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NLP Centre, Faculty of Informatics, Masaryk University 14

aqua_rat__I8oaLCtCOhbqsJDO

At a Supermarket a certain item has increased from 72 cents per pound to 78 cents per pound. What is the % increase in the cost of item? Select: A) 6.33% B) 7.22% C) 8.33% D) 8% E) 7%

Percent change = (New Value- Old Value )/ old value x 100 =((78-72)/72)x100 = (6/72)*100 = 8.33% There was an 8.33% increase in the cost of item answer -8.33% = 8.33% <result>C</result>

C

At a Supermarket a certain item has increased from 72 cents per pound to 78 cents per pound. What is the % increase in the cost of item?

aqua_rat__wb30Ksc8cGwCILeW

How many positive 5-digit integers have the odd sum E of their digits? Choose one: A) 9*10^2 B) 9*10^3 C) 10^4 D) 45*10^3 E) 9*10^4

We are looking at numbers between 10000 and 99999 both inclusive. There are 90000 numbers. Now for 10000 : sum of digits is odd; 10001 :sum of digits is even; 10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd. (Exception for the above statement : When it is 10009 the E sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal) This means exactly half of the numbers will have odd sum of their digits. i.e 45000 Answer :45*10^3 <result>D</result>

D

How many positive 5-digit integers have the odd sum E of their digits?

aqua_rat__kaQB1RFW086ew0kN

There are different 15 circles. What is the number of the greatest possible points with which the circles intersect? Pick. A) 390 B) 100 C) 110 D) 180 E) 210

Maximum points of intersection between n different circles = n*(n - 1) = 15*14= <gadget id="calculator">15*14</gadget> <output>210</output> 210 Answer: 210 <result>E</result>

E

There are different 15 circles. What is the number of the greatest possible points with which the circles intersect?

aqua_rat__XGdeSFvhQqBUC3TZ

B completes a work in 9 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days? Answers. A) 3.75 days B) 4.73 days C) 5.75 days D) 6.75 days E) 7.73 days

1/9 + 1/10 = 19/90 90/19 = 4.73 days ANSWER: 4.73 days <result>B</result>

B

B completes a work in 9 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days?

aqua_rat__s8uQk0bc51hySg26

A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? Choose the correct choice from the following options A) 1/3 B) 1/4 C) 1/5 D) 1/7 E) 1/8

Explanation: Suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture =(3-3x/8+x)litres Quantity of syrup in new mixture =(5-5x/8)litres (3 - 3x/8 +x)=(5 - 5x/8) =&gt;5x + 24 = 40 - 5x =&gt;10x = 16 =&gt;x = 8/5 So, part of the mixture replaced =(8/5 x 1/8)=1/5. ANSWER IS 1/5 <result>C</result>

C

A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

aqua_rat__inMmL25vZ8KAdZQN

A car is running at a speed of 96kmph. What distance will it cover in 14sec? Choose the correct choice from the following: A) 378m B) 350m C) 380m D) 200m E) 250m

Speed = 96kmph = 96*5/18 = 27 m/s Distance covered in 14sec = 27*14= <gadget id="calculator">27*14</gadget> <output>378</output> 378m 378mnswer is 378m <result>A</result>

A

A car is running at a speed of 96kmph. What distance will it cover in 14sec?

aqua_rat__Ne7V8kFukOG98LkR

The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is? Pick one: A) 4 B) 3 C) 5 D) 6 E) 7

Let seventh observation = X. Then, according to the question we have =&gt; (66 + X) / 7 = 10 =&gt; X = 4. Hence, the seventh observation is 4. 4NSWER:4 <result>A</result>

A

The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is?

aqua_rat__HcWQnjBW9SizA9S9

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is : Choose the correct choice from the following choices. A) 4.37% B) 5% C) 6% D) 8.75% E) None of these

Solution Increase in 10 year= (262500 - 175000)= <gadget id="calculator">(262500 - 175000)</gadget> <output>87_500</output> 87500. Increase%=( f87500/175000x 100 )% = 50% ∴ Required average = ( 50/10 )= <gadget id="calculator">( 50/10 )</gadget> <output>5</output> 5% Answer 5% <result>B</result>

B

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is :

aqua_rat__LCqYyPMnDsEFymR9

If a + b = y and a - b = z , then 3ab = can someone explain! Pick one: A) (3y^2 - 3z^2)/4 B) (3z^2 - 3y^2)/4 C) 3y+3z/2 D) 3y - 3z/2 E) 3y^2 - 3z^2/2

plugging numbers is quite fast in this case: Let a=1 b=2 Then; y= 1+2= <gadget id="calculator">1+2</gadget> <output>3</output> &gt; 3 and z= 1-2=&gt; -1 Question asks 3ab=......... As our number 3ab= 3*1*2= <gadget id="calculator">3*1*2</gadget> <output>6</output> 6 now plug the value of y and z in the answer choices. Option A gives 6 and that is the number we need. Hence: (3y^2 - 3z^2)/4ns is (3y^2 - 3z^2)/4. <result>A</result>

A

If a + b = y and a - b = z , then 3ab = can someone explain!

aqua_rat__dEgUAz3dqyLesgIr

If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number? Choose the correct choice from the following choices A) 12 B) 18 C) 20 D) 24 E) 26

2:3 2x + 10 : 3x + 10 = 3 : 4 4[2x + 10] = 3[3x + 10] 8x + 40 = 9x + 30 9x - 8x = 40 - 30= <gadget id="calculator">40 - 30</gadget> <output>10</output> 10 Then smallest number is= 2 2x = 20 20 <result>C</result>

C

If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?

aqua_rat__BeAaicz41iziKFhg

A batsman in his 12th innings makes a score of 65 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’? Choose the correct choice from the following answers A) 42 B) 43 C) 44 D) 45 E) 46

Let ‘x’ be the average score after 12 th innings ⇒ 12x = 11 × (x – 2) + 65 ∴ x = 43 Answer 43 <result>B</result>

B

A batsman in his 12th innings makes a score of 65 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’?

aqua_rat__4NvlfUrWYgFd2M7G

In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 7 to the thrice of the remainder. The dividend is Choose the most appropriate option: A) 74 B) 78 C) 86 D) 92 E) 106

Divisor = (6 * 3) + 7= <gadget id="calculator">(6 * 3) + 7</gadget> <output>25</output> 25 5 * Quotient= 25 Quotient = 5. Dividend = (Divisor * Quotient) + Remainder Dividend = (20 * 5) + 6= <gadget id="calculator">(20 * 5) + 6</gadget> <output>106</output> 106. 106) <result>E</result>

E

In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 7 to the thrice of the remainder. The dividend is

aqua_rat__N5nrguix9AfK4vSR

The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person? Answers A) 70kg B) 75kg C) 80kg D) 85kg E) 90kg

Total weight increased = (8 x 2.5) kg = 20 kg. Weight of new person = (55 + 20)= <gadget id="calculator">(55 + 20)</gadget> <output>75</output> 75 kg. 75kg) <result>B</result>

B

The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person?

