question_id
int64 5
1.53k
| db_id
stringclasses 11
values | question
stringlengths 23
286
| evidence
stringlengths 0
468
| SQL
stringlengths 29
1.23k
| difficulty
stringclasses 3
values |
|---|---|---|---|---|---|
895 | formula_1 | What is the average lap time for Lewis Hamilton in the 2009 Malaysian Grand Prix? | average lap time = AVG(milliseconds); 'Lewis Hamilton' refers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname; 'Malaysian Grand Prix' refers to races.name = 'Malaysian Grand Prix' | SELECT AVG(T2.milliseconds) FROM races AS T1 INNER JOIN lapTimes AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Lewis' AND T3.surname = 'Hamilton' AND T1.year = 2009 AND T1.name = 'Malaysian Grand Prix' | moderate |
896 | formula_1 | Calculate the percentage whereby Hamilton was not at the 1st track of the the f1 circuit since 2010. | percentage = DIVIDE(COUNT(raceId) where surname = 'Hamilton' and position>1), (COUNT(raceId) where surname = 'Hamilton'); since 2010 refers to year >= 2010 | SELECT CAST(COUNT(CASE WHEN T2.position <> 1 THEN T2.position END) AS REAL) * 100 / COUNT(T2.driverStandingsId) FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.surname = 'Hamilton' AND T1.year >= 2010 | challenging |
897 | formula_1 | Name the driver with the most winning. Mention his nationality and what is his maximum point scores. | Full name of the driver refers to drivers.forename and drivers.surname; the most winning refers to MAX(COUNT(wins)); average point scores refers to MAX(points); | SELECT T1.forename, T1.surname, T1.nationality, MAX(T2.points) FROM drivers AS T1 INNER JOIN driverStandings AS T2 ON T2.driverId = T1.driverId WHERE T2.wins >= 1 GROUP BY T1.forename, T1.surname, T1.nationality ORDER BY COUNT(T2.wins) DESC LIMIT 1 | moderate |
898 | formula_1 | How old is the youngest Japanese driver? What is his name? | date of birth refers to drivers.dob; The larger the birthday value, the younger the person is, and vice versa; Japanese refers to nationality = 'Japanese'; age = YEAR(CURRENT_TIMESTAMP) - YEAR(dob); | SELECT STRFTIME('%Y', CURRENT_TIMESTAMP) - STRFTIME('%Y', dob), forename , surname FROM drivers WHERE nationality = 'Japanese' ORDER BY dob DESC LIMIT 1 | simple |
901 | formula_1 | Name the races along with its circuit name and location for f1 races hosted in September 2005. | in September 2005 refers to MONTH(date) = 9 and YEAR(date) = 2005 | SELECT DISTINCT T2.name, T1.name, T1.location FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.year = 2005 AND STRFTIME('%m', T2.date) = '09' | simple |
902 | formula_1 | Which race was Alex Yoong in when he was in track number less than 20? | Alex Yoong refers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname;track number less than 10 refers to position < 20 | SELECT T1.name FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Alex' AND T3.surname = 'Yoong' AND T2.position < 20 | simple |
904 | formula_1 | State the race and year of race in which Michael Schumacher had his fastest lap. | fastest lap refers to min(milliseconds); Alex Yoong refers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname; | SELECT T1.name, T1.year FROM races AS T1 INNER JOIN lapTimes AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Michael' AND T3.surname = 'Schumacher' ORDER BY T2.milliseconds ASC LIMIT 1 | moderate |
906 | formula_1 | Which was Lewis Hamilton first race? What was his points recorded for his first race event? | first race refers to min(Year); Lewis Hamiltonrefers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname; | SELECT T1.name, T2.points FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Lewis' AND T3.surname = 'Hamilton' ORDER BY T1.year ASC LIMIT 1 | moderate |
909 | formula_1 | Among all European Grand Prix races, what is the percentage of the races were hosted in Germany? | European Grand Prix races refers to races.name = 'European Grand Prix';percentage = divide(COUNT(races where country = Germany and name = 'Europearn Grand Prix'),COUNT(races where name = 'Europearn Grand Prix'))*100 | SELECT CAST(COUNT(CASE WHEN T1.country = 'Germany' THEN T2.circuitID END) AS REAL) * 100 / COUNT(T2.circuitId) FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.name = 'European Grand Prix' | moderate |
910 | formula_1 | What's the location coordinates of Silverstone Circuit? | location coordinates refers to (lat, lng); Silverstone Circuit refers to circuits.name = 'Silverstone Circuit' | SELECT lat, lng FROM circuits WHERE name = 'Silverstone Circuit' | simple |
912 | formula_1 | What's the reference name of Marina Bay Street Circuit? | reference name refers to circuitRef; Marina Bay Street Circuit refers to circuits.name = 'Marina Bay Street Circuit' | SELECT circuitRef FROM circuits WHERE name = 'Marina Bay Street Circuit' | simple |
915 | formula_1 | Which country is the oldest driver from? | date of birth refers to drivers.dob; The larger the birthday value, the younger the person is, and vice versa; | SELECT nationality FROM drivers WHERE dob IS NOT NULL ORDER BY dob ASC LIMIT 1 | simple |
928 | formula_1 | Which driver ranked the first in the Canadian Grand Prix in 2007? Please give his reference name. | reference name refers to driverRef; Canadian Grand Prix refers to races.name = 'Canadian Grand Prix'; | SELECT T3.forename, T3.surname, T3.driverRef FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T1.name = 'Canadian Grand Prix' AND T2.rank = 1 AND T1.year = 2007 | moderate |
