children per adult crow in Maple Creek, and the number of adult eagle in Beverly Forest. The average number of newborn children per adult crow in Beverly Forest equals 3. The average number of newborn children per adult eagle in Maple Creek equals 3. The average number of newborn children per adult parrot in Oakridge Riverside equals 1. The average number of newborn children per adult eagle in Beverly Forest equals the average number of newborn children per adult crow in Beverly Forest. The average number of newborn children per adult blue jay in Maple Creek equals 3. The number of adult parrot in Maple Creek equals 4. The number of adult eagle in Pine Ridge equals 2. The number of adult eagle in Maple Creek equals 4. The number of adult crow in Pine Ridge equals 4. The number of adult crow in Beverly Forest equals 2 times the sum of the total number of adult animals in Pine Ridge, the total number of newborn animal children in Maple Creek, and the number of adult eagle in Maple Creek. The number of adult owl in Cedar Valley equals the sum of the average number of newborn children per adult eagle in Pine Ridge, the average number of newborn children per adult eagle in Maple Creek, the average number of newborn children per adult blue jay in Maple Creek, and the average number of newborn children per adult eagle in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals 4. The average number of newborn children per adult crow in Maple Creek equals 2. The number of adult blue jay in Maple Creek equals 1. Question: What is the average number of newborn children per adult eagle in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult wolf in Mayer Aquarium equals the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult wolf in Jefferson Circus equals the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult bear in Mayer Aquarium equals 3. The number of adult bear in Jefferson Circus equals the sum of the average number of newborn children per adult wolf in Jefferson Circus, the total number of adult animals in Bundle Ranch, and the average number of newborn children per adult wolf in Bundle Ranch. The number of adult wolf in Mayer Aquarium equals the number of adult deer in Jefferson Circus. The average number of newborn children per adult bear in Bundle Ranch equals 4. The number of adult wolf in Bundle Ranch equals the average number of newborn children per adult wolf in Jefferson Circus. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult wolf in Bundle Ranch equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult bear in Bundle Ranch equals 1. The number of adult deer in Mayer Aquarium equals the number of adult wolf in Jefferson Circus. The average number of newborn children per adult bear in Jefferson Circus equals the sum of the average number of newborn children per adult wolf in Jefferson Circus and the average number of newborn children per adult wolf in Jefferson Circus. The number of adult deer in Jefferson Circus equals 2 plus the sum of the average number of newborn children per adult deer in Jefferson Circus and the number of adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 2 plus the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Mayer Aquarium equals 4. The average number of newborn children per adult deer in Jefferson Circus equals 4. | What is the average number of newborn children per adult wolf in Bundle Ranch? | Define average number of newborn children per adult deer in Mayer Aquarium as l; so l = 4. Define average number of newborn children per adult wolf in Bundle Ranch as b; so b = l = 4. Answer: 4. | 2 | 3 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult wolf in Mayer Aquarium equals the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult wolf in Jefferson Circus equals the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult bear in Mayer Aquarium equals 3. The number of adult bear in Jefferson Circus equals the sum of the average number of newborn children per adult wolf in Jefferson Circus, the total number of adult animals in Bundle Ranch, and the average number of newborn children per adult wolf in Bundle Ranch. The number of adult wolf in Mayer Aquarium equals the number of adult deer in Jefferson Circus. The average number of newborn children per adult bear in Bundle Ranch equals 4. The number of adult wolf in Bundle Ranch equals the average number of newborn children per adult wolf in Jefferson Circus. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult wolf in Bundle Ranch equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult bear in Bundle Ranch equals 1. The number of adult deer in Mayer Aquarium equals the number of adult wolf in Jefferson Circus. The average number of newborn children per adult bear in Jefferson Circus equals the sum of the average number of newborn children per adult wolf in Jefferson Circus and the average number of newborn children per adult wolf in Jefferson Circus. The number of adult deer in Jefferson Circus equals 2 plus the sum of the average number of newborn children per adult deer in Jefferson Circus and the number of adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 2 plus the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Mayer Aquarium equals 4. The average number of newborn children per adult deer in Jefferson Circus equals 4. Question: What is the average number of newborn children per adult wolf in Bundle Ranch? Solution: "
}
] |
The number of adult racoon in Bundle Ranch equals 4 times the sum of the number of adult bear in Bundle Ranch, the number of adult fox in Hamilton Farm, and the average number of newborn children per adult deer in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 1. The number of adult fox in South Zoo equals 4. The average number of newborn children per adult fox in Hamilton Farm equals 4. The number of adult fox in Mayer Aquarium equals 2 times the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult fox in South Zoo equals the average number of newborn children per adult deer in Jefferson Circus. The number of adult deer in Bundle Ranch equals 2. The number of adult bear in Hamilton Farm equals the number of adult bear in Bundle Ranch. The average number of newborn children per adult bear in Mayer Aquarium equals 2 times the number of adult bear in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 2. The number of adult deer in South Zoo equals 4. The average number of newborn children per adult deer in Jefferson Circus equals 4. The number of adult racoon in Jefferson Circus equals 1. The average number of newborn children per adult fox in Mayer Aquarium equals the sum of the average number of newborn children per adult racoon in Jefferson Circus, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult bear in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 4 times the difference between the number of adult fox in Hamilton Farm and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult racoon in Bundle Ranch equals 3 plus the sum of the number of adult bear in Mayer Aquarium and the average number of newborn children per adult deer in Hamilton Farm. The number of adult fox in Hamilton Farm equals 2. The number of adult racoon in South Zoo equals 3 times the average number of newborn children per adult bear in Jefferson Circus. The average number of newborn children per adult deer in Bundle Ranch equals the sum of the average number of newborn children per adult fox in South Zoo, the total number of newborn animal children in Jefferson Circus, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult racoon in Hamilton Farm equals the number of adult fox in Mayer Aquarium. The average number of newborn children per adult bear in Jefferson Circus equals 4. The average number of newborn children per adult deer in Mayer Aquarium equals 1 plus the sum of the number of adult bear in Bundle Ranch and the number of adult bear in Mayer Aquarium. The number of adult bear in Bundle Ranch equals the number of adult fox in Hamilton Farm. The average number of newborn children per adult racoon in Jefferson Circus equals 2. The number of adult bear in Mayer Aquarium equals the number of adult fox in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 4 plus the number of adult deer in Mayer Aquarium. The number of adult deer in Hamilton Farm equals the difference between the number of adult fox in South Zoo and the average number of newborn children per adult bear in Mayer Aquarium. The average number of newborn children per adult fox in Bundle Ranch equals 4 times the sum of the number of adult fox in Hamilton Farm, the number of adult bear in Mayer Aquarium, and the number of adult deer in Mayer Aquarium. The average number of newborn children per adult racoon in South Zoo equals 3. The average number of newborn children per adult bear in Hamilton Farm equals 3 times the difference between the total number of adult animals in Bundle Ranch and the average number of newborn children per adult fox in Mayer Aquarium. The number of adult deer in Jefferson Circus equals 3. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult fox in Bundle Ranch. The average number of newborn children per adult deer in Hamilton Farm equals 1 plus the difference between the number of adult deer in Mayer Aquarium and the number of adult bear in Mayer Aquarium. The number of adult fox in Bundle Ranch equals the number of adult racoon in Jefferson Circus. The average number of newborn children per adult fox in Jefferson Circus equals 1. The average number of newborn children per adult bear in Bundle Ranch equals the sum of the number of adult bear in Bundle Ranch, the average number of newborn children per adult deer in Mayer Aquarium, and the number of adult racoon in Hamilton Farm. | What is the average number of newborn children per adult fox in South Zoo? | Define average number of newborn children per adult deer in Jefferson Circus as d; so d = 4. Define average number of newborn children per adult fox in South Zoo as N; so N = d = 4. Answer: 4. | 2 | 20 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult racoon in Bundle Ranch equals 4 times the sum of the number of adult bear in Bundle Ranch, the number of adult fox in Hamilton Farm, and the average number of newborn children per adult deer in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 1. The number of adult fox in South Zoo equals 4. The average number of newborn children per adult fox in Hamilton Farm equals 4. The number of adult fox in Mayer Aquarium equals 2 times the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult fox in South Zoo equals the average number of newborn children per adult deer in Jefferson Circus. The number of adult deer in Bundle Ranch equals 2. The number of adult bear in Hamilton Farm equals the number of adult bear in Bundle Ranch. The average number of newborn children per adult bear in Mayer Aquarium equals 2 times the number of adult bear in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 2. The number of adult deer in South Zoo equals 4. The average number of newborn children per adult deer in Jefferson Circus equals 4. The number of adult racoon in Jefferson Circus equals 1. The average number of newborn children per adult fox in Mayer Aquarium equals the sum of the average number of newborn children per adult racoon in Jefferson Circus, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult bear in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 4 times the difference between the number of adult fox in Hamilton Farm and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult racoon in Bundle Ranch equals 3 plus the sum of the number of adult bear in Mayer Aquarium and the average number of newborn children per adult deer in Hamilton Farm. The number of adult fox in Hamilton Farm equals 2. The number of adult racoon in South Zoo equals 3 times the average number of newborn children per adult bear in Jefferson Circus. The average number of newborn children per adult deer in Bundle Ranch equals the sum of the average number of newborn children per adult fox in South Zoo, the total number of newborn animal children in Jefferson Circus, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult racoon in Hamilton Farm equals the number of adult fox in Mayer Aquarium. The average number of newborn children per adult bear in Jefferson Circus equals 4. The average number of newborn children per adult deer in Mayer Aquarium equals 1 plus the sum of the number of adult bear in Bundle Ranch and the number of adult bear in Mayer Aquarium. The number of adult bear in Bundle Ranch equals the number of adult fox in Hamilton Farm. The average number of newborn children per adult racoon in Jefferson Circus equals 2. The number of adult bear in Mayer Aquarium equals the number of adult fox in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 4 plus the number of adult deer in Mayer Aquarium. The number of adult deer in Hamilton Farm equals the difference between the number of adult fox in South Zoo and the average number of newborn children per adult bear in Mayer Aquarium. The average number of newborn children per adult fox in Bundle Ranch equals 4 times the sum of the number of adult fox in Hamilton Farm, the number of adult bear in Mayer Aquarium, and the number of adult deer in Mayer Aquarium. The average number of newborn children per adult racoon in South Zoo equals 3. The average number of newborn children per adult bear in Hamilton Farm equals 3 times the difference between the total number of adult animals in Bundle Ranch and the average number of newborn children per adult fox in Mayer Aquarium. The number of adult deer in Jefferson Circus equals 3. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult fox in Bundle Ranch. The average number of newborn children per adult deer in Hamilton Farm equals 1 plus the difference between the number of adult deer in Mayer Aquarium and the number of adult bear in Mayer Aquarium. The number of adult fox in Bundle Ranch equals the number of adult racoon in Jefferson Circus. The average number of newborn children per adult fox in Jefferson Circus equals 1. The average number of newborn children per adult bear in Bundle Ranch equals the sum of the number of adult bear in Bundle Ranch, the average number of newborn children per adult deer in Mayer Aquarium, and the number of adult racoon in Hamilton Farm. Question: What is the average number of newborn children per adult fox in South Zoo? Solution: "
}
] |
The number of adult racoon in Mayer Aquarium equals 2 times the average number of newborn children per adult fox in Jefferson Circus. The average number of newborn children per adult fox in Hamilton Farm equals 4. The number of adult fox in Hamilton Farm equals the sum of the average number of newborn children per adult fox in Jefferson Circus and the average number of newborn children per adult racoon in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2 times the average number of newborn children per adult fox in Jefferson Circus. The number of adult racoon in Jefferson Circus equals the average number of newborn children per adult fox in Mayer Aquarium. The average number of newborn children per adult fox in Jefferson Circus equals 4 times the number of adult fox in Jefferson Circus. The number of adult fox in Mayer Aquarium equals the number of adult fox in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the number of adult fox in Mayer Aquarium. The average number of newborn children per adult racoon in Mayer Aquarium equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the number of adult fox in Mayer Aquarium and the average number of newborn children per adult fox in Jefferson Circus. The number of adult fox in Jefferson Circus equals 1. The number of adult wolf in Mayer Aquarium equals the average number of newborn children per adult fox in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 3. The average number of newborn children per adult fox in Mayer Aquarium equals 2. The average number of newborn children per adult wolf in Hamilton Farm equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult wolf in Mayer Aquarium. The average number of newborn children per adult wolf in Mayer Aquarium equals the difference between the total number of adult animals in Mayer Aquarium and the total number of adult animals in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus equals 3. The average number of newborn children per adult racoon in Hamilton Farm equals the average number of newborn children per adult racoon in Jefferson Circus. | What is the average number of newborn children per adult racoon in Hamilton Farm? | Define average number of newborn children per adult racoon in Jefferson Circus as M; so M = 3. Define average number of newborn children per adult racoon in Hamilton Farm as o; so o = M = 3. Answer: 3. | 2 | 19 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult racoon in Mayer Aquarium equals 2 times the average number of newborn children per adult fox in Jefferson Circus. The average number of newborn children per adult fox in Hamilton Farm equals 4. The number of adult fox in Hamilton Farm equals the sum of the average number of newborn children per adult fox in Jefferson Circus and the average number of newborn children per adult racoon in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2 times the average number of newborn children per adult fox in Jefferson Circus. The number of adult racoon in Jefferson Circus equals the average number of newborn children per adult fox in Mayer Aquarium. The average number of newborn children per adult fox in Jefferson Circus equals 4 times the number of adult fox in Jefferson Circus. The number of adult fox in Mayer Aquarium equals the number of adult fox in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the number of adult fox in Mayer Aquarium. The average number of newborn children per adult racoon in Mayer Aquarium equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the number of adult fox in Mayer Aquarium and the average number of newborn children per adult fox in Jefferson Circus. The number of adult fox in Jefferson Circus equals 1. The number of adult wolf in Mayer Aquarium equals the average number of newborn children per adult fox in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 3. The average number of newborn children per adult fox in Mayer Aquarium equals 2. The average number of newborn children per adult wolf in Hamilton Farm equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult wolf in Mayer Aquarium. The average number of newborn children per adult wolf in Mayer Aquarium equals the difference between the total number of adult animals in Mayer Aquarium and the total number of adult animals in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus equals 3. The average number of newborn children per adult racoon in Hamilton Farm equals the average number of newborn children per adult racoon in Jefferson Circus. Question: What is the average number of newborn children per adult racoon in Hamilton Farm? Solution: "
}
] |
The number of adult parrot in Mayer Aquarium equals the sum of the number of adult crow in Mayer Aquarium, the average number of newborn children per adult blue jay in Hamilton Farm, and the average number of newborn children per adult crow in Hamilton Farm. The number of adult parrot in Hamilton Farm equals the number of adult parrot in South Zoo. The average number of newborn children per adult blue jay in Hamilton Farm equals 4. The number of adult crow in Mayer Aquarium equals 4. The average number of newborn children per adult parrot in Hamilton Farm equals 4 plus the sum of the average number of newborn children per adult crow in Hamilton Farm, the average number of newborn children per adult blue jay in Hamilton Farm, and the number of adult blue jay in Hamilton Farm. The number of adult parrot in South Zoo equals 2 times the difference between the number of adult parrot in Mayer Aquarium and the number of adult crow in Mayer Aquarium. The average number of newborn children per adult crow in Mayer Aquarium equals 3 times the average number of newborn children per adult parrot in Mayer Aquarium. The average number of newborn children per adult parrot in South Zoo equals 4. The average number of newborn children per adult blue jay in South Zoo equals the number of adult crow in Mayer Aquarium. The number of adult crow in Hamilton Farm equals 4 times the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 3. The number of adult blue jay in South Zoo equals 4. The average number of newborn children per adult crow in Hamilton Farm equals the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult parrot in Mayer Aquarium equals the number of adult crow in Mayer Aquarium. | What is the average number of newborn children per adult crow in Hamilton Farm? | Define average number of newborn children per adult blue jay in Hamilton Farm as z; so z = 4. Define average number of newborn children per adult crow in Hamilton Farm as u; so u = z = 4. Answer: 4. | 2 | 16 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult parrot in Mayer Aquarium equals the sum of the number of adult crow in Mayer Aquarium, the average number of newborn children per adult blue jay in Hamilton Farm, and the average number of newborn children per adult crow in Hamilton Farm. The number of adult parrot in Hamilton Farm equals the number of adult parrot in South Zoo. The average number of newborn children per adult blue jay in Hamilton Farm equals 4. The number of adult crow in Mayer Aquarium equals 4. The average number of newborn children per adult parrot in Hamilton Farm equals 4 plus the sum of the average number of newborn children per adult crow in Hamilton Farm, the average number of newborn children per adult blue jay in Hamilton Farm, and the number of adult blue jay in Hamilton Farm. The number of adult parrot in South Zoo equals 2 times the difference between the number of adult parrot in Mayer Aquarium and the number of adult crow in Mayer Aquarium. The average number of newborn children per adult crow in Mayer Aquarium equals 3 times the average number of newborn children per adult parrot in Mayer Aquarium. The average number of newborn children per adult parrot in South Zoo equals 4. The average number of newborn children per adult blue jay in South Zoo equals the number of adult crow in Mayer Aquarium. The number of adult crow in Hamilton Farm equals 4 times the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 3. The number of adult blue jay in South Zoo equals 4. The average number of newborn children per adult crow in Hamilton Farm equals the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult parrot in Mayer Aquarium equals the number of adult crow in Mayer Aquarium. Question: What is the average number of newborn children per adult crow in Hamilton Farm? Solution: "
}
] |
The average number of newborn children per adult eagle in Oakridge Riverside equals 3. The number of adult parrot in Cedar Valley equals the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals the sum of the number of adult owl in Maple Creek, the average number of newborn children per adult crow in Cedar Valley, the average number of newborn children per adult owl in Oakridge Riverside, and the number of adult crow in Oakridge Riverside. The average number of newborn children per adult parrot in Maple Creek equals the number of adult crow in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 4. The average number of newborn children per adult parrot in Oakridge Riverside equals the number of adult eagle in Maple Creek. The average number of newborn children per adult owl in Oakridge Riverside equals 1. The number of adult crow in Cedar Valley equals 3. The number of adult parrot in Oakridge Riverside equals the average number of newborn children per adult eagle in Maple Creek. The average number of newborn children per adult eagle in Maple Creek equals 4. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult eagle in Maple Creek equals the sum of the number of adult crow in Oakridge Riverside, the average number of newborn children per adult crow in Cedar Valley, the average number of newborn children per adult owl in Oakridge Riverside, and the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult owl in Maple Creek equals the difference between the average number of newborn children per adult owl in Oakridge Riverside and the number of adult owl in Maple Creek. The average number of newborn children per adult owl in Cedar Valley equals the average number of newborn children per adult crow in Oakridge Riverside. The number of adult owl in Cedar Valley equals 3. The number of adult eagle in Oakridge Riverside equals 4 times the number of adult crow in Oakridge Riverside. The number of adult crow in Maple Creek equals 4 times the sum of the total number of adult animals in Cedar Valley and the number of adult owl in Maple Creek. The average number of newborn children per adult crow in Cedar Valley equals the average number of newborn children per adult owl in Maple Creek. The number of adult parrot in Maple Creek equals 3 times the sum of the average number of newborn children per adult crow in Oakridge Riverside, the average number of newborn children per adult owl in Cedar Valley, and the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 4. The average number of newborn children per adult crow in Maple Creek equals 2 plus the sum of the number of adult crow in Maple Creek, the number of adult crow in Oakridge Riverside, and the number of adult eagle in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals the number of adult owl in Maple Creek. | What is the average number of newborn children per adult owl in Cedar Valley? | Define average number of newborn children per adult crow in Oakridge Riverside as t; so t = 3. Define average number of newborn children per adult owl in Cedar Valley as w; so w = t = 3. Answer: 3. | 2 | 9 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult eagle in Oakridge Riverside equals 3. The number of adult parrot in Cedar Valley equals the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals the sum of the number of adult owl in Maple Creek, the average number of newborn children per adult crow in Cedar Valley, the average number of newborn children per adult owl in Oakridge Riverside, and the number of adult crow in Oakridge Riverside. The average number of newborn children per adult parrot in Maple Creek equals the number of adult crow in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 4. The average number of newborn children per adult parrot in Oakridge Riverside equals the number of adult eagle in Maple Creek. The average number of newborn children per adult owl in Oakridge Riverside equals 1. The number of adult crow in Cedar Valley equals 3. The number of adult parrot in Oakridge Riverside equals the average number of newborn children per adult eagle in Maple Creek. The average number of newborn children per adult eagle in Maple Creek equals 4. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult eagle in Maple Creek equals the sum of the number of adult crow in Oakridge Riverside, the average number of newborn children per adult crow in Cedar Valley, the average number of newborn children per adult owl in Oakridge Riverside, and the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult owl in Maple Creek equals the difference between the average number of newborn children per adult owl in Oakridge Riverside and the number of adult owl in Maple Creek. The average number of newborn children per adult owl in Cedar Valley equals the average number of newborn children per adult crow in Oakridge Riverside. The number of adult owl in Cedar Valley equals 3. The number of adult eagle in Oakridge Riverside equals 4 times the number of adult crow in Oakridge Riverside. The number of adult crow in Maple Creek equals 4 times the sum of the total number of adult animals in Cedar Valley and the number of adult owl in Maple Creek. The average number of newborn children per adult crow in Cedar Valley equals the average number of newborn children per adult owl in Maple Creek. The number of adult parrot in Maple Creek equals 3 times the sum of the average number of newborn children per adult crow in Oakridge Riverside, the average number of newborn children per adult owl in Cedar Valley, and the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 4. The average number of newborn children per adult crow in Maple Creek equals 2 plus the sum of the number of adult crow in Maple Creek, the number of adult crow in Oakridge Riverside, and the number of adult eagle in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals the number of adult owl in Maple Creek. Question: What is the average number of newborn children per adult owl in Cedar Valley? Solution: "
}
] |
The number of adult parrot in Pine Ridge equals 1. The number of adult blue jay in Cedar Valley equals the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 2. The number of adult eagle in Pine Ridge equals 2 times the average number of newborn children per adult eagle in Pine Ridge. The average number of newborn children per adult eagle in Oakridge Riverside equals the average number of newborn children per adult blue jay in Oakridge Riverside. The average number of newborn children per adult parrot in Pine Ridge equals the number of adult eagle in Pine Ridge. The number of adult parrot in Cedar Valley equals 3. The average number of newborn children per adult blue jay in Cedar Valley equals 3. The average number of newborn children per adult eagle in Pine Ridge equals 1. The number of adult eagle in Oakridge Riverside equals 4 times the difference between the average number of newborn children per adult blue jay in Cedar Valley and the number of adult blue jay in Cedar Valley. The average number of newborn children per adult blue jay in Oakridge Riverside equals 3. The average number of newborn children per adult parrot in Cedar Valley equals the sum of the average number of newborn children per adult blue jay in Oakridge Riverside, the number of adult blue jay in Oakridge Riverside, the average number of newborn children per adult eagle in Oakridge Riverside, and the average number of newborn children per adult eagle in Pine Ridge. | What is the average number of newborn children per adult eagle in Oakridge Riverside? | Define average number of newborn children per adult blue jay in Oakridge Riverside as d; so d = 3. Define average number of newborn children per adult eagle in Oakridge Riverside as q; so q = d = 3. Answer: 3. | 2 | 2 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult parrot in Pine Ridge equals 1. The number of adult blue jay in Cedar Valley equals the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 2. The number of adult eagle in Pine Ridge equals 2 times the average number of newborn children per adult eagle in Pine Ridge. The average number of newborn children per adult eagle in Oakridge Riverside equals the average number of newborn children per adult blue jay in Oakridge Riverside. The average number of newborn children per adult parrot in Pine Ridge equals the number of adult eagle in Pine Ridge. The number of adult parrot in Cedar Valley equals 3. The average number of newborn children per adult blue jay in Cedar Valley equals 3. The average number of newborn children per adult eagle in Pine Ridge equals 1. The number of adult eagle in Oakridge Riverside equals 4 times the difference between the average number of newborn children per adult blue jay in Cedar Valley and the number of adult blue jay in Cedar Valley. The average number of newborn children per adult blue jay in Oakridge Riverside equals 3. The average number of newborn children per adult parrot in Cedar Valley equals the sum of the average number of newborn children per adult blue jay in Oakridge Riverside, the number of adult blue jay in Oakridge Riverside, the average number of newborn children per adult eagle in Oakridge Riverside, and the average number of newborn children per adult eagle in Pine Ridge. Question: What is the average number of newborn children per adult eagle in Oakridge Riverside? Solution: "
}
] |
The average number of newborn children per adult crow in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley, the average number of newborn children per adult owl in Cedar Valley, and the number of adult owl in Cedar Valley. The average number of newborn children per adult blue jay in Cedar Valley equals the sum of the average number of newborn children per adult owl in Cedar Valley, the number of adult crow in Maple Creek, the total number of adult animals in Maple Creek, and the average number of newborn children per adult owl in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 3 plus the sum of the average number of newborn children per adult blue jay in Maple Creek, the average number of newborn children per adult owl in Maple Creek, and the number of adult blue jay in Oakridge Riverside. The average number of newborn children per adult blue jay in Maple Creek equals 4. The average number of newborn children per adult crow in Cedar Valley equals 3. The average number of newborn children per adult crow in Maple Creek equals the average number of newborn children per adult blue jay in Maple Creek. The average number of newborn children per adult blue jay in Oakridge Riverside equals the sum of the average number of newborn children per adult crow in Maple Creek, the number of adult owl in Maple Creek, the number of adult blue jay in Maple Creek, and the total number of adult animals in Cedar Valley. The number of adult blue jay in Maple Creek equals 4. The average number of newborn children per adult owl in Oakridge Riverside equals 2. The number of adult blue jay in Oakridge Riverside equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Cedar Valley equals 3. The number of adult crow in Maple Creek equals the sum of the average number of newborn children per adult owl in Cedar Valley and the average number of newborn children per adult crow in Oakridge Riverside. The number of adult crow in Cedar Valley equals 3. The average number of newborn children per adult owl in Maple Creek equals the sum of the number of adult blue jay in Oakridge Riverside and the average number of newborn children per adult crow in Maple Creek. The number of adult owl in Cedar Valley equals the average number of newborn children per adult owl in Oakridge Riverside. The average number of newborn children per adult owl in Cedar Valley equals 4 plus the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 1. The number of adult crow in Oakridge Riverside equals 3. | How many adult owl does Cedar Valley have? | Define average number of newborn children per adult owl in Oakridge Riverside as f; so f = 2. Define adult owl in Cedar Valley as X; so X = f = 2. Answer: 2. | 2 | 21 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult crow in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley, the average number of newborn children per adult owl in Cedar Valley, and the number of adult owl in Cedar Valley. The average number of newborn children per adult blue jay in Cedar Valley equals the sum of the average number of newborn children per adult owl in Cedar Valley, the number of adult crow in Maple Creek, the total number of adult animals in Maple Creek, and the average number of newborn children per adult owl in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 3 plus the sum of the average number of newborn children per adult blue jay in Maple Creek, the average number of newborn children per adult owl in Maple Creek, and the number of adult blue jay in Oakridge Riverside. The average number of newborn children per adult blue jay in Maple Creek equals 4. The average number of newborn children per adult crow in Cedar Valley equals 3. The average number of newborn children per adult crow in Maple Creek equals the average number of newborn children per adult blue jay in Maple Creek. The average number of newborn children per adult blue jay in Oakridge Riverside equals the sum of the average number of newborn children per adult crow in Maple Creek, the number of adult owl in Maple Creek, the number of adult blue jay in Maple Creek, and the total number of adult animals in Cedar Valley. The number of adult blue jay in Maple Creek equals 4. The average number of newborn children per adult owl in Oakridge Riverside equals 2. The number of adult blue jay in Oakridge Riverside equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Cedar Valley equals 3. The number of adult crow in Maple Creek equals the sum of the average number of newborn children per adult owl in Cedar Valley and the average number of newborn children per adult crow in Oakridge Riverside. The number of adult crow in Cedar Valley equals 3. The average number of newborn children per adult owl in Maple Creek equals the sum of the number of adult blue jay in Oakridge Riverside and the average number of newborn children per adult crow in Maple Creek. The number of adult owl in Cedar Valley equals the average number of newborn children per adult owl in Oakridge Riverside. The average number of newborn children per adult owl in Cedar Valley equals 4 plus the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 1. The number of adult crow in Oakridge Riverside equals 3. Question: How many adult owl does Cedar Valley have? Solution: "
}
] |
The number of adult parrot in Oakridge Riverside equals 1. The average number of newborn children per adult owl in Oakridge Riverside equals the difference between the total number of adult animals in Beverly Forest and the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals the number of adult owl in Maple Creek. The number of adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Maple Creek equals 3. The number of adult crow in Cedar Valley equals 3. The number of adult parrot in Beverly Forest equals 4 plus the average number of newborn children per adult blue jay in Beverly Forest. The number of adult crow in Oakridge Riverside equals 3 times the average number of newborn children per adult parrot in Oakridge Riverside. The number of adult crow in Beverly Forest equals the sum of the number of adult blue jay in Cedar Valley, the average number of newborn children per adult crow in Cedar Valley, and the number of adult crow in Cedar Valley. The number of adult blue jay in Maple Creek equals the sum of the average number of newborn children per adult parrot in Oakridge Riverside and the number of adult blue jay in Cedar Valley. The average number of newborn children per adult crow in Maple Creek equals the sum of the number of adult parrot in Beverly Forest, the number of adult crow in Cedar Valley, and the average number of newborn children per adult owl in Maple Creek. The number of adult blue jay in Cedar Valley equals 4 plus the number of adult crow in Cedar Valley. The average number of newborn children per adult parrot in Oakridge Riverside equals the sum of the average number of newborn children per adult owl in Cedar Valley and the average number of newborn children per adult crow in Cedar Valley. The number of adult owl in Oakridge Riverside equals 2. The number of adult parrot in Cedar Valley equals 2 plus the sum of the number of adult blue jay in Cedar Valley, the total number of adult animals in Beverly Forest, and the average number of newborn children per adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the average number of newborn children per adult owl in Oakridge Riverside. The average number of newborn children per adult parrot in Cedar Valley equals 2. The average number of newborn children per adult crow in Beverly Forest equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult parrot in Cedar Valley. The average number of newborn children per adult parrot in Beverly Forest equals the sum of the number of adult crow in Maple Creek, the average number of newborn children per adult owl in Cedar Valley, the number of adult owl in Maple Creek, and the number of adult crow in Cedar Valley. The number of adult owl in Maple Creek equals 3 plus the sum of the number of adult crow in Maple Creek, the number of adult crow in Beverly Forest, and the average number of newborn children per adult crow in Cedar Valley. The average number of newborn children per adult blue jay in Cedar Valley equals 4 plus the average number of newborn children per adult blue jay in Beverly Forest. The average number of newborn children per adult owl in Cedar Valley equals 3 plus the number of adult crow in Cedar Valley. The number of adult crow in Maple Creek equals the average number of newborn children per adult crow in Cedar Valley. The average number of newborn children per adult crow in Cedar Valley equals 3 plus the sum of the number of adult crow in Cedar Valley and the number of adult blue jay in Cedar Valley. The number of adult parrot in Maple Creek equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The average number of newborn children per adult crow in Oakridge Riverside equals the difference between the number of adult owl in Maple Creek and the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult owl in Maple Creek equals the sum of the number of adult parrot in Beverly Forest and the average number of newborn children per adult parrot in Cedar Valley. | What is the average number of newborn children per adult blue jay in Beverly Forest? | Define average number of newborn children per adult parrot in Cedar Valley as A; so A = 2. Define average number of newborn children per adult blue jay in Beverly Forest as e; so e = A = 2. Answer: 2. | 2 | 19 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult parrot in Oakridge Riverside equals 1. The average number of newborn children per adult owl in Oakridge Riverside equals the difference between the total number of adult animals in Beverly Forest and the average number of newborn children per adult owl in Maple Creek. The average number of newborn children per adult parrot in Maple Creek equals the number of adult owl in Maple Creek. The number of adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Maple Creek equals 3. The number of adult crow in Cedar Valley equals 3. The number of adult parrot in Beverly Forest equals 4 plus the average number of newborn children per adult blue jay in Beverly Forest. The number of adult crow in Oakridge Riverside equals 3 times the average number of newborn children per adult parrot in Oakridge Riverside. The number of adult crow in Beverly Forest equals the sum of the number of adult blue jay in Cedar Valley, the average number of newborn children per adult crow in Cedar Valley, and the number of adult crow in Cedar Valley. The number of adult blue jay in Maple Creek equals the sum of the average number of newborn children per adult parrot in Oakridge Riverside and the number of adult blue jay in Cedar Valley. The average number of newborn children per adult crow in Maple Creek equals the sum of the number of adult parrot in Beverly Forest, the number of adult crow in Cedar Valley, and the average number of newborn children per adult owl in Maple Creek. The number of adult blue jay in Cedar Valley equals 4 plus the number of adult crow in Cedar Valley. The average number of newborn children per adult parrot in Oakridge Riverside equals the sum of the average number of newborn children per adult owl in Cedar Valley and the average number of newborn children per adult crow in Cedar Valley. The number of adult owl in Oakridge Riverside equals 2. The number of adult parrot in Cedar Valley equals 2 plus the sum of the number of adult blue jay in Cedar Valley, the total number of adult animals in Beverly Forest, and the average number of newborn children per adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the average number of newborn children per adult owl in Oakridge Riverside. The average number of newborn children per adult parrot in Cedar Valley equals 2. The average number of newborn children per adult crow in Beverly Forest equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult parrot in Cedar Valley. The average number of newborn children per adult parrot in Beverly Forest equals the sum of the number of adult crow in Maple Creek, the average number of newborn children per adult owl in Cedar Valley, the number of adult owl in Maple Creek, and the number of adult crow in Cedar Valley. The number of adult owl in Maple Creek equals 3 plus the sum of the number of adult crow in Maple Creek, the number of adult crow in Beverly Forest, and the average number of newborn children per adult crow in Cedar Valley. The average number of newborn children per adult blue jay in Cedar Valley equals 4 plus the average number of newborn children per adult blue jay in Beverly Forest. The average number of newborn children per adult owl in Cedar Valley equals 3 plus the number of adult crow in Cedar Valley. The number of adult crow in Maple Creek equals the average number of newborn children per adult crow in Cedar Valley. The average number of newborn children per adult crow in Cedar Valley equals 3 plus the sum of the number of adult crow in Cedar Valley and the number of adult blue jay in Cedar Valley. The number of adult parrot in Maple Creek equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The average number of newborn children per adult crow in Oakridge Riverside equals the difference between the number of adult owl in Maple Creek and the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult owl in Maple Creek equals the sum of the number of adult parrot in Beverly Forest and the average number of newborn children per adult parrot in Cedar Valley. Question: What is the average number of newborn children per adult blue jay in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult wolf in Maple Creek equals 3 plus the number of adult racoon in Pine Ridge. The number of adult fox in Oakridge Riverside equals 3. The average number of newborn children per adult fox in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Pine Ridge equals 4. The number of adult racoon in Pine Ridge equals the number of adult wolf in Maple Creek. The number of adult deer in Oakridge Riverside equals 4. The number of adult wolf in Maple Creek equals 2. The average number of newborn children per adult deer in Oakridge Riverside equals the number of adult wolf in Maple Creek. | What is the total number of adult animals in Maple Creek? | Define adult wolf in Maple Creek as J; so J = 2. Define total number of adult animals in Maple Creek as v; so v = J = 2. Answer: 2. | 2 | 1 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult wolf in Maple Creek equals 3 plus the number of adult racoon in Pine Ridge. The number of adult fox in Oakridge Riverside equals 3. The average number of newborn children per adult fox in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Pine Ridge equals 4. The number of adult racoon in Pine Ridge equals the number of adult wolf in Maple Creek. The number of adult deer in Oakridge Riverside equals 4. The number of adult wolf in Maple Creek equals 2. The average number of newborn children per adult deer in Oakridge Riverside equals the number of adult wolf in Maple Creek. Question: What is the total number of adult animals in Maple Creek? Solution: "