aqua_rat__OweQL0202nOySW9K

Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip? Choose the correct option: A) 10 B) 8 C) 6 D) 4 E) 2

Explanation: Amy can travel clockwise or anticlockwise on the diagram. Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes. Total routes = 8 Answer: 8 <result>B</result>

B

Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?

aqua_rat__n4cPbpsOLZXhNwHh

Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 25 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B? Choose the correct answer: A) 80 lakh B) 50 lakh C) 40 lakh D) 60 lakh E) None of these

Let the incomes of two companies A and B be 5x and 8x respectively. From the question, 5x+25/8x=5/4 ⇒ 20x + 100 = 40x ∴ x = 5 ∴ Income of company B = 8x = 40 lakh Answer 40 lakh <result>C</result>

C

Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 25 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?

aqua_rat__lA6s1O026nURHNYA

The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides. Answers: A) 0 sq m B) 2 sq m C) 9 sq m D) 20 sq m E) 5 sq m

S = (1 + 2 + 3)/2= <gadget id="calculator">(1 + 2 + 3)/2</gadget> <output>3</output> 3=&gt; No triangle exists 0 sq mnswer: 0 sq m <result>A</result>

A

The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.

aqua_rat__aMvXv0MPZczuQFMz

P and Q started a business investing Rs. 85,000 and Rs. 30,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? Choose one A) 17:6 B) 17:0 C) 17:4 D) 17:2 E) 17:3

P:Q = 85000 : 30000 = 17:6. 17:6nswer: 17:6 <result>A</result>

A

P and Q started a business investing Rs. 85,000 and Rs. 30,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?

aqua_rat__NPAoMCf7w6rnOxl6

A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?" B immediately gave the desired answer. It was :- Choose the correct choice from the following answers. A) 3, 37 and 119 B) 3, 37 and 111 C) 9, 37 and 111 D) 3, 9 and 37 E) None

Explanation : Each of the number can be written as a multiple of 111. And, The factors of 111 are 3 and 37. Thus, the desired answer is 3, 37 and 111. Answer : 3, 37 and 111 <result>B</result>

B

A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?" B immediately gave the desired answer. It was :-

aqua_rat__Kyp30wYgEnEMNXWK

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long? Choose the correct choice from the following options. A) 277 Sec B) 190 Sec C) 187 Sec D) 286 Sec E) 215 Sec

L = S*T S= 1200/120= <gadget id="calculator">1200/120</gadget> <output>10</output> 10 m/Sec. Total length (D)= 1900 m T = D/S T = 1900/10= <gadget id="calculator">1900/10</gadget> <output>190</output> 190 Sec Answer:190 Sec <result>B</result>

B

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?

aqua_rat__30c9oOT59mz9zaqN

In how many different ways can the letters of the word ‘ARMOUM’ be arranged? Choose the correct choice from the following answers: A) 200 B) 210 C) 230 D) 250 E) 360

ARMOUR = 6 letter whereas R repeated twice 6! 6xSx4x3x2x1 =&gt; 360 360 <result>E</result>

E

In how many different ways can the letters of the word ‘ARMOUM’ be arranged?

aqua_rat__DpEn5rHWd7KbRCRQ

Which digits should come in place of @ and # if the number 62684@# is divisible by both 8 and 5? Choose the correct choice from the following: A) 4,0 B) 0,4 C) 4,4 D) 0,0 E) None

Explanation : Since the given number is divisible by 5, so 0 or 5 must come in place of #. But, a number ending with 5 is never divisible by 8. So, 0 will replace #. Now, the number formed by the last three digits is 4@0, which becomes divisible by 8, if @ is replaced by 4. Hence, digits in place of @ and # are 4 and 0 respectively. 4,0nswer : 4,0 <result>A</result>

A

Which digits should come in place of @ and # if the number 62684@# is divisible by both 8 and 5?

aqua_rat__s2fGOVLYdxyXQGIi

A train 125 m long passes a man, running at 1 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is? Answers A) 65 km/hr B) 17 km/hr C) 76 km/hr D) 50 km/hr E) 46 km/hr

Speed of the train relative to man = 125/10 = 25/2 m/sec. = 25/2 * 18/5= <gadget id="calculator">25/2 * 18/5</gadget> <output>45</output> 45 km/hr Let the speed of the train be x km/hr. Then, relative speed= (x - 1) km/hr. x - 1 = 45 =&gt; x = 46 km/hr. Answer: 46 km/hr <result>E</result>

E

A train 125 m long passes a man, running at 1 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?

aqua_rat__AHy42pJfdjmdCWpH

A work which could be finished in 8 days was finished 3 days earlier after 10 more men joined. The number of men employed was? Options: A) 22 B) 30 C) 88 D) 71 E) 11

x ------- 8 (x + 10) ---- 6 x * 8 = (x + 10)6 x = 30 \Answer: 30 <result>B</result>

B

A work which could be finished in 8 days was finished 3 days earlier after 10 more men joined. The number of men employed was?

aqua_rat__DGSRQYJbouYbGIlD

Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H Select: A) 153 B) 159 C) 137 D) 121 E) 89

let the number be x, now x is halved =&gt; x/2..the question asks what is x? x(number) + x/2 (half of that number) = something =&gt; 3x/2 = something =&gt; x = 2 (something) / 3 so the answer choice must be divisible by 3 eliminate C, E right away check the rest B satisfies 3x/ 2 = 159 =&gt; x = 106 Verify. 106 + 53 = 159 Answer is 159 <result>B</result>

B

Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H

aqua_rat__1BBszVbfPVPmM2DT

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: Choose the correct choice from the following. A) 9 B) 2 C) 7 D) 8 E) 1

Let the numbers 13a and 13b. Then, 13a x 13b = 2028 =&gt;ab = 12. Now, the co-primes with product 12 are (1, 12) and (3, 4). [Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ] So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4). Clearly, there are 2 such pairs. Answer: 2 <result>B</result>

B

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

aqua_rat__JTrKDRLMPffMdX87

Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone? Select the correct option: A) 8 B) 12 C) 14 D) 15 E) 17

Renu’s one day’s work = 1/8 Suma’s one day’s work = 1/4 - 1/8 = 1/8 Suma can do it alone in 8 days. 8NSWER:8 <result>A</result>

A

Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?

aqua_rat__jKI9A3daSikmwF8D

There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the stretch while the other two keep running. Then he comes back without wasting time and picks up another person from the way, drives him across the stretch, and does the same for the last person. How long does this whole process take? Choose the most appropriate option: A) 24 hrs B) 16 hrs C) 56/3 hrs D) 58/3 hrs E) 18 hrs

Expl : Time taken to carry 2nd person = 300/50= <gadget id="calculator">300/50</gadget> <output>6</output> 6 hrs. Time taken to meet 3rd person=(300-6*10)/(50+10)= <gadget id="calculator">(300-6*10)/(50+10)</gadget> <output>4</output> 4 hrs Time taken to carry 3rd person= 4 hours Time taken to meet 4th person = (300 –140)/60 = 8/3 Total time = 6+4+4+8/3+8/3 = 58/3 hours Answer :58/3 hrs <result>D</result>