930 | formula_1 | In which Formula_1 race did Lewis Hamilton rank the highest? | rank the highest refers to min(rank); Lewis Hamilton refers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname; | SELECT name FROM races WHERE raceId IN ( SELECT raceId FROM results WHERE rank = 1 AND driverId = ( SELECT driverId FROM drivers WHERE forename = 'Lewis' AND surname = 'Hamilton' ) ) | simple |
931 | formula_1 | What was the fastest lap speed among all drivers in the 2009 Spanish Grand Prix? | the fastest lap speed among all refers to max(fastestLapSpeed); Spanish Grand Prix refers to races.name = 'Spanish Grand Prix'; | SELECT T2.fastestLapSpeed FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId WHERE T1.name = 'Spanish Grand Prix' AND T1.year = 2009 AND T2.fastestLapSpeed IS NOT NULL ORDER BY T2.fastestLapSpeed DESC LIMIT 1 | moderate |
933 | formula_1 | What was Lewis Hamilton's final rank in the 2008 Chinese Grand Prix? | Lewis Hamilton refers to the full name of the driver; Full name of the driver refers to drivers.forename and drivers.surname; final rank refers to positionOrder; Chinese Grand Prix refers to races.name = 'Chinese Grand Prix'; | SELECT T2.positionOrder FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Lewis' AND T3.surname = 'Hamilton' AND T1.name = 'Chinese Grand Prix' AND T1.year = 2008 | moderate |
937 | formula_1 | What's the finish time for the driver who ranked second in 2008's AustChineseralian Grand Prix? | finish time refers to time; Chinese Grand Prix refers to races.name = 'Chinese Grand Prix'; | SELECT T1.time FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId WHERE T1.rank = 2 AND T2.name = 'Chinese Grand Prix' AND T2.year = 2008 | simple |
940 | formula_1 | Among the drivers that finished the race in the 2008 Chinese Grand Prix, how many of them have participated in Formula_1 races? | COUNT(raceID) > 0 reveals that this driver participated in races; drivers who finished the race refers to time has value. | SELECT COUNT(*) FROM ( SELECT T1.driverId FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId WHERE T2.name = 'Chinese Grand Prix' AND T2.year = 2008 AND T1.time IS NOT NULL GROUP BY T1.driverId HAVING COUNT(T2.raceId) > 0 ) | moderate |
944 | formula_1 | How much faster in percentage is the champion than the driver who finished the race last in the 2008 Australian Grand Prix? | how much faster in percentage = divide(subtract(incremental time, champion time), last_driver time) * 100; last driver finished time = incremental time + champion time; only champion's finished time is represented by 'HH:MM:SS.mmm'; finished the game refers to time is not null | WITH time_in_seconds AS ( SELECT T1.positionOrder, CASE WHEN T1.positionOrder = 1 THEN (CAST(SUBSTR(T1.time, 1, 1) AS REAL) * 3600) + (CAST(SUBSTR(T1.time, 3, 2) AS REAL) * 60) + CAST(SUBSTR(T1.time, 6) AS REAL) ELSE CAST(SUBSTR(T1.time, 2) AS REAL) END AS time_seconds FROM results AS T1 INNER JOIN races AS T2 ON T1.raceId = T2.raceId WHERE T2.name = 'Australian Grand Prix' AND T1.time IS NOT NULL AND T2.year = 2008 ), champion_time AS ( SELECT time_seconds FROM time_in_seconds WHERE positionOrder = 1), last_driver_incremental AS ( SELECT time_seconds FROM time_in_seconds WHERE positionOrder = (SELECT MAX(positionOrder) FROM time_in_seconds) ) SELECT (CAST((SELECT time_seconds FROM last_driver_incremental) AS REAL) * 100) / (SELECT time_seconds + (SELECT time_seconds FROM last_driver_incremental) FROM champion_time) | challenging |
945 | formula_1 | How many circuits are there in Adelaide, Australia? | Australia is the country; Melbourne is the location of circuit; | SELECT COUNT(circuitId) FROM circuits WHERE location = 'Adelaide' AND country = 'Australia' | simple |
948 | formula_1 | What are the maximum points of British constructors? | maximum points = MAX(points); British is a nationality | SELECT MAX(T1.points) FROM constructorStandings AS T1 INNER JOIN constructors AS T2 on T1.constructorId = T2.constructorId WHERE T2.nationality = 'British' | simple |
950 | formula_1 | Please list the constructor names with 0 points at race 291. | race at 291 refers to raceID = 291; | SELECT T2.name FROM constructorStandings AS T1 INNER JOIN constructors AS T2 on T1.constructorId = T2.constructorId WHERE T1.points = 0 AND T1.raceId = 291 | simple |
951 | formula_1 | How many Japanese constructors have 0 points in 2 races? | 2 races refers to COUNT(raceID) = 2; Japanese refers to constructors.nationality = 'Japanese'; | SELECT COUNT(T1.raceId) FROM constructorStandings AS T1 INNER JOIN constructors AS T2 on T1.constructorId = T2.constructorId WHERE T1.points = 0 AND T2.nationality = 'Japanese' GROUP BY T1.constructorId HAVING COUNT(raceId) = 2 | simple |
954 | formula_1 | Please calculate the race completion percentage of Japanese drivers from 2007 to 2009. | from 2007 to 2009 refers to year between 2007 and 2009; race completion refers to time is not null; percentage = Divide(COUNT(DriverID where time is not null and year between 2007 and 2009),Count (DriverID where year between 2007 and 2009))*100; | SELECT CAST(SUM(IIF(T1.time IS NOT NULL, 1, 0)) AS REAL) * 100 / COUNT(T1.raceId) FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId INNER JOIN drivers AS T3 on T1.driverId = T3.driverId WHERE T3.nationality = 'Japanese' AND T2.year BETWEEN 2007 AND 2009 | challenging |