}
] |
The number of adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Beverly Forest equals 3. The average number of newborn children per adult crow in Cedar Valley equals 3. The number of adult parrot in Cedar Valley equals the number of adult crow in Cedar Valley. The number of adult crow in Cedar Valley equals the number of adult blue jay in Beverly Forest. The average number of newborn children per adult eagle in Cedar Valley equals 1 plus the average number of newborn children per adult blue jay in Beverly Forest. The average number of newborn children per adult parrot in Cedar Valley equals 2 times the sum of the number of adult blue jay in Beverly Forest, the average number of newborn children per adult crow in Cedar Valley, and the number of adult eagle in Cedar Valley. The number of adult eagle in Cedar Valley equals the sum of the number of adult blue jay in Beverly Forest, the total number of adult animals in Beverly Forest, and the number of adult crow in Cedar Valley. | What is the total number of adult animals in Beverly Forest? | Define adult blue jay in Beverly Forest as S; so S = 2. Define total number of adult animals in Beverly Forest as i; so i = S = 2. Answer: 2. | 2 | 17 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult blue jay in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Beverly Forest equals 3. The average number of newborn children per adult crow in Cedar Valley equals 3. The number of adult parrot in Cedar Valley equals the number of adult crow in Cedar Valley. The number of adult crow in Cedar Valley equals the number of adult blue jay in Beverly Forest. The average number of newborn children per adult eagle in Cedar Valley equals 1 plus the average number of newborn children per adult blue jay in Beverly Forest. The average number of newborn children per adult parrot in Cedar Valley equals 2 times the sum of the number of adult blue jay in Beverly Forest, the average number of newborn children per adult crow in Cedar Valley, and the number of adult eagle in Cedar Valley. The number of adult eagle in Cedar Valley equals the sum of the number of adult blue jay in Beverly Forest, the total number of adult animals in Beverly Forest, and the number of adult crow in Cedar Valley. Question: What is the total number of adult animals in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult fox in Jefferson Circus equals the difference between the number of adult deer in South Zoo and the number of adult fox in Jefferson Circus. The number of adult fox in South Zoo equals the sum of the average number of newborn children per adult wolf in South Zoo, the number of adult deer in South Zoo, and the number of adult wolf in South Zoo. The average number of newborn children per adult fox in Bundle Ranch equals the difference between the total number of adult animals in Mayer Aquarium and the total number of newborn animal children in Bundle Ranch. The average number of newborn children per adult deer in Jefferson Circus equals the number of adult deer in South Zoo. The average number of newborn children per adult deer in South Zoo equals the difference between the average number of newborn children per adult deer in Jefferson Circus and the number of adult fox in Jefferson Circus. The number of adult deer in South Zoo equals the number of adult wolf in South Zoo. The number of adult bear in Bundle Ranch equals the number of adult deer in South Zoo. The number of adult fox in Bundle Ranch equals the average number of newborn children per adult deer in South Zoo. The average number of newborn children per adult fox in South Zoo equals the sum of the number of adult fox in South Zoo, the average number of newborn children per adult bear in Mayer Aquarium, and the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult wolf in South Zoo equals 4 times the difference between the number of adult wolf in South Zoo and the number of adult deer in South Zoo. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the total number of adult animals in Mayer Aquarium, the average number of newborn children per adult bear in Bundle Ranch, the number of adult bear in Mayer Aquarium, and the average number of newborn children per adult bear in Bundle Ranch. The number of adult deer in Mayer Aquarium equals 3. The number of adult wolf in South Zoo equals 4. The number of adult bear in Jefferson Circus equals 3 plus the number of adult fox in South Zoo. The average number of newborn children per adult bear in Jefferson Circus equals the number of adult bear in Jefferson Circus. The number of adult bear in Mayer Aquarium equals the average number of newborn children per adult bear in Bundle Ranch. The average number of newborn children per adult bear in Bundle Ranch equals 2. The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult bear in Bundle Ranch. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 3. | How many adult bear does Mayer Aquarium have? | Define average number of newborn children per adult bear in Bundle Ranch as w; so w = 2. Define adult bear in Mayer Aquarium as i; so i = w = 2. Answer: 2. | 2 | 0 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult fox in Jefferson Circus equals the difference between the number of adult deer in South Zoo and the number of adult fox in Jefferson Circus. The number of adult fox in South Zoo equals the sum of the average number of newborn children per adult wolf in South Zoo, the number of adult deer in South Zoo, and the number of adult wolf in South Zoo. The average number of newborn children per adult fox in Bundle Ranch equals the difference between the total number of adult animals in Mayer Aquarium and the total number of newborn animal children in Bundle Ranch. The average number of newborn children per adult deer in Jefferson Circus equals the number of adult deer in South Zoo. The average number of newborn children per adult deer in South Zoo equals the difference between the average number of newborn children per adult deer in Jefferson Circus and the number of adult fox in Jefferson Circus. The number of adult deer in South Zoo equals the number of adult wolf in South Zoo. The number of adult bear in Bundle Ranch equals the number of adult deer in South Zoo. The number of adult fox in Bundle Ranch equals the average number of newborn children per adult deer in South Zoo. The average number of newborn children per adult fox in South Zoo equals the sum of the number of adult fox in South Zoo, the average number of newborn children per adult bear in Mayer Aquarium, and the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult wolf in South Zoo equals 4 times the difference between the number of adult wolf in South Zoo and the number of adult deer in South Zoo. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the total number of adult animals in Mayer Aquarium, the average number of newborn children per adult bear in Bundle Ranch, the number of adult bear in Mayer Aquarium, and the average number of newborn children per adult bear in Bundle Ranch. The number of adult deer in Mayer Aquarium equals 3. The number of adult wolf in South Zoo equals 4. The number of adult bear in Jefferson Circus equals 3 plus the number of adult fox in South Zoo. The average number of newborn children per adult bear in Jefferson Circus equals the number of adult bear in Jefferson Circus. The number of adult bear in Mayer Aquarium equals the average number of newborn children per adult bear in Bundle Ranch. The average number of newborn children per adult bear in Bundle Ranch equals 2. The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult bear in Bundle Ranch. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 3. Question: How many adult bear does Mayer Aquarium have? Solution: "
}
] |
The number of adult wolf in Jefferson Circus equals 1. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the average number of newborn children per adult deer in Hamilton Farm and the total number of adult animals in Jefferson Circus. The average number of newborn children per adult fox in Jefferson Circus equals 3 times the sum of the number of adult fox in Jefferson Circus and the average number of newborn children per adult deer in South Zoo. The number of adult deer in Jefferson Circus equals 3. The number of adult wolf in South Zoo equals 2. The number of adult deer in Hamilton Farm equals 3. The number of adult fox in Jefferson Circus equals 4. The number of adult fox in Hamilton Farm equals 1. The number of adult wolf in Hamilton Farm equals 2. The average number of newborn children per adult fox in Hamilton Farm equals 2 times the sum of the average number of newborn children per adult deer in Hamilton Farm, the average number of newborn children per adult deer in South Zoo, and the total number of adult animals in Hamilton Farm. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult deer in Hamilton Farm. The average number of newborn children per adult wolf in Hamilton Farm equals 3. The number of adult deer in South Zoo equals the sum of the number of adult deer in Hamilton Farm, the number of adult wolf in Hamilton Farm, the number of adult fox in Jefferson Circus, and the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Hamilton Farm equals 3. The average number of newborn children per adult wolf in South Zoo equals 3. The average number of newborn children per adult deer in Jefferson Circus equals the number of adult wolf in Hamilton Farm. | What is the average number of newborn children per adult deer in South Zoo? | Define average number of newborn children per adult deer in Hamilton Farm as t; so t = 3. Define average number of newborn children per adult deer in South Zoo as O; so O = t = 3. Answer: 3. | 2 | 11 | crazy_zootopia | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of adult wolf in Jefferson Circus equals 1. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the average number of newborn children per adult deer in Hamilton Farm and the total number of adult animals in Jefferson Circus. The average number of newborn children per adult fox in Jefferson Circus equals 3 times the sum of the number of adult fox in Jefferson Circus and the average number of newborn children per adult deer in South Zoo. The number of adult deer in Jefferson Circus equals 3. The number of adult wolf in South Zoo equals 2. The number of adult deer in Hamilton Farm equals 3. The number of adult fox in Jefferson Circus equals 4. The number of adult fox in Hamilton Farm equals 1. The number of adult wolf in Hamilton Farm equals 2. The average number of newborn children per adult fox in Hamilton Farm equals 2 times the sum of the average number of newborn children per adult deer in Hamilton Farm, the average number of newborn children per adult deer in South Zoo, and the total number of adult animals in Hamilton Farm. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult deer in Hamilton Farm. The average number of newborn children per adult wolf in Hamilton Farm equals 3. The number of adult deer in South Zoo equals the sum of the number of adult deer in Hamilton Farm, the number of adult wolf in Hamilton Farm, the number of adult fox in Jefferson Circus, and the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Hamilton Farm equals 3. The average number of newborn children per adult wolf in South Zoo equals 3. The average number of newborn children per adult deer in Jefferson Circus equals the number of adult wolf in Hamilton Farm. Question: What is the average number of newborn children per adult deer in South Zoo? Solution: "
}
] |
The average number of teachers per culinarian school in Westhaven City equals 4 times the number of public highschool in Westhaven City. The average number of teachers per elementary school in Westhaven City equals the sum of the average number of teachers per regional medical school in Brightford, the number of regional medical school in Brightford, the average number of teachers per culinarian school in Westhaven City, and the average number of teachers per regional medical school in Brightford. The average number of teachers per regional medical school in Brightford equals 2. The number of regional medical school in Brightford equals 3 plus the number of public highschool in Westhaven City. The number of elementary school in Westhaven City equals the average number of teachers per regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 4. The average number of teachers per public highschool in Westhaven City equals the number of regional medical school in Westhaven City. The average number of teachers per regional medical school in Westhaven City equals 3. The number of public highschool in Westhaven City equals 3. The number of culinarian school in Westhaven City equals 1. | How many elementary school does Westhaven City have? | Define average number of teachers per regional medical school in Westhaven City as c; so c = 3. Define elementary school in Westhaven City as S; so S = c = 3. Answer: 3. | 2 | 13 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per culinarian school in Westhaven City equals 4 times the number of public highschool in Westhaven City. The average number of teachers per elementary school in Westhaven City equals the sum of the average number of teachers per regional medical school in Brightford, the number of regional medical school in Brightford, the average number of teachers per culinarian school in Westhaven City, and the average number of teachers per regional medical school in Brightford. The average number of teachers per regional medical school in Brightford equals 2. The number of regional medical school in Brightford equals 3 plus the number of public highschool in Westhaven City. The number of elementary school in Westhaven City equals the average number of teachers per regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 4. The average number of teachers per public highschool in Westhaven City equals the number of regional medical school in Westhaven City. The average number of teachers per regional medical school in Westhaven City equals 3. The number of public highschool in Westhaven City equals 3. The number of culinarian school in Westhaven City equals 1. Question: How many elementary school does Westhaven City have? Solution: "
}
] |
The average number of teachers per public highschool in Brightford equals 4. The number of private middle school in Glenfield City equals the sum of the number of public highschool in Brightford, the average number of teachers per culinarian school in Brightford, and the average number of teachers per private middle school in Brightford. The average number of teachers per private middle school in Glenfield City equals 4. The average number of teachers per public highschool in Hawkesbury equals 1. The number of private middle school in Hawkesbury equals 1. The average number of teachers per private middle school in Hawkesbury equals 4. The number of culinarian school in Glenfield City equals 3. The average number of teachers per public highschool in Westhaven City equals the average number of teachers per public highschool in Hawkesbury. The number of public highschool in Glenfield City equals 2. The number of private middle school in Westhaven City equals the sum of the average number of teachers per culinarian school in Brightford, the number of private middle school in Hawkesbury, and the number of private middle school in Brightford. The average number of teachers per culinarian school in Brightford equals 1 plus the number of private middle school in Brightford. The average number of teachers per public highschool in Glenfield City equals 3 times the sum of the average number of teachers per culinarian school in Brightford, the average number of teachers per private middle school in Glenfield City, and the average number of teachers per culinarian school in Glenfield City. The average number of teachers per culinarian school in Glenfield City equals the sum of the number of culinarian school in Glenfield City, the number of private middle school in Brightford, and the average number of teachers per culinarian school in Brightford. The average number of teachers per culinarian school in Hawkesbury equals 3. The number of private middle school in Brightford equals 4. The average number of teachers per culinarian school in Westhaven City equals 4. The number of public highschool in Westhaven City equals the sum of the average number of teachers per culinarian school in Glenfield City and the average number of teachers per culinarian school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals 2 times the average number of teachers per private middle school in Glenfield City. The number of culinarian school in Hawkesbury equals 1. The number of culinarian school in Westhaven City equals the difference between the average number of teachers per private middle school in Hawkesbury and the total number of teachers from all schools in Hawkesbury. The number of culinarian school in Brightford equals the number of private middle school in Hawkesbury. The average number of teachers per private middle school in Brightford equals the average number of teachers per private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals 4. The number of public highschool in Brightford equals the number of private middle school in Hawkesbury. | What is the average number of teachers per private middle school in Brightford? | Define average number of teachers per private middle school in Hawkesbury as K; so K = 4. Define average number of teachers per private middle school in Brightford as i; so i = K = 4. Answer: 4. | 2 | 17 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per public highschool in Brightford equals 4. The number of private middle school in Glenfield City equals the sum of the number of public highschool in Brightford, the average number of teachers per culinarian school in Brightford, and the average number of teachers per private middle school in Brightford. The average number of teachers per private middle school in Glenfield City equals 4. The average number of teachers per public highschool in Hawkesbury equals 1. The number of private middle school in Hawkesbury equals 1. The average number of teachers per private middle school in Hawkesbury equals 4. The number of culinarian school in Glenfield City equals 3. The average number of teachers per public highschool in Westhaven City equals the average number of teachers per public highschool in Hawkesbury. The number of public highschool in Glenfield City equals 2. The number of private middle school in Westhaven City equals the sum of the average number of teachers per culinarian school in Brightford, the number of private middle school in Hawkesbury, and the number of private middle school in Brightford. The average number of teachers per culinarian school in Brightford equals 1 plus the number of private middle school in Brightford. The average number of teachers per public highschool in Glenfield City equals 3 times the sum of the average number of teachers per culinarian school in Brightford, the average number of teachers per private middle school in Glenfield City, and the average number of teachers per culinarian school in Glenfield City. The average number of teachers per culinarian school in Glenfield City equals the sum of the number of culinarian school in Glenfield City, the number of private middle school in Brightford, and the average number of teachers per culinarian school in Brightford. The average number of teachers per culinarian school in Hawkesbury equals 3. The number of private middle school in Brightford equals 4. The average number of teachers per culinarian school in Westhaven City equals 4. The number of public highschool in Westhaven City equals the sum of the average number of teachers per culinarian school in Glenfield City and the average number of teachers per culinarian school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals 2 times the average number of teachers per private middle school in Glenfield City. The number of culinarian school in Hawkesbury equals 1. The number of culinarian school in Westhaven City equals the difference between the average number of teachers per private middle school in Hawkesbury and the total number of teachers from all schools in Hawkesbury. The number of culinarian school in Brightford equals the number of private middle school in Hawkesbury. The average number of teachers per private middle school in Brightford equals the average number of teachers per private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals 4. The number of public highschool in Brightford equals the number of private middle school in Hawkesbury. Question: What is the average number of teachers per private middle school in Brightford? Solution: "
}
] |
The number of public highschool in Glenfield City equals the sum of the average number of teachers per culinarian school in Brightford and the average number of teachers per public highschool in Westhaven City. The average number of teachers per public highschool in Westhaven City equals the number of elementary school in Glenfield City. The average number of teachers per culinarian school in Hawkesbury equals the sum of the average number of teachers per regional medical school in Hawkesbury, the average number of teachers per regional medical school in Hawkesbury, and the average number of teachers per elementary school in Hawkesbury. The number of regional medical school in Brightford equals 4. The average number of teachers per regional medical school in Brightford equals the average number of teachers per regional medical school in Westhaven City. The average number of teachers per public highschool in Hawkesbury equals 4. The average number of teachers per public highschool in Brightford equals the number of public highschool in Hawkesbury. The number of culinarian school in Westhaven City equals 3. The number of elementary school in Westhaven City equals the average number of teachers per regional medical school in Glenfield City. The average number of teachers per elementary school in Glenfield City equals the difference between the number of public highschool in Hawkesbury and the average number of teachers per culinarian school in Brightford. The number of regional medical school in Westhaven City equals 2. The average number of teachers per elementary school in Hawkesbury equals 4. The number of culinarian school in Hawkesbury equals the sum of the number of public highschool in Hawkesbury, the average number of teachers per public highschool in Westhaven City, the number of regional medical school in Brightford, and the average number of teachers per regional medical school in Glenfield City. The average number of teachers per culinarian school in Brightford equals 2. The number of culinarian school in Brightford equals 4. The average number of teachers per culinarian school in Westhaven City equals the difference between the average number of teachers per elementary school in Brightford and the average number of teachers per public highschool in Westhaven City. The average number of teachers per public highschool in Glenfield City equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the total number of teachers from all schools in Westhaven City, and the number of culinarian school in Westhaven City. The number of regional medical school in Glenfield City equals the difference between the average number of teachers per culinarian school in Brightford and the number of regional medical school in Brightford. The number of public highschool in Brightford equals the difference between the number of public highschool in Hawkesbury and the total number of teachers from all schools in Westhaven City. The number of elementary school in Hawkesbury equals the number of public highschool in Hawkesbury. The number of elementary school in Glenfield City equals 1. The number of culinarian school in Glenfield City equals 4. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per elementary school in Hawkesbury. The number of public highschool in Westhaven City equals 1. The average number of teachers per elementary school in Westhaven City equals 4. The average number of teachers per culinarian school in Glenfield City equals 3. The number of regional medical school in Hawkesbury equals 2. The average number of teachers per regional medical school in Glenfield City equals the number of public highschool in Hawkesbury. The average number of teachers per regional medical school in Westhaven City equals 3. The average number of teachers per elementary school in Brightford equals 3. The number of elementary school in Brightford equals the number of public highschool in Hawkesbury. The number of public highschool in Hawkesbury equals 1. | What is the average number of teachers per regional medical school in Hawkesbury? | Define average number of teachers per elementary school in Hawkesbury as Z; so Z = 4. Define average number of teachers per regional medical school in Hawkesbury as O; so O = Z = 4. Answer: 4. | 2 | 21 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of public highschool in Glenfield City equals the sum of the average number of teachers per culinarian school in Brightford and the average number of teachers per public highschool in Westhaven City. The average number of teachers per public highschool in Westhaven City equals the number of elementary school in Glenfield City. The average number of teachers per culinarian school in Hawkesbury equals the sum of the average number of teachers per regional medical school in Hawkesbury, the average number of teachers per regional medical school in Hawkesbury, and the average number of teachers per elementary school in Hawkesbury. The number of regional medical school in Brightford equals 4. The average number of teachers per regional medical school in Brightford equals the average number of teachers per regional medical school in Westhaven City. The average number of teachers per public highschool in Hawkesbury equals 4. The average number of teachers per public highschool in Brightford equals the number of public highschool in Hawkesbury. The number of culinarian school in Westhaven City equals 3. The number of elementary school in Westhaven City equals the average number of teachers per regional medical school in Glenfield City. The average number of teachers per elementary school in Glenfield City equals the difference between the number of public highschool in Hawkesbury and the average number of teachers per culinarian school in Brightford. The number of regional medical school in Westhaven City equals 2. The average number of teachers per elementary school in Hawkesbury equals 4. The number of culinarian school in Hawkesbury equals the sum of the number of public highschool in Hawkesbury, the average number of teachers per public highschool in Westhaven City, the number of regional medical school in Brightford, and the average number of teachers per regional medical school in Glenfield City. The average number of teachers per culinarian school in Brightford equals 2. The number of culinarian school in Brightford equals 4. The average number of teachers per culinarian school in Westhaven City equals the difference between the average number of teachers per elementary school in Brightford and the average number of teachers per public highschool in Westhaven City. The average number of teachers per public highschool in Glenfield City equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the total number of teachers from all schools in Westhaven City, and the number of culinarian school in Westhaven City. The number of regional medical school in Glenfield City equals the difference between the average number of teachers per culinarian school in Brightford and the number of regional medical school in Brightford. The number of public highschool in Brightford equals the difference between the number of public highschool in Hawkesbury and the total number of teachers from all schools in Westhaven City. The number of elementary school in Hawkesbury equals the number of public highschool in Hawkesbury. The number of elementary school in Glenfield City equals 1. The number of culinarian school in Glenfield City equals 4. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per elementary school in Hawkesbury. The number of public highschool in Westhaven City equals 1. The average number of teachers per elementary school in Westhaven City equals 4. The average number of teachers per culinarian school in Glenfield City equals 3. The number of regional medical school in Hawkesbury equals 2. The average number of teachers per regional medical school in Glenfield City equals the number of public highschool in Hawkesbury. The average number of teachers per regional medical school in Westhaven City equals 3. The average number of teachers per elementary school in Brightford equals 3. The number of elementary school in Brightford equals the number of public highschool in Hawkesbury. The number of public highschool in Hawkesbury equals 1. Question: What is the average number of teachers per regional medical school in Hawkesbury? Solution: "
}
] |
The number of elementary school in Ruby Bay equals the average number of teachers per elementary school in Ruby Bay. The average number of teachers per culinarian school in Oakbridge City equals the average number of teachers per elementary school in Oakbridge City. The average number of teachers per culinarian school in Ruby Bay equals the sum of the average number of teachers per culinarian school in Oakbridge City and the average number of teachers per elementary school in Oakbridge City. The average number of teachers per elementary school in Oakbridge City equals 3. The average number of teachers per elementary school in Ruby Bay equals 3. The number of culinarian school in Oakbridge City equals the difference between the average number of teachers per culinarian school in Oakbridge City and the number of elementary school in Oakbridge City. The number of culinarian school in Ruby Bay equals 4 times the difference between the average number of teachers per elementary school in Ruby Bay and the number of elementary school in Ruby Bay. The number of elementary school in Oakbridge City equals the sum of the average number of teachers per elementary school in Oakbridge City and the average number of teachers per culinarian school in Oakbridge City. | What is the average number of teachers per culinarian school in Oakbridge City? | Define average number of teachers per elementary school in Oakbridge City as X; so X = 3. Define average number of teachers per culinarian school in Oakbridge City as V; so V = X = 3. Answer: 3. | 2 | 6 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of elementary school in Ruby Bay equals the average number of teachers per elementary school in Ruby Bay. The average number of teachers per culinarian school in Oakbridge City equals the average number of teachers per elementary school in Oakbridge City. The average number of teachers per culinarian school in Ruby Bay equals the sum of the average number of teachers per culinarian school in Oakbridge City and the average number of teachers per elementary school in Oakbridge City. The average number of teachers per elementary school in Oakbridge City equals 3. The average number of teachers per elementary school in Ruby Bay equals 3. The number of culinarian school in Oakbridge City equals the difference between the average number of teachers per culinarian school in Oakbridge City and the number of elementary school in Oakbridge City. The number of culinarian school in Ruby Bay equals 4 times the difference between the average number of teachers per elementary school in Ruby Bay and the number of elementary school in Ruby Bay. The number of elementary school in Oakbridge City equals the sum of the average number of teachers per elementary school in Oakbridge City and the average number of teachers per culinarian school in Oakbridge City. Question: What is the average number of teachers per culinarian school in Oakbridge City? Solution: "
}
] |
The number of public highschool in Evervale City equals 1 plus the sum of the average number of teachers per culinarian school in Hawkesbury and the number of private middle school in Hawkesbury. The number of private middle school in Evervale City equals 2. The average number of teachers per public highschool in Evervale City equals 3 times the number of elementary school in Brightford. The average number of teachers per private middle school in Evervale City equals 2. The average number of teachers per culinarian school in Brightford equals 2 plus the sum of the average number of teachers per regional medical school in Brightford, the total number of schools in Hawkesbury, and the average number of teachers per regional medical school in Brightford. The average number of teachers per private middle school in Brightford equals the sum of the number of private middle school in Hawkesbury, the average number of teachers per private middle school in Evervale City, the number of regional medical school in Brightford, and the number of private middle school in Evervale City. The number of culinarian school in Hawkesbury equals 2 plus the sum of the average number of teachers per private middle school in Evervale City, the number of private middle school in Evervale City, and the average number of teachers per elementary school in Brightford. The average number of teachers per culinarian school in Hawkesbury equals 1. The average number of teachers per regional medical school in Brightford equals 2. The number of private middle school in Brightford equals 4. The average number of teachers per public highschool in Hawkesbury equals the average number of teachers per regional medical school in Brightford. The number of elementary school in Brightford equals the sum of the number of private middle school in Brightford and the average number of teachers per private middle school in Evervale City. The number of public highschool in Hawkesbury equals 3. The number of private middle school in Hawkesbury equals 2. The number of culinarian school in Brightford equals 4 times the sum of the number of private middle school in Evervale City, the average number of teachers per public highschool in Hawkesbury, and the average number of teachers per public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 2 times the average number of teachers per elementary school in Brightford. The number of regional medical school in Brightford equals the number of private middle school in Evervale City. The average number of teachers per elementary school in Brightford equals the number of private middle school in Evervale City. | What is the average number of teachers per public highschool in Hawkesbury? | Define average number of teachers per regional medical school in Brightford as q; so q = 2. Define average number of teachers per public highschool in Hawkesbury as l; so l = q = 2. Answer: 2. | 2 | 5 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of public highschool in Evervale City equals 1 plus the sum of the average number of teachers per culinarian school in Hawkesbury and the number of private middle school in Hawkesbury. The number of private middle school in Evervale City equals 2. The average number of teachers per public highschool in Evervale City equals 3 times the number of elementary school in Brightford. The average number of teachers per private middle school in Evervale City equals 2. The average number of teachers per culinarian school in Brightford equals 2 plus the sum of the average number of teachers per regional medical school in Brightford, the total number of schools in Hawkesbury, and the average number of teachers per regional medical school in Brightford. The average number of teachers per private middle school in Brightford equals the sum of the number of private middle school in Hawkesbury, the average number of teachers per private middle school in Evervale City, the number of regional medical school in Brightford, and the number of private middle school in Evervale City. The number of culinarian school in Hawkesbury equals 2 plus the sum of the average number of teachers per private middle school in Evervale City, the number of private middle school in Evervale City, and the average number of teachers per elementary school in Brightford. The average number of teachers per culinarian school in Hawkesbury equals 1. The average number of teachers per regional medical school in Brightford equals 2. The number of private middle school in Brightford equals 4. The average number of teachers per public highschool in Hawkesbury equals the average number of teachers per regional medical school in Brightford. The number of elementary school in Brightford equals the sum of the number of private middle school in Brightford and the average number of teachers per private middle school in Evervale City. The number of public highschool in Hawkesbury equals 3. The number of private middle school in Hawkesbury equals 2. The number of culinarian school in Brightford equals 4 times the sum of the number of private middle school in Evervale City, the average number of teachers per public highschool in Hawkesbury, and the average number of teachers per public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 2 times the average number of teachers per elementary school in Brightford. The number of regional medical school in Brightford equals the number of private middle school in Evervale City. The average number of teachers per elementary school in Brightford equals the number of private middle school in Evervale City. Question: What is the average number of teachers per public highschool in Hawkesbury? Solution: "
}
] |
The number of regional medical school in Brightford equals the average number of teachers per regional medical school in Brightford. The number of private middle school in Westhaven City equals 2. The average number of teachers per private middle school in Westhaven City equals the number of private middle school in Brightford. The number of private middle school in Brightford equals 3. The number of regional medical school in Westhaven City equals the difference between the average number of teachers per regional medical school in Brightford and the total number of schools in Westhaven City. The average number of teachers per private middle school in Brightford equals 2 times the number of private middle school in Westhaven City. The average number of teachers per regional medical school in Brightford equals 4. The average number of teachers per regional medical school in Westhaven City equals 1 plus the difference between the number of regional medical school in Brightford and the average number of teachers per private middle school in Westhaven City. | What is the average number of teachers per private middle school in Westhaven City? | Define private middle school in Brightford as r; so r = 3. Define average number of teachers per private middle school in Westhaven City as b; so b = r = 3. Answer: 3. | 2 | 9 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of regional medical school in Brightford equals the average number of teachers per regional medical school in Brightford. The number of private middle school in Westhaven City equals 2. The average number of teachers per private middle school in Westhaven City equals the number of private middle school in Brightford. The number of private middle school in Brightford equals 3. The number of regional medical school in Westhaven City equals the difference between the average number of teachers per regional medical school in Brightford and the total number of schools in Westhaven City. The average number of teachers per private middle school in Brightford equals 2 times the number of private middle school in Westhaven City. The average number of teachers per regional medical school in Brightford equals 4. The average number of teachers per regional medical school in Westhaven City equals 1 plus the difference between the number of regional medical school in Brightford and the average number of teachers per private middle school in Westhaven City. Question: What is the average number of teachers per private middle school in Westhaven City? Solution: "