D

There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the stretch while the other two keep running. Then he comes back without wasting time and picks up another person from the way, drives him across the stretch, and does the same for the last person. How long does this whole process take?

aqua_rat__XsPQJa0w1MSuhrh0

The security gate at a storage facility requires a Six-digit lock code. If the lock code must consist only of digits from 1 through 9, inclusive, with no repeated digits, and the first and last digits of the code must be odd, how many lock codes are possible? Choose the correct choice from the following answers: A) 120 B) 240 C) 360 D) 720 E) 16800

X-X-X-X-X --&gt; there are 5 odd digits from 1 to 9, inclusive thus options for the first and the last X's are: 5-X-X-X-X-4. Other X's can take following values: 5-7-6-5-4-4 -&gt; 5*7*6*5*4*4=16800. Answer: 16800. <result>E</result>

E

The security gate at a storage facility requires a Six-digit lock code. If the lock code must consist only of digits from 1 through 9, inclusive, with no repeated digits, and the first and last digits of the code must be odd, how many lock codes are possible?

aqua_rat__eKbssOTk1e0iDHMw

If by selling an article for Rs.60, a person loses 1/7 of money, what would he have gained or lost % by selling it for Rs.77? Choose the most appropriate option: A) 5% B) 10% C) 20% D) 30% E) 45%

Sol. CP - = EC7 = 70 1-7 6 77-70 % Profit = 100 = 10% 10% <result>B</result>

B

If by selling an article for Rs.60, a person loses 1/7 of money, what would he have gained or lost % by selling it for Rs.77?

aqua_rat__RqS4EsJgqMPwxTBy

If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour? Choose the correct choice from the following answers. A) 451 times B) 638 times C) 838 times D) 436 times E) 435 times

There are 60 minutes in an hour. In ¾ of an hour there are (60 * ¾) minutes = 45 minutes. In ¾ of an hour there are (60 * 45)= <gadget id="calculator"> (60 * 45)</gadget> <output>2_700</output> 2700 seconds. Light flashed for every 6 seconds. In 2700 seconds 2700/6= <gadget id="calculator">2700/6</gadget> <output>450</output> 450 times. The count start after the first flash, the light will flashes 451 times in ¾ of an hour. 451 timesnswer:451 times <result>A</result>

A

If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?

aqua_rat__d5y2C3UvFxa4uw5w

Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $6,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue? Answers. A) $14,000 B) $40,000 C) $42,000 D) $46,000 E) $50,000

Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +40 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +6 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T): (40 + 6 + T)/3 = 2 46 + T = 6 T = -40 Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -40 represents a $40,000 advantage in favor of Store B. Choice ($40,000) is correct. <result>B</result>

B

Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $6,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?

aqua_rat__Dsont6M2OcmqXzll

some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct Answers. A) 530 B) 540 C) 550 D) 560 E) 570

( 6*6*5*4*3*2)/(2! *2!*2!)= 540 ways ANSWER:540( 6*6*5*4*3*2)/(2 *2 *2 )= <gadget id="calculator">( 6*6*5*4*3*2)/(2 *2 *2 )</gadget> <output>540</output> 540 ways ANSWER:540 <result>B</result>

B

some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct

aqua_rat__sqYN8LL8r5LlmLGL

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is: Answers A) 600 B) 698 C) 675 D) 688 E) 900

1 year = Rs. (854 - 815) = Rs. 39. 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 - 117) = Rs. 698 ANSWER 698 <result>B</result>

B

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:

aqua_rat__7bZ9OZici2k1DClQ

Each of the following equations has at least one solution EXCEPT D. Is it true? Pick: A) -2*-a = 2a B) 2*a = (–2)*-a C) -4*a = -3-a D) -3*a = -3-a E) (–2)-a = –2-a

If we put a= 1 then A. 2 B. 2 C. -4 E. -3 D. -3=-4 Not true <result>D</result>

D

Each of the following equations has at least one solution EXCEPT D. Is it true?

aqua_rat__fpB6QRPfo6evXyen

10 people went to a hotel for combine dinner party 5 of them spent Rs. 20 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them. Select: A) 1628.4 B) 1534 C) 1492 D) 240 E) None of these

Solution: Let average expenditure of 10 people be x. then, 10x = 20*5+5*(x+4); Or, 10x = 20*5+5x+20; Or, x = 24; So, total money spent = 24*10 = Rs. 240. Answer: Option 240 <result>D</result>

D

10 people went to a hotel for combine dinner party 5 of them spent Rs. 20 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them.

aqua_rat__8y2SxzSKvAVb7GaH

If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ? Pick one: A) 30 B) 34 C) 36 D) 37 E) 39

It basically asks for the number of 5s in 150! 150/5 + 150/25 + 150/125 = 30 + 6 + 1. Hence 37 Answer: 37. <result>D</result>

D

If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ?

aqua_rat__fqAcwHpnahducukO

Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M? Choose the correct choice from the following. A) 328 units B) 368 units C) 392 units D) 616 units E) None of the above

The final product is obtained by mixing 864 units of product M with water. In 864 units of Product M, amount of B = 864×77/108 = 616 In the final mixture, concentration of B is 50%. Therefore, the total quantity of final mixture = 616 × 2 = 1232 Water added = 1232 – 864 = 368 The correct answer is Choice 368 units. <result>B</result>

B

Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?

aqua_rat__VANOx4ljSJnTFIsq

In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many Z different victory circles are possible? Pick one. A) 24 B) 52 C) 96 D) 144 E) 648

Possible scenarios are: 1. Gold/Silver/Bronze/No medal (no ties) - 4!=24; 2. Gold/Gold/Silver/No medal - 4!/2!=12; 3. Gold/Silver/Silver/No medal - 4!/2!=12; 4. Gold/Gold/Gold/No medal - 4!/3!=4. Total Z: 24+12+12+4= <gadget id="calculator">24+12+12+4</gadget> <output>52</output> 52 Answer: 52. <result>B</result>

B

In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many Z different victory circles are possible?

aqua_rat__rxLjAtoLQp1d9TMJ

X completes a work in 20 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be? Choose the correct choice: A) 10 days. B) 12 days. C) 14 days. D) 8 days. E) 20 days.