955 | formula_1 | What is the average time in seconds of champion for each year, before year 1975? | only champion's finished time is represented by 'HH:MM:SS.mmm'; finished the game refers to time is not null; before year 1975 refers to year < 1975; | WITH time_in_seconds AS ( SELECT T2.year, T2.raceId, T1.positionOrder, CASE WHEN T1.positionOrder = 1 THEN (CAST(SUBSTR(T1.time, 1, 1) AS REAL) * 3600) + (CAST(SUBSTR(T1.time, 3, 2) AS REAL) * 60) + CAST(SUBSTR(T1.time, 6,2) AS REAL ) + CAST(SUBSTR(T1.time, 9) AS REAL)/1000 ELSE 0 END AS time_seconds FROM results AS T1 INNER JOIN races AS T2 ON T1.raceId = T2.raceId WHERE T1.time IS NOT NULL ), champion_time AS ( SELECT year, raceId, time_seconds FROM time_in_seconds WHERE positionOrder = 1 ) SELECT year, AVG(time_seconds) FROM champion_time WHERE year < 1975 GROUP BY year HAVING AVG(time_seconds) IS NOT NULL | challenging |
959 | formula_1 | What is the fastest lap number of the champion in 2009? | in 2009 refers to year = 2009; Only the time of the champion shows in the format of "hour: minutes: seconds.millionsecond" | SELECT T1.fastestLap FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId WHERE T2.year = 2009 AND T1.time LIKE '_:%:__.___' | simple |
960 | formula_1 | What is the average of fastest lap speed in the 2009 Spanish Grand Prix race? | Spanish Grand Prix is the name of race refers to name = 'Spanish Grand Prix'; average fastest lap speed refers to avg(fastestLapSpeed); | SELECT AVG(T1.fastestLapSpeed) FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId WHERE T2.year = 2009 AND T2.name = 'Spanish Grand Prix' | moderate |
962 | formula_1 | From 2000 to 2005, what percentage of drivers who were born before 1985 and the lap numbers were over 50? | born before 1985 refers to year(dob)<1985; in 2000 to 2005 refers to year between 2000 and 2005; percentage = Divide(COUNT(driverId where year (dob) <1985 and laps >50),COUNT(DriverID where year between 2000 and 2005) *100; | SELECT CAST(SUM(IIF(STRFTIME('%Y', T3.dob) < '1985' AND T1.laps > 50, 1, 0)) AS REAL) * 100 / COUNT(*) FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId INNER JOIN drivers AS T3 on T1.driverId = T3.driverId WHERE T2.year BETWEEN 2000 AND 2005 | challenging |
963 | formula_1 | How many French drivers who obtain the laptime less than 02:00.00? | lap time less than 02:00.00 refers to seconds < 120; | SELECT COUNT(T1.driverId) FROM drivers AS T1 INNER JOIN lapTimes AS T2 on T1.driverId = T2.driverId WHERE T1.nationality = 'French' AND (CAST(SUBSTR(T2.time, 1, 2) AS INTEGER) * 60 + CAST(SUBSTR(T2.time, 4, 2) AS INTEGER) + CAST(SUBSTR(T2.time, 7, 2) AS REAL) / 1000) < 120 | moderate |
964 | formula_1 | List out the code for drivers who have nationality in American. | nationality = 'American' | SELECT code FROM drivers WHERE Nationality = 'American' | simple |
967 | formula_1 | State code numbers of top 3 yougest drivers. How many Netherlandic drivers among them? | youngest driver refers to Max (year(dob)); Netherlandic and Dutch refer to the same country | SELECT COUNT(*) FROM ( SELECT T1.nationality FROM drivers AS T1 ORDER BY JULIANDAY(T1.dob) DESC LIMIT 3) AS T3 WHERE T3.nationality = 'Dutch' | simple |
971 | formula_1 | Please state the reference name of the oldest German driver. | oldest refers to MIN(year(dob)); reference names appear in drverRef. | SELECT driverRef FROM drivers WHERE nationality = 'German' ORDER BY JULIANDAY(dob) ASC LIMIT 1 | simple |
972 | formula_1 | Which drivers who were born in 1971 and has the fastest lap time on the race? Give id and code of these drivers. | born in 1971 refers to year(dob) = 1971; has the fastest lap time refers to fastestLapTime has values | SELECT T2.driverId, T2.code FROM results AS T1 INNER JOIN drivers AS T2 on T1.driverId = T2.driverId WHERE STRFTIME('%Y', T2.dob) = '1971' AND T1.fastestLapTime IS NOT NULL | moderate |
977 | formula_1 | From race no. 50 to 100, how many finishers have been disqualified? | disqualified refers to statusID = 2, finisher refers to time! = null; race no. refers to raceId; raceId > 50 and raceId < 100; | SELECT SUM(IIF(time IS NOT NULL, 1, 0)) FROM results WHERE statusId = 2 AND raceID < 100 AND raceId > 50 | simple |
978 | formula_1 | How many times the circuits were held in Austria? Please give their location and coordinates. | location coordinates refers to (lat,lng); Austria refers to country = 'Austria'; | SELECT DISTINCT location, lat, lng FROM circuits WHERE country = 'Austria' | simple |
981 | formula_1 | On what year did the youngest driver had his first qualifying race? Also state the name, date and time of the race. | date of birth refers to drivers.dob; The larger the birthday value, the younger the person is, and vice versa; first qualifying race refers to MIN(races.date); | SELECT T3.year, T3.name, T3.date, T3.time FROM qualifying AS T1 INNER JOIN drivers AS T2 on T1.driverId = T2.driverId INNER JOIN races AS T3 on T1.raceId = T3.raceId WHERE T1.driverId = ( SELECT driverId FROM drivers ORDER BY dob DESC LIMIT 1 ) ORDER BY T3.date ASC LIMIT 1 | moderate |