}
] |
The number of elementary school in Westhaven City equals the number of private middle school in Glenfield City. The average number of teachers per private middle school in Glenfield City equals the difference between the average number of teachers per private middle school in Brightford and the average number of teachers per elementary school in Westhaven City. The number of regional medical school in Evervale City equals 4. The number of public highschool in Westhaven City equals 3. The number of private middle school in Glenfield City equals 2. The number of regional medical school in Brightford equals 4. The number of private middle school in Brightford equals 3 plus the difference between the number of elementary school in Westhaven City and the average number of teachers per elementary school in Westhaven City. The average number of teachers per public highschool in Westhaven City equals 1 plus the sum of the average number of teachers per elementary school in Westhaven City and the average number of teachers per private middle school in Brightford. The average number of teachers per regional medical school in Brightford equals 2 times the total number of schools in Evervale City. The average number of teachers per elementary school in Westhaven City equals 3. The average number of teachers per regional medical school in Evervale City equals the average number of teachers per private middle school in Brightford. The average number of teachers per private middle school in Brightford equals 3 times the average number of teachers per elementary school in Westhaven City. | What is the total number of schools in Glenfield City? | Define private middle school in Glenfield City as i; so i = 2. Define total number of schools in Glenfield City as r; so r = i = 2. Answer: 2. | 2 | 15 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of elementary school in Westhaven City equals the number of private middle school in Glenfield City. The average number of teachers per private middle school in Glenfield City equals the difference between the average number of teachers per private middle school in Brightford and the average number of teachers per elementary school in Westhaven City. The number of regional medical school in Evervale City equals 4. The number of public highschool in Westhaven City equals 3. The number of private middle school in Glenfield City equals 2. The number of regional medical school in Brightford equals 4. The number of private middle school in Brightford equals 3 plus the difference between the number of elementary school in Westhaven City and the average number of teachers per elementary school in Westhaven City. The average number of teachers per public highschool in Westhaven City equals 1 plus the sum of the average number of teachers per elementary school in Westhaven City and the average number of teachers per private middle school in Brightford. The average number of teachers per regional medical school in Brightford equals 2 times the total number of schools in Evervale City. The average number of teachers per elementary school in Westhaven City equals 3. The average number of teachers per regional medical school in Evervale City equals the average number of teachers per private middle school in Brightford. The average number of teachers per private middle school in Brightford equals 3 times the average number of teachers per elementary school in Westhaven City. Question: What is the total number of schools in Glenfield City? Solution: "
}
] |
The average number of teachers per private middle school in Evervale City equals the average number of teachers per culinarian school in Brightford. The average number of teachers per culinarian school in Brightford equals 1. The average number of teachers per private middle school in Hawkesbury equals 4. The average number of teachers per culinarian school in Hawkesbury equals 3. The average number of teachers per elementary school in Brightford equals the number of private middle school in Evervale City. The number of culinarian school in Evervale City equals 3. The average number of teachers per elementary school in Hawkesbury equals 1 plus the sum of the average number of teachers per culinarian school in Hawkesbury, the average number of teachers per private middle school in Evervale City, and the average number of teachers per elementary school in Evervale City. The number of culinarian school in Brightford equals the average number of teachers per private middle school in Hawkesbury. The number of private middle school in Hawkesbury equals 3 plus the difference between the average number of teachers per private middle school in Hawkesbury and the number of elementary school in Evervale City. The number of elementary school in Evervale City equals the difference between the average number of teachers per elementary school in Evervale City and the average number of teachers per culinarian school in Evervale City. The average number of teachers per culinarian school in Evervale City equals 3. The number of elementary school in Hawkesbury equals 4. The number of culinarian school in Hawkesbury equals 1 plus the sum of the average number of teachers per culinarian school in Evervale City, the average number of teachers per private middle school in Hawkesbury, and the average number of teachers per elementary school in Evervale City. The number of private middle school in Evervale City equals the average number of teachers per culinarian school in Brightford. The number of elementary school in Brightford equals the number of culinarian school in Brightford. The average number of teachers per elementary school in Evervale City equals 2 plus the average number of teachers per culinarian school in Evervale City. | What is the average number of teachers per private middle school in Evervale City? | Define average number of teachers per culinarian school in Brightford as j; so j = 1. Define average number of teachers per private middle school in Evervale City as N; so N = j = 1. Answer: 1. | 2 | 21 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per private middle school in Evervale City equals the average number of teachers per culinarian school in Brightford. The average number of teachers per culinarian school in Brightford equals 1. The average number of teachers per private middle school in Hawkesbury equals 4. The average number of teachers per culinarian school in Hawkesbury equals 3. The average number of teachers per elementary school in Brightford equals the number of private middle school in Evervale City. The number of culinarian school in Evervale City equals 3. The average number of teachers per elementary school in Hawkesbury equals 1 plus the sum of the average number of teachers per culinarian school in Hawkesbury, the average number of teachers per private middle school in Evervale City, and the average number of teachers per elementary school in Evervale City. The number of culinarian school in Brightford equals the average number of teachers per private middle school in Hawkesbury. The number of private middle school in Hawkesbury equals 3 plus the difference between the average number of teachers per private middle school in Hawkesbury and the number of elementary school in Evervale City. The number of elementary school in Evervale City equals the difference between the average number of teachers per elementary school in Evervale City and the average number of teachers per culinarian school in Evervale City. The average number of teachers per culinarian school in Evervale City equals 3. The number of elementary school in Hawkesbury equals 4. The number of culinarian school in Hawkesbury equals 1 plus the sum of the average number of teachers per culinarian school in Evervale City, the average number of teachers per private middle school in Hawkesbury, and the average number of teachers per elementary school in Evervale City. The number of private middle school in Evervale City equals the average number of teachers per culinarian school in Brightford. The number of elementary school in Brightford equals the number of culinarian school in Brightford. The average number of teachers per elementary school in Evervale City equals 2 plus the average number of teachers per culinarian school in Evervale City. Question: What is the average number of teachers per private middle school in Evervale City? Solution: "
}
] |
The average number of teachers per regional medical school in Ruby Bay equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per culinarian school in Ruby Bay equals the number of culinarian school in Ruby Bay. The average number of teachers per public highschool in Oakbridge City equals 4. The average number of teachers per culinarian school in Clearwater Bay equals 2 times the sum of the number of elementary school in Clearwater Bay, the number of culinarian school in Ruby Bay, and the average number of teachers per culinarian school in Ruby Bay. The number of regional medical school in Oakbridge City equals 3. The number of public highschool in Clearwater Bay equals 3. The average number of teachers per elementary school in Ruby Bay equals the average number of teachers per public highschool in Clearwater Bay. The number of elementary school in Ruby Bay equals 3 times the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per elementary school in Oakbridge City equals 4. The number of public highschool in Ruby Bay equals 1 plus the sum of the average number of teachers per culinarian school in Ruby Bay and the average number of teachers per regional medical school in Ruby Bay. The average number of teachers per elementary school in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The number of elementary school in Clearwater Bay equals the sum of the average number of teachers per culinarian school in Ruby Bay and the number of culinarian school in Ruby Bay. The number of elementary school in Oakbridge City equals 1. The number of regional medical school in Ruby Bay equals the number of public highschool in Clearwater Bay. The average number of teachers per regional medical school in Oakbridge City equals 3. The number of culinarian school in Clearwater Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of culinarian school in Ruby Bay equals 3. The average number of teachers per public highschool in Ruby Bay equals 3 times the average number of teachers per culinarian school in Clearwater Bay. The number of public highschool in Oakbridge City equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per public highschool in Clearwater Bay equals 2. | What is the average number of teachers per regional medical school in Ruby Bay? | Define average number of teachers per regional medical school in Oakbridge City as R; so R = 3. Define average number of teachers per regional medical school in Ruby Bay as I; so I = R = 3. Answer: 3. | 2 | 14 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per regional medical school in Ruby Bay equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per culinarian school in Ruby Bay equals the number of culinarian school in Ruby Bay. The average number of teachers per public highschool in Oakbridge City equals 4. The average number of teachers per culinarian school in Clearwater Bay equals 2 times the sum of the number of elementary school in Clearwater Bay, the number of culinarian school in Ruby Bay, and the average number of teachers per culinarian school in Ruby Bay. The number of regional medical school in Oakbridge City equals 3. The number of public highschool in Clearwater Bay equals 3. The average number of teachers per elementary school in Ruby Bay equals the average number of teachers per public highschool in Clearwater Bay. The number of elementary school in Ruby Bay equals 3 times the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per elementary school in Oakbridge City equals 4. The number of public highschool in Ruby Bay equals 1 plus the sum of the average number of teachers per culinarian school in Ruby Bay and the average number of teachers per regional medical school in Ruby Bay. The average number of teachers per elementary school in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The number of elementary school in Clearwater Bay equals the sum of the average number of teachers per culinarian school in Ruby Bay and the number of culinarian school in Ruby Bay. The number of elementary school in Oakbridge City equals 1. The number of regional medical school in Ruby Bay equals the number of public highschool in Clearwater Bay. The average number of teachers per regional medical school in Oakbridge City equals 3. The number of culinarian school in Clearwater Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of culinarian school in Ruby Bay equals 3. The average number of teachers per public highschool in Ruby Bay equals 3 times the average number of teachers per culinarian school in Clearwater Bay. The number of public highschool in Oakbridge City equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per public highschool in Clearwater Bay equals 2. Question: What is the average number of teachers per regional medical school in Ruby Bay? Solution: "
}
] |
The average number of teachers per elementary school in Evervale City equals the number of elementary school in Evervale City. The average number of teachers per public highschool in Glenfield City equals 1. The average number of teachers per culinarian school in Evervale City equals the sum of the total number of schools in Glenfield City and the average number of teachers per public highschool in Glenfield City. The number of public highschool in Glenfield City equals 2 plus the difference between the number of regional medical school in Evervale City and the number of culinarian school in Evervale City. The number of regional medical school in Glenfield City equals 1. The number of regional medical school in Westhaven City equals the sum of the number of regional medical school in Evervale City, the number of public highschool in Glenfield City, and the average number of teachers per regional medical school in Glenfield City. The number of elementary school in Evervale City equals 4. The average number of teachers per public highschool in Westhaven City equals 2. The average number of teachers per culinarian school in Glenfield City equals 4. The average number of teachers per elementary school in Westhaven City equals the difference between the average number of teachers per regional medical school in Glenfield City and the total number of schools in Westhaven City. The number of culinarian school in Evervale City equals 2 times the number of regional medical school in Evervale City. The average number of teachers per regional medical school in Glenfield City equals 3. The number of culinarian school in Glenfield City equals the difference between the average number of teachers per public highschool in Westhaven City and the average number of teachers per regional medical school in Westhaven City. The number of public highschool in Westhaven City equals the difference between the number of regional medical school in Glenfield City and the total number of schools in Evervale City. The average number of teachers per regional medical school in Evervale City equals 2. The average number of teachers per regional medical school in Westhaven City equals the average number of teachers per regional medical school in Evervale City. The number of regional medical school in Evervale City equals 2. The number of elementary school in Westhaven City equals 2. | What is the average number of teachers per regional medical school in Westhaven City? | Define average number of teachers per regional medical school in Evervale City as w; so w = 2. Define average number of teachers per regional medical school in Westhaven City as Q; so Q = w = 2. Answer: 2. | 2 | 8 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per elementary school in Evervale City equals the number of elementary school in Evervale City. The average number of teachers per public highschool in Glenfield City equals 1. The average number of teachers per culinarian school in Evervale City equals the sum of the total number of schools in Glenfield City and the average number of teachers per public highschool in Glenfield City. The number of public highschool in Glenfield City equals 2 plus the difference between the number of regional medical school in Evervale City and the number of culinarian school in Evervale City. The number of regional medical school in Glenfield City equals 1. The number of regional medical school in Westhaven City equals the sum of the number of regional medical school in Evervale City, the number of public highschool in Glenfield City, and the average number of teachers per regional medical school in Glenfield City. The number of elementary school in Evervale City equals 4. The average number of teachers per public highschool in Westhaven City equals 2. The average number of teachers per culinarian school in Glenfield City equals 4. The average number of teachers per elementary school in Westhaven City equals the difference between the average number of teachers per regional medical school in Glenfield City and the total number of schools in Westhaven City. The number of culinarian school in Evervale City equals 2 times the number of regional medical school in Evervale City. The average number of teachers per regional medical school in Glenfield City equals 3. The number of culinarian school in Glenfield City equals the difference between the average number of teachers per public highschool in Westhaven City and the average number of teachers per regional medical school in Westhaven City. The number of public highschool in Westhaven City equals the difference between the number of regional medical school in Glenfield City and the total number of schools in Evervale City. The average number of teachers per regional medical school in Evervale City equals 2. The average number of teachers per regional medical school in Westhaven City equals the average number of teachers per regional medical school in Evervale City. The number of regional medical school in Evervale City equals 2. The number of elementary school in Westhaven City equals 2. Question: What is the average number of teachers per regional medical school in Westhaven City? Solution: "
}
] |
The number of regional medical school in Brightford equals 4 plus the sum of the total number of teachers from all schools in Evervale City, the average number of teachers per private middle school in Westhaven City, and the number of public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 2 times the sum of the number of regional medical school in Westhaven City, the number of private middle school in Westhaven City, and the average number of teachers per regional medical school in Brightford. The number of private middle school in Hawkesbury equals the sum of the average number of teachers per private middle school in Evervale City, the average number of teachers per private middle school in Evervale City, and the total number of teachers from all schools in Evervale City. The number of private middle school in Westhaven City equals the average number of teachers per regional medical school in Brightford. The average number of teachers per regional medical school in Brightford equals 3. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per private middle school in Evervale City. The number of regional medical school in Westhaven City equals 3. The average number of teachers per private middle school in Evervale City equals 3. The number of culinarian school in Westhaven City equals the average number of teachers per private middle school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals 3. The number of culinarian school in Evervale City equals 2. The number of regional medical school in Hawkesbury equals 4 plus the number of private middle school in Hawkesbury. The average number of teachers per culinarian school in Westhaven City equals the average number of teachers per private middle school in Evervale City. The average number of teachers per public highschool in Hawkesbury equals the total number of schools in Brightford. The number of public highschool in Brightford equals 4. The average number of teachers per culinarian school in Evervale City equals 3. The number of regional medical school in Evervale City equals 2. The number of private middle school in Evervale City equals 3. The average number of teachers per regional medical school in Evervale City equals 4. The average number of teachers per regional medical school in Westhaven City equals 3. The average number of teachers per public highschool in Brightford equals 1 plus the sum of the average number of teachers per private middle school in Westhaven City, the number of regional medical school in Westhaven City, and the average number of teachers per private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals the number of culinarian school in Evervale City. | What is the average number of teachers per regional medical school in Hawkesbury? | Define average number of teachers per private middle school in Evervale City as A; so A = 3. Define average number of teachers per regional medical school in Hawkesbury as i; so i = A = 3. Answer: 3. | 2 | 14 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of regional medical school in Brightford equals 4 plus the sum of the total number of teachers from all schools in Evervale City, the average number of teachers per private middle school in Westhaven City, and the number of public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 2 times the sum of the number of regional medical school in Westhaven City, the number of private middle school in Westhaven City, and the average number of teachers per regional medical school in Brightford. The number of private middle school in Hawkesbury equals the sum of the average number of teachers per private middle school in Evervale City, the average number of teachers per private middle school in Evervale City, and the total number of teachers from all schools in Evervale City. The number of private middle school in Westhaven City equals the average number of teachers per regional medical school in Brightford. The average number of teachers per regional medical school in Brightford equals 3. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per private middle school in Evervale City. The number of regional medical school in Westhaven City equals 3. The average number of teachers per private middle school in Evervale City equals 3. The number of culinarian school in Westhaven City equals the average number of teachers per private middle school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals 3. The number of culinarian school in Evervale City equals 2. The number of regional medical school in Hawkesbury equals 4 plus the number of private middle school in Hawkesbury. The average number of teachers per culinarian school in Westhaven City equals the average number of teachers per private middle school in Evervale City. The average number of teachers per public highschool in Hawkesbury equals the total number of schools in Brightford. The number of public highschool in Brightford equals 4. The average number of teachers per culinarian school in Evervale City equals 3. The number of regional medical school in Evervale City equals 2. The number of private middle school in Evervale City equals 3. The average number of teachers per regional medical school in Evervale City equals 4. The average number of teachers per regional medical school in Westhaven City equals 3. The average number of teachers per public highschool in Brightford equals 1 plus the sum of the average number of teachers per private middle school in Westhaven City, the number of regional medical school in Westhaven City, and the average number of teachers per private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals the number of culinarian school in Evervale City. Question: What is the average number of teachers per regional medical school in Hawkesbury? Solution: "
}
] |
The average number of teachers per private middle school in Riverton City equals the sum of the number of private middle school in Ruby Bay, the number of elementary school in Riverton City, and the average number of teachers per elementary school in Riverton City. The number of elementary school in Riverton City equals the average number of teachers per elementary school in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals 3. The average number of teachers per elementary school in Oakbridge City equals the average number of teachers per private middle school in Oakbridge City. The average number of teachers per elementary school in Riverton City equals 4. The average number of teachers per regional medical school in Riverton City equals the average number of teachers per elementary school in Ruby Bay. The number of private middle school in Riverton City equals 2. The number of elementary school in Oakbridge City equals 1. The number of private middle school in Ruby Bay equals 3 plus the average number of teachers per private middle school in Oakbridge City. The average number of teachers per private middle school in Oakbridge City equals 4. The number of regional medical school in Riverton City equals the difference between the average number of teachers per private middle school in Ruby Bay and the average number of teachers per regional medical school in Ruby Bay. The average number of teachers per regional medical school in Oakbridge City equals the difference between the average number of teachers per elementary school in Oakbridge City and the number of elementary school in Oakbridge City. The average number of teachers per elementary school in Ruby Bay equals 4. The number of regional medical school in Oakbridge City equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per regional medical school in Ruby Bay equals the average number of teachers per private middle school in Ruby Bay. The number of regional medical school in Ruby Bay equals the difference between the average number of teachers per private middle school in Oakbridge City and the number of regional medical school in Oakbridge City. The number of private middle school in Oakbridge City equals the sum of the average number of teachers per private middle school in Ruby Bay, the average number of teachers per private middle school in Ruby Bay, the number of regional medical school in Ruby Bay, and the average number of teachers per elementary school in Ruby Bay. The number of elementary school in Ruby Bay equals 4 plus the average number of teachers per private middle school in Oakbridge City. | What is the average number of teachers per regional medical school in Ruby Bay? | Define average number of teachers per private middle school in Ruby Bay as W; so W = 3. Define average number of teachers per regional medical school in Ruby Bay as h; so h = W = 3. Answer: 3. | 2 | 10 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per private middle school in Riverton City equals the sum of the number of private middle school in Ruby Bay, the number of elementary school in Riverton City, and the average number of teachers per elementary school in Riverton City. The number of elementary school in Riverton City equals the average number of teachers per elementary school in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals 3. The average number of teachers per elementary school in Oakbridge City equals the average number of teachers per private middle school in Oakbridge City. The average number of teachers per elementary school in Riverton City equals 4. The average number of teachers per regional medical school in Riverton City equals the average number of teachers per elementary school in Ruby Bay. The number of private middle school in Riverton City equals 2. The number of elementary school in Oakbridge City equals 1. The number of private middle school in Ruby Bay equals 3 plus the average number of teachers per private middle school in Oakbridge City. The average number of teachers per private middle school in Oakbridge City equals 4. The number of regional medical school in Riverton City equals the difference between the average number of teachers per private middle school in Ruby Bay and the average number of teachers per regional medical school in Ruby Bay. The average number of teachers per regional medical school in Oakbridge City equals the difference between the average number of teachers per elementary school in Oakbridge City and the number of elementary school in Oakbridge City. The average number of teachers per elementary school in Ruby Bay equals 4. The number of regional medical school in Oakbridge City equals the average number of teachers per regional medical school in Oakbridge City. The average number of teachers per regional medical school in Ruby Bay equals the average number of teachers per private middle school in Ruby Bay. The number of regional medical school in Ruby Bay equals the difference between the average number of teachers per private middle school in Oakbridge City and the number of regional medical school in Oakbridge City. The number of private middle school in Oakbridge City equals the sum of the average number of teachers per private middle school in Ruby Bay, the average number of teachers per private middle school in Ruby Bay, the number of regional medical school in Ruby Bay, and the average number of teachers per elementary school in Ruby Bay. The number of elementary school in Ruby Bay equals 4 plus the average number of teachers per private middle school in Oakbridge City. Question: What is the average number of teachers per regional medical school in Ruby Bay? Solution: "
}
] |
The average number of teachers per regional medical school in Glenfield City equals the difference between the total number of schools in Glenfield City and the number of regional medical school in Glenfield City. The average number of teachers per elementary school in Glenfield City equals the sum of the number of elementary school in Brightford, the number of elementary school in Glenfield City, the average number of teachers per elementary school in Hawkesbury, and the number of private middle school in Glenfield City. The average number of teachers per private middle school in Hawkesbury equals 2 plus the sum of the average number of teachers per regional medical school in Hawkesbury, the average number of teachers per private middle school in Glenfield City, and the average number of teachers per regional medical school in Hawkesbury. The number of elementary school in Hawkesbury equals 3 plus the number of private middle school in Hawkesbury. The number of elementary school in Brightford equals 2 plus the number of private middle school in Glenfield City. The average number of teachers per elementary school in Hawkesbury equals the number of private middle school in Glenfield City. The number of elementary school in Glenfield City equals 2. The average number of teachers per elementary school in Brightford equals the number of private middle school in Glenfield City. The average number of teachers per private middle school in Glenfield City equals 4. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per private middle school in Glenfield City. The number of private middle school in Glenfield City equals 4. The number of regional medical school in Hawkesbury equals 4. The number of private middle school in Hawkesbury equals the number of elementary school in Glenfield City. The number of regional medical school in Glenfield City equals the average number of teachers per private middle school in Glenfield City. | What is the average number of teachers per regional medical school in Hawkesbury? | Define average number of teachers per private middle school in Glenfield City as G; so G = 4. Define average number of teachers per regional medical school in Hawkesbury as W; so W = G = 4. Answer: 4. | 2 | 19 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per regional medical school in Glenfield City equals the difference between the total number of schools in Glenfield City and the number of regional medical school in Glenfield City. The average number of teachers per elementary school in Glenfield City equals the sum of the number of elementary school in Brightford, the number of elementary school in Glenfield City, the average number of teachers per elementary school in Hawkesbury, and the number of private middle school in Glenfield City. The average number of teachers per private middle school in Hawkesbury equals 2 plus the sum of the average number of teachers per regional medical school in Hawkesbury, the average number of teachers per private middle school in Glenfield City, and the average number of teachers per regional medical school in Hawkesbury. The number of elementary school in Hawkesbury equals 3 plus the number of private middle school in Hawkesbury. The number of elementary school in Brightford equals 2 plus the number of private middle school in Glenfield City. The average number of teachers per elementary school in Hawkesbury equals the number of private middle school in Glenfield City. The number of elementary school in Glenfield City equals 2. The average number of teachers per elementary school in Brightford equals the number of private middle school in Glenfield City. The average number of teachers per private middle school in Glenfield City equals 4. The average number of teachers per regional medical school in Hawkesbury equals the average number of teachers per private middle school in Glenfield City. The number of private middle school in Glenfield City equals 4. The number of regional medical school in Hawkesbury equals 4. The number of private middle school in Hawkesbury equals the number of elementary school in Glenfield City. The number of regional medical school in Glenfield City equals the average number of teachers per private middle school in Glenfield City. Question: What is the average number of teachers per regional medical school in Hawkesbury? Solution: "
}
] |
The average number of teachers per regional medical school in Westhaven City equals 3 times the number of elementary school in Brightford. The number of elementary school in Evervale City equals the sum of the average number of teachers per elementary school in Evervale City, the average number of teachers per regional medical school in Brightford, the average number of teachers per private middle school in Brightford, and the total number of teachers from all schools in Brightford. The average number of teachers per public highschool in Hawkesbury equals 1 plus the average number of teachers per private middle school in Glenfield City. The average number of teachers per elementary school in Westhaven City equals the total number of schools in Brightford. The average number of teachers per culinarian school in Westhaven City equals the sum of the number of regional medical school in Brightford, the average number of teachers per culinarian school in Evervale City, the average number of teachers per elementary school in Evervale City, and the total number of teachers from all schools in Brightford. The number of elementary school in Brightford equals 1. The number of private middle school in Glenfield City equals the sum of the average number of teachers per regional medical school in Brightford and the average number of teachers per culinarian school in Evervale City. The number of culinarian school in Westhaven City equals the sum of the total number of teachers from all schools in Brightford, the average number of teachers per elementary school in Brightford, and the number of elementary school in Evervale City. The average number of teachers per culinarian school in Evervale City equals 3. The average number of teachers per regional medical school in Brightford equals 3. The average number of teachers per private middle school in Glenfield City equals 1. The average number of teachers per elementary school in Evervale City equals the average number of teachers per culinarian school in Evervale City. The average number of teachers per private middle school in Brightford equals 3. The number of culinarian school in Brightford equals 4. The number of regional medical school in Westhaven City equals 2. The number of regional medical school in Brightford equals 4. The number of elementary school in Westhaven City equals 4. The number of culinarian school in Evervale City equals 2 times the sum of the total number of schools in Westhaven City, the total number of teachers from all schools in Brightford, and the number of regional medical school in Brightford. The number of public highschool in Hawkesbury equals the sum of the average number of teachers per regional medical school in Westhaven City, the average number of teachers per regional medical school in Brightford, the average number of teachers per private middle school in Brightford, and the average number of teachers per regional medical school in Brightford. The average number of teachers per culinarian school in Brightford equals 4. The average number of teachers per elementary school in Brightford equals 2. The number of private middle school in Brightford equals 1. | What is the average number of teachers per elementary school in Evervale City? | Define average number of teachers per culinarian school in Evervale City as A; so A = 3. Define average number of teachers per elementary school in Evervale City as e; so e = A = 3. Answer: 3. | 2 | 22 | teachers_in_school | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of teachers per regional medical school in Westhaven City equals 3 times the number of elementary school in Brightford. The number of elementary school in Evervale City equals the sum of the average number of teachers per elementary school in Evervale City, the average number of teachers per regional medical school in Brightford, the average number of teachers per private middle school in Brightford, and the total number of teachers from all schools in Brightford. The average number of teachers per public highschool in Hawkesbury equals 1 plus the average number of teachers per private middle school in Glenfield City. The average number of teachers per elementary school in Westhaven City equals the total number of schools in Brightford. The average number of teachers per culinarian school in Westhaven City equals the sum of the number of regional medical school in Brightford, the average number of teachers per culinarian school in Evervale City, the average number of teachers per elementary school in Evervale City, and the total number of teachers from all schools in Brightford. The number of elementary school in Brightford equals 1. The number of private middle school in Glenfield City equals the sum of the average number of teachers per regional medical school in Brightford and the average number of teachers per culinarian school in Evervale City. The number of culinarian school in Westhaven City equals the sum of the total number of teachers from all schools in Brightford, the average number of teachers per elementary school in Brightford, and the number of elementary school in Evervale City. The average number of teachers per culinarian school in Evervale City equals 3. The average number of teachers per regional medical school in Brightford equals 3. The average number of teachers per private middle school in Glenfield City equals 1. The average number of teachers per elementary school in Evervale City equals the average number of teachers per culinarian school in Evervale City. The average number of teachers per private middle school in Brightford equals 3. The number of culinarian school in Brightford equals 4. The number of regional medical school in Westhaven City equals 2. The number of regional medical school in Brightford equals 4. The number of elementary school in Westhaven City equals 4. The number of culinarian school in Evervale City equals 2 times the sum of the total number of schools in Westhaven City, the total number of teachers from all schools in Brightford, and the number of regional medical school in Brightford. The number of public highschool in Hawkesbury equals the sum of the average number of teachers per regional medical school in Westhaven City, the average number of teachers per regional medical school in Brightford, the average number of teachers per private middle school in Brightford, and the average number of teachers per regional medical school in Brightford. The average number of teachers per culinarian school in Brightford equals 4. The average number of teachers per elementary school in Brightford equals 2. The number of private middle school in Brightford equals 1. Question: What is the average number of teachers per elementary school in Evervale City? Solution: "
}
] |
The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the sum of the average number of nominations per calm road movie in Golden Banana Movie Festival, the number of calm road movie in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, and the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 3 plus the number of intense detective thriller in Northwood Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per calm road movie in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the number of calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1. | How many futuristic sci-fi movie does Northwood Movie Festival have? | Define average number of nominations per calm road movie in Northwood Movie Festival as c; so c = 3. Define futuristic sci-fi movie in Northwood Movie Festival as S; so S = c = 3. Answer: 3. | 2 | 12 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the sum of the average number of nominations per calm road movie in Golden Banana Movie Festival, the number of calm road movie in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, and the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 3 plus the number of intense detective thriller in Northwood Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per calm road movie in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the number of calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1. Question: How many futuristic sci-fi movie does Northwood Movie Festival have? Solution: "