If X can complete a work in x days and Y can complete the same work in y days, then, both of them together can complete the work in x y/ x+ y days Therefore, here, the required number of days = 20× 30/ 50 = 12 days. 12 days.) <result>B</result>

B

X completes a work in 20 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?

aqua_rat__tPZoExV46iWjmtyZ

A chair is bought for Rs.300/- and sold at Rs.420/- find gain or loss percentage Choose the correct choice from the following choices. A) 15% loss B) 40% gain C) 25% gain D) 30% gain E) 35% gain

Formula = (Selling price ~ Cost price)/Cost price * 100 = (450- 300)/300= 40% gain 40% gain <result>B</result>

B

A chair is bought for Rs.300/- and sold at Rs.420/- find gain or loss percentage

aqua_rat__4dcJ30ba9ps4vuu4

What is the least number to be subtracted from 696 to make it a perfect square? Choose the correct choice from the following answers A) 1 B) 16 C) 20 D) 71 E) 60

The numbers less than 696 and are squares of certain numbers are 676, 625. The least number that should be subtracted from 696 to make it perfect square = 696 - 676= <gadget id="calculator">696 - 676</gadget> <output>20</output> 20. ANSWER:20 <result>C</result>

C

What is the least number to be subtracted from 696 to make it a perfect square?

aqua_rat__nKP4lpGYwghOPoG9

There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback? Choose the correct choice from the following answers A) a) 40 B) b) 45 C) c) 36 D) d) 55 E) e) 60

approach 1 at-least 1 paper back = total - no paper back 8c3-6c3 = 36 approach 2 at-least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 2c1*6c2+2c2*6c1 = 36 Answer is c) 36 <result>C</result>

C

There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback?

aqua_rat__PY90yHZNUnlhgZl8

If a sum of money doubles itself in 20 years at simple interest, the ratepercent per annum is Choose the correct choice from the following choices A) 12 B) 12.5 C) 13 D) 5 E) 14

Explanation: Let sum = x then Simple Interest = x Rate = (100 * x) / (x * 20) = 5 Option 5 <result>D</result>

D

If a sum of money doubles itself in 20 years at simple interest, the ratepercent per annum is

aqua_rat__OHe9nsW0L2fZSKsA

Choose the missing terms out of the given alternatives. AZ, BY, CX, DW ? Choose one A) EF B) GH C) EV D) DW E) KN

C EV The first letter moves one step forward. The second letter moves one step backward. Answer is EV <result>C</result>

C

Choose the missing terms out of the given alternatives. AZ, BY, CX, DW ?

aqua_rat__G2cAMIAZv7iMIDv8

Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures? Choose the correct choice from the following answers: A) 5/14 B) 1/2 C) 17/28 D) 9/14 E) 9/11

Total revenues = x Spent on marketing = x/4 Remaining amount = x-x/4 = 3x/4 1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28 Amount left = 3x/4-3x/28 = 9x/14 Answer 9/14 <result>D</result>

D

Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?

aqua_rat__txTr447qXVwuUNL7

A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long? Choose the correct choice from the following answers: A) 40 sec B) 42 sec C) 45 sec D) 48 sec E) 58 sec

Speed = 45 * 5/18 = 25/2 m/sec Total distance covered = 360 + 140= <gadget id="calculator">360 + 140</gadget> <output>500</output> 500 m Required time= 500 * 2/25= <gadget id="calculator">500 * 2/25</gadget> <output>40</output> 40 sec 40 secNSWER:40 sec <result>A</result>

A

A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

aqua_rat__HrvP3zF2mrBIyayj

What is the scope including 1/21+1/22+1/23+......+1/30? Pick: A) 1/6~1/5 B) 1/5~1/4 C) 1/4~1/3 D) 1/3~1/2 E) 1/2~1

For Maximum value : It should be less than 1/21 + 1/21 +1/21... 10 times = 10/21 ~ 1/2 For Minimum Value : It should be greater than 1/30+ 1/30+ 1/30 .. 10 times = 10/30 = 1/3 Thus, the answer should lie between 1/3 and 1/2. Correct ans : 1/3~1/2. <result>D</result>

D

What is the scope including 1/21+1/22+1/23+......+1/30?

aqua_rat__gMDCtvaLK925fyGD

Company A has 13 employees, 9 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift? Choose the most appropriate option. A) 56 B) 231 C) 336 D) 350 E) 756

Looks easy: -- 9C4*5C1 + 9C5= 756 (756). <result>E</result>

E

Company A has 13 employees, 9 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

aqua_rat__ijstjSqRBlpU2vpH

A bag contains 5 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls? Choose one A) 1/7 B) 2/9 C) 3/11 D) 4/17 E) 2/3

Total number of balls = 5+2= <gadget id="calculator">5+2</gadget> <output>7</output> 7 n(S)= 7C3 = 7*6*5 / 3*2 = 35 n(E) = 2C2* 5C1 = 5 Probability = 5/35 = 1/7 1/7nswer is 1/7 <result>A</result>

A

A bag contains 5 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?

aqua_rat__hAb7e2hOxCkZmmB1

A woman complete a journey in 20 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. Answers A) 334 km. B) 216 km. C) 314 km. D) 448 km. E) 544 km.

0.5x/21 + 0.5x/24 = 20 --&gt; x/21 + x/24 = 40 --&gt; x =448 km. 448 km. <result>D</result>

D

A woman complete a journey in 20 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

aqua_rat__sjuoDS1VyI5K7KPV

The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people? Options: A) 179 cm and 172 cm B) 181 cm and 169 cm C) 173 cm and 178 cm D) 176 cm and 176 cm E) 174 cm and 177 cm

Denote X as the sum of the heights of the two new people. From the stem it follows that (700+X)6&gt;175. This reduces to X&gt;350. Only the heights from B add up to 350 cm. All other pairs add up to more than 350 cm. Answer: 181 cm and 169 cm <result>B</result>

B

The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people?

aqua_rat__95w8sH7hW8RPZXDq

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence? Choose the correct choice from the following: A) 70 B) 55 C) 60 D) 65 E) 80

70+B=60 70=2B 2B+B=60===&gt;B=20 70=40 5 yrs ages 45 and 25 Sum of their ages = 70 70NSWER 70 <result>A</result>

A

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?

aqua_rat__GWj8xT4UvVMvYTZE

Find the number which when multiplied by 15 is increased by 196. Choose the correct choice from the following answers A) 14 B) 20 C) 26 D) 28 E) 30

Let the number be x. Then, 15x - x = 196 &lt;=&gt; 14x = 196 &lt;=&gt; x = 14. 14nswer :14 <result>A</result>

A

Find the number which when multiplied by 15 is increased by 196.

aqua_rat__lshNHk4XMhEotMQC

A number X equals 80% of the average of 5, 7, 14 and a number Y. If the average of X and Y is 26, the value of Y is? Choose the correct choice: A) 13 B) 26 C) 39 D) 36 E) None of these

Average of 5, 7, 14 and Y = ( 5 + 7 + 14 + Y )/ 4 Therefore, X = 80% of ( 5 + 7 + 14 + y )/ 4 = (80/100) x (26 + Y)/4 =&gt; X = (26 + Y)/5 5X - Y = 26----- (i) Also, (X + Y)/2 = 26 ----- (ii) From (i)and (ii) X = 13 Y = 39. ANSWER:39 <result>C</result>

C

A number X equals 80% of the average of 5, 7, 14 and a number Y. If the average of X and Y is 26, the value of Y is?

aqua_rat__O2HIEoS1bRCqXkaL

A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is. Choose the most appropriate option. A) 30 km B) 40 km C) 45 km D) 50 km E) 55 km

Let distance = x m Usual rate = y kmph x/y – x/y+3 = 40/60 hr 2y(y+3) = 9x ---------------------------------(1) x/y-2 – x/y = 40/60 hr y(y-2) = 3x -----------(2) divide 1 &amp; 2 equations by solving we get x = 40 km Answer : 40 km <result>B</result>

B

A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is.