988 | formula_1 | List down top 3 German drivers who has the shortest average pit stop duration and were born between 1980-1985. | Full name of the driver refers to drivers.forename and drivers.surname; born between 1980-1985 refers to 1980<= year(dob) <=1985; Average pitstop duration refers to Divide(SUM(duration),COUNT(duration)); shortest average refers to Min(avg(duration)); | SELECT T2.forename, T2.surname FROM pitStops AS T1 INNER JOIN drivers AS T2 on T1.driverId = T2.driverId WHERE T2.nationality = 'German' AND STRFTIME('%Y', T2.dob) BETWEEN '1980' AND '1985' GROUP BY T2.forename, T2.surname ORDER BY AVG(T1.duration) LIMIT 3 | challenging |
989 | formula_1 | Who is the champion of the Canadian Grand Prix in 2008? Indicate his finish time. | Only the time of the champion shows in the format of "hour: minutes: seconds.millionsecond"; | SELECT T1.time FROM results AS T1 INNER JOIN races AS T2 ON T1.raceId = T2.raceId WHERE T2.name = 'Canadian Grand Prix' AND T2.year = 2008 AND T1.time LIKE '_:%:__.___' | moderate |
990 | formula_1 | What is the constructor reference name of the champion in the 2009 Singapore Grand Prix? Please give its website. | the time of the champion shows in the format of "minutes: seconds.millionsecond" in which Max(time); constructor reference name refers to constructorRef; website refers to url | SELECT T3.constructorRef, T3.url FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId INNER JOIN constructors AS T3 on T1.constructorId = T3.constructorId WHERE T2.name = 'Singapore Grand Prix' AND T2.year = 2009 AND T1.time LIKE '_:%:__.___' | challenging |
717 | superhero | Please list all the superpowers of 3-D Man. | 3-D Man refers to superhero_name = '3-D Man'; superpowers refers to power_name | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = '3-D Man' | simple |
994 | formula_1 | Which constructor scored most points from Monaco Grand Prix between 1980 and 2010? List the score, name and nationality of this team. | Monaco Grand Priz refers to the race; race in year between 1980 and 2010 | SELECT SUM(T1.points), T2.name, T2.nationality FROM constructorResults AS T1 INNER JOIN constructors AS T2 ON T1.constructorId = T2.constructorId INNER JOIN races AS T3 ON T3.raceid = T1.raceid WHERE T3.name = 'Monaco Grand Prix' AND T3.year BETWEEN 1980 AND 2010 GROUP BY T2.name ORDER BY SUM(T1.points) DESC LIMIT 1 | challenging |
1,001 | formula_1 | What is full name of the racer who ranked 1st in the 3rd qualifying race held in the Marina Bay Street Circuit in 2008? | Ranked 1st in the 3rd qualifying race refer to MIN(q3); 2008 is the year of race; full name of racer = forename, surname | SELECT T2.forename, T2.surname FROM qualifying AS T1 INNER JOIN drivers AS T2 on T1.driverId = T2.driverId INNER JOIN races AS T3 ON T1.raceid = T3.raceid WHERE q3 IS NOT NULL AND T3.year = 2008 AND T3.circuitId IN ( SELECT circuitId FROM circuits WHERE name = 'Marina Bay Street Circuit' ) ORDER BY CAST(SUBSTR(q3, 1, INSTR(q3, ':') - 1) AS INTEGER) * 60 + CAST(SUBSTR(q3, INSTR(q3, ':') + 1, INSTR(q3, '.') - INSTR(q3, ':') - 1) AS REAL) + CAST(SUBSTR(q3, INSTR(q3, '.') + 1) AS REAL) / 1000 ASC LIMIT 1 | challenging |
1,002 | formula_1 | As of the present, what is the full name of the youngest racer? Indicate her nationality and the name of the race to which he/she first joined. | full name refers to forename+surname; Youngest racer = MAX(dob) | SELECT T1.forename, T1.surname, T1.nationality, T3.name FROM drivers AS T1 INNER JOIN driverStandings AS T2 on T1.driverId = T2.driverId INNER JOIN races AS T3 on T2.raceId = T3.raceId ORDER BY JULIANDAY(T1.dob) DESC LIMIT 1 | moderate |
1,003 | formula_1 | How many accidents did the driver who had the highest number accidents in the Canadian Grand Prix have? | number of accidents refers to the number where statusid = 3; Canadian Grand Prix refers to the race of name
| SELECT COUNT(T1.driverId) FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId INNER JOIN status AS T3 on T1.statusId = T3.statusId WHERE T3.statusId = 3 AND T2.name = 'Canadian Grand Prix' GROUP BY T1.driverId ORDER BY COUNT(T1.driverId) DESC LIMIT 1 | moderate |
1,011 | formula_1 | Which top 20 driver created the shortest lap time ever record in a Formula_1 race? Please give them full names. | shortest lap time refers to MIN(time); the time format for the shortest lap time is 'MM:SS.mmm' or 'M:SS.mmm'; full name of the driver refers to forename, surname | WITH lap_times_in_seconds AS (SELECT driverId, (CASE WHEN SUBSTR(time, 1, INSTR(time, ':') - 1) <> '' THEN CAST(SUBSTR(time, 1, INSTR(time, ':') - 1) AS REAL) * 60 ELSE 0 END + CASE WHEN SUBSTR(time, INSTR(time, ':') + 1, INSTR(time, '.') - INSTR(time, ':') - 1) <> '' THEN CAST(SUBSTR(time, INSTR(time, ':') + 1, INSTR(time, '.') - INSTR(time, ':') - 1) AS REAL) ELSE 0 END + CASE WHEN SUBSTR(time, INSTR(time, '.') + 1) <> '' THEN CAST(SUBSTR(time, INSTR(time, '.') + 1) AS REAL) / 1000 ELSE 0 END) AS time_in_seconds FROM lapTimes) SELECT T2.forename, T2.surname, T1.driverId FROM (SELECT driverId, MIN(time_in_seconds) AS min_time_in_seconds FROM lap_times_in_seconds GROUP BY driverId) AS T1 INNER JOIN drivers AS T2 ON T1.driverId = T2.driverId ORDER BY T1.min_time_in_seconds ASC LIMIT 20 | challenging |