}
] |
The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the number of futuristic sci-fi movie in Golden Banana Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, and the average number of nominations per solemn period drama in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals 4. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 1. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Verdi Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 1 plus the number of solemn period drama in Golden Banana Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals 3 times the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per intense detective thriller in West Sahara Movie Festival, and the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals the sum of the number of futuristic sci-fi movie in West Sahara Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per solemn period drama in Verdi Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals the sum of the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival and the average number of nominations per solemn period drama in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2 times the average number of nominations per intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 1. The number of solemn period drama in Northwood Movie Festival equals the difference between the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival and the total number of movie nominations in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. | What is the average number of nominations per solemn period drama in Golden Banana Movie Festival? | Define average number of nominations per futuristic sci-fi movie in Verdi Movie Festival as K; so K = 4. Define average number of nominations per solemn period drama in Golden Banana Movie Festival as i; so i = K = 4. Answer: 4. | 2 | 3 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the number of futuristic sci-fi movie in Golden Banana Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, and the average number of nominations per solemn period drama in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals 4. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 1. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Verdi Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 1 plus the number of solemn period drama in Golden Banana Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals 3 times the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per intense detective thriller in West Sahara Movie Festival, and the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals the sum of the number of futuristic sci-fi movie in West Sahara Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per solemn period drama in Verdi Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals the sum of the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival and the average number of nominations per solemn period drama in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2 times the average number of nominations per intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 1. The number of solemn period drama in Northwood Movie Festival equals the difference between the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival and the total number of movie nominations in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. Question: What is the average number of nominations per solemn period drama in Golden Banana Movie Festival? Solution: "
}
] |
The number of futuristic sci-fi movie in West Sahara Movie Festival equals the sum of the average number of nominations per calm road movie in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals the sum of the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival, the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival, and the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals the average number of nominations per intense detective thriller in Northwood Movie Festival. The average number of nominations per calm road movie in Verdi Movie Festival equals 4. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3. The number of futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per intense detective thriller in West Sahara Movie Festival. The average number of nominations per calm road movie in West Sahara Movie Festival equals the difference between the number of calm road movie in Verdi Movie Festival and the average number of nominations per calm road movie in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals the sum of the number of calm road movie in Verdi Movie Festival, the average number of nominations per calm road movie in Northwood Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in West Sahara Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals the difference between the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, the total number of movie nominations in Northwood Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the difference between the average number of nominations per calm road movie in Golden Banana Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the difference between the number of calm road movie in Verdi Movie Festival and the total number of movie nominations in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 1. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals 1. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals the number of calm road movie in Verdi Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 1. | What is the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival? | Define average number of nominations per intense detective thriller in Verdi Movie Festival as Z; so Z = 4. Define average number of nominations per futuristic sci-fi movie in Verdi Movie Festival as O; so O = Z = 4. Answer: 4. | 2 | 10 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of futuristic sci-fi movie in West Sahara Movie Festival equals the sum of the average number of nominations per calm road movie in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals the sum of the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival, the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival, and the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals the average number of nominations per intense detective thriller in Northwood Movie Festival. The average number of nominations per calm road movie in Verdi Movie Festival equals 4. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3. The number of futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per intense detective thriller in West Sahara Movie Festival. The average number of nominations per calm road movie in West Sahara Movie Festival equals the difference between the number of calm road movie in Verdi Movie Festival and the average number of nominations per calm road movie in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals the sum of the number of calm road movie in Verdi Movie Festival, the average number of nominations per calm road movie in Northwood Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in West Sahara Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals the difference between the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, the total number of movie nominations in Northwood Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the difference between the average number of nominations per calm road movie in Golden Banana Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the difference between the number of calm road movie in Verdi Movie Festival and the total number of movie nominations in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 1. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals 1. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals the number of calm road movie in Verdi Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 1. Question: What is the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival? Solution: "
}
] |
The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the average number of nominations per intense detective thriller in Festival de Clairmont. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the sum of the average number of nominations per upbeat metropolis comedy in Festival de Clairmont and the average number of nominations per intense detective thriller in Festival de Clairmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 3. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals 3. The number of upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per upbeat metropolis comedy in Festival de Clairmont and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Saint-Rivage equals 4 times the difference between the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals the sum of the average number of nominations per intense detective thriller in Festival de Clairmont and the average number of nominations per upbeat metropolis comedy in Festival de Clairmont. | What is the average number of nominations per upbeat metropolis comedy in Festival de Clairmont? | Define average number of nominations per intense detective thriller in Festival de Clairmont as X; so X = 3. Define average number of nominations per upbeat metropolis comedy in Festival de Clairmont as V; so V = X = 3. Answer: 3. | 2 | 7 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the average number of nominations per intense detective thriller in Festival de Clairmont. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the sum of the average number of nominations per upbeat metropolis comedy in Festival de Clairmont and the average number of nominations per intense detective thriller in Festival de Clairmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 3. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals 3. The number of upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per upbeat metropolis comedy in Festival de Clairmont and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Saint-Rivage equals 4 times the difference between the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals the sum of the average number of nominations per intense detective thriller in Festival de Clairmont and the average number of nominations per upbeat metropolis comedy in Festival de Clairmont. Question: What is the average number of nominations per upbeat metropolis comedy in Festival de Clairmont? Solution: "
}
] |
The number of solemn period drama in Taylor Movie Festival equals 1 plus the sum of the average number of nominations per intense detective thriller in Verdi Movie Festival and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2. The average number of nominations per solemn period drama in Taylor Movie Festival equals 3 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Taylor Movie Festival equals 2. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 2 plus the sum of the average number of nominations per solemn period drama in Golden Banana Movie Festival, the total number of movies in Verdi Movie Festival, and the average number of nominations per solemn period drama in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the sum of the number of futuristic sci-fi movie in Verdi Movie Festival, the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2 plus the sum of the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival, the number of futuristic sci-fi movie in Taylor Movie Festival, and the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 1. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals the average number of nominations per solemn period drama in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival and the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 4 times the sum of the number of futuristic sci-fi movie in Taylor Movie Festival, the average number of nominations per solemn period drama in Verdi Movie Festival, and the average number of nominations per solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 2 times the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. | What is the average number of nominations per solemn period drama in Verdi Movie Festival? | Define average number of nominations per solemn period drama in Golden Banana Movie Festival as q; so q = 2. Define average number of nominations per solemn period drama in Verdi Movie Festival as l; so l = q = 2. Answer: 2. | 2 | 22 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of solemn period drama in Taylor Movie Festival equals 1 plus the sum of the average number of nominations per intense detective thriller in Verdi Movie Festival and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2. The average number of nominations per solemn period drama in Taylor Movie Festival equals 3 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Taylor Movie Festival equals 2. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 2 plus the sum of the average number of nominations per solemn period drama in Golden Banana Movie Festival, the total number of movies in Verdi Movie Festival, and the average number of nominations per solemn period drama in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the sum of the number of futuristic sci-fi movie in Verdi Movie Festival, the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2 plus the sum of the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival, the number of futuristic sci-fi movie in Taylor Movie Festival, and the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 1. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals the average number of nominations per solemn period drama in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival and the average number of nominations per futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 4 times the sum of the number of futuristic sci-fi movie in Taylor Movie Festival, the average number of nominations per solemn period drama in Verdi Movie Festival, and the average number of nominations per solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 2 times the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. Question: What is the average number of nominations per solemn period drama in Verdi Movie Festival? Solution: "
}
] |
The number of solemn period drama in Golden Banana Movie Festival equals the average number of nominations per solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The average number of nominations per calm road movie in Northwood Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of solemn period drama in Northwood Movie Festival equals the difference between the average number of nominations per solemn period drama in Golden Banana Movie Festival and the total number of movies in Northwood Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2 times the number of calm road movie in Northwood Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 1 plus the difference between the number of solemn period drama in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. | What is the average number of nominations per calm road movie in Northwood Movie Festival? | Define calm road movie in Golden Banana Movie Festival as r; so r = 3. Define average number of nominations per calm road movie in Northwood Movie Festival as b; so b = r = 3. Answer: 3. | 2 | 7 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of solemn period drama in Golden Banana Movie Festival equals the average number of nominations per solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The average number of nominations per calm road movie in Northwood Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of solemn period drama in Northwood Movie Festival equals the difference between the average number of nominations per solemn period drama in Golden Banana Movie Festival and the total number of movies in Northwood Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 2 times the number of calm road movie in Northwood Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 1 plus the difference between the number of solemn period drama in Golden Banana Movie Festival and the average number of nominations per calm road movie in Northwood Movie Festival. Question: What is the average number of nominations per calm road movie in Northwood Movie Festival? Solution: "
}
] |
The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals the difference between the average number of nominations per calm road movie in Golden Banana Movie Festival and the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals 3 plus the difference between the number of upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 1 plus the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2 times the total number of movies in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Taylor Movie Festival equals the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 3 times the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. | What is the total number of movies in West Sahara Movie Festival? | Define solemn period drama in West Sahara Movie Festival as i; so i = 2. Define total number of movies in West Sahara Movie Festival as r; so r = i = 2. Answer: 2. | 2 | 2 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals the difference between the average number of nominations per calm road movie in Golden Banana Movie Festival and the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals 3 plus the difference between the number of upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 1 plus the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2 times the total number of movies in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Taylor Movie Festival equals the average number of nominations per calm road movie in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 3 times the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. Question: What is the total number of movies in West Sahara Movie Festival? Solution: "
}
] |
The average number of nominations per solemn period drama in Taylor Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 1. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals 1 plus the sum of the average number of nominations per solemn period drama in Verdi Movie Festival, the average number of nominations per solemn period drama in Taylor Movie Festival, and the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3 plus the difference between the average number of nominations per intense detective thriller in Verdi Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the difference between the average number of nominations per intense detective thriller in Taylor Movie Festival and the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 1 plus the sum of the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival, the average number of nominations per intense detective thriller in Verdi Movie Festival, and the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 2 plus the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. | What is the average number of nominations per solemn period drama in Taylor Movie Festival? | Define average number of nominations per intense detective thriller in Golden Banana Movie Festival as j; so j = 1. Define average number of nominations per solemn period drama in Taylor Movie Festival as N; so N = j = 1. Answer: 1. | 2 | 1 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per solemn period drama in Taylor Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 1. The average number of nominations per intense detective thriller in Verdi Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals 1 plus the sum of the average number of nominations per solemn period drama in Verdi Movie Festival, the average number of nominations per solemn period drama in Taylor Movie Festival, and the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3 plus the difference between the average number of nominations per intense detective thriller in Verdi Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the difference between the average number of nominations per intense detective thriller in Taylor Movie Festival and the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 1 plus the sum of the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival, the average number of nominations per intense detective thriller in Verdi Movie Festival, and the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 2 plus the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. Question: What is the average number of nominations per solemn period drama in Taylor Movie Festival? Solution: "
}
] |
The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the average number of nominations per futuristic sci-fi movie in Festival de Clairmont. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The average number of nominations per calm road movie in Festival de Clairmont equals 4. The average number of nominations per intense detective thriller in Rêves de Belleville equals 2 times the sum of the number of upbeat metropolis comedy in Rêves de Belleville, the number of calm road movie in Festival de Saint-Rivage, and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3 times the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1 plus the sum of the average number of nominations per calm road movie in Festival de Saint-Rivage and the average number of nominations per intense detective thriller in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Rêves de Belleville equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals the sum of the average number of nominations per calm road movie in Festival de Saint-Rivage and the number of calm road movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Clairmont equals 1. The number of intense detective thriller in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Festival de Clairmont equals 3. The number of intense detective thriller in Rêves de Belleville equals the average number of nominations per upbeat metropolis comedy in Rêves de Belleville. The number of calm road movie in Festival de Saint-Rivage equals 3. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage equals 3 times the average number of nominations per intense detective thriller in Rêves de Belleville. The number of calm road movie in Festival de Clairmont equals the average number of nominations per futuristic sci-fi movie in Festival de Clairmont. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals 2. | What is the average number of nominations per intense detective thriller in Festival de Saint-Rivage? | Define average number of nominations per futuristic sci-fi movie in Festival de Clairmont as R; so R = 3. Define average number of nominations per intense detective thriller in Festival de Saint-Rivage as I; so I = R = 3. Answer: 3. | 2 | 18 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the average number of nominations per futuristic sci-fi movie in Festival de Clairmont. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The average number of nominations per calm road movie in Festival de Clairmont equals 4. The average number of nominations per intense detective thriller in Rêves de Belleville equals 2 times the sum of the number of upbeat metropolis comedy in Rêves de Belleville, the number of calm road movie in Festival de Saint-Rivage, and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3 times the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1 plus the sum of the average number of nominations per calm road movie in Festival de Saint-Rivage and the average number of nominations per intense detective thriller in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Rêves de Belleville equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals the sum of the average number of nominations per calm road movie in Festival de Saint-Rivage and the number of calm road movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Clairmont equals 1. The number of intense detective thriller in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Festival de Clairmont equals 3. The number of intense detective thriller in Rêves de Belleville equals the average number of nominations per upbeat metropolis comedy in Rêves de Belleville. The number of calm road movie in Festival de Saint-Rivage equals 3. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage equals 3 times the average number of nominations per intense detective thriller in Rêves de Belleville. The number of calm road movie in Festival de Clairmont equals the average number of nominations per futuristic sci-fi movie in Festival de Clairmont. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals 2. Question: What is the average number of nominations per intense detective thriller in Festival de Saint-Rivage? Solution: "
}
] |
The average number of nominations per calm road movie in Taylor Movie Festival equals the number of calm road movie in Taylor Movie Festival. The average number of nominations per calm road movie in West Sahara Movie Festival equals 1. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the average number of nominations per calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2 plus the difference between the number of intense detective thriller in Taylor Movie Festival and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 1. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the number of intense detective thriller in Taylor Movie Festival, the number of calm road movie in West Sahara Movie Festival, and the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 2. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals 4. The average number of nominations per calm road movie in Northwood Movie Festival equals the difference between the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival and the total number of movies in Northwood Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the number of intense detective thriller in Taylor Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 3. The number of intense detective thriller in West Sahara Movie Festival equals the difference between the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the difference between the number of futuristic sci-fi movie in West Sahara Movie Festival and the total number of movies in Taylor Movie Festival. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 2. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 2. | What is the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival? | Define average number of nominations per intense detective thriller in Taylor Movie Festival as w; so w = 2. Define average number of nominations per futuristic sci-fi movie in Northwood Movie Festival as Q; so Q = w = 2. Answer: 2. | 2 | 5 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per calm road movie in Taylor Movie Festival equals the number of calm road movie in Taylor Movie Festival. The average number of nominations per calm road movie in West Sahara Movie Festival equals 1. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the average number of nominations per calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2 plus the difference between the number of intense detective thriller in Taylor Movie Festival and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 1. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the number of intense detective thriller in Taylor Movie Festival, the number of calm road movie in West Sahara Movie Festival, and the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 2. The average number of nominations per intense detective thriller in West Sahara Movie Festival equals 4. The average number of nominations per calm road movie in Northwood Movie Festival equals the difference between the average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival and the total number of movies in Northwood Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the number of intense detective thriller in Taylor Movie Festival. The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 3. The number of intense detective thriller in West Sahara Movie Festival equals the difference between the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival and the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the difference between the number of futuristic sci-fi movie in West Sahara Movie Festival and the total number of movies in Taylor Movie Festival. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 2. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 2. Question: What is the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival? Solution: "
}
] |
The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 plus the sum of the total number of movie nominations in Taylor Movie Festival, the average number of nominations per calm road movie in Northwood Movie Festival, and the number of solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 2 times the sum of the number of solemn period drama in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, and the average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the average number of nominations per solemn period drama in Taylor Movie Festival, the average number of nominations per solemn period drama in Taylor Movie Festival, and the total number of movie nominations in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals the average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The average number of nominations per calm road movie in Verdi Movie Festival equals the average number of nominations per solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 3. The average number of nominations per solemn period drama in Taylor Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals 3. The number of calm road movie in Taylor Movie Festival equals 2. The number of calm road movie in Verdi Movie Festival equals 4 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per solemn period drama in Taylor Movie Festival. The average number of nominations per solemn period drama in Verdi Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per calm road movie in Taylor Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals 3. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 1 plus the sum of the average number of nominations per calm road movie in Northwood Movie Festival, the number of solemn period drama in Northwood Movie Festival, and the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of calm road movie in Taylor Movie Festival. | What is the average number of nominations per calm road movie in Verdi Movie Festival? | Define average number of nominations per solemn period drama in Taylor Movie Festival as A; so A = 3. Define average number of nominations per calm road movie in Verdi Movie Festival as i; so i = A = 3. Answer: 3. | 2 | 16 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 plus the sum of the total number of movie nominations in Taylor Movie Festival, the average number of nominations per calm road movie in Northwood Movie Festival, and the number of solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 2 times the sum of the number of solemn period drama in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, and the average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the average number of nominations per solemn period drama in Taylor Movie Festival, the average number of nominations per solemn period drama in Taylor Movie Festival, and the total number of movie nominations in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals the average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The average number of nominations per calm road movie in Verdi Movie Festival equals the average number of nominations per solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 3. The average number of nominations per solemn period drama in Taylor Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals 3. The number of calm road movie in Taylor Movie Festival equals 2. The number of calm road movie in Verdi Movie Festival equals 4 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per solemn period drama in Taylor Movie Festival. The average number of nominations per solemn period drama in Verdi Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per calm road movie in Taylor Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals 3. The average number of nominations per intense detective thriller in Taylor Movie Festival equals 4. The average number of nominations per solemn period drama in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 1 plus the sum of the average number of nominations per calm road movie in Northwood Movie Festival, the number of solemn period drama in Northwood Movie Festival, and the average number of nominations per futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of calm road movie in Taylor Movie Festival. Question: What is the average number of nominations per calm road movie in Verdi Movie Festival? Solution: "
}
] |
The average number of nominations per calm road movie in Festival Lumière de Valmont equals the sum of the number of solemn period drama in Festival de Saint-Rivage, the number of solemn period drama in Festival Lumière de Valmont, and the average number of nominations per solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival de Saint-Rivage. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 3. The average number of nominations per calm road movie in Festival de Clairmont equals the average number of nominations per solemn period drama in Festival de Clairmont. The average number of nominations per solemn period drama in Festival Lumière de Valmont equals 4. The average number of nominations per upbeat metropolis comedy in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival Lumière de Valmont equals 2. The number of calm road movie in Festival de Clairmont equals 1. The number of solemn period drama in Festival de Saint-Rivage equals 3 plus the average number of nominations per solemn period drama in Festival de Clairmont. The average number of nominations per solemn period drama in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the difference between the average number of nominations per solemn period drama in Festival de Saint-Rivage and the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per calm road movie in Festival de Clairmont and the number of calm road movie in Festival de Clairmont. The average number of nominations per calm road movie in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in Festival de Clairmont equals the average number of nominations per upbeat metropolis comedy in Festival de Clairmont. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the difference between the average number of nominations per solemn period drama in Festival de Clairmont and the number of upbeat metropolis comedy in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals the sum of the average number of nominations per solemn period drama in Festival de Saint-Rivage, the average number of nominations per solemn period drama in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 4 plus the average number of nominations per solemn period drama in Festival de Clairmont. | What is the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage? | Define average number of nominations per solemn period drama in Festival de Saint-Rivage as W; so W = 3. Define average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage as h; so h = W = 3. Answer: 3. | 2 | 20 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per calm road movie in Festival Lumière de Valmont equals the sum of the number of solemn period drama in Festival de Saint-Rivage, the number of solemn period drama in Festival Lumière de Valmont, and the average number of nominations per solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival de Saint-Rivage. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 3. The average number of nominations per calm road movie in Festival de Clairmont equals the average number of nominations per solemn period drama in Festival de Clairmont. The average number of nominations per solemn period drama in Festival Lumière de Valmont equals 4. The average number of nominations per upbeat metropolis comedy in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival Lumière de Valmont equals 2. The number of calm road movie in Festival de Clairmont equals 1. The number of solemn period drama in Festival de Saint-Rivage equals 3 plus the average number of nominations per solemn period drama in Festival de Clairmont. The average number of nominations per solemn period drama in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the difference between the average number of nominations per solemn period drama in Festival de Saint-Rivage and the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per calm road movie in Festival de Clairmont and the number of calm road movie in Festival de Clairmont. The average number of nominations per calm road movie in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in Festival de Clairmont equals the average number of nominations per upbeat metropolis comedy in Festival de Clairmont. The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals the average number of nominations per solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the difference between the average number of nominations per solemn period drama in Festival de Clairmont and the number of upbeat metropolis comedy in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals the sum of the average number of nominations per solemn period drama in Festival de Saint-Rivage, the average number of nominations per solemn period drama in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 4 plus the average number of nominations per solemn period drama in Festival de Clairmont. Question: What is the average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage? Solution: "
}
] |
The average number of nominations per calm road movie in West Sahara Movie Festival equals the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals the sum of the number of upbeat metropolis comedy in Golden Banana Movie Festival, the number of solemn period drama in West Sahara Movie Festival, the average number of nominations per calm road movie in Verdi Movie Festival, and the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the sum of the average number of nominations per solemn period drama in Verdi Movie Festival, the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival, and the average number of nominations per solemn period drama in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 3 plus the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 plus the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per calm road movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival. | What is the average number of nominations per solemn period drama in Verdi Movie Festival? | Define average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival as G; so G = 4. Define average number of nominations per solemn period drama in Verdi Movie Festival as W; so W = G = 4. Answer: 4. | 2 | 13 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per calm road movie in West Sahara Movie Festival equals the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival. The average number of nominations per solemn period drama in West Sahara Movie Festival equals the sum of the number of upbeat metropolis comedy in Golden Banana Movie Festival, the number of solemn period drama in West Sahara Movie Festival, the average number of nominations per calm road movie in Verdi Movie Festival, and the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the sum of the average number of nominations per solemn period drama in Verdi Movie Festival, the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival, and the average number of nominations per solemn period drama in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 3 plus the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 plus the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per calm road movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival equals 4. The average number of nominations per solemn period drama in Verdi Movie Festival equals the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the average number of nominations per upbeat metropolis comedy in West Sahara Movie Festival. Question: What is the average number of nominations per solemn period drama in Verdi Movie Festival? Solution: "
}
] |
The average number of nominations per intense detective thriller in Northwood Movie Festival equals 3 times the number of solemn period drama in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the sum of the average number of nominations per intense detective thriller in Taylor Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival, and the total number of movie nominations in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 1 plus the average number of nominations per solemn period drama in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Golden Banana Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals the sum of the number of intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival, the average number of nominations per intense detective thriller in Taylor Movie Festival, and the total number of movie nominations in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 1. The number of solemn period drama in West Sahara Movie Festival equals the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival and the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals the sum of the total number of movie nominations in Golden Banana Movie Festival, the average number of nominations per solemn period drama in Golden Banana Movie Festival, and the number of intense detective thriller in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals 3. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 3. The average number of nominations per solemn period drama in West Sahara Movie Festival equals 1. The average number of nominations per intense detective thriller in Taylor Movie Festival equals the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of calm road movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the sum of the total number of movies in Northwood Movie Festival, the total number of movie nominations in Golden Banana Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the average number of nominations per intense detective thriller in Northwood Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 1. | What is the average number of nominations per intense detective thriller in Taylor Movie Festival? | Define average number of nominations per upbeat metropolis comedy in Taylor Movie Festival as A; so A = 3. Define average number of nominations per intense detective thriller in Taylor Movie Festival as e; so e = A = 3. Answer: 3. | 2 | 7 | movie_festival_awards | normalforward | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated."