aqua_rat__B8zOb89nllyaqT7j

The number of livestock in a farm at the beginning of year 2000 was 130,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 130,000. Which of the following expressions is correct? Choose the correct answer: A) With the exception of 1 instance, p will be equal to q B) q > p C) p = q D) p > q E) There is no relation between p and q

Number plugging in will be best strategy for this question. Let p = 5%, Per the question 100000(1.05)(1-q/100) = 100000 ---&gt; q = 4.7%. Thus p &gt; q and hence p &gt; q is the correct answer. <result>D</result>

D

The number of livestock in a farm at the beginning of year 2000 was 130,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 130,000. Which of the following expressions is correct?

aqua_rat__ryplcnQ8kUwc2fqJ

If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it? Pick: A) 19/60 B) 9/60 C) 2/3 D) 5/18 E) 6/24

Explanation: 3 men reap 1/10 field in 1 day 1 man reap 1/(3 x 10) 4 women reap 1/10 field in 1 day 1 woman reap 1/(10 x 4) 5 men and 6 women reap (5/(3 x 10)+ 6/(4 x 10)) =19/60 in 1 day 5 men and 6 women will reap the field in 19/60 days 19/60nswer: Option 19/60 <result>A</result>

A

If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it?

aqua_rat__KKMwTyoMgqqpoCC9

What is the greatest possible value of integer n if 100! is divisible by 15^n Pick one: A) 20 B) 21 C) 22 D) 23 E) 24

15^n = 5^n * 3^n Highest prime factor will be the limiting factor. 100/5 +100/25 =20+4= <gadget id="calculator">20+4</gadget> <output>24</output> 24 ANSW24R:24 <result>E</result>

E

What is the greatest possible value of integer n if 100! is divisible by 15^n

aqua_rat__WCcrZaD0bdkqJrqZ

Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756 Choose the correct choice: A) 15 B) 16 C) 34 D) 105 E) 2124

2nd term = (1st term) * 1 + 1 = 15 *1 + 1= <gadget id="calculator">15 *1 + 1</gadget> <output>16</output> 16. 3rd term= (2nd term) * 2 + 2 = 16 * 2 + 2= <gadget id="calculator">16 * 2 + 2</gadget> <output>34</output> 34 4th term= (3th term) *3 + 3 = 34 * 3 + 3= <gadget id="calculator">34 * 3 + 3</gadget> <output>105</output> 105 5th term= (4th term) * 4 + 4 = 105 * 4 + 4= <gadget id="calculator">105 * 4 + 4</gadget> <output>424</output> 424 6th term= (5th term) * 5 + 5 = 424 * 5 + 5= <gadget id="calculator">424 * 5 + 5</gadget> <output>2_125</output> 2125 6th term should 2125 instead of 2124. 2124 <result>E</result>

E

Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756

aqua_rat__h4KPJKWaO61fyLp1

On Monday, a certain animal shelter housed 45 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday? Select the correct option. A) 10 B) 11 C) 12 D) 13 E) 14

To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 &gt; 1/5. The greatest multiple of 4 less than 45 is 40 (such that the remaining number is divisible by 5), so let's assume there were 40 dogs and 5 cats. Then the maximum number of adopted pets is 1/4*(40) + 1/5*(5) = 10 + 1= <gadget id="calculator">10 + 1</gadget> <output>11</output> 11. The answer is 11. <result>B</result>

B

On Monday, a certain animal shelter housed 45 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?

aqua_rat__iCBYZLIkeiluCjJY

A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price? Choose the correct option A) 3,000 B) 4,000 C) 2,400 D) 2,000 E) None of these

Original price = 1120 × 100⁄70 × 100⁄80 = 2000 Answer 2,000 <result>D</result>

D

A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price?

aqua_rat__iHkVt2M76gI6z0dY

The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A.? Options A) 16 B) 12 C) 10 D) 20 E) 10

(A+B)-(B-10)=10 A-10=10 Answer is 10 <result>C</result>

C

The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A.?

aqua_rat__30yf3Wfb9h9n128t

In an election between two candidates, 10% of votes are were declares invalid. First candidate got 3600 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was: Choose the correct choice from the following answers: A) 9000 B) 98000 C) 20000 D) 11000 E) 12000

100 % - 10 % = 90 % 54%-36%=18% 18% ------&gt; 3600 ( 18 × 200 54 -36= <gadget id="calculator"> 54 -36</gadget> <output>18</output> 18% 18% ------&gt; 3600 ( 18 × 200= 3600) 100% -------&gt; 20000 votes (100 × 200 = 20000) 20000 <result>C</result>

C

In an election between two candidates, 10% of votes are were declares invalid. First candidate got 3600 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:

aqua_rat__QBXmNpkAoglE7ClI

Find a 8 digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times. Choose the most appropriate option. A) 12345679 B) 42345675 C) 22347379 D) 52345673 E) 21345679

12345679 The number is: 12345679 12345679 * 9= <gadget id="calculator">12345679 * 9</gadget> <output>111_111_111</output> 111111111 12345679 * 18= <gadget id="calculator">12345679 * 18</gadget> <output>222_222_222</output> 222222222 12345679 * 27= <gadget id="calculator">12345679 * 27</gadget> <output>333_333_333</output> 333333333 12345679nd so on... <result>A</result>

A

Find a 8 digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.

aqua_rat__HwlDCgnD05KZ83eq

A and B invests Rs.3000 and Rs.7000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? Choose the correct choice from the following. A) 9:6 B) 9:8 C) 9:14 D) 9:9 E) 9:5

(3*6 + 6*6): (7*12) 54:84 =&gt; 9:14.Answer:9:14 <result>C</result>

C

A and B invests Rs.3000 and Rs.7000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?

aqua_rat__V4ZSJZWXMy8kny9q

A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary? Select the correct option: A) 5000 B) 2889 C) 2779 D) 6257 E) 5362

Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80*(20/100) = Rs. 96 Present Savings = 100 – 96 =Rs. 4 100 ------ 4 ? --------- 200 =&gt; 5000 5000nswer: 5000 <result>A</result>

A

A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?

aqua_rat__VmugNihBIa8RPk37

A boat covers a certain distance downstream in 1 hour, while it comes back in 11⁄2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water? Answers A) 31 kmph B) 16 kmph C) 19 kmph D) 15 kmph E) 14 kmph

Let the speed of the water in still water =x Given that speed of the stream = 3 kmph Speed downstream =(x+3) kmph Speed upstream =(x−3) kmph He travels a certain distance downstream in 1 hour and come back in 11⁄2 hour. i.e., distance travelled downstream in 1 hour = distance travelled upstream in 11⁄2 hour Since distance = speed × time, we have (x+3)×1=(x-3)3/2 2(x+3)=3(x-3) 2x+6=3x-9 x=6+9= <gadget id="calculator">6+9</gadget> <output>15</output> 15 kmph Answer: 15 kmph <result>D</result>

D

A boat covers a certain distance downstream in 1 hour, while it comes back in 11⁄2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

aqua_rat__JOCoQVYIsNkWo7ns

A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year? Choose the correct choice from the following choices A) 2:5 B) 3:5 C) 4:5 D) 3:7 E) 5:7

