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mjerome89

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ORPO-SQL

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How many heads of the departments are older than 56 ?

SELECT count(*) FROM head WHERE age > 56

SELECT COUNT(*) FROM department_heads WHERE age > 56;

List the name, born state and age of the heads of departments ordered by age.

SELECT name , born_state , age FROM head ORDER BY age

SELECT name, born_state, age FROM heads_of_departments ORDER BY age;

List the creation year, name and budget of each department.

SELECT creation , name , budget_in_billions FROM department

SELECT creation_year, name, budget FROM department;

What are the maximum and minimum budget of the departments?

SELECT max(budget_in_billions) , min(budget_in_billions) FROM department

SELECT MAX(budget) AS max_budget, MIN(budget) AS min_budget FROM departments;

What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'?

SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'

SELECT DISTINCT departments.creation_year FROM departments JOIN secretaries ON departments.secretary_id = secretaries.id WHERE secretaries.birth_state = 'Alabama';

What are the names of the states where at least 3 heads were born?

SELECT born_state FROM head GROUP BY born_state HAVING count(*) >= 3

SELECT state_name FROM states WHERE (SELECT COUNT(*) FROM heads WHERE heads.state_id = states.state_id) >= 3;

In which year were most departments established?

SELECT creation FROM department GROUP BY creation ORDER BY count(*) DESC LIMIT 1

SELECT year_established, COUNT(*) AS num_departments FROM departments GROUP BY year_established ORDER BY num_departments DESC LIMIT 1

Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'?

SELECT T1.name , T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'

SELECT departments.name, COUNT(employees.id) AS number_of_employees FROM departments JOIN employees ON departments.id = employees.department_id JOIN department_heads ON departments.head_id = department_heads.id WHERE department_heads.temporary_acting = 'Yes' GROUP BY departments.name;

How many acting statuses are there?

SELECT count(DISTINCT temporary_acting) FROM management

SELECT COUNT(DISTINCT acting_status) FROM actors;

How many departments are led by heads who are not mentioned?

SELECT count(*) FROM department WHERE department_id NOT IN (SELECT department_id FROM management);

SELECT COUNT(*) FROM departments WHERE head IS NULL;

What are the distinct ages of the heads who are acting?

SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'

SELECT DISTINCT age FROM heads WHERE status = 'acting';

List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born.

SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'

SELECT state_of_birth FROM secretaries WHERE department = 'Treasury' INTERSECT SELECT state_of_birth FROM secretaries WHERE department = 'Homeland Security';

Which department has more than 1 head at a time? List the id, name and the number of heads.

SELECT T1.department_id , T1.name , count(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING count(*) > 1

SELECT department_id, department_name, COUNT(head_id) AS number_of_heads FROM departments JOIN department_heads ON departments.department_id = department_heads.department_id GROUP BY department_id, department_name HAVING COUNT(head_id) > 1;

How many farms are there?

SELECT count(*) FROM farm

SELECT COUNT(*) FROM farms;

Count the number of farms.

SELECT count(*) FROM farm

SELECT COUNT(*) FROM farms

List the total number of horses on farms in ascending order.

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

SELECT farm_id, COUNT(horse_id) AS total_horses FROM horses GROUP BY farm_id ORDER BY total_horses ASC;

What is the total horses record for each farm, sorted ascending?

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

SELECT farm_id, COUNT(horse_id) AS total_horses FROM horses GROUP BY farm_id ORDER BY total_horses ASC;

What are the hosts of competitions whose theme is not "Aliens"?

SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'

SELECT host FROM competitions WHERE theme <> 'Aliens';

What are the themes of farm competitions sorted by year in ascending order?

SELECT Theme FROM farm_competition ORDER BY YEAR ASC

SELECT year, theme FROM farm_competitions ORDER BY year ASC;

What are the maximum and minimum number of cows across all farms.

SELECT max(Cows) , min(Cows) FROM farm

SELECT MAX(number_of_cows) AS max_cows, MIN(number_of_cows) AS min_cows FROM farms;

Return the maximum and minimum number of cows across all farms.

SELECT max(Cows) , min(Cows) FROM farm

SELECT MAX(number_of_cows), MIN(number_of_cows) FROM farms;

How many different statuses do cities have?

SELECT count(DISTINCT Status) FROM city

SELECT COUNT(DISTINCT status) FROM cities;

Count the number of different statuses.

SELECT count(DISTINCT Status) FROM city

SELECT COUNT(DISTINCT status) FROM table_name;

Show the years and the official names of the host cities of competitions.

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

SELECT year, city_official_name FROM competitions;

Give the years and official names of the cities of each competition.

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

SELECT competitions.year, cities.official_name FROM competitions JOIN cities ON competitions.city_id = cities.id;

Show the official names of the cities that have hosted more than one competition.

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

SELECT city_official_name FROM competitions GROUP BY city_official_name HAVING COUNT(DISTINCT competition_id) > 1;

What are the official names of cities that have hosted more than one competition?

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

SELECT official_name FROM cities WHERE hosted_competitions > 1;

Show the status of the city that has hosted the greatest number of competitions.

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

SELECT city, status FROM competitions GROUP BY city ORDER BY COUNT(*) DESC LIMIT 1;

What is the status of the city that has hosted the most competitions?

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

SELECT status FROM city WHERE id = ( SELECT city_id FROM competitions GROUP BY city_id ORDER BY COUNT(*) DESC LIMIT 1 )

Please show the themes of competitions with host cities having populations larger than 1000.

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

SELECT c.theme FROM competitions c JOIN cities ci ON c.host_city_id = ci.city_id WHERE ci.population > 1000;

What are the themes of competitions that have corresponding host cities with more than 1000 residents?

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

SELECT DISTINCT competition_theme FROM competitions JOIN host_cities ON competitions.host_city_id = host_cities.id WHERE host_cities.population > 1000;

Please show the different statuses of cities and the average population of cities with each status.

SELECT Status , avg(Population) FROM city GROUP BY Status

SELECT status, AVG(population) AS average_population FROM cities GROUP BY status;

What are the statuses and average populations of each city?

SELECT Status , avg(Population) FROM city GROUP BY Status

SELECT status, AVG(population) as average_population FROM cities GROUP BY status;

Please show the different statuses, ordered by the number of cities that have each.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

SELECT status, COUNT(DISTINCT city) AS city_count FROM your_table_name GROUP BY status ORDER BY city_count DESC;

Return the different statuses of cities, ascending by frequency.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

SELECT status, COUNT(*) AS frequency FROM cities GROUP BY status ORDER BY frequency ASC;

List the most common type of Status across cities.

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

SELECT Status, COUNT(Status) AS StatusCount FROM table_name GROUP BY Status ORDER BY StatusCount DESC LIMIT 1;

What is the most common status across all cities?

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

SELECT status, COUNT(*) as count FROM table_name GROUP BY status ORDER BY count DESC LIMIT 1;

List the official names of cities that have not held any competition.

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

SELECT city_official_name FROM cities WHERE city_id NOT IN ( SELECT DISTINCT city_id FROM competitions );

What are the official names of cities that have not hosted a farm competition?

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

SELECT city_name FROM cities WHERE city_id NOT IN (SELECT city_id FROM farm_competitions);