},
{
"role": "user",
"content": "Problem: The average number of nominations per intense detective thriller in Northwood Movie Festival equals 3 times the number of solemn period drama in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the sum of the average number of nominations per intense detective thriller in Taylor Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival, and the total number of movie nominations in Golden Banana Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 1 plus the average number of nominations per solemn period drama in West Sahara Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Golden Banana Movie Festival. The average number of nominations per calm road movie in Northwood Movie Festival equals the sum of the number of intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival, the average number of nominations per intense detective thriller in Taylor Movie Festival, and the total number of movie nominations in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 1. The number of solemn period drama in West Sahara Movie Festival equals the sum of the average number of nominations per intense detective thriller in Golden Banana Movie Festival and the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals the sum of the total number of movie nominations in Golden Banana Movie Festival, the average number of nominations per solemn period drama in Golden Banana Movie Festival, and the number of intense detective thriller in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Taylor Movie Festival equals 3. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 3. The average number of nominations per solemn period drama in West Sahara Movie Festival equals 1. The average number of nominations per intense detective thriller in Taylor Movie Festival equals the average number of nominations per upbeat metropolis comedy in Taylor Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of calm road movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the sum of the total number of movies in Northwood Movie Festival, the total number of movie nominations in Golden Banana Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the average number of nominations per intense detective thriller in Northwood Movie Festival, the average number of nominations per intense detective thriller in Golden Banana Movie Festival, the average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival, and the average number of nominations per intense detective thriller in Golden Banana Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 4. The average number of nominations per solemn period drama in Golden Banana Movie Festival equals 2. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 1. Question: What is the average number of nominations per intense detective thriller in Taylor Movie Festival? Solution: "
}
] |
The average number of newborn children per adult fox in Hamilton Farm equals 2. The number of adult racoon in South Zoo equals 4 plus the number of adult bear in Hamilton Farm. The number of adult bear in Bundle Ranch equals the difference between the average number of newborn children per adult racoon in South Zoo and the average number of newborn children per adult bear in Hamilton Farm. The number of adult racoon in Bundle Ranch equals 3. The average number of newborn children per adult bear in Hamilton Farm equals 4. The average number of newborn children per adult racoon in South Zoo is greater than 0. The average number of newborn children per adult bear in Hamilton Farm equals the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult bear in Bundle Ranch equals the sum of the number of adult fox in Hamilton Farm, the total number of adult animals in Bundle Ranch, the number of adult bear in Hamilton Farm, and the total number of adult animals in South Zoo. The average number of newborn children per adult racoon in Bundle Ranch equals 2 times the number of adult racoon in South Zoo. The number of adult fox in Hamilton Farm equals 1 plus the number of adult racoon in Bundle Ranch. The number of adult bear in Hamilton Farm equals 4. | What is the average number of newborn children per adult racoon in South Zoo? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult racoon in South Zoo as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult bear in Hamilton Farm as w; so w = x = x. We know w = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 16 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult fox in Hamilton Farm equals 2. The number of adult racoon in South Zoo equals 4 plus the number of adult bear in Hamilton Farm. The number of adult bear in Bundle Ranch equals the difference between the average number of newborn children per adult racoon in South Zoo and the average number of newborn children per adult bear in Hamilton Farm. The number of adult racoon in Bundle Ranch equals 3. The average number of newborn children per adult bear in Hamilton Farm equals 4. The average number of newborn children per adult racoon in South Zoo is greater than 0. The average number of newborn children per adult bear in Hamilton Farm equals the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult bear in Bundle Ranch equals the sum of the number of adult fox in Hamilton Farm, the total number of adult animals in Bundle Ranch, the number of adult bear in Hamilton Farm, and the total number of adult animals in South Zoo. The average number of newborn children per adult racoon in Bundle Ranch equals 2 times the number of adult racoon in South Zoo. The number of adult fox in Hamilton Farm equals 1 plus the number of adult racoon in Bundle Ranch. The number of adult bear in Hamilton Farm equals 4. Question: What is the average number of newborn children per adult racoon in South Zoo? Solution: "
}
] |
The average number of newborn children per adult owl in Pine Ridge equals 2. The number of adult eagle in Pine Ridge equals 4. The average number of newborn children per adult eagle in Pine Ridge is greater than 0. The number of adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Pine Ridge equals the average number of newborn children per adult eagle in Pine Ridge. | What is the average number of newborn children per adult eagle in Pine Ridge? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult eagle in Pine Ridge as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult owl in Pine Ridge as N; so N = x = x. We know N = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 10 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult owl in Pine Ridge equals 2. The number of adult eagle in Pine Ridge equals 4. The average number of newborn children per adult eagle in Pine Ridge is greater than 0. The number of adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Pine Ridge equals the average number of newborn children per adult eagle in Pine Ridge. Question: What is the average number of newborn children per adult eagle in Pine Ridge? Solution: "
}
] |
The number of adult wolf in Jefferson Circus equals the average number of newborn children per adult bear in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 3. The number of adult wolf in Hamilton Farm equals the average number of newborn children per adult bear in Jefferson Circus. The number of adult bear in Jefferson Circus equals 2 plus the number of adult wolf in Jefferson Circus. The average number of newborn children per adult racoon in Hamilton Farm equals 2. The average number of newborn children per adult racoon in Jefferson Circus equals the difference between the number of adult wolf in Jefferson Circus and the average number of newborn children per adult bear in Jefferson Circus. The average number of newborn children per adult wolf in Hamilton Farm is greater than 0. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the average number of newborn children per adult wolf in Hamilton Farm, the average number of newborn children per adult bear in Jefferson Circus, the number of adult wolf in Hamilton Farm, and the number of adult wolf in Mayer Aquarium. The average number of newborn children per adult racoon in Hamilton Farm equals the average number of newborn children per adult wolf in Hamilton Farm. The average number of newborn children per adult bear in Jefferson Circus equals 2. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the average number of newborn children per adult wolf in Hamilton Farm and the number of adult wolf in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals the sum of the average number of newborn children per adult bear in Jefferson Circus, the number of adult wolf in Jefferson Circus, and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult wolf in Mayer Aquarium equals 1 plus the average number of newborn children per adult bear in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals 4. | What is the average number of newborn children per adult wolf in Hamilton Farm? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult wolf in Hamilton Farm as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult racoon in Hamilton Farm as B; so B = x = x. We know B = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 17 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult wolf in Jefferson Circus equals the average number of newborn children per adult bear in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 3. The number of adult wolf in Hamilton Farm equals the average number of newborn children per adult bear in Jefferson Circus. The number of adult bear in Jefferson Circus equals 2 plus the number of adult wolf in Jefferson Circus. The average number of newborn children per adult racoon in Hamilton Farm equals 2. The average number of newborn children per adult racoon in Jefferson Circus equals the difference between the number of adult wolf in Jefferson Circus and the average number of newborn children per adult bear in Jefferson Circus. The average number of newborn children per adult wolf in Hamilton Farm is greater than 0. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the average number of newborn children per adult wolf in Hamilton Farm, the average number of newborn children per adult bear in Jefferson Circus, the number of adult wolf in Hamilton Farm, and the number of adult wolf in Mayer Aquarium. The average number of newborn children per adult racoon in Hamilton Farm equals the average number of newborn children per adult wolf in Hamilton Farm. The average number of newborn children per adult bear in Jefferson Circus equals 2. The average number of newborn children per adult wolf in Jefferson Circus equals the difference between the average number of newborn children per adult wolf in Hamilton Farm and the number of adult wolf in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals the sum of the average number of newborn children per adult bear in Jefferson Circus, the number of adult wolf in Jefferson Circus, and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult wolf in Mayer Aquarium equals 1 plus the average number of newborn children per adult bear in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals 4. Question: What is the average number of newborn children per adult wolf in Hamilton Farm? Solution: "
}
] |
The average number of newborn children per adult parrot in Maple Creek equals the total number of adult animals in Pine Ridge. The total number of adult animals in Pine Ridge equals 3. The average number of newborn children per adult owl in Pine Ridge equals 3. The number of adult parrot in Beverly Forest equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals the difference between the number of adult owl in Pine Ridge and the total number of adult animals in Pine Ridge. The average number of newborn children per adult parrot in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Maple Creek equals the total number of adult animals in Pine Ridge. The number of adult parrot in Maple Creek equals 4 plus the average number of newborn children per adult parrot in Beverly Forest. The number of adult owl in Pine Ridge exists, and its number is greater than 0. | How many adult owl does Pine Ridge have? | The question is difficult, so we use equations to solve it. Define adult owl in Pine Ridge as x; we don't know its value yet but will find it out later. Define total number of adult animals in Pine Ridge as p; so p = x = x. We know p = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 7 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult parrot in Maple Creek equals the total number of adult animals in Pine Ridge. The total number of adult animals in Pine Ridge equals 3. The average number of newborn children per adult owl in Pine Ridge equals 3. The number of adult parrot in Beverly Forest equals 1 plus the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals the difference between the number of adult owl in Pine Ridge and the total number of adult animals in Pine Ridge. The average number of newborn children per adult parrot in Beverly Forest equals 2. The average number of newborn children per adult blue jay in Maple Creek equals the total number of adult animals in Pine Ridge. The number of adult parrot in Maple Creek equals 4 plus the average number of newborn children per adult parrot in Beverly Forest. The number of adult owl in Pine Ridge exists, and its number is greater than 0. Question: How many adult owl does Pine Ridge have? Solution: "
}
] |
The number of adult racoon in Mayer Aquarium equals 1. The number of adult deer in Mayer Aquarium equals 4 plus the number of adult deer in South Zoo. The number of adult racoon in Bundle Ranch equals 1. The number of adult fox in South Zoo equals 1. The number of adult deer in South Zoo equals 4. The number of adult racoon in South Zoo equals the number of adult deer in Mayer Aquarium. The average number of newborn children per adult racoon in South Zoo is greater than 0. The average number of newborn children per adult fox in South Zoo equals the difference between the number of adult deer in South Zoo and the number of adult deer in Mayer Aquarium. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult racoon in Bundle Ranch equals 1. The average number of newborn children per adult deer in South Zoo equals 3. The average number of newborn children per adult racoon in Mayer Aquarium equals the sum of the average number of newborn children per adult racoon in Bundle Ranch, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult deer in Mayer Aquarium equals 3 times the total number of adult animals in South Zoo. | What is the average number of newborn children per adult racoon in South Zoo? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult racoon in South Zoo as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult deer in South Zoo as P; so P = x = x. We know P = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 17 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult racoon in Mayer Aquarium equals 1. The number of adult deer in Mayer Aquarium equals 4 plus the number of adult deer in South Zoo. The number of adult racoon in Bundle Ranch equals 1. The number of adult fox in South Zoo equals 1. The number of adult deer in South Zoo equals 4. The number of adult racoon in South Zoo equals the number of adult deer in Mayer Aquarium. The average number of newborn children per adult racoon in South Zoo is greater than 0. The average number of newborn children per adult fox in South Zoo equals the difference between the number of adult deer in South Zoo and the number of adult deer in Mayer Aquarium. The average number of newborn children per adult deer in South Zoo equals the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult racoon in Bundle Ranch equals 1. The average number of newborn children per adult deer in South Zoo equals 3. The average number of newborn children per adult racoon in Mayer Aquarium equals the sum of the average number of newborn children per adult racoon in Bundle Ranch, the average number of newborn children per adult fox in South Zoo, and the average number of newborn children per adult racoon in South Zoo. The average number of newborn children per adult deer in Mayer Aquarium equals 3 times the total number of adult animals in South Zoo. Question: What is the average number of newborn children per adult racoon in South Zoo? Solution: "
}
] |
The number of adult owl in Pine Ridge equals 3 plus the number of adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the number of adult parrot in Pine Ridge. The average number of newborn children per adult parrot in Pine Ridge equals the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals 1. The number of adult parrot in Cedar Valley equals 1. The number of adult parrot in Pine Ridge equals the number of adult parrot in Cedar Valley. The average number of newborn children per adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Cedar Valley is greater than 0. The average number of newborn children per adult parrot in Pine Ridge equals 1. | What is the average number of newborn children per adult owl in Cedar Valley? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult owl in Cedar Valley as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult parrot in Pine Ridge as E; so E = x = x. We know E = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 5 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult owl in Pine Ridge equals 3 plus the number of adult parrot in Cedar Valley. The number of adult owl in Cedar Valley equals the number of adult parrot in Pine Ridge. The average number of newborn children per adult parrot in Pine Ridge equals the average number of newborn children per adult owl in Cedar Valley. The average number of newborn children per adult parrot in Cedar Valley equals 1. The number of adult parrot in Cedar Valley equals 1. The number of adult parrot in Pine Ridge equals the number of adult parrot in Cedar Valley. The average number of newborn children per adult owl in Pine Ridge equals 2. The average number of newborn children per adult owl in Cedar Valley is greater than 0. The average number of newborn children per adult parrot in Pine Ridge equals 1. Question: What is the average number of newborn children per adult owl in Cedar Valley? Solution: "
}
] |
The average number of newborn children per adult owl in Oakridge Riverside equals 2. The number of adult blue jay in Maple Creek equals the number of adult blue jay in Pine Ridge. The number of adult blue jay in Pine Ridge equals 2. The number of adult owl in Pine Ridge equals 4 plus the sum of the average number of newborn children per adult owl in Pine Ridge and the number of adult blue jay in Pine Ridge. The average number of newborn children per adult crow in Maple Creek equals 1. The average number of newborn children per adult blue jay in Oakridge Riverside equals 3. The average number of newborn children per adult crow in Maple Creek equals the number of adult owl in Maple Creek. The average number of newborn children per adult blue jay in Pine Ridge equals 4 times the number of adult owl in Maple Creek. The number of adult owl in Maple Creek exists, and its number is greater than 0. The average number of newborn children per adult owl in Pine Ridge equals 2. The number of adult owl in Oakridge Riverside equals 3 plus the average number of newborn children per adult crow in Pine Ridge. The average number of newborn children per adult blue jay in Maple Creek equals 4. The number of adult crow in Maple Creek equals 4 times the sum of the average number of newborn children per adult owl in Pine Ridge, the number of adult owl in Pine Ridge, and the number of adult blue jay in Pine Ridge. The number of adult crow in Pine Ridge equals 3. The average number of newborn children per adult crow in Pine Ridge equals 2 times the sum of the average number of newborn children per adult owl in Pine Ridge, the number of adult blue jay in Pine Ridge, and the number of adult owl in Pine Ridge. The average number of newborn children per adult owl in Maple Creek equals the total number of adult animals in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals the average number of newborn children per adult blue jay in Maple Creek. | How many adult owl does Maple Creek have? | The question is difficult, so we use equations to solve it. Define adult owl in Maple Creek as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult crow in Maple Creek as v; so v = x = x. We know v = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 20 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult owl in Oakridge Riverside equals 2. The number of adult blue jay in Maple Creek equals the number of adult blue jay in Pine Ridge. The number of adult blue jay in Pine Ridge equals 2. The number of adult owl in Pine Ridge equals 4 plus the sum of the average number of newborn children per adult owl in Pine Ridge and the number of adult blue jay in Pine Ridge. The average number of newborn children per adult crow in Maple Creek equals 1. The average number of newborn children per adult blue jay in Oakridge Riverside equals 3. The average number of newborn children per adult crow in Maple Creek equals the number of adult owl in Maple Creek. The average number of newborn children per adult blue jay in Pine Ridge equals 4 times the number of adult owl in Maple Creek. The number of adult owl in Maple Creek exists, and its number is greater than 0. The average number of newborn children per adult owl in Pine Ridge equals 2. The number of adult owl in Oakridge Riverside equals 3 plus the average number of newborn children per adult crow in Pine Ridge. The average number of newborn children per adult blue jay in Maple Creek equals 4. The number of adult crow in Maple Creek equals 4 times the sum of the average number of newborn children per adult owl in Pine Ridge, the number of adult owl in Pine Ridge, and the number of adult blue jay in Pine Ridge. The number of adult crow in Pine Ridge equals 3. The average number of newborn children per adult crow in Pine Ridge equals 2 times the sum of the average number of newborn children per adult owl in Pine Ridge, the number of adult blue jay in Pine Ridge, and the number of adult owl in Pine Ridge. The average number of newborn children per adult owl in Maple Creek equals the total number of adult animals in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals the average number of newborn children per adult blue jay in Maple Creek. Question: How many adult owl does Maple Creek have? Solution: "
}
] |
The average number of newborn children per adult blue jay in South Zoo equals 4. The number of adult blue jay in South Zoo equals the difference between the average number of newborn children per adult owl in South Zoo and the average number of newborn children per adult parrot in Hamilton Farm. The average number of newborn children per adult blue jay in South Zoo equals the average number of newborn children per adult owl in Hamilton Farm. The average number of newborn children per adult parrot in Hamilton Farm equals the average number of newborn children per adult owl in South Zoo. The number of adult parrot in Hamilton Farm equals 4. The average number of newborn children per adult blue jay in Hamilton Farm equals 4. The average number of newborn children per adult owl in Hamilton Farm is greater than 0. The average number of newborn children per adult owl in South Zoo equals 3. The number of adult owl in South Zoo equals 3. The number of adult blue jay in Hamilton Farm equals 2. The number of adult owl in Hamilton Farm equals 3 plus the sum of the average number of newborn children per adult owl in Hamilton Farm, the average number of newborn children per adult owl in South Zoo, and the total number of adult animals in Hamilton Farm. | What is the average number of newborn children per adult owl in Hamilton Farm? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult owl in Hamilton Farm as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult blue jay in South Zoo as G; so G = x = x. We know G = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 12 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult blue jay in South Zoo equals 4. The number of adult blue jay in South Zoo equals the difference between the average number of newborn children per adult owl in South Zoo and the average number of newborn children per adult parrot in Hamilton Farm. The average number of newborn children per adult blue jay in South Zoo equals the average number of newborn children per adult owl in Hamilton Farm. The average number of newborn children per adult parrot in Hamilton Farm equals the average number of newborn children per adult owl in South Zoo. The number of adult parrot in Hamilton Farm equals 4. The average number of newborn children per adult blue jay in Hamilton Farm equals 4. The average number of newborn children per adult owl in Hamilton Farm is greater than 0. The average number of newborn children per adult owl in South Zoo equals 3. The number of adult owl in South Zoo equals 3. The number of adult blue jay in Hamilton Farm equals 2. The number of adult owl in Hamilton Farm equals 3 plus the sum of the average number of newborn children per adult owl in Hamilton Farm, the average number of newborn children per adult owl in South Zoo, and the total number of adult animals in Hamilton Farm. Question: What is the average number of newborn children per adult owl in Hamilton Farm? Solution: "
}
] |
The number of adult racoon in Maple Creek equals 2 times the sum of the average number of newborn children per adult racoon in Pine Ridge, the number of adult racoon in Pine Ridge, and the number of adult racoon in Cedar Valley. The average number of newborn children per adult racoon in Pine Ridge equals 2 times the number of adult bear in Maple Creek. The average number of newborn children per adult bear in Pine Ridge equals the average number of newborn children per adult bear in Cedar Valley. The average number of newborn children per adult racoon in Maple Creek equals 4. The number of adult bear in Maple Creek equals 3. The number of adult racoon in Pine Ridge equals 1. The average number of newborn children per adult bear in Pine Ridge equals 1. The average number of newborn children per adult bear in Cedar Valley is greater than 0. The average number of newborn children per adult racoon in Cedar Valley equals the number of adult bear in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals 2 times the sum of the number of adult racoon in Cedar Valley, the average number of newborn children per adult bear in Pine Ridge, and the average number of newborn children per adult racoon in Cedar Valley. The number of adult bear in Pine Ridge equals 1 plus the average number of newborn children per adult racoon in Pine Ridge. The number of adult bear in Cedar Valley equals 3. The number of adult racoon in Cedar Valley equals the number of adult bear in Maple Creek. | What is the average number of newborn children per adult bear in Cedar Valley? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult bear in Cedar Valley as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult bear in Pine Ridge as A; so A = x = x. We know A = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 7 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult racoon in Maple Creek equals 2 times the sum of the average number of newborn children per adult racoon in Pine Ridge, the number of adult racoon in Pine Ridge, and the number of adult racoon in Cedar Valley. The average number of newborn children per adult racoon in Pine Ridge equals 2 times the number of adult bear in Maple Creek. The average number of newborn children per adult bear in Pine Ridge equals the average number of newborn children per adult bear in Cedar Valley. The average number of newborn children per adult racoon in Maple Creek equals 4. The number of adult bear in Maple Creek equals 3. The number of adult racoon in Pine Ridge equals 1. The average number of newborn children per adult bear in Pine Ridge equals 1. The average number of newborn children per adult bear in Cedar Valley is greater than 0. The average number of newborn children per adult racoon in Cedar Valley equals the number of adult bear in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals 2 times the sum of the number of adult racoon in Cedar Valley, the average number of newborn children per adult bear in Pine Ridge, and the average number of newborn children per adult racoon in Cedar Valley. The number of adult bear in Pine Ridge equals 1 plus the average number of newborn children per adult racoon in Pine Ridge. The number of adult bear in Cedar Valley equals 3. The number of adult racoon in Cedar Valley equals the number of adult bear in Maple Creek. Question: What is the average number of newborn children per adult bear in Cedar Valley? Solution: "
}
] |
The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult deer in Hamilton Farm. The number of adult wolf in Mayer Aquarium equals the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus equals 3. The number of adult deer in Jefferson Circus equals the number of adult deer in Hamilton Farm. The average number of newborn children per adult deer in Hamilton Farm equals 2. The average number of newborn children per adult wolf in Hamilton Farm equals 2 times the number of adult wolf in Hamilton Farm. The number of adult deer in Mayer Aquarium equals 3. The average number of newborn children per adult wolf in Mayer Aquarium equals 2. The number of adult deer in Hamilton Farm equals 1. The average number of newborn children per adult racoon in Mayer Aquarium equals the sum of the number of adult deer in Hamilton Farm, the average number of newborn children per adult wolf in Mayer Aquarium, the number of adult wolf in Hamilton Farm, and the number of adult racoon in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 3 times the number of adult racoon in Mayer Aquarium. The number of adult racoon in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus is greater than 0. The number of adult racoon in Mayer Aquarium equals 1. | What is the average number of newborn children per adult racoon in Jefferson Circus? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult racoon in Jefferson Circus as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult deer in Jefferson Circus as G; so G = x = x. We know G = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 12 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult deer in Hamilton Farm. The number of adult wolf in Mayer Aquarium equals the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus equals 3. The number of adult deer in Jefferson Circus equals the number of adult deer in Hamilton Farm. The average number of newborn children per adult deer in Hamilton Farm equals 2. The average number of newborn children per adult wolf in Hamilton Farm equals 2 times the number of adult wolf in Hamilton Farm. The number of adult deer in Mayer Aquarium equals 3. The average number of newborn children per adult wolf in Mayer Aquarium equals 2. The number of adult deer in Hamilton Farm equals 1. The average number of newborn children per adult racoon in Mayer Aquarium equals the sum of the number of adult deer in Hamilton Farm, the average number of newborn children per adult wolf in Mayer Aquarium, the number of adult wolf in Hamilton Farm, and the number of adult racoon in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 3 times the number of adult racoon in Mayer Aquarium. The number of adult racoon in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus is greater than 0. The number of adult racoon in Mayer Aquarium equals 1. Question: What is the average number of newborn children per adult racoon in Jefferson Circus? Solution: "
}
] |
The number of adult deer in South Zoo equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3 times the number of adult deer in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus equals the number of adult deer in Jefferson Circus. The average number of newborn children per adult deer in Mayer Aquarium equals 4 times the number of adult bear in Jefferson Circus. The number of adult bear in Jefferson Circus equals 1. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus is greater than 0. The average number of newborn children per adult deer in South Zoo equals 2 plus the difference between the number of adult bear in Jefferson Circus and the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult bear in Jefferson Circus equals 2. The number of adult deer in Jefferson Circus equals 3. The number of adult racoon in Jefferson Circus equals 4 times the difference between the average number of newborn children per adult deer in Mayer Aquarium and the number of adult bear in Jefferson Circus. | What is the average number of newborn children per adult deer in Jefferson Circus? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult deer in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult deer in Jefferson Circus as A; so A = x = x. We know A = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 5 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult deer in South Zoo equals the average number of newborn children per adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3 times the number of adult deer in Jefferson Circus. The average number of newborn children per adult racoon in Jefferson Circus equals the number of adult deer in Jefferson Circus. The average number of newborn children per adult deer in Mayer Aquarium equals 4 times the number of adult bear in Jefferson Circus. The number of adult bear in Jefferson Circus equals 1. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult deer in Jefferson Circus. The average number of newborn children per adult deer in Jefferson Circus is greater than 0. The average number of newborn children per adult deer in South Zoo equals 2 plus the difference between the number of adult bear in Jefferson Circus and the average number of newborn children per adult deer in Mayer Aquarium. The average number of newborn children per adult bear in Jefferson Circus equals 2. The number of adult deer in Jefferson Circus equals 3. The number of adult racoon in Jefferson Circus equals 4 times the difference between the average number of newborn children per adult deer in Mayer Aquarium and the number of adult bear in Jefferson Circus. Question: What is the average number of newborn children per adult deer in Jefferson Circus? Solution: "
}
] |
The average number of newborn children per adult parrot in Beverly Forest equals 1. The number of adult parrot in Oakridge Riverside equals 2 plus the number of adult parrot in Beverly Forest. The average number of newborn children per adult blue jay in Oakridge Riverside equals the number of adult blue jay in Maple Creek. The number of adult blue jay in Oakridge Riverside equals 2. The average number of newborn children per adult blue jay in Maple Creek is greater than 0. The average number of newborn children per adult parrot in Oakridge Riverside equals the total number of adult animals in Maple Creek. The number of adult blue jay in Oakridge Riverside equals the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals the average number of newborn children per adult parrot in Beverly Forest. The number of adult parrot in Beverly Forest equals 4. | What is the average number of newborn children per adult blue jay in Maple Creek? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult blue jay in Maple Creek as x; we don't know its value yet but will find it out later. Define adult blue jay in Oakridge Riverside as f; so f = x = x. We know f = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 22 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult parrot in Beverly Forest equals 1. The number of adult parrot in Oakridge Riverside equals 2 plus the number of adult parrot in Beverly Forest. The average number of newborn children per adult blue jay in Oakridge Riverside equals the number of adult blue jay in Maple Creek. The number of adult blue jay in Oakridge Riverside equals 2. The average number of newborn children per adult blue jay in Maple Creek is greater than 0. The average number of newborn children per adult parrot in Oakridge Riverside equals the total number of adult animals in Maple Creek. The number of adult blue jay in Oakridge Riverside equals the average number of newborn children per adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals the average number of newborn children per adult parrot in Beverly Forest. The number of adult parrot in Beverly Forest equals 4. Question: What is the average number of newborn children per adult blue jay in Maple Creek? Solution: "
}
] |
The average number of newborn children per adult bear in Bundle Ranch equals 2 times the total number of adult animals in Hamilton Farm. The average number of newborn children per adult racoon in Bundle Ranch equals the average number of newborn children per adult bear in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 1 plus the average number of newborn children per adult racoon in Bundle Ranch. The number of adult bear in Hamilton Farm equals 1. The average number of newborn children per adult bear in Hamilton Farm is greater than 0. The average number of newborn children per adult racoon in Bundle Ranch equals 2. The number of adult racoon in Bundle Ranch equals the sum of the average number of newborn children per adult bear in Hamilton Farm, the average number of newborn children per adult racoon in Bundle Ranch, and the average number of newborn children per adult bear in Bundle Ranch. The number of adult bear in Bundle Ranch equals 2. The average number of newborn children per adult racoon in Hamilton Farm equals 3. | What is the average number of newborn children per adult bear in Hamilton Farm? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult bear in Hamilton Farm as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult racoon in Bundle Ranch as u; so u = x = x. We know u = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 2 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult bear in Bundle Ranch equals 2 times the total number of adult animals in Hamilton Farm. The average number of newborn children per adult racoon in Bundle Ranch equals the average number of newborn children per adult bear in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 1 plus the average number of newborn children per adult racoon in Bundle Ranch. The number of adult bear in Hamilton Farm equals 1. The average number of newborn children per adult bear in Hamilton Farm is greater than 0. The average number of newborn children per adult racoon in Bundle Ranch equals 2. The number of adult racoon in Bundle Ranch equals the sum of the average number of newborn children per adult bear in Hamilton Farm, the average number of newborn children per adult racoon in Bundle Ranch, and the average number of newborn children per adult bear in Bundle Ranch. The number of adult bear in Bundle Ranch equals 2. The average number of newborn children per adult racoon in Hamilton Farm equals 3. Question: What is the average number of newborn children per adult bear in Hamilton Farm? Solution: "
}
] |
The number of adult bear in South Zoo equals 4. The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult deer in Jefferson Circus. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult deer in South Zoo equals 3 plus the average number of newborn children per adult bear in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3 times the number of adult fox in Jefferson Circus. The number of adult fox in Mayer Aquarium equals 3 times the number of adult bear in Mayer Aquarium. The average number of newborn children per adult deer in Mayer Aquarium equals 2. The average number of newborn children per adult fox in Mayer Aquarium equals 1 plus the number of adult fox in Mayer Aquarium. The number of adult fox in Jefferson Circus equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult fox in South Zoo equals the difference between the number of adult fox in Jefferson Circus and the number of adult fox in Mayer Aquarium. The average number of newborn children per adult deer in Jefferson Circus is greater than 0. The average number of newborn children per adult fox in Jefferson Circus equals the number of adult fox in South Zoo. The number of adult fox in South Zoo equals the sum of the number of adult fox in Mayer Aquarium, the number of adult bear in Mayer Aquarium, and the average number of newborn children per adult fox in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 3. The average number of newborn children per adult bear in South Zoo equals 2. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult fox in Mayer Aquarium. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult bear in South Zoo. The average number of newborn children per adult bear in Jefferson Circus equals 3 times the number of adult fox in South Zoo. The number of adult deer in South Zoo equals 1 plus the average number of newborn children per adult bear in Jefferson Circus. | What is the average number of newborn children per adult deer in Jefferson Circus? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult deer in Jefferson Circus as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult deer in Mayer Aquarium as U; so U = x = x. We know U = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 9 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult bear in South Zoo equals 4. The average number of newborn children per adult deer in Mayer Aquarium equals the average number of newborn children per adult deer in Jefferson Circus. The number of adult bear in Mayer Aquarium equals 1. The average number of newborn children per adult deer in South Zoo equals 3 plus the average number of newborn children per adult bear in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3 times the number of adult fox in Jefferson Circus. The number of adult fox in Mayer Aquarium equals 3 times the number of adult bear in Mayer Aquarium. The average number of newborn children per adult deer in Mayer Aquarium equals 2. The average number of newborn children per adult fox in Mayer Aquarium equals 1 plus the number of adult fox in Mayer Aquarium. The number of adult fox in Jefferson Circus equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult bear in Mayer Aquarium. The average number of newborn children per adult fox in South Zoo equals the difference between the number of adult fox in Jefferson Circus and the number of adult fox in Mayer Aquarium. The average number of newborn children per adult deer in Jefferson Circus is greater than 0. The average number of newborn children per adult fox in Jefferson Circus equals the number of adult fox in South Zoo. The number of adult fox in South Zoo equals the sum of the number of adult fox in Mayer Aquarium, the number of adult bear in Mayer Aquarium, and the average number of newborn children per adult fox in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 3. The average number of newborn children per adult bear in South Zoo equals 2. The average number of newborn children per adult bear in Mayer Aquarium equals the sum of the average number of newborn children per adult fox in Mayer Aquarium and the number of adult fox in Mayer Aquarium. The number of adult deer in Jefferson Circus equals the average number of newborn children per adult bear in South Zoo. The average number of newborn children per adult bear in Jefferson Circus equals 3 times the number of adult fox in South Zoo. The number of adult deer in South Zoo equals 1 plus the average number of newborn children per adult bear in Jefferson Circus. Question: What is the average number of newborn children per adult deer in Jefferson Circus? Solution: "