2:5 : B (4000*4)+(1000*8) : (6000*8)+(3000*4) 24000 : 60000 2 : 5 2:5nswer: 2:5 <result>A</result>

A

A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year?

aqua_rat__AIwUzTVXDKzEBUWi

0.5, 0.55, 0.65, 0.8, ? Choose the correct option: A) 0.7 B) 0.9 C) 0.95 D) 1 E) 2

The pattern is + 0.05, + 0.10, + 0.15, ..... Answer : 1. <result>D</result>

D

0.5, 0.55, 0.65, 0.8, ?

aqua_rat__fBbzIoGxJv8tudsx

If 15 women or 10 men can complete a project in 55 days, in how many days will 5 women and 4 men working together complete the same project ? Pick one: A) 75 B) 8 C) 9 D) 85 E) None of these

15 W = 10 M Now, 5W + 4M = 5W + 4×15/10W = 5W + 6W = = 11 W If 15 women can complete the project in 55 days, 11 women can complete the same project in 55×15/11=75days 75nswer 75 <result>A</result>

A

If 15 women or 10 men can complete a project in 55 days, in how many days will 5 women and 4 men working together complete the same project ?

aqua_rat__Z5kq5A32E0vTZE9U

If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n? Choose one: A) 10 B) 20 C) 30 D) 40 E) 50

450 = 2 * 3^2 * 5^2 If 450 divides n^2, then n must be divisible by 2 * 3 * 5= <gadget id="calculator"> 2 * 3 * 5</gadget> <output>30</output> 30 The answer is 30. <result>C</result>

C

If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n?

aqua_rat__R09yVf0KneForcdl

Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill? Choose one. A) 6 B) 8 C) 7 D) 4 E) 1

1/10 + 1/15 = 1/6 * 4 = 2/3 1 - 2/3 = 1/3 1/10 + 1/15 - 1/x = 1/3 x = 8 Answer:8 <result>B</result>

B

Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?

aqua_rat__crThlSAYyDfFuf9q

A certain club has 14 members, including Harry. One of the 14 members is to be chosen at random to be the president, one of the remaining 13 members is to be chosen at random to be the secretary, and one of the remaining 12 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer? Choose the correct choice from the following answers: A) 5/7 B) 4/7 C) 3/7 D) 1/7 E) 2/7

Each member out of 14, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the secretary is 1/14 and the probability that Harry will be selected to be the treasurer is also 1/14. So, the probability that Harry will be selected to be either the secretary or the the treasurer is 1/14+1/14=2/14. Answer: 1/7. <result>D</result>

D

A certain club has 14 members, including Harry. One of the 14 members is to be chosen at random to be the president, one of the remaining 13 members is to be chosen at random to be the secretary, and one of the remaining 12 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer?

aqua_rat__YdLHp9cnAdJK49bV

Afreena walks 8 km towards East and then walks 13 km back, then she turns left and walks 4 km; then walks 5 km after turning left; she turns left again and walks 3 km. How far is she from the starting point ? Answers: A) 3 km B) 2 km C) 1 km D) 6 km E) 7 km

Explanation: From given details we know that she walks in square shaped path and will be in 1 km away from starting point. ANSWER IS 1 km <result>C</result>

C

Afreena walks 8 km towards East and then walks 13 km back, then she turns left and walks 4 km; then walks 5 km after turning left; she turns left again and walks 3 km. How far is she from the starting point ?

aqua_rat__WEbWdNdV8dHxsuLm

A coed soccer team has W women and M men on the team. If 4 women and 2 men are added to the team roster, and if one person on the team is selected at random to serve as team captain, then the probability that the team captain will be a woman can be represented as Choose one: A) (W + 4)/(W + M + 6) B) (W + 4)/(W + M + 2) C) (W + 4)/(M + 2) D) (W + 4)/(W + M) E) W/M

W women and M men..now 4 women and 2 men are added then total women = W+4 and total men = M+2.. if we club both as total one team (W + M + 6) We need to find the probability that the team captain will be a woman =&gt; W+4 / (W + M + 6).. IMO option (W + 4)/(W + M + 6) is correct answer... <result>A</result>

A

A coed soccer team has W women and M men on the team. If 4 women and 2 men are added to the team roster, and if one person on the team is selected at random to serve as team captain, then the probability that the team captain will be a woman can be represented as

aqua_rat__Yf2HsD2Dz5dUHTL2

A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is Choose the correct choice from the following options: A) 14 years B) 28 years C) 20 years D) 22 years E) None

Solution Let the son's present age be x years .Then, man's present age = (x+30)years. Then ‹=›(x+30)+2= 2(x+2) ‹=›x+32=2x+4 x= 28. Answer 28 years <result>B</result>

B

A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is

aqua_rat__6J1p6T2P2Umgaie8

Chris mixed 3 pounds of raisins with 3 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? Choose the most appropriate option. A) 1/7 B) 1/5 C) 1/4 D) 1/3 E) 3/7

1 lbs of raisin = $1 3 lbs of raisin = $3 1 lbs of nuts = $3 3 lbs of nuts = $9 Total value of mixture = 9+3= <gadget id="calculator">9+3</gadget> <output>12</output> 12 Fraction of the value of raisin= 3/12 = 1/4 Ans:1/4 <result>C</result>

C

Chris mixed 3 pounds of raisins with 3 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?

aqua_rat__neyquBpVPa7Ztb9M

A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct? Pick one: A) 2 p.m. on Tuesday B) 2 p.m. on Wednesday C) 3 p.m. on Thursday D) 1 p.m. on Friday E) None

Solution Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours. =170 hours. The watch gains = (2 + 4 x4/5)min = 34 / 5 min.in 170 hrs. Now,34/5 min are gained in 170 hrs. 2 min are gained in(170x 5/34 x2)hrs. Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.on Wednesday. Answer 2 p.m. on Wednesday <result>B</result>

B

A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?

aqua_rat__DTPIwH93FbuhOZJ1

Otto and Han are driving at constant speeds in opposite directions on a straight highway. At a certain time they are driving toward each other and are 40 miles apart. One and a half hours later, they are again 40 miles apart, driving away from each other. If Otto drives at a speed of x miles per hour, then, in terms of x, Han drives at a speed of how many miles per hour? Choose the most appropriate option A) a) 80-x B) b) 53.33-x C) c) 80-2x D) d) 120-x E) e) 40-x/2

Let's say the two cars have speeds V1 and V2. The fact that they are moving in opposite direction means that their relative speed is (V1 + V2). In other words, any gap between them will be changing in size at a rate of (V1 + V2). It doesn't matter whether they are moving toward each other or away from each other. If they are approaching each other, the gap between them is decreasing at a rate of (V1 + V2). If they are moving away from each other, the gap between them is increasing at a rate of (V1 + V2). Either way, the number for the rate of change remains the same. Here, the two cars approach a distance 40 mi, then move away from each other another distance of 40 miles. That's a total distance of 80 miles in 1.5 hr, which gives a rate of: R = (80 mi)/(1.5) = 53.33 mph That's the rate of change of the gap, so it must equal the sum of the speeds of the two cars. One of the speeds is x, and let's call the other y. We want y. x + y = 53.33 y = 53.33 - x Answer =(b) 53.33-x) <result>B</result>