1,014 | formula_1 | Please list the lap records for the circuits in Italy. | lap record means the fastest time recorded which refers to time | WITH fastest_lap_times AS (SELECT T1.raceId, T1.FastestLapTime, (CAST(SUBSTR(T1.FastestLapTime, 1, INSTR(T1.FastestLapTime, ':') - 1) AS REAL) * 60) + (CAST(SUBSTR(T1.FastestLapTime, INSTR(T1.FastestLapTime, ':') + 1, INSTR(T1.FastestLapTime, '.') - INSTR(T1.FastestLapTime, ':') - 1) AS REAL)) + (CAST(SUBSTR(T1.FastestLapTime, INSTR(T1.FastestLapTime, '.') + 1) AS REAL) / 1000) as time_in_seconds FROM results AS T1 WHERE T1.FastestLapTime IS NOT NULL ) SELECT T1.FastestLapTime as lap_record FROM results AS T1 INNER JOIN races AS T2 on T1.raceId = T2.raceId INNER JOIN circuits AS T3 on T2.circuitId = T3.circuitId INNER JOIN (SELECT MIN(fastest_lap_times.time_in_seconds) as min_time_in_seconds FROM fastest_lap_times INNER JOIN races AS T2 on fastest_lap_times.raceId = T2.raceId INNER JOIN circuits AS T3 on T2.circuitId = T3.circuitId WHERE T3.country = 'Italy' ) AS T4 ON (CAST(SUBSTR(T1.FastestLapTime, 1, INSTR(T1.FastestLapTime, ':') - 1) AS REAL) * 60) + (CAST(SUBSTR(T1.FastestLapTime, INSTR(T1.FastestLapTime, ':') + 1, INSTR(T1.FastestLapTime, '.') - INSTR(T1.FastestLapTime, ':') - 1) AS REAL)) + (CAST(SUBSTR(T1.FastestLapTime, INSTR(T1.FastestLapTime, '.') + 1) AS REAL) / 1000) = T4.min_time_in_seconds LIMIT 1 | challenging |
719 | superhero | Among the superheroes with the super power of "Super Strength", how many of them have a height of over 200cm? | super power of "Super Strength" refers to power_name = 'Super Strength'; a height of over 200cm refers to height_cm > 200 | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Super Strength' AND T1.height_cm > 200 | moderate |
723 | superhero | Among the superheroes with blue eyes, how many of them have the super power of "Agility"? | blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; super power of "Agility" refers to power_name = 'Agility' | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN colour AS T4 ON T1.eye_colour_id = T4.id WHERE T3.power_name = 'Agility' AND T4.colour = 'Blue' | moderate |
724 | superhero | Please list the superhero names of all the superheroes that have blue eyes and blond hair. | blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; blond hair refers to colour = 'Blond' and hair_colour_id = colour.id; super power of "Agility" refers to power_name = 'Agility' | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Blond' | challenging |
726 | superhero | Rank heroes published by Marvel Comics by their height in descending order. | name refers to superhero_name; the tallest hero refers to MAX(height_cm); published by Marvel Comics refers to publisher_name = 'Marvel Comics' | SELECT superhero_name, height_cm, RANK() OVER (ORDER BY height_cm DESC) AS HeightRank FROM superhero INNER JOIN publisher ON superhero.publisher_id = publisher.id WHERE publisher.publisher_name = 'Marvel Comics' | moderate |
728 | superhero | Rank superheroes from Marvel Comics by their eye color popularity, starting with the most common color. | the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; most common color refers to COUNT(superhero.id) DESC; | SELECT colour.colour AS EyeColor, COUNT(superhero.id) AS Count, RANK() OVER (ORDER BY COUNT(superhero.id) DESC) AS PopularityRank FROM superhero INNER JOIN colour ON superhero.eye_colour_id = colour.id INNER JOIN publisher ON superhero.publisher_id = publisher.id WHERE publisher.publisher_name = 'Marvel Comics' GROUP BY colour.colour | moderate |
730 | superhero | List the superheroes from Marvel Comics who have the super power of 'Super Strength'. | the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; super power of "Super Strength" refers to power_name = 'Super Strength'; | SELECT superhero_name FROM superhero AS T1 WHERE EXISTS (SELECT 1 FROM hero_power AS T2 INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Super Strength' AND T1.id = T2.hero_id)AND EXISTS (SELECT 1 FROM publisher AS T4 WHERE T4.publisher_name = 'Marvel Comics' AND T1.publisher_id = T4.id) | challenging |
732 | superhero | Which publisher published the slowest superhero? | the slowest superhero refers to attribute_name = 'Speed' where MIN(attribute_value); publisher refers to publisher_name | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN hero_attribute AS T3 ON T1.id = T3.hero_id INNER JOIN attribute AS T4 ON T3.attribute_id = T4.id WHERE T4.attribute_name = 'Speed' ORDER BY T3.attribute_value LIMIT 1 | moderate |
733 | superhero | How many gold-eyed superheroes did Marvel Comics publish? | gold-eyed refers to colour = 'Gold' where eye_colour_id = colour.id; superheroes that Marvel Comics published refers to publisher_name = 'Marvel Comics' | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN colour AS T3 ON T1.eye_colour_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.colour = 'Gold' | moderate |
736 | superhero | Who is the dumbest superhero? | the dumbest superhero refers to MIN(attribute_value) where attribute_name = 'Intelligence' | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Intelligence' ORDER BY T2.attribute_value LIMIT 1 | moderate |