}
] |
The average number of newborn children per adult bear in Beverly Forest equals 3. The average number of newborn children per adult fox in Beverly Forest is greater than 0. The average number of newborn children per adult fox in Maple Creek equals the average number of newborn children per adult fox in Beverly Forest. The average number of newborn children per adult fox in Maple Creek equals 4. The average number of newborn children per adult bear in Maple Creek equals the sum of the average number of newborn children per adult fox in Maple Creek, the average number of newborn children per adult fox in Beverly Forest, the number of adult fox in Maple Creek, and the average number of newborn children per adult bear in Beverly Forest. The number of adult bear in Maple Creek equals 1. The number of adult fox in Maple Creek equals the difference between the average number of newborn children per adult fox in Maple Creek and the average number of newborn children per adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals the average number of newborn children per adult bear in Beverly Forest. The number of adult bear in Beverly Forest equals 3 plus the sum of the average number of newborn children per adult bear in Maple Creek, the average number of newborn children per adult fox in Maple Creek, and the total number of adult animals in Maple Creek. | What is the average number of newborn children per adult fox in Beverly Forest? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult fox in Beverly Forest as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult fox in Maple Creek as S; so S = x = x. We know S = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 2 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult bear in Beverly Forest equals 3. The average number of newborn children per adult fox in Beverly Forest is greater than 0. The average number of newborn children per adult fox in Maple Creek equals the average number of newborn children per adult fox in Beverly Forest. The average number of newborn children per adult fox in Maple Creek equals 4. The average number of newborn children per adult bear in Maple Creek equals the sum of the average number of newborn children per adult fox in Maple Creek, the average number of newborn children per adult fox in Beverly Forest, the number of adult fox in Maple Creek, and the average number of newborn children per adult bear in Beverly Forest. The number of adult bear in Maple Creek equals 1. The number of adult fox in Maple Creek equals the difference between the average number of newborn children per adult fox in Maple Creek and the average number of newborn children per adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals the average number of newborn children per adult bear in Beverly Forest. The number of adult bear in Beverly Forest equals 3 plus the sum of the average number of newborn children per adult bear in Maple Creek, the average number of newborn children per adult fox in Maple Creek, and the total number of adult animals in Maple Creek. Question: What is the average number of newborn children per adult fox in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult racoon in Bundle Ranch equals the average number of newborn children per adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The number of adult racoon in Jefferson Circus equals the difference between the average number of newborn children per adult racoon in Jefferson Circus and the average number of newborn children per adult racoon in Bundle Ranch. The average number of newborn children per adult wolf in Jefferson Circus is greater than 0. The average number of newborn children per adult racoon in Jefferson Circus equals 2. The average number of newborn children per adult racoon in Bundle Ranch equals 4. The number of adult wolf in Bundle Ranch equals 2 times the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult wolf in Bundle Ranch equals 2. The number of adult racoon in Bundle Ranch equals 4. | What is the average number of newborn children per adult wolf in Jefferson Circus? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult wolf in Jefferson Circus as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult racoon in Bundle Ranch as S; so S = x = x. We know S = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 4 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult racoon in Bundle Ranch equals the average number of newborn children per adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the average number of newborn children per adult racoon in Jefferson Circus. The number of adult racoon in Jefferson Circus equals the difference between the average number of newborn children per adult racoon in Jefferson Circus and the average number of newborn children per adult racoon in Bundle Ranch. The average number of newborn children per adult wolf in Jefferson Circus is greater than 0. The average number of newborn children per adult racoon in Jefferson Circus equals 2. The average number of newborn children per adult racoon in Bundle Ranch equals 4. The number of adult wolf in Bundle Ranch equals 2 times the average number of newborn children per adult racoon in Jefferson Circus. The average number of newborn children per adult wolf in Bundle Ranch equals 2. The number of adult racoon in Bundle Ranch equals 4. Question: What is the average number of newborn children per adult wolf in Jefferson Circus? Solution: "
}
] |
The number of adult crow in Jefferson Circus equals the average number of newborn children per adult crow in Jefferson Circus. The average number of newborn children per adult owl in Jefferson Circus equals the total number of adult animals in Jefferson Circus. The average number of newborn children per adult crow in Jefferson Circus is greater than 0. The average number of newborn children per adult owl in Hamilton Farm equals 3 times the average number of newborn children per adult crow in Hamilton Farm. The number of adult owl in Jefferson Circus equals 1. The average number of newborn children per adult crow in Hamilton Farm equals 2 plus the sum of the average number of newborn children per adult crow in Jefferson Circus, the number of adult owl in Jefferson Circus, and the average number of newborn children per adult crow in Jefferson Circus. The number of adult crow in Hamilton Farm equals 2. The number of adult crow in Jefferson Circus equals 4. The number of adult owl in Hamilton Farm equals the number of adult crow in Hamilton Farm. | What is the average number of newborn children per adult crow in Jefferson Circus? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult crow in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult crow in Jefferson Circus as c; so c = x = x. We know c = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 21 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult crow in Jefferson Circus equals the average number of newborn children per adult crow in Jefferson Circus. The average number of newborn children per adult owl in Jefferson Circus equals the total number of adult animals in Jefferson Circus. The average number of newborn children per adult crow in Jefferson Circus is greater than 0. The average number of newborn children per adult owl in Hamilton Farm equals 3 times the average number of newborn children per adult crow in Hamilton Farm. The number of adult owl in Jefferson Circus equals 1. The average number of newborn children per adult crow in Hamilton Farm equals 2 plus the sum of the average number of newborn children per adult crow in Jefferson Circus, the number of adult owl in Jefferson Circus, and the average number of newborn children per adult crow in Jefferson Circus. The number of adult crow in Hamilton Farm equals 2. The number of adult crow in Jefferson Circus equals 4. The number of adult owl in Hamilton Farm equals the number of adult crow in Hamilton Farm. Question: What is the average number of newborn children per adult crow in Jefferson Circus? Solution: "
}
] |
The number of adult crow in Pine Ridge equals 2 plus the sum of the average number of newborn children per adult crow in Oakridge Riverside and the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Beverly Forest equals the sum of the total number of adult animals in Pine Ridge, the average number of newborn children per adult owl in Pine Ridge, the total number of adult animals in Oakridge Riverside, and the average number of newborn children per adult blue jay in Oakridge Riverside. The average number of newborn children per adult owl in Pine Ridge is greater than 0. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult crow in Beverly Forest equals the number of adult crow in Pine Ridge. The average number of newborn children per adult owl in Beverly Forest equals the average number of newborn children per adult owl in Pine Ridge. The average number of newborn children per adult crow in Pine Ridge equals the sum of the number of adult owl in Pine Ridge, the number of adult crow in Pine Ridge, and the average number of newborn children per adult crow in Oakridge Riverside. The average number of newborn children per adult owl in Beverly Forest equals 4. The number of adult blue jay in Oakridge Riverside equals 4. The number of adult owl in Beverly Forest equals 4. The number of adult owl in Pine Ridge equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult owl in Beverly Forest. The average number of newborn children per adult crow in Beverly Forest equals 1. The average number of newborn children per adult blue jay in Pine Ridge equals 1. The average number of newborn children per adult blue jay in Oakridge Riverside equals the difference between the average number of newborn children per adult owl in Pine Ridge and the number of adult blue jay in Pine Ridge. The number of adult blue jay in Pine Ridge equals the difference between the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult owl in Beverly Forest. The number of adult crow in Oakridge Riverside equals 3. | What is the average number of newborn children per adult owl in Pine Ridge? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult owl in Pine Ridge as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult owl in Beverly Forest as g; so g = x = x. We know g = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 10 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult crow in Pine Ridge equals 2 plus the sum of the average number of newborn children per adult crow in Oakridge Riverside and the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Beverly Forest equals the sum of the total number of adult animals in Pine Ridge, the average number of newborn children per adult owl in Pine Ridge, the total number of adult animals in Oakridge Riverside, and the average number of newborn children per adult blue jay in Oakridge Riverside. The average number of newborn children per adult owl in Pine Ridge is greater than 0. The average number of newborn children per adult crow in Oakridge Riverside equals 3. The number of adult crow in Beverly Forest equals the number of adult crow in Pine Ridge. The average number of newborn children per adult owl in Beverly Forest equals the average number of newborn children per adult owl in Pine Ridge. The average number of newborn children per adult crow in Pine Ridge equals the sum of the number of adult owl in Pine Ridge, the number of adult crow in Pine Ridge, and the average number of newborn children per adult crow in Oakridge Riverside. The average number of newborn children per adult owl in Beverly Forest equals 4. The number of adult blue jay in Oakridge Riverside equals 4. The number of adult owl in Beverly Forest equals 4. The number of adult owl in Pine Ridge equals 4. The average number of newborn children per adult blue jay in Beverly Forest equals the average number of newborn children per adult owl in Beverly Forest. The average number of newborn children per adult crow in Beverly Forest equals 1. The average number of newborn children per adult blue jay in Pine Ridge equals 1. The average number of newborn children per adult blue jay in Oakridge Riverside equals the difference between the average number of newborn children per adult owl in Pine Ridge and the number of adult blue jay in Pine Ridge. The number of adult blue jay in Pine Ridge equals the difference between the average number of newborn children per adult owl in Pine Ridge and the average number of newborn children per adult owl in Beverly Forest. The number of adult crow in Oakridge Riverside equals 3. Question: What is the average number of newborn children per adult owl in Pine Ridge? Solution: "
}
] |
The average number of newborn children per adult fox in Cedar Valley equals 1. The average number of newborn children per adult deer in Maple Creek equals the sum of the number of adult deer in Oakridge Riverside, the average number of newborn children per adult bear in Cedar Valley, the average number of newborn children per adult fox in Cedar Valley, and the number of adult fox in Cedar Valley. The number of adult fox in Oakridge Riverside equals 3 times the number of adult fox in Cedar Valley. The average number of newborn children per adult bear in Cedar Valley equals 3 times the number of adult fox in Oakridge Riverside. The number of adult deer in Maple Creek equals the average number of newborn children per adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 4 times the number of adult fox in Oakridge Riverside. The number of adult bear in Maple Creek equals 3. The number of adult fox in Maple Creek equals 3 plus the sum of the number of adult deer in Oakridge Riverside, the number of adult fox in Oakridge Riverside, and the average number of newborn children per adult fox in Oakridge Riverside. The average number of newborn children per adult fox in Maple Creek equals 3. The number of adult deer in Oakridge Riverside equals 4. The number of adult deer in Cedar Valley equals the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult deer in Oakridge Riverside equals 4. The average number of newborn children per adult fox in Oakridge Riverside equals the average number of newborn children per adult bear in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult bear in Oakridge Riverside equals 3. The number of adult fox in Cedar Valley equals 2. The average number of newborn children per adult bear in Maple Creek equals 4. The average number of newborn children per adult deer in Cedar Valley is greater than 0. The number of adult bear in Oakridge Riverside equals the number of adult fox in Cedar Valley. | What is the average number of newborn children per adult deer in Cedar Valley? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult deer in Cedar Valley as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult bear in Oakridge Riverside as n; so n = x = x. We know n = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 20 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult fox in Cedar Valley equals 1. The average number of newborn children per adult deer in Maple Creek equals the sum of the number of adult deer in Oakridge Riverside, the average number of newborn children per adult bear in Cedar Valley, the average number of newborn children per adult fox in Cedar Valley, and the number of adult fox in Cedar Valley. The number of adult fox in Oakridge Riverside equals 3 times the number of adult fox in Cedar Valley. The average number of newborn children per adult bear in Cedar Valley equals 3 times the number of adult fox in Oakridge Riverside. The number of adult deer in Maple Creek equals the average number of newborn children per adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 4 times the number of adult fox in Oakridge Riverside. The number of adult bear in Maple Creek equals 3. The number of adult fox in Maple Creek equals 3 plus the sum of the number of adult deer in Oakridge Riverside, the number of adult fox in Oakridge Riverside, and the average number of newborn children per adult fox in Oakridge Riverside. The average number of newborn children per adult fox in Maple Creek equals 3. The number of adult deer in Oakridge Riverside equals 4. The number of adult deer in Cedar Valley equals the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult deer in Oakridge Riverside equals 4. The average number of newborn children per adult fox in Oakridge Riverside equals the average number of newborn children per adult bear in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the average number of newborn children per adult deer in Cedar Valley. The average number of newborn children per adult bear in Oakridge Riverside equals 3. The number of adult fox in Cedar Valley equals 2. The average number of newborn children per adult bear in Maple Creek equals 4. The average number of newborn children per adult deer in Cedar Valley is greater than 0. The number of adult bear in Oakridge Riverside equals the number of adult fox in Cedar Valley. Question: What is the average number of newborn children per adult deer in Cedar Valley? Solution: "
}
] |
The number of adult eagle in Bundle Ranch equals 3 times the average number of newborn children per adult owl in Bundle Ranch. The average number of newborn children per adult blue jay in Mayer Aquarium equals 1. The average number of newborn children per adult blue jay in Bundle Ranch equals 3. The average number of newborn children per adult eagle in Mayer Aquarium equals the difference between the number of adult owl in Mayer Aquarium and the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Bundle Ranch equals the average number of newborn children per adult eagle in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 3. The number of adult blue jay in Bundle Ranch equals the difference between the average number of newborn children per adult eagle in Mayer Aquarium and the average number of newborn children per adult blue jay in Bundle Ranch. The number of adult eagle in Hamilton Farm equals 4. The average number of newborn children per adult blue jay in Hamilton Farm is greater than 0. The average number of newborn children per adult owl in Hamilton Farm equals 2. The number of adult owl in Mayer Aquarium equals 3. The average number of newborn children per adult owl in Mayer Aquarium equals the average number of newborn children per adult owl in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 2. The average number of newborn children per adult owl in Hamilton Farm equals the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult owl in Bundle Ranch equals 2 times the number of adult owl in Mayer Aquarium. The average number of newborn children per adult blue jay in Hamilton Farm is greater than 0. The average number of newborn children per adult eagle in Hamilton Farm equals 2. The number of adult owl in Hamilton Farm equals 3. The number of adult owl in Bundle Ranch equals the average number of newborn children per adult eagle in Mayer Aquarium. | What is the average number of newborn children per adult blue jay in Hamilton Farm? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult blue jay in Hamilton Farm as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult owl in Hamilton Farm as K; so K = x = x. We know K = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 16 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult eagle in Bundle Ranch equals 3 times the average number of newborn children per adult owl in Bundle Ranch. The average number of newborn children per adult blue jay in Mayer Aquarium equals 1. The average number of newborn children per adult blue jay in Bundle Ranch equals 3. The average number of newborn children per adult eagle in Mayer Aquarium equals the difference between the number of adult owl in Mayer Aquarium and the average number of newborn children per adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Bundle Ranch equals the average number of newborn children per adult eagle in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 3. The number of adult blue jay in Bundle Ranch equals the difference between the average number of newborn children per adult eagle in Mayer Aquarium and the average number of newborn children per adult blue jay in Bundle Ranch. The number of adult eagle in Hamilton Farm equals 4. The average number of newborn children per adult blue jay in Hamilton Farm is greater than 0. The average number of newborn children per adult owl in Hamilton Farm equals 2. The number of adult owl in Mayer Aquarium equals 3. The average number of newborn children per adult owl in Mayer Aquarium equals the average number of newborn children per adult owl in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 2. The average number of newborn children per adult owl in Hamilton Farm equals the average number of newborn children per adult blue jay in Hamilton Farm. The average number of newborn children per adult owl in Bundle Ranch equals 2 times the number of adult owl in Mayer Aquarium. The average number of newborn children per adult blue jay in Hamilton Farm is greater than 0. The average number of newborn children per adult eagle in Hamilton Farm equals 2. The number of adult owl in Hamilton Farm equals 3. The number of adult owl in Bundle Ranch equals the average number of newborn children per adult eagle in Mayer Aquarium. Question: What is the average number of newborn children per adult blue jay in Hamilton Farm? Solution: "
}
] |
The average number of newborn children per adult deer in Beverly Forest is greater than 0. The number of adult wolf in Beverly Forest equals the average number of newborn children per adult deer in Beverly Forest. The number of adult bear in Beverly Forest equals 2 times the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult bear in Beverly Forest equals the sum of the average number of newborn children per adult wolf in Beverly Forest and the average number of newborn children per adult deer in Beverly Forest. The number of adult wolf in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals 3 times the average number of newborn children per adult wolf in Beverly Forest. The average number of newborn children per adult wolf in Beverly Forest equals 3. | What is the average number of newborn children per adult deer in Beverly Forest? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult deer in Beverly Forest as x; we don't know its value yet but will find it out later. Define adult wolf in Beverly Forest as w; so w = x = x. We know w = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 22 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult deer in Beverly Forest is greater than 0. The number of adult wolf in Beverly Forest equals the average number of newborn children per adult deer in Beverly Forest. The number of adult bear in Beverly Forest equals 2 times the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult bear in Beverly Forest equals the sum of the average number of newborn children per adult wolf in Beverly Forest and the average number of newborn children per adult deer in Beverly Forest. The number of adult wolf in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals 3 times the average number of newborn children per adult wolf in Beverly Forest. The average number of newborn children per adult wolf in Beverly Forest equals 3. Question: What is the average number of newborn children per adult deer in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult eagle in South Zoo is greater than 0. The number of adult blue jay in Jefferson Circus equals the sum of the number of adult blue jay in South Zoo, the number of adult owl in Jefferson Circus, and the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult owl in Jefferson Circus equals 4 times the average number of newborn children per adult eagle in Jefferson Circus. The number of adult eagle in Bundle Ranch equals 4 plus the average number of newborn children per adult owl in Bundle Ranch. The average number of newborn children per adult eagle in Bundle Ranch equals 3 plus the number of adult eagle in Bundle Ranch. The average number of newborn children per adult blue jay in South Zoo equals the average number of newborn children per adult eagle in South Zoo. The number of adult eagle in South Zoo equals 2. The number of adult eagle in Jefferson Circus equals the sum of the average number of newborn children per adult blue jay in Bundle Ranch and the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult owl in Bundle Ranch equals 1. The average number of newborn children per adult eagle in South Zoo is greater than 0. The number of adult owl in Bundle Ranch equals 2 plus the sum of the average number of newborn children per adult blue jay in Bundle Ranch, the average number of newborn children per adult owl in Jefferson Circus, and the number of adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Jefferson Circus equals 1 plus the difference between the average number of newborn children per adult owl in Bundle Ranch and the number of adult eagle in Bundle Ranch. The average number of newborn children per adult blue jay in South Zoo equals 2. The number of adult owl in Jefferson Circus equals 1. The number of adult blue jay in South Zoo equals 3. The average number of newborn children per adult blue jay in Bundle Ranch equals 1 plus the sum of the average number of newborn children per adult owl in Bundle Ranch and the number of adult eagle in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals the number of adult eagle in Bundle Ranch. | What is the average number of newborn children per adult eagle in South Zoo? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult eagle in South Zoo as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult blue jay in South Zoo as P; so P = x = x. We know P = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 14 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult eagle in South Zoo is greater than 0. The number of adult blue jay in Jefferson Circus equals the sum of the number of adult blue jay in South Zoo, the number of adult owl in Jefferson Circus, and the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult owl in Jefferson Circus equals 4 times the average number of newborn children per adult eagle in Jefferson Circus. The number of adult eagle in Bundle Ranch equals 4 plus the average number of newborn children per adult owl in Bundle Ranch. The average number of newborn children per adult eagle in Bundle Ranch equals 3 plus the number of adult eagle in Bundle Ranch. The average number of newborn children per adult blue jay in South Zoo equals the average number of newborn children per adult eagle in South Zoo. The number of adult eagle in South Zoo equals 2. The number of adult eagle in Jefferson Circus equals the sum of the average number of newborn children per adult blue jay in Bundle Ranch and the average number of newborn children per adult eagle in Jefferson Circus. The average number of newborn children per adult owl in Bundle Ranch equals 1. The average number of newborn children per adult eagle in South Zoo is greater than 0. The number of adult owl in Bundle Ranch equals 2 plus the sum of the average number of newborn children per adult blue jay in Bundle Ranch, the average number of newborn children per adult owl in Jefferson Circus, and the number of adult blue jay in Bundle Ranch. The average number of newborn children per adult eagle in Jefferson Circus equals 1 plus the difference between the average number of newborn children per adult owl in Bundle Ranch and the number of adult eagle in Bundle Ranch. The average number of newborn children per adult blue jay in South Zoo equals 2. The number of adult owl in Jefferson Circus equals 1. The number of adult blue jay in South Zoo equals 3. The average number of newborn children per adult blue jay in Bundle Ranch equals 1 plus the sum of the average number of newborn children per adult owl in Bundle Ranch and the number of adult eagle in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals the number of adult eagle in Bundle Ranch. Question: What is the average number of newborn children per adult eagle in South Zoo? Solution: "
}
] |
The number of adult wolf in Maple Creek equals 1 plus the sum of the number of adult bear in Cedar Valley, the average number of newborn children per adult bear in Maple Creek, and the number of adult bear in Oakridge Riverside. The number of adult deer in Cedar Valley equals the number of adult bear in Maple Creek. The average number of newborn children per adult deer in Maple Creek equals the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Maple Creek is greater than 0. The average number of newborn children per adult deer in Oakridge Riverside equals 4. The average number of newborn children per adult wolf in Oakridge Riverside equals 1. The number of adult bear in Maple Creek equals the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Oakridge Riverside equals the average number of newborn children per adult bear in Maple Creek. The number of adult wolf in Oakridge Riverside equals the sum of the average number of newborn children per adult deer in Maple Creek and the number of adult wolf in Maple Creek. The average number of newborn children per adult wolf in Cedar Valley equals 2. The average number of newborn children per adult bear in Cedar Valley equals 4 plus the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Cedar Valley equals the difference between the average number of newborn children per adult wolf in Oakridge Riverside and the average number of newborn children per adult bear in Maple Creek. The number of adult deer in Oakridge Riverside equals 2. The average number of newborn children per adult deer in Cedar Valley equals 1. The number of adult deer in Maple Creek equals the sum of the average number of newborn children per adult deer in Cedar Valley, the average number of newborn children per adult wolf in Maple Creek, the average number of newborn children per adult wolf in Oakridge Riverside, and the average number of newborn children per adult bear in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals 4 times the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the sum of the average number of newborn children per adult deer in Maple Creek and the average number of newborn children per adult bear in Maple Creek. The average number of newborn children per adult deer in Oakridge Riverside equals the average number of newborn children per adult wolf in Maple Creek. The number of adult wolf in Cedar Valley equals the difference between the average number of newborn children per adult deer in Cedar Valley and the average number of newborn children per adult bear in Maple Creek. | What is the average number of newborn children per adult wolf in Maple Creek? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult wolf in Maple Creek as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult deer in Oakridge Riverside as q; so q = x = x. We know q = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 5 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult wolf in Maple Creek equals 1 plus the sum of the number of adult bear in Cedar Valley, the average number of newborn children per adult bear in Maple Creek, and the number of adult bear in Oakridge Riverside. The number of adult deer in Cedar Valley equals the number of adult bear in Maple Creek. The average number of newborn children per adult deer in Maple Creek equals the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Maple Creek is greater than 0. The average number of newborn children per adult deer in Oakridge Riverside equals 4. The average number of newborn children per adult wolf in Oakridge Riverside equals 1. The number of adult bear in Maple Creek equals the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Oakridge Riverside equals the average number of newborn children per adult bear in Maple Creek. The number of adult wolf in Oakridge Riverside equals the sum of the average number of newborn children per adult deer in Maple Creek and the number of adult wolf in Maple Creek. The average number of newborn children per adult wolf in Cedar Valley equals 2. The average number of newborn children per adult bear in Cedar Valley equals 4 plus the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Cedar Valley equals the difference between the average number of newborn children per adult wolf in Oakridge Riverside and the average number of newborn children per adult bear in Maple Creek. The number of adult deer in Oakridge Riverside equals 2. The average number of newborn children per adult deer in Cedar Valley equals 1. The number of adult deer in Maple Creek equals the sum of the average number of newborn children per adult deer in Cedar Valley, the average number of newborn children per adult wolf in Maple Creek, the average number of newborn children per adult wolf in Oakridge Riverside, and the average number of newborn children per adult bear in Maple Creek. The average number of newborn children per adult bear in Maple Creek equals 4 times the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult bear in Oakridge Riverside equals the sum of the average number of newborn children per adult deer in Maple Creek and the average number of newborn children per adult bear in Maple Creek. The average number of newborn children per adult deer in Oakridge Riverside equals the average number of newborn children per adult wolf in Maple Creek. The number of adult wolf in Cedar Valley equals the difference between the average number of newborn children per adult deer in Cedar Valley and the average number of newborn children per adult bear in Maple Creek. Question: What is the average number of newborn children per adult wolf in Maple Creek? Solution: "
}
] |
The number of adult racoon in Cedar Valley equals 3. The average number of newborn children per adult racoon in Cedar Valley equals the difference between the average number of newborn children per adult fox in Cedar Valley and the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult racoon in Maple Creek equals 2. The number of adult fox in Maple Creek equals the sum of the total number of adult animals in Cedar Valley, the average number of newborn children per adult fox in Cedar Valley, and the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Oakridge Riverside equals the average number of newborn children per adult fox in Maple Creek. The average number of newborn children per adult fox in Cedar Valley equals 1. The average number of newborn children per adult fox in Maple Creek is greater than 0. The average number of newborn children per adult wolf in Cedar Valley equals 1 plus the difference between the average number of newborn children per adult fox in Cedar Valley and the number of adult racoon in Maple Creek. The number of adult racoon in Maple Creek equals 1 plus the average number of newborn children per adult fox in Cedar Valley. The number of adult fox in Cedar Valley equals 1. The number of adult wolf in Cedar Valley equals 2. The number of adult wolf in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Maple Creek equals the average number of newborn children per adult fox in Maple Creek. | What is the average number of newborn children per adult fox in Maple Creek? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult fox in Maple Creek as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult racoon in Maple Creek as a; so a = x = x. We know a = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 21 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult racoon in Cedar Valley equals 3. The average number of newborn children per adult racoon in Cedar Valley equals the difference between the average number of newborn children per adult fox in Cedar Valley and the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult racoon in Maple Creek equals 2. The number of adult fox in Maple Creek equals the sum of the total number of adult animals in Cedar Valley, the average number of newborn children per adult fox in Cedar Valley, and the average number of newborn children per adult wolf in Oakridge Riverside. The average number of newborn children per adult wolf in Oakridge Riverside equals the average number of newborn children per adult fox in Maple Creek. The average number of newborn children per adult fox in Cedar Valley equals 1. The average number of newborn children per adult fox in Maple Creek is greater than 0. The average number of newborn children per adult wolf in Cedar Valley equals 1 plus the difference between the average number of newborn children per adult fox in Cedar Valley and the number of adult racoon in Maple Creek. The number of adult racoon in Maple Creek equals 1 plus the average number of newborn children per adult fox in Cedar Valley. The number of adult fox in Cedar Valley equals 1. The number of adult wolf in Cedar Valley equals 2. The number of adult wolf in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Maple Creek equals the average number of newborn children per adult fox in Maple Creek. Question: What is the average number of newborn children per adult fox in Maple Creek? Solution: "
}
] |
The number of adult fox in Oakridge Riverside equals the average number of newborn children per adult deer in Oakridge Riverside. The number of adult deer in Maple Creek equals the sum of the average number of newborn children per adult deer in Oakridge Riverside, the average number of newborn children per adult racoon in Maple Creek, and the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult deer in Maple Creek equals 1 plus the number of adult deer in Beverly Forest. The number of adult racoon in Beverly Forest equals 2. The average number of newborn children per adult deer in Oakridge Riverside equals the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult deer in Oakridge Riverside equals 3. The average number of newborn children per adult racoon in Beverly Forest equals the sum of the number of adult fox in Oakridge Riverside and the average number of newborn children per adult deer in Beverly Forest. The number of adult racoon in Maple Creek equals the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult fox in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Maple Creek equals 4. The number of adult deer in Oakridge Riverside equals 1. The number of adult deer in Beverly Forest equals the difference between the average number of newborn children per adult racoon in Maple Creek and the number of adult deer in Oakridge Riverside. The average number of newborn children per adult deer in Beverly Forest is greater than 0. | What is the average number of newborn children per adult deer in Beverly Forest? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult deer in Beverly Forest as x; we don't know its value yet but will find it out later. Define average number of newborn children per adult deer in Oakridge Riverside as U; so U = x = x. We know U = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 1 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of adult fox in Oakridge Riverside equals the average number of newborn children per adult deer in Oakridge Riverside. The number of adult deer in Maple Creek equals the sum of the average number of newborn children per adult deer in Oakridge Riverside, the average number of newborn children per adult racoon in Maple Creek, and the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult deer in Maple Creek equals 1 plus the number of adult deer in Beverly Forest. The number of adult racoon in Beverly Forest equals 2. The average number of newborn children per adult deer in Oakridge Riverside equals the average number of newborn children per adult deer in Beverly Forest. The average number of newborn children per adult deer in Oakridge Riverside equals 3. The average number of newborn children per adult racoon in Beverly Forest equals the sum of the number of adult fox in Oakridge Riverside and the average number of newborn children per adult deer in Beverly Forest. The number of adult racoon in Maple Creek equals the average number of newborn children per adult racoon in Maple Creek. The average number of newborn children per adult fox in Oakridge Riverside equals 4. The average number of newborn children per adult racoon in Maple Creek equals 4. The number of adult deer in Oakridge Riverside equals 1. The number of adult deer in Beverly Forest equals the difference between the average number of newborn children per adult racoon in Maple Creek and the number of adult deer in Oakridge Riverside. The average number of newborn children per adult deer in Beverly Forest is greater than 0. Question: What is the average number of newborn children per adult deer in Beverly Forest? Solution: "