B

Otto and Han are driving at constant speeds in opposite directions on a straight highway. At a certain time they are driving toward each other and are 40 miles apart. One and a half hours later, they are again 40 miles apart, driving away from each other. If Otto drives at a speed of x miles per hour, then, in terms of x, Han drives at a speed of how many miles per hour?

aqua_rat__oFlXAi3vxH2cfV2m

The angle between two hands at 3.45 is Choices: A) 110 degree B) 115 degree C) 112 1/2 degree D) 117 degree E) 157 1/2 degree

theta degree=11/2m-30h =11/2(45)-30(3) =247.5-90= <gadget id="calculator">247.5-90</gadget> <output>157.5</output> 157.5 or 157 1/2 degree ANSW157 1/2 degreeR:157 1/2 degree <result>E</result>

E

The angle between two hands at 3.45 is

aqua_rat__aRoH1OPv1sFqlm4U

A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Options: A) 148 Kmph B) 152 Kmph C) 106 Kmph D) 103 Kmph E) 165 Kmph

Time = 4 103 Kmphistance = 620 3/2 of 4 hours = 4 * 3/2= <gadget id="calculator">4 * 3/2</gadget> <output>6</output> 6 Hours Required speed= 620/6 = 103 Kmph 103 Kmph) <result>D</result>

D

A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?

aqua_rat__JXut7KjP7jsJjnZO

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together. Choose the most appropriate option: A) 10x11/10 B) 10x10/11 C) 11x10/11 D) 12x10/11 E) None

Solution At 8 o'clock, the hour is at 8 and the minute hand is at 12,i.e. the two hands are 20 min. Spaces apart. So, the minute hand gain = (30 - 20)minute 55 minutes will be gained in 60 min. 10 minutes spaces will be gained in (60/55 x10) min. = 10x10/11 min. The hands will be in the same straight line but not together at 10x10/11 min.past 8. Answer 10x10/11 <result>B</result>

B

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together.

aqua_rat__2CJMXMeIty2M6d66

On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday four of his spiders, Wednesday would then have four times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences? Choose the correct choice from the following choices: A) 6 B) 7 C) 8 D) 10 E) 12

If Pugsley were to give Wednesday four of his spiders, Wednesday would then have five times as many spiders as Pugsley does: (w + 4) = 4(p - 4) If Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded: p + 5 ( + 4)= <gadget id="calculator"> ( + 4)</gadget> <output>4</output> 4(p - 4) If Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded: p + 5= w - 5 Solving gives p = 10 and w = 20. Answer: 10. <result>D</result>

D

On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday four of his spiders, Wednesday would then have four times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences?

aqua_rat__jS2Gi2AQ0BJW0xsE

To apply for the position of photographer at a local magazine, a photographer needs to include two or three photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine? Choose the correct choice from the following options. A) 32 B) 35 C) 36 D) 40 E) 42

6C2 + 6C3 = 15 + 20= <gadget id="calculator">15 + 20</gadget> <output>35</output> 35 The answer is 35. <result>B</result>

B

To apply for the position of photographer at a local magazine, a photographer needs to include two or three photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine?

aqua_rat__zIbEnCvJLwyTKIPX

If x is an integer and y = 3x + 2, which of the following CANNOT be a divisor of y? Choose the correct choice: A) 4 B) 5 C) 6 D) 7 E) 8

Just to add some more to Bunuel's explanation, if a number is a multiple of 3, it will be in a form: n = 3*k, where k is an integer And if a number is a multiple of 6, it will be in a form : m = 6*l, where l is an integer so m = 2 * 3 * l = (2*l) * 3 = 3 * p, where p is an integer. In other words, the prime factorization of m must have 3 as a factor, if it's a multiple of 6, but the expression can't have that (as explained by Bunuel), so it can't be a multiple of 6 either ANSWER:6 <result>C</result>

C

If x is an integer and y = 3x + 2, which of the following CANNOT be a divisor of y?

aqua_rat__GjJanh2nP0Dgvdn6

A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price W. The store sold the first 150 copies in the first week at 80% more than W, and then over the next month, sold a 100 more at 20% more than W. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than W. What was the bookstore’s net percent profit or loss on the entire lot of 400 books? Pick one: A) 30% loss B) 10% loss C) 10% profit D) 20% profit E) 60% profit

C.P. = 400W S.P. = 1.8W*150 + 1.2W*100 + 0.6W*150 = 480W Since, S.P. &gt; C.P., there is net profit. Profit 1.8 *150 + 1.2 *100 + 0.6 *150= <gadget id="calculator">1.8 *150 + 1.2 *100 + 0.6 *150</gadget> <output>480</output> 480W Since, S.P. &gt; C.P., there is net profit. Profit= S.P. - C.P. = 480W - 400W = 80W Profit % 480 - 400= <gadget id="calculator">480 - 400</gadget> <output>80</output> 80W Profit %= (Profit/C.P.)*100 = (80W/400W)*100 = 20% So, the correct answer is 20% profit.(80 /400 )*100= <gadget id="calculator">(80 /400 )*100</gadget> <output>20</output> 20% So, the correct answer is 20% profit. <result>D</result>

D

A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price W. The store sold the first 150 copies in the first week at 80% more than W, and then over the next month, sold a 100 more at 20% more than W. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than W. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?

aqua_rat__VJUy2EKPnPMYLZOd

A committee of 2 people is to be selected out of 3 teachers and 4 preachers. If the committee is selected at random, what is the probability that the committee will be composed of at least 1 preacher? Choose the correct choice from the following answers A) 1/4 B) 1/3 C) 2/3 D) 6/7 E) 8/9

Total no of ways in which you can select a committee of 2 people out of 7 people is 7C2 ways= 21 ways Requirement is at-least 1 preacher= 4C1*3C1+4C2 or 7C2-3C2=18 ways Probability= 18/21 = 6/7 ANSWER:6/7 <result>D</result>

D

A committee of 2 people is to be selected out of 3 teachers and 4 preachers. If the committee is selected at random, what is the probability that the committee will be composed of at least 1 preacher?

aqua_rat__sBB067hq7c5xt9du

If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end? Choose the correct choice from the following answers: A) 16 B) 17 C) 18 D) 19 E) 20

Prime Factoring: you need a 2 and a 5 to make a 10 (a "zero"), and there are TONS of 2's so let's skip these and focus on the (rarer) 5s: 80! = 1*2*3*4*5*6...*78*79*80 Since there are 80 consecutive numbers, there are 16 multiples of 5 in there, but if we're prime factoring, we need to remember that SOME multiples of 5 actually contain more than just one 5. Which? 25 comes to mind -- it's got two of them! So all the multiples of 25 actually contain two 5's (ie: 50 and 75) So, to recap, we have 16 of them, plus 3 more (the additional 5's in 25, 50, and 75), so that makes 19, and since we have more than enough 2's, we know our number will have exactly 19 zeros at the end. ANSWER:19 <result>D</result>