737 | superhero | What is Copycat's race? | Copycat is the superhero_name; | SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.superhero_name = 'Copycat' | simple |
738 | superhero | Which superheroes have a durability attribute value of less than 50? | durability of less than 50 refers to attribute_name = 'Durability' AND attribute_value < 50 | SELECT superhero_name FROM superhero AS T1 WHERE EXISTS (SELECT 1 FROM hero_attribute AS T2 INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Durability' AND T2.attribute_value < 50 AND T1.id = T2.hero_id) | simple |
739 | superhero | What are the names of the superheroes with the power of death touch? | name of superheroes refers to refers to superhero_name; the power of death touch refers to power_name = 'Death Touch' | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Death Touch' | moderate |
740 | superhero | How many female superheroes have a strength value of 100? | female refers to gender = 'Female'; strength value of 100 refers to attribute_name = 'Strength' AND attribute_value = 100 | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.attribute_name = 'Strength' AND T2.attribute_value = 100 AND T4.gender = 'Female' | moderate |
743 | superhero | What is the percentage of superheroes who act in their own self-interest or make decisions based on their own moral code? Indicate how many of the said superheroes were published by Marvel Comics. | published by Marvel Comics refers to publisher_name = 'Marvel Comics'; superheroes who act in their own self-interest or make decisions based on their own moral code refers to alignment = 'Bad'; calculation = MULTIPLY(DIVIDE(SUM(alignment = 'Bad); count(id)), 100) | SELECT (CAST(COUNT(*) AS REAL) * 100 / (SELECT COUNT(*) FROM superhero)), CAST(SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) AS REAL) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN alignment AS T3 ON T3.id = T1.alignment_id WHERE T3.alignment = 'Bad' | challenging |
744 | superhero | Between DC and Marvel Comics, which publisher has published more superheroes? Find the difference in the number of superheroes they have published. | DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; calculation = SUBTRACT(SUM(publisher_name = 'Marvel Comics'), SUM(publisher_name = 'DC Comics')) | SELECT SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id | challenging |
745 | superhero | Give the publisher ID of Star Trek. | Star Trek is the publisher_name; | SELECT id FROM publisher WHERE publisher_name = 'Star Trek' | simple |
747 | superhero | What is the total number of superheroes without full name? | superheroes without full name refers to full_name IS NULL | SELECT COUNT(id) FROM superhero WHERE full_name IS NULL | simple |
750 | superhero | What is the average weight of all female superheroes? | female refers to gender = 'Female'; average weight refers to AVG(weight_kg) | SELECT AVG(T1.weight_kg) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Female' | simple |
751 | superhero | List down at least five superpowers of male superheroes. | male refers to gender = 'Male'; superpowers refers to power_name; | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T3.id = T2.power_id INNER JOIN gender AS T4 ON T4.id = T1.gender_id WHERE T4.gender = 'Male' LIMIT 5 | moderate |
753 | superhero | Among the superheroes with height from 170 to 190, list the names of the superheroes with no eye color. | height from 170 to 190 refers to height_cm BETWEEN 170 AND 190; no eye color refers to colour = 'No Colour' | SELECT DISTINCT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.height_cm BETWEEN 170 AND 190 AND T2.colour = 'No Colour' | moderate |
758 | superhero | Provide the hair colour of the human superhero who is 185 cm tall. | 185 cm tall refers to height_cm = 185; human superhero refers to race = 'human'; hair colour refers to colour where hair_colour_id = colour.id; | SELECT DISTINCT T3.colour FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T1.height_cm = 185 AND T2.race = 'Human' | moderate |
760 | superhero | In superheroes with height between 150 to 180, what is the percentage of heroes published by Marvel Comics? | height between 150 to 180 refers to height_cm BETWEEN 150 AND 180; heroes published by Marvel Comics refers to publisher_name = 'Marvel Comics'; calculation = MULTIPLY(DIVIDE(SUM(publisher.id = 13)), COUNT(publisher.id), 100) | SELECT CAST(COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.height_cm BETWEEN 150 AND 180 | challenging |
761 | superhero | Among the male superheroes, list the super hero names of superheroes with weight greater than the 79% average weight of all superheroes. | super hero names refers to superhero_name;male superheros refers to gender = 'Male';Calculation = weight_kg > MULTIPLY(AVG(weight_kg), 0.79) | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Male' AND T1.weight_kg * 100 > ( SELECT AVG(weight_kg) FROM superhero ) * 79 | moderate |
764 | superhero | What are the superpowers of heroes with ID 1? | superpowers refers to power_name; heroes with ID 1 refers to hero_id = 1; | SELECT DISTINCT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T1.hero_id = 1 | simple |
765 | superhero | How many heroes have stealth power? | stealth power refers to power_name = 'Stealth'; | SELECT COUNT(T1.hero_id) FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Stealth' | simple |