}
] |
The average number of newborn children per adult bear in Pine Ridge equals the difference between the total number of adult animals in Cedar Valley and the total number of adult animals in Pine Ridge. The average number of newborn children per adult racoon in Beverly Forest equals 4. The average number of newborn children per adult racoon in Pine Ridge is greater than 0. The average number of newborn children per adult deer in Cedar Valley equals 2. The average number of newborn children per adult racoon in Cedar Valley equals 4 plus the average number of newborn children per adult bear in Cedar Valley. The average number of newborn children per adult bear in Beverly Forest equals 4 times the sum of the average number of newborn children per adult bear in Pine Ridge, the average number of newborn children per adult bear in Cedar Valley, and the number of adult deer in Cedar Valley. The number of adult bear in Beverly Forest equals 3. The average number of newborn children per adult bear in Cedar Valley equals 4. The average number of newborn children per adult deer in Beverly Forest equals 2 plus the sum of the average number of newborn children per adult bear in Cedar Valley, the average number of newborn children per adult racoon in Cedar Valley, and the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Beverly Forest equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Beverly Forest equals 4. The number of adult bear in Cedar Valley equals 3. The number of adult deer in Beverly Forest equals the difference between the average number of newborn children per adult bear in Cedar Valley and the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Pine Ridge equals the number of adult bear in Beverly Forest. The average number of newborn children per adult deer in Pine Ridge equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult bear in Pine Ridge equals 4. The number of adult deer in Pine Ridge equals 1. The number of adult deer in Cedar Valley equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Cedar Valley equals 3. | What is the average number of newborn children per adult racoon in Pine Ridge? | The question is difficult, so we use equations to solve it. Define average number of newborn children per adult racoon in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult bear in Beverly Forest as z; so z = x = x. We know z = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 2 | crazy_zootopia | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of adult animals in one location refers to sum of all types of adult animals ever mentioned for the specific location throughout the problem EXCLUDING their number of newborn children. IMPORTANT: if the a type of animal is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems animal quantities are not applicable for the present one. The average number of newborn children of the same type of animal might vary across different locations. The total newborn animal children of a location refers to the sum of the TOTAL newborn children (not average newborn children) from all adult animals mentioned for that specific location. Hint: the total newborn children of one type of animal in a location equals the average children per that animal in location times the number of that animal in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of animals MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of newborn children per adult bear in Pine Ridge equals the difference between the total number of adult animals in Cedar Valley and the total number of adult animals in Pine Ridge. The average number of newborn children per adult racoon in Beverly Forest equals 4. The average number of newborn children per adult racoon in Pine Ridge is greater than 0. The average number of newborn children per adult deer in Cedar Valley equals 2. The average number of newborn children per adult racoon in Cedar Valley equals 4 plus the average number of newborn children per adult bear in Cedar Valley. The average number of newborn children per adult bear in Beverly Forest equals 4 times the sum of the average number of newborn children per adult bear in Pine Ridge, the average number of newborn children per adult bear in Cedar Valley, and the number of adult deer in Cedar Valley. The number of adult bear in Beverly Forest equals 3. The average number of newborn children per adult bear in Cedar Valley equals 4. The average number of newborn children per adult deer in Beverly Forest equals 2 plus the sum of the average number of newborn children per adult bear in Cedar Valley, the average number of newborn children per adult racoon in Cedar Valley, and the average number of newborn children per adult deer in Cedar Valley. The number of adult bear in Beverly Forest equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Beverly Forest equals 4. The number of adult bear in Cedar Valley equals 3. The number of adult deer in Beverly Forest equals the difference between the average number of newborn children per adult bear in Cedar Valley and the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Pine Ridge equals the number of adult bear in Beverly Forest. The average number of newborn children per adult deer in Pine Ridge equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult bear in Pine Ridge equals 4. The number of adult deer in Pine Ridge equals 1. The number of adult deer in Cedar Valley equals the average number of newborn children per adult racoon in Pine Ridge. The number of adult racoon in Cedar Valley equals 3. Question: What is the average number of newborn children per adult racoon in Pine Ridge? Solution: "
}
] |
The average number of teachers per regional medical school in Ruby Bay equals 2. The number of culinarian school in Riverton City equals 4 plus the number of elementary school in Ruby Bay. The number of elementary school in Oakbridge City equals the difference between the average number of teachers per culinarian school in Riverton City and the average number of teachers per elementary school in Ruby Bay. The number of culinarian school in Oakbridge City equals 3. The average number of teachers per elementary school in Ruby Bay equals 4. The average number of teachers per culinarian school in Riverton City is greater than 0. The average number of teachers per elementary school in Ruby Bay equals the average number of teachers per culinarian school in Riverton City. The average number of teachers per elementary school in Oakbridge City equals the sum of the number of regional medical school in Ruby Bay, the total number of schools in Oakbridge City, the number of elementary school in Ruby Bay, and the total number of schools in Riverton City. The average number of teachers per culinarian school in Oakbridge City equals 2 times the number of culinarian school in Riverton City. The number of regional medical school in Ruby Bay equals 1 plus the number of culinarian school in Oakbridge City. The number of elementary school in Ruby Bay equals 4. | What is the average number of teachers per culinarian school in Riverton City? | The question is difficult, so we use equations to solve it. Define average number of teachers per culinarian school in Riverton City as x; we don't know its value yet but will find it out later. Define average number of teachers per elementary school in Ruby Bay as w; so w = x = x. We know w = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 6 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per regional medical school in Ruby Bay equals 2. The number of culinarian school in Riverton City equals 4 plus the number of elementary school in Ruby Bay. The number of elementary school in Oakbridge City equals the difference between the average number of teachers per culinarian school in Riverton City and the average number of teachers per elementary school in Ruby Bay. The number of culinarian school in Oakbridge City equals 3. The average number of teachers per elementary school in Ruby Bay equals 4. The average number of teachers per culinarian school in Riverton City is greater than 0. The average number of teachers per elementary school in Ruby Bay equals the average number of teachers per culinarian school in Riverton City. The average number of teachers per elementary school in Oakbridge City equals the sum of the number of regional medical school in Ruby Bay, the total number of schools in Oakbridge City, the number of elementary school in Ruby Bay, and the total number of schools in Riverton City. The average number of teachers per culinarian school in Oakbridge City equals 2 times the number of culinarian school in Riverton City. The number of regional medical school in Ruby Bay equals 1 plus the number of culinarian school in Oakbridge City. The number of elementary school in Ruby Bay equals 4. Question: What is the average number of teachers per culinarian school in Riverton City? Solution: "
}
] |
The average number of teachers per public highschool in Westhaven City equals 2. The number of elementary school in Westhaven City equals 4. The average number of teachers per elementary school in Westhaven City is greater than 0. The number of public highschool in Westhaven City equals 2. The average number of teachers per public highschool in Westhaven City equals the average number of teachers per elementary school in Westhaven City. | What is the average number of teachers per elementary school in Westhaven City? | The question is difficult, so we use equations to solve it. Define average number of teachers per elementary school in Westhaven City as x; we don't know its value yet but will find it out later. Define average number of teachers per public highschool in Westhaven City as N; so N = x = x. We know N = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 21 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per public highschool in Westhaven City equals 2. The number of elementary school in Westhaven City equals 4. The average number of teachers per elementary school in Westhaven City is greater than 0. The number of public highschool in Westhaven City equals 2. The average number of teachers per public highschool in Westhaven City equals the average number of teachers per elementary school in Westhaven City. Question: What is the average number of teachers per elementary school in Westhaven City? Solution: "
}
] |
The number of culinarian school in Clearwater Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 3. The number of culinarian school in Ruby Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of elementary school in Clearwater Bay equals 2 plus the number of culinarian school in Clearwater Bay. The average number of teachers per private middle school in Ruby Bay equals 2. The average number of teachers per private middle school in Clearwater Bay equals the difference between the number of culinarian school in Clearwater Bay and the average number of teachers per elementary school in Clearwater Bay. The average number of teachers per culinarian school in Ruby Bay is greater than 0. The number of private middle school in Shoreline City equals 1. The average number of teachers per private middle school in Shoreline City equals the sum of the average number of teachers per culinarian school in Ruby Bay, the average number of teachers per elementary school in Clearwater Bay, the number of culinarian school in Ruby Bay, and the number of elementary school in Shoreline City. The average number of teachers per private middle school in Ruby Bay equals the average number of teachers per culinarian school in Ruby Bay. The average number of teachers per elementary school in Clearwater Bay equals 2. The average number of teachers per culinarian school in Clearwater Bay equals the difference between the average number of teachers per culinarian school in Ruby Bay and the number of elementary school in Shoreline City. The number of private middle school in Ruby Bay equals the sum of the average number of teachers per elementary school in Clearwater Bay, the number of culinarian school in Clearwater Bay, and the number of private middle school in Shoreline City. The average number of teachers per elementary school in Shoreline City equals 1 plus the average number of teachers per elementary school in Clearwater Bay. The number of elementary school in Shoreline City equals 4. | What is the average number of teachers per culinarian school in Ruby Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per culinarian school in Ruby Bay as x; we don't know its value yet but will find it out later. Define average number of teachers per private middle school in Ruby Bay as B; so B = x = x. We know B = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 8 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of culinarian school in Clearwater Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 3. The number of culinarian school in Ruby Bay equals the average number of teachers per elementary school in Clearwater Bay. The number of elementary school in Clearwater Bay equals 2 plus the number of culinarian school in Clearwater Bay. The average number of teachers per private middle school in Ruby Bay equals 2. The average number of teachers per private middle school in Clearwater Bay equals the difference between the number of culinarian school in Clearwater Bay and the average number of teachers per elementary school in Clearwater Bay. The average number of teachers per culinarian school in Ruby Bay is greater than 0. The number of private middle school in Shoreline City equals 1. The average number of teachers per private middle school in Shoreline City equals the sum of the average number of teachers per culinarian school in Ruby Bay, the average number of teachers per elementary school in Clearwater Bay, the number of culinarian school in Ruby Bay, and the number of elementary school in Shoreline City. The average number of teachers per private middle school in Ruby Bay equals the average number of teachers per culinarian school in Ruby Bay. The average number of teachers per elementary school in Clearwater Bay equals 2. The average number of teachers per culinarian school in Clearwater Bay equals the difference between the average number of teachers per culinarian school in Ruby Bay and the number of elementary school in Shoreline City. The number of private middle school in Ruby Bay equals the sum of the average number of teachers per elementary school in Clearwater Bay, the number of culinarian school in Clearwater Bay, and the number of private middle school in Shoreline City. The average number of teachers per elementary school in Shoreline City equals 1 plus the average number of teachers per elementary school in Clearwater Bay. The number of elementary school in Shoreline City equals 4. Question: What is the average number of teachers per culinarian school in Ruby Bay? Solution: "
}
] |
The average number of teachers per private middle school in Brightford equals the total number of schools in Westhaven City. The total number of schools in Westhaven City equals 3. The average number of teachers per public highschool in Westhaven City equals 3. The number of private middle school in Evervale City equals 1 plus the average number of teachers per regional medical school in Brightford. The number of regional medical school in Brightford equals the difference between the number of public highschool in Westhaven City and the total number of schools in Westhaven City. The average number of teachers per private middle school in Evervale City equals 2. The average number of teachers per regional medical school in Brightford equals the total number of schools in Westhaven City. The number of private middle school in Brightford equals 4 plus the average number of teachers per private middle school in Evervale City. The number of public highschool in Westhaven City exists, and its number is greater than 0. | How many public highschool does Westhaven City have? | The question is difficult, so we use equations to solve it. Define public highschool in Westhaven City as x; we don't know its value yet but will find it out later. Define total number of schools in Westhaven City as p; so p = x = x. We know p = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 13 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per private middle school in Brightford equals the total number of schools in Westhaven City. The total number of schools in Westhaven City equals 3. The average number of teachers per public highschool in Westhaven City equals 3. The number of private middle school in Evervale City equals 1 plus the average number of teachers per regional medical school in Brightford. The number of regional medical school in Brightford equals the difference between the number of public highschool in Westhaven City and the total number of schools in Westhaven City. The average number of teachers per private middle school in Evervale City equals 2. The average number of teachers per regional medical school in Brightford equals the total number of schools in Westhaven City. The number of private middle school in Brightford equals 4 plus the average number of teachers per private middle school in Evervale City. The number of public highschool in Westhaven City exists, and its number is greater than 0. Question: How many public highschool does Westhaven City have? Solution: "
}
] |
The number of culinarian school in Shoreline City equals 1. The number of public highschool in Shoreline City equals 4 plus the number of culinarian school in Riverton City. The number of culinarian school in Oakbridge City equals 1. The number of regional medical school in Riverton City equals 1. The number of culinarian school in Riverton City equals 4. The number of public highschool in Riverton City equals the number of public highschool in Shoreline City. The average number of teachers per public highschool in Riverton City is greater than 0. The average number of teachers per regional medical school in Riverton City equals the difference between the number of culinarian school in Riverton City and the number of public highschool in Shoreline City. The average number of teachers per culinarian school in Riverton City equals the average number of teachers per public highschool in Riverton City. The average number of teachers per culinarian school in Oakbridge City equals 1. The average number of teachers per culinarian school in Riverton City equals 3. The average number of teachers per culinarian school in Shoreline City equals the sum of the average number of teachers per culinarian school in Oakbridge City, the average number of teachers per regional medical school in Riverton City, and the average number of teachers per public highschool in Riverton City. The average number of teachers per public highschool in Shoreline City equals 3 times the total number of schools in Riverton City. | What is the average number of teachers per public highschool in Riverton City? | The question is difficult, so we use equations to solve it. Define average number of teachers per public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define average number of teachers per culinarian school in Riverton City as P; so P = x = x. We know P = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 5 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of culinarian school in Shoreline City equals 1. The number of public highschool in Shoreline City equals 4 plus the number of culinarian school in Riverton City. The number of culinarian school in Oakbridge City equals 1. The number of regional medical school in Riverton City equals 1. The number of culinarian school in Riverton City equals 4. The number of public highschool in Riverton City equals the number of public highschool in Shoreline City. The average number of teachers per public highschool in Riverton City is greater than 0. The average number of teachers per regional medical school in Riverton City equals the difference between the number of culinarian school in Riverton City and the number of public highschool in Shoreline City. The average number of teachers per culinarian school in Riverton City equals the average number of teachers per public highschool in Riverton City. The average number of teachers per culinarian school in Oakbridge City equals 1. The average number of teachers per culinarian school in Riverton City equals 3. The average number of teachers per culinarian school in Shoreline City equals the sum of the average number of teachers per culinarian school in Oakbridge City, the average number of teachers per regional medical school in Riverton City, and the average number of teachers per public highschool in Riverton City. The average number of teachers per public highschool in Shoreline City equals 3 times the total number of schools in Riverton City. Question: What is the average number of teachers per public highschool in Riverton City? Solution: "
}
] |
The number of public highschool in Westhaven City equals 3 plus the number of private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals the number of private middle school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals the average number of teachers per public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 1. The number of private middle school in Hawkesbury equals 1. The number of private middle school in Westhaven City equals the number of private middle school in Hawkesbury. The average number of teachers per public highschool in Westhaven City equals 2. The average number of teachers per public highschool in Hawkesbury is greater than 0. The average number of teachers per private middle school in Westhaven City equals 1. | What is the average number of teachers per public highschool in Hawkesbury? | The question is difficult, so we use equations to solve it. Define average number of teachers per public highschool in Hawkesbury as x; we don't know its value yet but will find it out later. Define average number of teachers per private middle school in Westhaven City as E; so E = x = x. We know E = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 22 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of public highschool in Westhaven City equals 3 plus the number of private middle school in Hawkesbury. The number of public highschool in Hawkesbury equals the number of private middle school in Westhaven City. The average number of teachers per private middle school in Westhaven City equals the average number of teachers per public highschool in Hawkesbury. The average number of teachers per private middle school in Hawkesbury equals 1. The number of private middle school in Hawkesbury equals 1. The number of private middle school in Westhaven City equals the number of private middle school in Hawkesbury. The average number of teachers per public highschool in Westhaven City equals 2. The average number of teachers per public highschool in Hawkesbury is greater than 0. The average number of teachers per private middle school in Westhaven City equals 1. Question: What is the average number of teachers per public highschool in Hawkesbury? Solution: "
}
] |
The average number of teachers per public highschool in Glenfield City equals 2. The number of regional medical school in Brightford equals the number of regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of culinarian school in Westhaven City equals 4 plus the sum of the average number of teachers per culinarian school in Westhaven City and the number of regional medical school in Westhaven City. The average number of teachers per public highschool in Brightford equals 1. The average number of teachers per regional medical school in Glenfield City equals 3. The average number of teachers per public highschool in Brightford equals the number of culinarian school in Brightford. The average number of teachers per regional medical school in Westhaven City equals 4 times the number of culinarian school in Brightford. The number of culinarian school in Brightford exists, and its number is greater than 0. The average number of teachers per culinarian school in Westhaven City equals 2. The number of public highschool in Glenfield City equals 3 plus the average number of teachers per public highschool in Westhaven City. The average number of teachers per regional medical school in Brightford equals 4. The number of public highschool in Brightford equals 4 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of culinarian school in Westhaven City, and the number of regional medical school in Westhaven City. The number of public highschool in Westhaven City equals 3. The average number of teachers per public highschool in Westhaven City equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of regional medical school in Westhaven City, and the number of culinarian school in Westhaven City. The average number of teachers per culinarian school in Brightford equals the total number of schools in Westhaven City. The number of regional medical school in Glenfield City equals the average number of teachers per regional medical school in Brightford. | How many culinarian school does Brightford have? | The question is difficult, so we use equations to solve it. Define culinarian school in Brightford as x; we don't know its value yet but will find it out later. Define average number of teachers per public highschool in Brightford as v; so v = x = x. We know v = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 21 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per public highschool in Glenfield City equals 2. The number of regional medical school in Brightford equals the number of regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of culinarian school in Westhaven City equals 4 plus the sum of the average number of teachers per culinarian school in Westhaven City and the number of regional medical school in Westhaven City. The average number of teachers per public highschool in Brightford equals 1. The average number of teachers per regional medical school in Glenfield City equals 3. The average number of teachers per public highschool in Brightford equals the number of culinarian school in Brightford. The average number of teachers per regional medical school in Westhaven City equals 4 times the number of culinarian school in Brightford. The number of culinarian school in Brightford exists, and its number is greater than 0. The average number of teachers per culinarian school in Westhaven City equals 2. The number of public highschool in Glenfield City equals 3 plus the average number of teachers per public highschool in Westhaven City. The average number of teachers per regional medical school in Brightford equals 4. The number of public highschool in Brightford equals 4 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of culinarian school in Westhaven City, and the number of regional medical school in Westhaven City. The number of public highschool in Westhaven City equals 3. The average number of teachers per public highschool in Westhaven City equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of regional medical school in Westhaven City, and the number of culinarian school in Westhaven City. The average number of teachers per culinarian school in Brightford equals the total number of schools in Westhaven City. The number of regional medical school in Glenfield City equals the average number of teachers per regional medical school in Brightford. Question: How many culinarian school does Brightford have? Solution: "
}
] |
The average number of teachers per regional medical school in Riverton City equals 4. The number of regional medical school in Riverton City equals the difference between the average number of teachers per public highschool in Riverton City and the average number of teachers per private middle school in Ruby Bay. The average number of teachers per regional medical school in Riverton City equals the average number of teachers per public highschool in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals the average number of teachers per public highschool in Riverton City. The number of private middle school in Ruby Bay equals 4. The average number of teachers per regional medical school in Ruby Bay equals 4. The average number of teachers per public highschool in Ruby Bay is greater than 0. The average number of teachers per public highschool in Riverton City equals 3. The number of public highschool in Riverton City equals 3. The number of regional medical school in Ruby Bay equals 2. The number of public highschool in Ruby Bay equals 3 plus the sum of the average number of teachers per public highschool in Ruby Bay, the average number of teachers per public highschool in Riverton City, and the total number of schools in Ruby Bay. | What is the average number of teachers per public highschool in Ruby Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per public highschool in Ruby Bay as x; we don't know its value yet but will find it out later. Define average number of teachers per regional medical school in Riverton City as G; so G = x = x. We know G = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 21 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per regional medical school in Riverton City equals 4. The number of regional medical school in Riverton City equals the difference between the average number of teachers per public highschool in Riverton City and the average number of teachers per private middle school in Ruby Bay. The average number of teachers per regional medical school in Riverton City equals the average number of teachers per public highschool in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals the average number of teachers per public highschool in Riverton City. The number of private middle school in Ruby Bay equals 4. The average number of teachers per regional medical school in Ruby Bay equals 4. The average number of teachers per public highschool in Ruby Bay is greater than 0. The average number of teachers per public highschool in Riverton City equals 3. The number of public highschool in Riverton City equals 3. The number of regional medical school in Ruby Bay equals 2. The number of public highschool in Ruby Bay equals 3 plus the sum of the average number of teachers per public highschool in Ruby Bay, the average number of teachers per public highschool in Riverton City, and the total number of schools in Ruby Bay. Question: What is the average number of teachers per public highschool in Ruby Bay? Solution: "
}
] |
The number of elementary school in Brightford equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of culinarian school in Westhaven City, and the number of culinarian school in Hawkesbury. The average number of teachers per culinarian school in Westhaven City equals 2 times the number of culinarian school in Brightford. The average number of teachers per elementary school in Westhaven City equals the average number of teachers per elementary school in Hawkesbury. The average number of teachers per elementary school in Brightford equals 4. The number of culinarian school in Brightford equals 3. The number of culinarian school in Westhaven City equals 1. The average number of teachers per elementary school in Westhaven City equals 1. The average number of teachers per elementary school in Hawkesbury is greater than 0. The average number of teachers per culinarian school in Hawkesbury equals the number of culinarian school in Brightford. The average number of teachers per culinarian school in Brightford equals 2 times the sum of the number of culinarian school in Hawkesbury, the average number of teachers per elementary school in Westhaven City, and the average number of teachers per culinarian school in Hawkesbury. The number of elementary school in Westhaven City equals 1 plus the average number of teachers per culinarian school in Westhaven City. The number of elementary school in Hawkesbury equals 3. The number of culinarian school in Hawkesbury equals the number of culinarian school in Brightford. | What is the average number of teachers per elementary school in Hawkesbury? | The question is difficult, so we use equations to solve it. Define average number of teachers per elementary school in Hawkesbury as x; we don't know its value yet but will find it out later. Define average number of teachers per elementary school in Westhaven City as A; so A = x = x. We know A = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 15 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of elementary school in Brightford equals 2 times the sum of the average number of teachers per culinarian school in Westhaven City, the number of culinarian school in Westhaven City, and the number of culinarian school in Hawkesbury. The average number of teachers per culinarian school in Westhaven City equals 2 times the number of culinarian school in Brightford. The average number of teachers per elementary school in Westhaven City equals the average number of teachers per elementary school in Hawkesbury. The average number of teachers per elementary school in Brightford equals 4. The number of culinarian school in Brightford equals 3. The number of culinarian school in Westhaven City equals 1. The average number of teachers per elementary school in Westhaven City equals 1. The average number of teachers per elementary school in Hawkesbury is greater than 0. The average number of teachers per culinarian school in Hawkesbury equals the number of culinarian school in Brightford. The average number of teachers per culinarian school in Brightford equals 2 times the sum of the number of culinarian school in Hawkesbury, the average number of teachers per elementary school in Westhaven City, and the average number of teachers per culinarian school in Hawkesbury. The number of elementary school in Westhaven City equals 1 plus the average number of teachers per culinarian school in Westhaven City. The number of elementary school in Hawkesbury equals 3. The number of culinarian school in Hawkesbury equals the number of culinarian school in Brightford. Question: What is the average number of teachers per elementary school in Hawkesbury? Solution: "
}
] |
The average number of teachers per public highschool in Shoreline City equals the average number of teachers per private middle school in Ruby Bay. The number of culinarian school in Shoreline City equals the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay equals 3. The number of culinarian school in Clearwater Bay equals the number of private middle school in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals 2. The average number of teachers per public highschool in Ruby Bay equals 2 times the number of public highschool in Ruby Bay. The number of public highschool in Shoreline City equals 3. The average number of teachers per culinarian school in Shoreline City equals 2. The number of private middle school in Ruby Bay equals 1. The average number of teachers per private middle school in Shoreline City equals the sum of the number of private middle school in Ruby Bay, the average number of teachers per culinarian school in Shoreline City, the number of public highschool in Ruby Bay, and the number of private middle school in Shoreline City. The number of public highschool in Ruby Bay equals 3 times the number of private middle school in Shoreline City. The number of public highschool in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The average number of teachers per public highschool in Clearwater Bay is greater than 0. The number of private middle school in Shoreline City equals 1. | What is the average number of teachers per public highschool in Clearwater Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per public highschool in Clearwater Bay as x; we don't know its value yet but will find it out later. Define average number of teachers per culinarian school in Clearwater Bay as G; so G = x = x. We know G = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 9 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per public highschool in Shoreline City equals the average number of teachers per private middle school in Ruby Bay. The number of culinarian school in Shoreline City equals the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay equals 3. The number of culinarian school in Clearwater Bay equals the number of private middle school in Ruby Bay. The average number of teachers per private middle school in Ruby Bay equals 2. The average number of teachers per public highschool in Ruby Bay equals 2 times the number of public highschool in Ruby Bay. The number of public highschool in Shoreline City equals 3. The average number of teachers per culinarian school in Shoreline City equals 2. The number of private middle school in Ruby Bay equals 1. The average number of teachers per private middle school in Shoreline City equals the sum of the number of private middle school in Ruby Bay, the average number of teachers per culinarian school in Shoreline City, the number of public highschool in Ruby Bay, and the number of private middle school in Shoreline City. The number of public highschool in Ruby Bay equals 3 times the number of private middle school in Shoreline City. The number of public highschool in Clearwater Bay equals the average number of teachers per public highschool in Clearwater Bay. The average number of teachers per public highschool in Clearwater Bay is greater than 0. The number of private middle school in Shoreline City equals 1. Question: What is the average number of teachers per public highschool in Clearwater Bay? Solution: "
}
] |
The number of public highschool in Riverton City equals the average number of teachers per public highschool in Shoreline City. The number of public highschool in Shoreline City equals 3 times the number of culinarian school in Clearwater Bay. The average number of teachers per elementary school in Clearwater Bay equals the number of culinarian school in Clearwater Bay. The average number of teachers per public highschool in Shoreline City equals 4 times the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 1. The number of culinarian school in Clearwater Bay equals the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay is greater than 0. The average number of teachers per public highschool in Riverton City equals 2 plus the difference between the number of public highschool in Clearwater Bay and the average number of teachers per public highschool in Shoreline City. The average number of teachers per public highschool in Clearwater Bay equals 2. The number of culinarian school in Clearwater Bay equals 3. The number of elementary school in Clearwater Bay equals 4 times the difference between the average number of teachers per public highschool in Shoreline City and the number of public highschool in Clearwater Bay. | What is the average number of teachers per culinarian school in Clearwater Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per culinarian school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define culinarian school in Clearwater Bay as A; so A = x = x. We know A = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 21 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of public highschool in Riverton City equals the average number of teachers per public highschool in Shoreline City. The number of public highschool in Shoreline City equals 3 times the number of culinarian school in Clearwater Bay. The average number of teachers per elementary school in Clearwater Bay equals the number of culinarian school in Clearwater Bay. The average number of teachers per public highschool in Shoreline City equals 4 times the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 1. The number of culinarian school in Clearwater Bay equals the average number of teachers per culinarian school in Clearwater Bay. The average number of teachers per culinarian school in Clearwater Bay is greater than 0. The average number of teachers per public highschool in Riverton City equals 2 plus the difference between the number of public highschool in Clearwater Bay and the average number of teachers per public highschool in Shoreline City. The average number of teachers per public highschool in Clearwater Bay equals 2. The number of culinarian school in Clearwater Bay equals 3. The number of elementary school in Clearwater Bay equals 4 times the difference between the average number of teachers per public highschool in Shoreline City and the number of public highschool in Clearwater Bay. Question: What is the average number of teachers per culinarian school in Clearwater Bay? Solution: "