D

If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end?

aqua_rat__6mgaxLAQd564MLjA

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income? Choose the correct answer A) 124% B) 120% C) 96% D) 80% E) 64%

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income). Thus, Mary's income (96) is 96% of Juan's income (100). Answer: 96% <result>C</result>

C

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

aqua_rat__qyHAk3peEFYn5jie

Y and Z start a business with Rs.3000 and Rs.6000 respectively. How should they share their profits at the end of one year? Choose the correct choice from the following answers. A) 4:1 B) 1:3 C) 1:4 D) 1:5 E) 1:2

They should share the profits in the ratio of their investments. The ratio of the investments made by Y and Z = 3000 : 6000 =&gt; 1:2 . Answer:1:2 <result>E</result>

E

Y and Z start a business with Rs.3000 and Rs.6000 respectively. How should they share their profits at the end of one year?

aqua_rat__56GRx1Bfy4dtO2gM

If 100!/x is not an integer, which of the following could be the value of x? Choose the correct choice from the following choices A) 5^24 B) 7^16 C) 11^9 D) 13^6 E) 17^6

he answer will be a number which doesn't completely divide 100! No of 5's in 100! = 24 No of 7's in 100! = 16 No of 11's in 100! = 9 No of 13's in 100! = 7 No of 17's in 100! = 5 There are 5 seventeens in 100! , however we are dividing by 17^6 , so this can not divide 100! Hence our answer will be 17^6 <result>E</result>

E

If 100!/x is not an integer, which of the following could be the value of x?

aqua_rat__o24FUpT4lkytVTEL

P is two years older than Q who is twice as old as R. The total of the ages of P, Q and R is 25. How old is Q? Choices: A) 7.2 years B) 8.2 years C) 9.8 years D) 9.2 years E) 9.4 years

Let age of R =x. Then, Age of Q =2x Age of P =2+2x Total age of P,Q and R =25 ⇒(2+2x)+2x+x=25 ⇒5x=23 ⇒x=23/5= <gadget id="calculator">23/5</gadget> <output>23/5 = around 4.6</output> 4.6 years B's age=2x=2×4.6=9.2 years ANSWER:9.2 years <result>D</result>

D

P is two years older than Q who is twice as old as R. The total of the ages of P, Q and R is 25. How old is Q?

aqua_rat__2PWgiw0sxFmriM5r

A man can row with a speed of 20 kmph in still water. If the stream flows at 7 kmph, then the speed in downstream is? Choose the correct option A) 27 B) 23 C) 20 D) 27 E) 12

M = 20 S = 7 27S = 20 + 7= <gadget id="calculator">20 + 7</gadget> <output>27</output> 27 Answer: 27 <result>D</result>

D

A man can row with a speed of 20 kmph in still water. If the stream flows at 7 kmph, then the speed in downstream is?

aqua_rat__CgbP3RSsaMBKj6G9

A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 75, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members? Options: A) 1:2 B) 1:4 C) 5:11 D) 1:3 E) 13:15

Deviation from the mean for the daytime staff = 75 - 65= <gadget id="calculator">75 - 65</gadget> <output>10</output> 10. Deviation from the mean for the evening staff= 65 - 60= <gadget id="calculator">65 - 60</gadget> <output>5</output> 5. Thus, the ratio of the number of daytime staff members to the number of evening staff members is 5:10= 1:2. The answer is 1:2. <result>A</result>

A

A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 75, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?

aqua_rat__ZaHWXRd8Z39P1lHE

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Four years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years? Options. A) A)24 B) B)89 C) C)67 D) D)32 E) E)45

Let the present ages of Sameer and Anand be 5x years and 4x years respectively. Then, (5x + 4/4x + 4)=11/9 9(5x + 4) = 11(4x + 4) 45x + 36 = 44x + 44 45x - 44x = 44 - 36= <gadget id="calculator">44 - 36</gadget> <output>8</output> 8. Anand's present age= 4x = 32 years. Answer:32 <result>D</result>

D

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Four years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

aqua_rat__eACYzD5FaDCnJ91k

If a man can cover 18 metres in one second, how many kilometres can he cover in 3 hours 45 minutes? Pick one. A) 288 B) 162 C) 878 D) 168 E) 243

18 m/s = 12 * 18/5 kmph 3 hours 45 minutes = 3 3/4 hours = 15/4 hours Distance = speed * time = 18 * 18/5 * 15/4= <gadget id="calculator">18 * 18/5 * 15/4</gadget> <output>243</output> 243 km. Answer: 243 <result>E</result>

E

If a man can cover 18 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?

aqua_rat__tlkU0aJT1cRYIHsB

How many meaningful English words can be formed with the letters ESRO using each letter only once in each word? Choose the correct choice from the following answers: A) 1 B) 3 C) 4 D) 8 E) 9

Explanation: Meaningful words are ROSE, SORE and EROS. Note the meaning of the words SORE and EROS with the help of dictionary. Answer: 3) Three <result>B</result>

B

How many meaningful English words can be formed with the letters ESRO using each letter only once in each word?

aqua_rat__AuGOqbl1Q8KVNtxJ

If S is the product of all positive integers less than 31, than what is the greatest integer k for which S/18^k is an integer? Choose the correct choice from the following answers: A) 3 B) 6 C) 7 D) 14 E) 26

30! S must be divisible by (3*3*2)^k. As I will find a lot of 2's among 30!'s factors I will focus on the 3's (that also occurs twice instead of only once as a factor in 18). Every multiple of 3 will provide me with atleast one factor of 3. There aren't that many so I list them quickly. 3 6 9* 12 15 18* 21 24 27** 30 The stars are marked as they are multiples of 9* or 27** and thus provides two or three 3's respectively. 3=3 (occurs 10 times) +10 3*3= <gadget id="calculator">3*3</gadget> <output>9</output> 9 (occurs 3 times) +3(adding just one additional three each as they were not counted for in the multiples of 3) 3*3*3= <gadget id="calculator">3*3*3</gadget> <output>27</output> 27 (occurs 1 time) +1 (again, adding just one as they were previously not counted) Total: 14. For every k we add two 3's. So we must divide 14 by 2 to get the highest integer K before we receive a non-integer result. Answer: 7 -&gt; Answer choice: 7. <result>C</result>

C

If S is the product of all positive integers less than 31, than what is the greatest integer k for which S/18^k is an integer?

aqua_rat__FdQ4CGqrjLkAagF1

What is the ratio between perimeters of two squares one having 3 times the diagonal then the other? Select the correct option: A) 3: 8 B) 3: 6 C) 3: 7 D) 3: 1 E) 3: 3

d = 3d d = d a√2 = 3d a√2 = d a = 3d/√2 a = d/√2 =&gt; 3: 1 Answer:3: 1 <result>D</result>

D

What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?

aqua_rat__MUAL3PQb5R1OXHBC

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ? Choose one A) 22 B) 72 C) 37 D) 16 E) 88

Explanation: L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes,they will together (30/2)+1= <gadget id="calculator"> (30/2)+1</gadget> <output>16</output> 16 times Answer: 16) 16 <result>D</result>

D

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?