766 | superhero | What is the hero's full name with the highest attribute in strength? | highest attribute in strength refers to MAX(attribute_value) WHERE attribute_name = 'strength'; | SELECT T1.full_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Strength' ORDER BY T2.attribute_value DESC LIMIT 1 | moderate |
769 | superhero | Which superhero has the most durability published by Dark Horse Comics? | which superhero refers to superhero_name; most durability refers to MAX(attribute_value) WHERE attribute_name = 'durability'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T3.id = T2.attribute_id INNER JOIN publisher AS T4 ON T4.id = T1.publisher_id WHERE T4.publisher_name = 'Dark Horse Comics' AND T3.attribute_name = 'Durability' ORDER BY T2.attribute_value DESC LIMIT 1 | challenging |
772 | superhero | List the eyes, hair and skin colour of all female superheroes published by Dark Horse Comics. | eyes refers to eye_colour_id; hair refers to hair_colour_id; skin colour refers to skin_colour_id; female superheroes refers to gender = 'Female'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'; | SELECT T1.eye_colour_id, T1.hair_colour_id, T1.skin_colour_id FROM superhero AS T1 INNER JOIN publisher AS T2 ON T2.id = T1.publisher_id INNER JOIN gender AS T3 ON T3.id = T1.gender_id WHERE T2.publisher_name = 'Dark Horse Comics' AND T3.gender = 'Female' | challenging |
773 | superhero | Which superhero has the same eyes, hair and skin colour? Indicate the publisher of the superhero. | which superhero refers to superhero_name; the same eyes, hair and skin colour refers to hair_colour_id = skin_colour_id AND hair_colour_id = eye_colour_id; publisher refers to publisher_name; | SELECT T1.superhero_name, T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.eye_colour_id = T1.hair_colour_id AND T1.eye_colour_id = T1.skin_colour_id | challenging |
775 | superhero | What is the percentage of blue female superheroes among all female superheroes? | percentage = MULTIPLY(DIVIDE(SUM(colour = 'Blue' WHERE gender = 'Female'), COUNT(gender = 'Female')), 100); blue refers to the color = 'Blue' WHERE skin_colour_id = colour.id; female refers to gender = 'Female'; | SELECT CAST(COUNT(CASE WHEN T3.colour = 'Blue' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.gender = 'Female' | challenging |
779 | superhero | How many powers does Amazo hero have? | Amazo hero refers to superhero_name = 'Amazo'; | SELECT COUNT(T1.power_id) FROM hero_power AS T1 INNER JOIN superhero AS T2 ON T1.hero_id = T2.id WHERE T2.superhero_name = 'Amazo' | simple |
781 | superhero | Provide the heights of the heroes whose eye colours are amber. | heights of the heroes refers to height_cm; eye colours are amber refers to colour.colour = 'Amber' WHERE eye_colour_id = colour.id; | SELECT T1.height_cm FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T2.colour = 'Amber' | simple |
782 | superhero | List the heroes' names whose eyes and hair colours are both black. | heroes' names refers to superhero_name; eyes and hair colours are both black refers to eye_colour_id AND hair_colour_id WHERE colour.colour = 'Black'; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id AND T1.hair_colour_id = T2.id WHERE T2.colour = 'Black' | moderate |
785 | superhero | Describe the names of neutral alignment superheroes. | names of superheroes refers to superhero_name; neutral alignment refers to alignment = 'Neutral'; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral' | simple |
786 | superhero | How many heroes have the highest attribute value in strength? | highest attribute value in strength refers to MAX(attribute_value) WHERE attribute_name = 'Strength'; | SELECT COUNT(T1.hero_id) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id WHERE T2.attribute_name = 'Strength' AND T1.attribute_value = ( SELECT MAX(attribute_value) FROM hero_attribute ) | moderate |
788 | superhero | How many percent of female heroes were published by Marvel Comics? | percent = MULTIPLY(DIVIDE(SUM(gender = 'Female' WHERE publisher_name = 'Marvel Comics'), COUNT(publisher_name = 'Marvel Comics')), 100); female heroes refers to gender = 'Female'; Marvel Comics refers to publisher_name = 'Marvel Comics'; | SELECT CAST(COUNT(CASE WHEN T3.gender = 'Female' AND T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) / COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) * 100 FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id | challenging |
790 | superhero | Calculate the difference between Emil Blonsky's weight and Charles Chandler's weight. | difference = SUBTRACT(SUM(weight_kg WHERE full_name = 'Emil Blonsky'), SUM(weight_kg WHERE full_name = 'Charles Chandler')); Emil Blonsky is the full name of superhero; Charles Chandler is the full name of superhero; | SELECT ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Emil Blonsky' ) - ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Charles Chandler' ) AS CALCULATE | moderate |
791 | superhero | Calculate the average height for all superhero. | average = DIVIDE(SUM(height_cm), COUNT(all heros)); | SELECT CAST(SUM(height_cm) AS REAL) / COUNT(id) FROM superhero | simple |