}
] |
The average number of teachers per private middle school in Evervale City equals 1. The number of regional medical school in Glenfield City equals 2 plus the number of private middle school in Evervale City. The average number of teachers per private middle school in Glenfield City equals the number of regional medical school in Brightford. The number of private middle school in Glenfield City equals 2. The average number of teachers per regional medical school in Brightford is greater than 0. The average number of teachers per regional medical school in Glenfield City equals the total number of schools in Brightford. The number of private middle school in Glenfield City equals the average number of teachers per regional medical school in Brightford. The number of regional medical school in Brightford equals the average number of teachers per private middle school in Evervale City. The number of private middle school in Evervale City equals 4. | What is the average number of teachers per regional medical school in Brightford? | The question is difficult, so we use equations to solve it. Define average number of teachers per regional medical school in Brightford as x; we don't know its value yet but will find it out later. Define private middle school in Glenfield City as f; so f = x = x. We know f = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 4 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per private middle school in Evervale City equals 1. The number of regional medical school in Glenfield City equals 2 plus the number of private middle school in Evervale City. The average number of teachers per private middle school in Glenfield City equals the number of regional medical school in Brightford. The number of private middle school in Glenfield City equals 2. The average number of teachers per regional medical school in Brightford is greater than 0. The average number of teachers per regional medical school in Glenfield City equals the total number of schools in Brightford. The number of private middle school in Glenfield City equals the average number of teachers per regional medical school in Brightford. The number of regional medical school in Brightford equals the average number of teachers per private middle school in Evervale City. The number of private middle school in Evervale City equals 4. Question: What is the average number of teachers per regional medical school in Brightford? Solution: "
}
] |
The average number of teachers per elementary school in Oakbridge City equals 2 times the total number of schools in Ruby Bay. The average number of teachers per culinarian school in Oakbridge City equals the average number of teachers per elementary school in Ruby Bay. The number of culinarian school in Ruby Bay equals 1 plus the average number of teachers per culinarian school in Oakbridge City. The number of elementary school in Ruby Bay equals 1. The average number of teachers per elementary school in Ruby Bay is greater than 0. The average number of teachers per culinarian school in Oakbridge City equals 2. The number of culinarian school in Oakbridge City equals the sum of the average number of teachers per elementary school in Ruby Bay, the average number of teachers per culinarian school in Oakbridge City, and the average number of teachers per elementary school in Oakbridge City. The number of elementary school in Oakbridge City equals 2. The average number of teachers per culinarian school in Ruby Bay equals 3. | What is the average number of teachers per elementary school in Ruby Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per elementary school in Ruby Bay as x; we don't know its value yet but will find it out later. Define average number of teachers per culinarian school in Oakbridge City as u; so u = x = x. We know u = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 7 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of teachers per elementary school in Oakbridge City equals 2 times the total number of schools in Ruby Bay. The average number of teachers per culinarian school in Oakbridge City equals the average number of teachers per elementary school in Ruby Bay. The number of culinarian school in Ruby Bay equals 1 plus the average number of teachers per culinarian school in Oakbridge City. The number of elementary school in Ruby Bay equals 1. The average number of teachers per elementary school in Ruby Bay is greater than 0. The average number of teachers per culinarian school in Oakbridge City equals 2. The number of culinarian school in Oakbridge City equals the sum of the average number of teachers per elementary school in Ruby Bay, the average number of teachers per culinarian school in Oakbridge City, and the average number of teachers per elementary school in Oakbridge City. The number of elementary school in Oakbridge City equals 2. The average number of teachers per culinarian school in Ruby Bay equals 3. Question: What is the average number of teachers per elementary school in Ruby Bay? Solution: "
}
] |
The number of public highschool in Riverton City equals 4. The average number of teachers per public highschool in Shoreline City equals the average number of teachers per regional medical school in Clearwater Bay. The number of regional medical school in Shoreline City equals 1. The average number of teachers per regional medical school in Riverton City equals 3 plus the average number of teachers per regional medical school in Shoreline City. The number of public highschool in Shoreline City equals 3 times the number of elementary school in Clearwater Bay. The number of elementary school in Shoreline City equals 3 times the number of regional medical school in Shoreline City. The average number of teachers per public highschool in Shoreline City equals 2. The average number of teachers per elementary school in Shoreline City equals 1 plus the number of elementary school in Shoreline City. The number of elementary school in Clearwater Bay equals the sum of the average number of teachers per elementary school in Shoreline City and the number of regional medical school in Shoreline City. The average number of teachers per elementary school in Riverton City equals the difference between the number of elementary school in Clearwater Bay and the number of elementary school in Shoreline City. The average number of teachers per regional medical school in Clearwater Bay is greater than 0. The average number of teachers per elementary school in Clearwater Bay equals the number of elementary school in Riverton City. The number of elementary school in Riverton City equals the sum of the number of elementary school in Shoreline City, the number of regional medical school in Shoreline City, and the average number of teachers per elementary school in Shoreline City. The number of public highschool in Clearwater Bay equals 3. The average number of teachers per public highschool in Riverton City equals 2. The average number of teachers per regional medical school in Shoreline City equals the sum of the average number of teachers per elementary school in Shoreline City and the number of elementary school in Shoreline City. The number of regional medical school in Clearwater Bay equals the average number of teachers per public highschool in Riverton City. The average number of teachers per public highschool in Clearwater Bay equals 3 times the number of elementary school in Riverton City. The number of regional medical school in Riverton City equals 1 plus the average number of teachers per public highschool in Clearwater Bay. | What is the average number of teachers per regional medical school in Clearwater Bay? | The question is difficult, so we use equations to solve it. Define average number of teachers per regional medical school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define average number of teachers per public highschool in Shoreline City as U; so U = x = x. We know U = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 6 | teachers_in_school | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Note: the total number of schools in one location refers to sum of all types of schools ever mentioned for the specific location throughout the problem. IMPORTANT: if the a type of school is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems school quantities are not applicable for the present one. The average number of teachers of the same type of school might vary across different locations. The number of teachers from all schools of a location refers to the sum of the TOTAL teachers (not average number of teachers) from all type of schools mentioned for that specific location. Hint: the number of teachers of one type of school in a location equals the average teacher per that type of schools in location times the number of that type of schools in location. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of schools or teachers MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of public highschool in Riverton City equals 4. The average number of teachers per public highschool in Shoreline City equals the average number of teachers per regional medical school in Clearwater Bay. The number of regional medical school in Shoreline City equals 1. The average number of teachers per regional medical school in Riverton City equals 3 plus the average number of teachers per regional medical school in Shoreline City. The number of public highschool in Shoreline City equals 3 times the number of elementary school in Clearwater Bay. The number of elementary school in Shoreline City equals 3 times the number of regional medical school in Shoreline City. The average number of teachers per public highschool in Shoreline City equals 2. The average number of teachers per elementary school in Shoreline City equals 1 plus the number of elementary school in Shoreline City. The number of elementary school in Clearwater Bay equals the sum of the average number of teachers per elementary school in Shoreline City and the number of regional medical school in Shoreline City. The average number of teachers per elementary school in Riverton City equals the difference between the number of elementary school in Clearwater Bay and the number of elementary school in Shoreline City. The average number of teachers per regional medical school in Clearwater Bay is greater than 0. The average number of teachers per elementary school in Clearwater Bay equals the number of elementary school in Riverton City. The number of elementary school in Riverton City equals the sum of the number of elementary school in Shoreline City, the number of regional medical school in Shoreline City, and the average number of teachers per elementary school in Shoreline City. The number of public highschool in Clearwater Bay equals 3. The average number of teachers per public highschool in Riverton City equals 2. The average number of teachers per regional medical school in Shoreline City equals the sum of the average number of teachers per elementary school in Shoreline City and the number of elementary school in Shoreline City. The number of regional medical school in Clearwater Bay equals the average number of teachers per public highschool in Riverton City. The average number of teachers per public highschool in Clearwater Bay equals 3 times the number of elementary school in Riverton City. The number of regional medical school in Riverton City equals 1 plus the average number of teachers per public highschool in Clearwater Bay. Question: What is the average number of teachers per regional medical school in Clearwater Bay? Solution: "
}
] |
The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Festival Lumière de Valmont equals 4 plus the number of calm road movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per intense detective thriller in Festival Lumière de Valmont and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals 3. The average number of nominations per calm road movie in Festival de Saint-Rivage equals 4. The average number of nominations per intense detective thriller in Festival Lumière de Valmont is greater than 0. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the average number of nominations per intense detective thriller in Festival Lumière de Valmont. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage, the total number of movies in Festival de Clairmont, the number of calm road movie in Festival de Saint-Rivage, and the total number of movies in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 2 times the number of intense detective thriller in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 1 plus the number of intense detective thriller in Festival de Clairmont. The number of calm road movie in Festival de Saint-Rivage equals 4. | What is the average number of nominations per intense detective thriller in Festival Lumière de Valmont? | The question is difficult, so we use equations to solve it. Define average number of nominations per intense detective thriller in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define average number of nominations per calm road movie in Festival de Saint-Rivage as w; so w = x = x. We know w = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 3 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Festival Lumière de Valmont equals 4 plus the number of calm road movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Clairmont equals the difference between the average number of nominations per intense detective thriller in Festival Lumière de Valmont and the average number of nominations per calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals 3. The average number of nominations per calm road movie in Festival de Saint-Rivage equals 4. The average number of nominations per intense detective thriller in Festival Lumière de Valmont is greater than 0. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the average number of nominations per intense detective thriller in Festival Lumière de Valmont. The average number of nominations per upbeat metropolis comedy in Festival de Clairmont equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage, the total number of movies in Festival de Clairmont, the number of calm road movie in Festival de Saint-Rivage, and the total number of movies in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 2 times the number of intense detective thriller in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 1 plus the number of intense detective thriller in Festival de Clairmont. The number of calm road movie in Festival de Saint-Rivage equals 4. Question: What is the average number of nominations per intense detective thriller in Festival Lumière de Valmont? Solution: "
}
] |
The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival is greater than 0. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. | What is the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival? | The question is difficult, so we use equations to solve it. Define average number of nominations per upbeat metropolis comedy in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define average number of nominations per futuristic sci-fi movie in Northwood Movie Festival as N; so N = x = x. We know N = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 11 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival is greater than 0. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. Question: What is the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival? Solution: "
}
] |
The number of upbeat metropolis comedy in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals 3. The number of solemn period drama in Festival de Saint-Rivage equals the average number of nominations per intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 2 plus the number of upbeat metropolis comedy in Rêves de Belleville. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals 2. The average number of nominations per solemn period drama in Rêves de Belleville equals the difference between the number of upbeat metropolis comedy in Rêves de Belleville and the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per solemn period drama in Festival de Saint-Rivage is greater than 0. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1. The average number of nominations per upbeat metropolis comedy in Cinéma de Montreval equals the sum of the average number of nominations per solemn period drama in Festival de Saint-Rivage, the average number of nominations per intense detective thriller in Rêves de Belleville, the number of solemn period drama in Festival de Saint-Rivage, and the number of solemn period drama in Cinéma de Montreval. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the average number of nominations per solemn period drama in Festival de Saint-Rivage. The average number of nominations per intense detective thriller in Rêves de Belleville equals 2. The average number of nominations per upbeat metropolis comedy in Rêves de Belleville equals the difference between the average number of nominations per solemn period drama in Festival de Saint-Rivage and the number of solemn period drama in Cinéma de Montreval. The number of intense detective thriller in Festival de Saint-Rivage equals the sum of the average number of nominations per intense detective thriller in Rêves de Belleville, the number of upbeat metropolis comedy in Rêves de Belleville, and the number of upbeat metropolis comedy in Cinéma de Montreval. The average number of nominations per solemn period drama in Cinéma de Montreval equals 1 plus the average number of nominations per intense detective thriller in Rêves de Belleville. The number of solemn period drama in Cinéma de Montreval equals 4. | What is the average number of nominations per solemn period drama in Festival de Saint-Rivage? | The question is difficult, so we use equations to solve it. Define average number of nominations per solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define average number of nominations per intense detective thriller in Festival de Saint-Rivage as B; so B = x = x. We know B = 2, so we have x = 2 and we solve it through the following steps: Simplifying the equation: x = 2. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2. | 2 | 2 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of upbeat metropolis comedy in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals 3. The number of solemn period drama in Festival de Saint-Rivage equals the average number of nominations per intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 2 plus the number of upbeat metropolis comedy in Rêves de Belleville. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals 2. The average number of nominations per solemn period drama in Rêves de Belleville equals the difference between the number of upbeat metropolis comedy in Rêves de Belleville and the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per solemn period drama in Festival de Saint-Rivage is greater than 0. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1. The average number of nominations per upbeat metropolis comedy in Cinéma de Montreval equals the sum of the average number of nominations per solemn period drama in Festival de Saint-Rivage, the average number of nominations per intense detective thriller in Rêves de Belleville, the number of solemn period drama in Festival de Saint-Rivage, and the number of solemn period drama in Cinéma de Montreval. The average number of nominations per intense detective thriller in Festival de Saint-Rivage equals the average number of nominations per solemn period drama in Festival de Saint-Rivage. The average number of nominations per intense detective thriller in Rêves de Belleville equals 2. The average number of nominations per upbeat metropolis comedy in Rêves de Belleville equals the difference between the average number of nominations per solemn period drama in Festival de Saint-Rivage and the number of solemn period drama in Cinéma de Montreval. The number of intense detective thriller in Festival de Saint-Rivage equals the sum of the average number of nominations per intense detective thriller in Rêves de Belleville, the number of upbeat metropolis comedy in Rêves de Belleville, and the number of upbeat metropolis comedy in Cinéma de Montreval. The average number of nominations per solemn period drama in Cinéma de Montreval equals 1 plus the average number of nominations per intense detective thriller in Rêves de Belleville. The number of solemn period drama in Cinéma de Montreval equals 4. Question: What is the average number of nominations per solemn period drama in Festival de Saint-Rivage? Solution: "
}
] |
The average number of nominations per solemn period drama in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The total number of movies in Northwood Movie Festival equals 3. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals 1 plus the average number of nominations per calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the difference between the number of futuristic sci-fi movie in Northwood Movie Festival and the total number of movies in Northwood Movie Festival. The average number of nominations per solemn period drama in Taylor Movie Festival equals 2. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4 plus the average number of nominations per solemn period drama in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival exists, and its number is greater than 0. | How many futuristic sci-fi movie does Northwood Movie Festival have? | The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Northwood Movie Festival as p; so p = x = x. We know p = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 18 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per solemn period drama in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The total number of movies in Northwood Movie Festival equals 3. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals 1 plus the average number of nominations per calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the difference between the number of futuristic sci-fi movie in Northwood Movie Festival and the total number of movies in Northwood Movie Festival. The average number of nominations per solemn period drama in Taylor Movie Festival equals 2. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4 plus the average number of nominations per solemn period drama in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival exists, and its number is greater than 0. Question: How many futuristic sci-fi movie does Northwood Movie Festival have? Solution: "
}
] |
The number of futuristic sci-fi movie in Cinéma de Montreval equals 1. The number of intense detective thriller in Cinéma de Montreval equals 4 plus the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Clairmont equals 1. The number of intense detective thriller in Festival Lumière de Valmont equals 1. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of calm road movie in Festival Lumière de Valmont equals the number of intense detective thriller in Cinéma de Montreval. The average number of nominations per calm road movie in Festival Lumière de Valmont is greater than 0. The average number of nominations per intense detective thriller in Festival Lumière de Valmont equals the difference between the number of futuristic sci-fi movie in Festival Lumière de Valmont and the number of intense detective thriller in Cinéma de Montreval. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 1. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals 3. The average number of nominations per futuristic sci-fi movie in Cinéma de Montreval equals the sum of the average number of nominations per intense detective thriller in Festival de Clairmont, the average number of nominations per intense detective thriller in Festival Lumière de Valmont, and the average number of nominations per calm road movie in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Cinéma de Montreval equals 3 times the total number of movies in Festival Lumière de Valmont. | What is the average number of nominations per calm road movie in Festival Lumière de Valmont? | The question is difficult, so we use equations to solve it. Define average number of nominations per calm road movie in Festival Lumière de Valmont as x; we don't know its value yet but will find it out later. Define average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont as P; so P = x = x. We know P = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 15 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of futuristic sci-fi movie in Cinéma de Montreval equals 1. The number of intense detective thriller in Cinéma de Montreval equals 4 plus the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Clairmont equals 1. The number of intense detective thriller in Festival Lumière de Valmont equals 1. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of calm road movie in Festival Lumière de Valmont equals the number of intense detective thriller in Cinéma de Montreval. The average number of nominations per calm road movie in Festival Lumière de Valmont is greater than 0. The average number of nominations per intense detective thriller in Festival Lumière de Valmont equals the difference between the number of futuristic sci-fi movie in Festival Lumière de Valmont and the number of intense detective thriller in Cinéma de Montreval. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals the average number of nominations per calm road movie in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Festival de Clairmont equals 1. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals 3. The average number of nominations per futuristic sci-fi movie in Cinéma de Montreval equals the sum of the average number of nominations per intense detective thriller in Festival de Clairmont, the average number of nominations per intense detective thriller in Festival Lumière de Valmont, and the average number of nominations per calm road movie in Festival Lumière de Valmont. The average number of nominations per intense detective thriller in Cinéma de Montreval equals 3 times the total number of movies in Festival Lumière de Valmont. Question: What is the average number of nominations per calm road movie in Festival Lumière de Valmont? Solution: "
}
] |
The number of solemn period drama in Northwood Movie Festival equals 3 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of futuristic sci-fi movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per solemn period drama in Northwood Movie Festival equals 2. The average number of nominations per solemn period drama in Verdi Movie Festival is greater than 0. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 1. | What is the average number of nominations per solemn period drama in Verdi Movie Festival? | The question is difficult, so we use equations to solve it. Define average number of nominations per solemn period drama in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define average number of nominations per futuristic sci-fi movie in Northwood Movie Festival as E; so E = x = x. We know E = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 5 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of solemn period drama in Northwood Movie Festival equals 3 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of futuristic sci-fi movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals the average number of nominations per solemn period drama in Verdi Movie Festival. The average number of nominations per futuristic sci-fi movie in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The average number of nominations per solemn period drama in Northwood Movie Festival equals 2. The average number of nominations per solemn period drama in Verdi Movie Festival is greater than 0. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 1. Question: What is the average number of nominations per solemn period drama in Verdi Movie Festival? Solution: "
}
] |
The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 1. The average number of nominations per calm road movie in West Sahara Movie Festival equals 3. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 4 times the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival exists, and its number is greater than 0. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3 plus the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals 4 times the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Northwood Movie Festival equals 2 times the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the number of futuristic sci-fi movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. | How many futuristic sci-fi movie does Golden Banana Movie Festival have? | The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define average number of nominations per calm road movie in Golden Banana Movie Festival as v; so v = x = x. We know v = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 21 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The average number of nominations per calm road movie in Golden Banana Movie Festival equals 1. The average number of nominations per calm road movie in West Sahara Movie Festival equals 3. The average number of nominations per calm road movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 4 times the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival exists, and its number is greater than 0. The average number of nominations per futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3 plus the average number of nominations per calm road movie in Northwood Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals 4 times the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 3. The average number of nominations per calm road movie in Northwood Movie Festival equals 2 times the sum of the average number of nominations per futuristic sci-fi movie in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the number of futuristic sci-fi movie in Northwood Movie Festival. The average number of nominations per futuristic sci-fi movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the average number of nominations per intense detective thriller in Golden Banana Movie Festival. Question: How many futuristic sci-fi movie does Golden Banana Movie Festival have? Solution: "
}
] |
The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the difference between the average number of nominations per calm road movie in Festival Lumière de Valmont and the average number of nominations per calm road movie in Festival de Saint-Rivage. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the average number of nominations per calm road movie in Festival Lumière de Valmont. The number of calm road movie in Festival de Saint-Rivage equals 4. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 4. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage is greater than 0. The average number of nominations per calm road movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 plus the sum of the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage, the average number of nominations per calm road movie in Festival Lumière de Valmont, and the total number of movies in Festival de Saint-Rivage. | What is the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage? | The question is difficult, so we use equations to solve it. Define average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont as G; so G = x = x. We know G = 4, so we have x = 4 and we solve it through the following steps: Simplifying the equation: x = 4. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4. | 2 | 11 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the difference between the average number of nominations per calm road movie in Festival Lumière de Valmont and the average number of nominations per calm road movie in Festival de Saint-Rivage. The average number of nominations per futuristic sci-fi movie in Festival Lumière de Valmont equals the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage. The average number of nominations per calm road movie in Festival de Saint-Rivage equals the average number of nominations per calm road movie in Festival Lumière de Valmont. The number of calm road movie in Festival de Saint-Rivage equals 4. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 4. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage is greater than 0. The average number of nominations per calm road movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 plus the sum of the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage, the average number of nominations per calm road movie in Festival Lumière de Valmont, and the total number of movies in Festival de Saint-Rivage. Question: What is the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage? Solution: "
}
] |
The number of intense detective thriller in Golden Banana Movie Festival equals 2 times the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, the number of upbeat metropolis comedy in Northwood Movie Festival, and the number of upbeat metropolis comedy in Verdi Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 2 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 1. The average number of nominations per intense detective thriller in Verdi Movie Festival is greater than 0. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the sum of the number of upbeat metropolis comedy in Verdi Movie Festival, the average number of nominations per intense detective thriller in Northwood Movie Festival, and the average number of nominations per upbeat metropolis comedy in Verdi Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 1 plus the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. | What is the average number of nominations per intense detective thriller in Verdi Movie Festival? | The question is difficult, so we use equations to solve it. Define average number of nominations per intense detective thriller in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define average number of nominations per intense detective thriller in Northwood Movie Festival as A; so A = x = x. We know A = 1, so we have x = 1 and we solve it through the following steps: Simplifying the equation: x = 1. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1. | 2 | 18 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The number of intense detective thriller in Golden Banana Movie Festival equals 2 times the sum of the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival, the number of upbeat metropolis comedy in Northwood Movie Festival, and the number of upbeat metropolis comedy in Verdi Movie Festival. The average number of nominations per upbeat metropolis comedy in Northwood Movie Festival equals 2 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per intense detective thriller in Northwood Movie Festival equals the average number of nominations per intense detective thriller in Verdi Movie Festival. The average number of nominations per intense detective thriller in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1. The average number of nominations per intense detective thriller in Northwood Movie Festival equals 1. The average number of nominations per intense detective thriller in Verdi Movie Festival is greater than 0. The average number of nominations per upbeat metropolis comedy in Verdi Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The average number of nominations per upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the sum of the number of upbeat metropolis comedy in Verdi Movie Festival, the average number of nominations per intense detective thriller in Northwood Movie Festival, and the average number of nominations per upbeat metropolis comedy in Verdi Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 1 plus the average number of nominations per upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. Question: What is the average number of nominations per intense detective thriller in Verdi Movie Festival? Solution: "
}
] |
The average number of nominations per futuristic sci-fi movie in Cinéma de Montreval equals the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Cinéma de Montreval equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage equals 2. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 2 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3. The average number of nominations per solemn period drama in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1. The average number of nominations per intense detective thriller in Cinéma de Montreval equals the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the average number of nominations per solemn period drama in Cinéma de Montreval, the number of solemn period drama in Festival de Saint-Rivage, and the number of intense detective thriller in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals 3 times the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per intense detective thriller in Rêves de Belleville is greater than 0. The number of intense detective thriller in Cinéma de Montreval equals 1. | What is the average number of nominations per intense detective thriller in Rêves de Belleville? | The question is difficult, so we use equations to solve it. Define average number of nominations per intense detective thriller in Rêves de Belleville as x; we don't know its value yet but will find it out later. Define average number of nominations per futuristic sci-fi movie in Rêves de Belleville as G; so G = x = x. We know G = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3. | 2 | 2 | movie_festival_awards | forwardreverse | zero_context | 3 | [
{
"role": "system",
"content": "You are a helpful assistant"
},
{
"role": "user",
"content": "Answer the questions below. Commedy, drama, and thriller are all movies types. Note: the total number of movies in one movie festival refers to sum of all types of movies ever mentioned for the specific movie festival throughout the problem. IMPORTANT: if the a type of movies is never mentioned for a location for that specific problem, assume its INEXISTENCE in that location (number in the location = 0). Previous problems movies quantities are not applicable for the present one. The average number of nominations of the same type of festival might vary across different locations. The number of total movie nominations from all movies of a festival refers to the sum of the TOTAL movie nominations (not average number of nominations) from all types of movies mentioned for that specific location. Hint: the number of total movie nomination of one type of movie in a festival equals the average nomination per that type of movie in festival times the number of that type of movies in festival. Each question is self-contained INDEPENDENT of the others. Quantities of previous problems is NOT correct for the new problem, so quantities of movies or nominations MUST be recalculated for each question! Explain your calculation in the detailed step-by-step manner. Please first give out the arguments then the answer. Final answer needs to be presented in the format 'Answer: xxx', where xxx is the number you calculated.The following questions might be easier to solve by equations."
},
{
"role": "user",
"content": "Problem: The average number of nominations per futuristic sci-fi movie in Cinéma de Montreval equals the average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Cinéma de Montreval equals the average number of nominations per futuristic sci-fi movie in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per futuristic sci-fi movie in Rêves de Belleville equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The average number of nominations per futuristic sci-fi movie in Festival de Saint-Rivage equals 2. The average number of nominations per solemn period drama in Festival de Saint-Rivage equals 2 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3. The average number of nominations per solemn period drama in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1. The average number of nominations per intense detective thriller in Cinéma de Montreval equals the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the average number of nominations per solemn period drama in Cinéma de Montreval, the number of solemn period drama in Festival de Saint-Rivage, and the number of intense detective thriller in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals 3 times the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals the average number of nominations per intense detective thriller in Rêves de Belleville. The average number of nominations per intense detective thriller in Rêves de Belleville is greater than 0. The number of intense detective thriller in Cinéma de Montreval equals 1. Question: What is the average number of nominations per intense detective thriller in Rêves de Belleville? Solution: "
}
] |
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