792 | superhero | What is Abomination's superpower? | Abomination refers to superhero_name = 'Abomination'; superpower refers to power_name; | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Abomination' | simple |
794 | superhero | Which hero was the fastest? | which hero refers to superhero_name; fastest refers to MAX(attribute_value) WHERE attribute_name = 'Speed'; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Speed' ORDER BY T2.attribute_value DESC LIMIT 1 | moderate |
796 | superhero | State all of 3-D Man's attributes along with their values. | 3-D Man is the superhero_name. attributes refers to attribute_name; values refers to attribute_value; | SELECT T3.attribute_name, T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = '3-D Man' | moderate |
797 | superhero | Which superheroes have blue eyes with brown hair? | which superheroes refers to superhero_name; blue eyes refers to color = 'Blue' and color.id = eye_colour_id; brown hair refers to color = 'Brown' and color.id = hair_colour_id; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Brown' | moderate |
798 | superhero | What is the publisher for Hawkman, Karate Kid and Speedy? | publisher refers to publisher_name; Hawkman refers to superhero_name = 'Hawkman'; Karate Kid refers to superhero_name = 'Karate Kid'; Speedy refers to superhero_name = 'Speedy'; | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name IN ('Hawkman', 'Karate Kid', 'Speedy') | moderate |
800 | superhero | Calculate the percentage of superheroes with blue eyes. | percentage = MULTIPLY(DIVIDE(SUM(superhero_name WHERE color = 'Blue'), COUNT(superhero_name)), 100.0); blue eyes refers to color = 'Blue' and color.id = eye_colour_id = 7; | SELECT CAST(COUNT(CASE WHEN T2.colour = 'Blue' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id | moderate |
801 | superhero | Find the ratio between male superheroes and female superheroes. | ratio = DIVIDE(SUM(gender_id = 1) / SUM(gender_id = 2)); male superheroes refers to gender = 'Female'; female superheroes refers to gender = 'Male'; | SELECT CAST(COUNT(CASE WHEN T2.gender = 'Male' THEN T1.id ELSE NULL END) AS REAL) / COUNT(CASE WHEN T2.gender = 'Female' THEN T1.id ELSE NULL END) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id | moderate |
806 | superhero | Provide the eye colour of the superhero who has Karen Beecher-Duncan as their full name. | eye colour refers to colour.colour where eye_colour_id = colour.id; Karen Beecher-Duncan is the full name of superhero; | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.full_name = 'Karen Beecher-Duncan' | simple |
819 | superhero | In superheroes with missing weight data, calculate the difference between the number of superheroes with blue eyes and no eye color. | missing weight data refers to weight_kg = 0 OR T1.weight_kg = NULL; difference = SUBTRACT(SUM(colour.id = 7), SUM(colour.id = 1)); blue eyes refers to eye_colour_id WHERE colour.id = 7; no eye color refers to eye_colour_id WHERE colour.id = 1; | SELECT SUM(CASE WHEN T2.id = 7 THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.id = 1 THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.weight_kg = 0 OR T1.weight_kg is NULL | challenging |
822 | superhero | How many green-skinned villains are there in the superhero universe? | green-skinned refers to colour.colour = 'Green' WHERE skin_colour_id = colour.id; villains refers to alignment = 'Bad'; | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.alignment = 'Bad' AND T3.colour = 'Green' | moderate |
824 | superhero | Identify superheroes who can control wind and list their names in alphabetical order. | superheroes refers to superhero_name; can control wind refers to power_name = 'Wind Control'; | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Wind Control' ORDER BY T1.superhero_name | moderate |
825 | superhero | Identify the gender of the superhero who has the ability of Phoenix Force. | ability of Phoenix Force refers to power_name = 'Phoenix Force'; | SELECT T4.gender FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.power_name = 'Phoenix Force' | moderate |
829 | superhero | Which publisher created more superheroes: DC or Marvel Comics? Find the difference in the number of superheroes. | DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; difference = SUBTRACT(SUM(publisher_name = 'DC Comics'), SUM(publisher_name = 'Marvel Comics')); | SELECT SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id | challenging |
531 | codebase_community | Which user has a higher reputation, Harlan or Jarrod Dixon? | "Harlan" and "Jarrod Dixon" are both DisplayName; highest reputation refers to Max(Reputation) | SELECT DisplayName FROM users WHERE DisplayName IN ('Harlan', 'Jarrod Dixon') AND Reputation = ( SELECT MAX(Reputation) FROM users WHERE DisplayName IN ('Harlan', 'Jarrod Dixon') ) | simple |
532 | codebase_community | Please list the display names of all the users whose accounts were created in the year 2011. | account created in the year 2011 refers to year(CreationDate) = 2011 | SELECT DisplayName FROM users WHERE STRFTIME('%Y', CreationDate) = '2011' | simple |
533 | codebase_community | How many users last accessed the website after 2014/9/1? | last accessed after 2014/9/1 refers to LastAccessDate > '2014-09-01' | SELECT COUNT(Id) FROM users WHERE date(LastAccessDate) > '2014-09-01' | simple |
Subsets and Splits